Answer:
The answer is below
Explanation:
Speed is the ratio of total distance traveled to the total time taken. It is given by the formula:
Speed = Distance / time taken
Given that the speed = The polynomial 45.000 mph.
In a day there are 24 hours, hence, the distance traveled is:
Speed = Distance / time taken
45 mph = Distance / 24 hours
Distance = 45 mph × 24 h = 1080 miles
But 1 mile = 1609.34 m
1080 miles = [tex]1080\ miles*\frac{1609.34 \ m}{1\ miles}=1738092\ m[/tex]
Given that Altuve = 1.65 m
Hence, the number of Altuve traveled = 1738092 m / 1.65 m = 1053389
1053389 Altuves was traveled
A biker accelerates from rest to 10 m/s in 5 seconds. What is the biker's
acceleration? Calculate for the missing variable
Your answer
Answer:
It starts from rest so Vi=0
Vf=10 m/s
t=5 seconds
Explanation:
a=Vf-Vi/t
a=10-0/5
a=10/5
a=2m/s^s
What happens to the acceleration of an object if the net force on it increases?
OA. The acceleration increases.
OB.
The acceleration decreases.
O C.
The acceleration becomes zero.
OD.
The acceleration remains the same.
Answer:
A
Explanation:
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased
Which phrase is not an example of intracellular communication?
A. molecular movement within a cell
B. reaction to pheromones
C.molecule in a cell changes function of cell
D. control of cell division
Answer:
The answer is C
Explanation:
I ave K12 and i just finished it.
The phrase which is not an example of intracellular communication is :
C) Molecule in a cell changes function of cell.
"Intracellular communication"The phrase which is not an example of intracellular communication is the molecule in a cell changes function of cell.
The intracellular communication could be a sort of communication which takes put inside a cell or interior a cell.
The intracellular speaks to inside a cell, subsequently, the development of the particle inside a cell may be with cytoplasmic gushing, cargo vesicle transport or any other instrument will speak to the intracellular communication.
Thus, the correct answer is C.
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Solve.
(3.0 × 107)x (1.5 × 103)
Answer:49594.5
Explanation:
The time period of a wave T is the the time taken to produce one complete wave. If the frequency of a wave is 2 Hz, what is it’s time period?
Answer:
0.5s
Explanation:
if the frequency is 2Hz that means it makes 2 complet cycles in one second. The time period for one cycle would be 0.5s
A force of 200N is creating a pressure of 50Pa on a surface. Calculate the area of the surface.
Answer:
4kg
Explanation:
pressure=50pa
force=200N
Area=?
now,
pressure=force/area
50=200/area
area=200/50
area=4kg
The pressure is the forces acting on a given area. Hence, the area of the surface with a pressure of 50 Pa by a force of 200 N is 4 m².
What is force?Force is an external agent acting on a object to deform it or to change its state form motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction. The unit of force is Newton (N).
Pressure is the force applied on unit area. Thus, as the force increases, pressure increases. Pressure can have the units in atm, pa, N/m² etc.
Pressure = Force / area.
Given that force = 200 N
pressure = 50 Pa = 50 N/m²
Therefore, area = force/pressure
= 200 N / 50 Pa
= 4 m²
Therefore, the area of the surface is 4 m².
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TEST
16. What is the average velocity of Mulan as
she covers 20 min 3.5 s to meet her
matchmaker?
0.175 m/s
10 m/s
70 m/s
5.71 m/s
CLEAR ALL
4.46 x 1010 /6.52x 10-8 =
Answer:
690.8895705521 × 10^8 is the perfect answer of your question.
A cyclist must travel 800 kilometers. How many days will the trip take if the cyclist travels at an average speed of 16 km/h
Answer:
2 days 2 hours or 50 hours
Explanation:
800/16=50
Explain the process that causes dew to form on blades of grass.
Answer:
AHAHHAH DEW DEW
Explanation:
Condensation causes dew to form on blades of grass. This is because the water molecules react to the grass when it is heated, and the surroundings became cool. The molecules would bring to calm and turn to liquid.Image result for heart eyes cat emoji
How does the “Sum of Forces” help you?
pls helppppppppppppppp
Explanation:
maaf kalau saya salah pada jawaban anda
PLEASE HELP ASAP!!!!
T1 = 2×W / squrt (3) +1
T2 = squrt(6) ×W/ squrt (3) +1
Here, T1 is along A.
T2 is along B
W = 250N.
Yo can directly use above formula to find solution.
In general, which factor is NOT critical when beginning an exercise program? A. using appropriate protective equipment during exercise B. finding friends who like to exercise the same way you do C. seeing your doctor for a physical assessment prior to beginning exercise D. choosing clothing that is designed to match your exercise program Please select the best answer from the choices provided.
O A
О В
O C
PLEASE HELP!!!
Answer:
B. I looked it up I hope it's right
Explanation:
i hope this helps.
Answer:
its obviously C
Explanation:
i smart like dat
A 95kg clock initially at rest on a horizontal floor requires a 560N horizontal force to set it in motion. After the clock is in motion, in horizontal force of 650N
Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is [tex]\mu_s = 0.60[/tex]
The value for static friction is [tex]\mu_k = 0.70[/tex]
Explanation:
From the question we are told that
The mass of the clock is [tex]m = 95 \ kg[/tex]
The first horizontal force is [tex]F _s = 560 \ N[/tex]
The second horizontal force is [tex]F _k = 650 \ N[/tex]
Generally the static frictional force is equal to the first horizontal force
So
[tex]F _s = m * g * \mu_s[/tex]
=> [tex]560 = 95 * 9.8 * \mu_s[/tex]
=> [tex]\mu_s = 0.60[/tex]
Generally the kinetic frictional force is equal to the second horizontal force
So
[tex]F _k = m * g * \mu_k[/tex]
[tex]650 = 95 * 9.8 * \mu_k[/tex]
[tex]\mu_k = 0.70[/tex]
Erica forgot to put gas in her car (again) for two weeks. The graph below shows the last few seconds of her car being stalled along Elkins Drive st 7:23 am Friday. During the time shown, what was the acceleration of her car?
a 54 m
b 108 m/s
c 3 m/s^2
D -3 m/s^2
Answer:
Option (D) : - 3 m/s^2
Explanation:
Acceleration = Slope of v-t graph
= 18/6
= - 3 m/s^2 (-ive since the car is decelerating )
Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 m/s
It lands on the ground with a final speed of 6.0 m/s
How long is the ball in the air?
Round the answer to two significant digits
Answer:
The correct answer is t = 0.92s
Explanation:
Initial velocity v0 = 3.0 m/s
Displacement Δy = ?
Acceleration a = -9.8m/s2
Final velocity v = -6.0m/s
Time t=? Target unknown
We can use the kinematic formula missing Δy to solve for the target unknown t:
V=v0+at
We can rearrange the equation to solve to t:
V-v0=at
t= v-v0/a
Substituting the known value into the kinematic formula gives:
t= (-6.0m/s)-(3.0m/s)
————————————
-9.8m/s2
= -9m/s
—————-
-9.8m/s2
=0.92s
Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 m/s. It lands on the ground with a final speed of 6.0 m/s.
How long is the ball in the air?
Answer: 0.92
Matter is all around us and is made of atoms. How are atoms of different elements different from each other? How do these differences relate to their properties?
Answer:
it all depends on the protons and the neutrons of that element.
Describe the relationship between air time and range.
Answer: For the angles below 40, The air time and range are directly proportional meaning that if air time increases, the range increases. Like said earlier, the total traveled distance in the x-direction depends on the initial velocity and time.
What other angle would give the same range at 19 degrees?
Answer:
I think it is acute angle.
Explanation:
Because it is an angle between 0° and 90°. Hope this answer wil help you.
An object example to decrease pressure.
Answer:
To reduce pressure - decrease the force or increase the area the force acts on. If you were standing on a frozen lake and the ice started to crack you could lie down to increase the area in contact with the ice. The same force (your weight) would apply, spread over a larger area, so the pressure would reduce.
Answer:
You can use the following things
Explanation:
Rubber ball - A rubber ball can decrease pressure if you throw it against the wall and catch it.
Rubber squeezy toy - If you squeeze this in your hands also you can decrease pressure.
Hope this helps....
Have a nice day!!!!
Explain the haudralic break system
Answer:
A hydraulic braking system transmits brake-pedal force to the wheel brakes through pressurized fluid.
Explanation:
A car accelerates from rest at 7.55 m/s2 for 4.25 s.
Determine the final velocity of the car.
And calculate the cars displacement.
Explanation:
This problem is on the motion of a car.
given data.
acceleration a=7.55m/s
time t= 4.25 sec
1. Determine the final velocity of the car.
we know that
acceleration= velocity/time
substituting our given data we have
7.55= v/4.25
v=7.55*4.25
v=32.08m/s
2. calculate the cars displacement.
we also know that
velocity= distance/time
distance= velocity*time
distance= 32.04*4.25
distance= 136.37m
Multiple Choice
Which of the following was not required by the Massachusetts Education Law of 1642?
O
Children were to be educated in basic religious principles and the laws of the commonwealth.
O Children were to be able to read and write.
O Children of servants were included in the law as recipients of said education.
Children were to be sent to designated schoolmasters for their learning.
Answer:
What was not required by the Massachusetts Education law of 1642 is;
Children were to be sent to designated schoolmaster for their learning
Explanation:
The Law of 1642 required that parents and master see to it that their children knew the principles of religion and the capital laws of the commonwealth.
The important aspects of the 1642 Law includes;
1) The responsibility for the basic education and literacy of a child are those of the parents and masters of child apprentices
2) Reading and writing competency of all children and servants are a requirement
3) It is the duty of the government, where a parent or master are unable to meet their tutoring responsibility, to see that a child is placed where the basic educational requirement will be met.
The role of a schoolmaster or the setting of a formal school were yet to be formed as at that time.
Answer:
The correct answer is Children were to be sent to designated schoolmasters for their learning
The responsibility of educating children was on parents and apprenticeship masters, not on designated teachers or schoolmasters. However, the law did allow the government to step in if the supervising adults failed in their responsibilities.
Explanation:
An object is projected with initial speed v0 from the edge of the roof of a building that has height H. The initial velocity of the object makes an angle α0 with the horizontal. Neglect air resistance. If α0 is 90∘, so that the object is thrown straight up (but misses the roof on the way down), what is the speed v of the object just before it strikes the ground?
Answer:
Explanation:
Initial velocity u = V₀ in upward direction so it will be negative
u = - V₀
Displacement s = H . It is downwards so it will be positive
Acceleration = g ( positive as it is also downwards )
Using the formula
v² = u² + 2 g s
v² = (- V₀ )² + 2 g H
= V₀² + 2 g H .
v = √ ( V₀² + 2 g H )
A soccer ball is kicked horizontally. What is its average speed if its displacement is 55.0 m after 12.00 s? What formula was used to solve this problem?
4.58 m/s
Speed = displacement / time
if the coefficient of friction is root 3 the angle of friction is
Explanation:
The coefficient of friction = tanθ,
the angle would be 30∘
Answer:
Tan¯¹ /3=60 degree
Explanation:
you know coefficient is friction is equal to tan 0 equal to square root of 3 is equal to tan of civil 20 skills equal to 60 degree
_________________ are labels for ranges of weight that are greater than what is generally considered healthy for a given height.
A. Overweight and obesity
B. Overweight and morbidity
C. Obesity and diabetes
D. Obesity and heft
Answer: A. Overweight and obesity
Explanation:
Overweight and obesity are labeled for ranges of weight that are greater than what is generally considered healthy for a given height. Hence, option A is correct.
What are Overweight and obesity?Overweight and obesity are calculated by Body Mass Index (BMI). BMI is a person's weight in kilograms divided by the square of height in meters. The healthy adult human BMI ranges from 18.5 to 25.
If BMI is less than 18.5, it falls within the underweight range. If the BMI ranges from 25.0 to 29.9, it falls within the overweight range. If the BMI is greater than 30, it comes under the obesity range. A high BMI indicates high fatness.
Obesity and overweight are determined as an abnormal growth or excessive fat accumulation in the healthy range. It is caused by an energy imbalance between calories consumed and calories expended.
Obesity and Being overweight can cause certain diseases and health issues. It increases the risk of high blood pressure, heart disease, diabetes, and stroke.
It is important to maintain a healthy range BMI. Obesity and overweight are reduced by making the choice of healthier foods and regular physical activities like yoga and exercise.
Hence, The correct option is A) Overweight and Obesity.
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Find the velocity of a ball traveling 5 meters for 20 seconds.
Formula:
Substitute:
Solution:
Answer:
The answer is
0.25 m/sExplanation:
The velocity of w given body given the distance and time taken can be found by using the formula
[tex]velocity = \frac{distance}{time} \\ [/tex]
From the question
distance = 5 m
time = 20 s
The velocity of the ball is
[tex]velocity = \frac{5}{20} = \frac{1}{4} \\ [/tex]
We have the final answer as
0.25 m/sHope this helps you
Formula: v = d/t
v = velocity
d = distance
t = time
We are given the distance (5 meters) and the time (20 seconds). Solve with these given values.
v = 5/20
v = 1/4 m/s
Best of Luck!
If an object is moving and it changes its position by 2 min
every 4 s starting from the origin, then the position vs. time
graph is:
Answer: a straight line with a positive slope
Explanation:
If an object is moving and it changes its position by 2 units every 4 s starting from the origin,
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second.
Learn more about speed from here If an object is moving and it changes its position by 2 units every 4 s starting from the origin,
speed = distance /time
= 2 units / 4 seconds
= 0.5 units/seconds
Thus, the speed of the object would be 0.5 units /seconds
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the question seems incomplete the complete question is If an object is moving and it changes its position by 2 units every 4 s starting from the origin, then the position vs. time graph is
A dog walks 8.0 meters due north and then 6.0 meters due east. Determine the magnitude of the dog's total displacement to the nearest tenths
Answer:
the magnitude of the dog's total displacement to the nearest tenths = 53.12°
Explanation:
Given that:
a dog walks 8.0m due to the north and 6.0 m due east.
We can determine the magnitude of the dog's total displacement by using the Pythagoras theorem.
Consider the north direction be the opposite and the east direction to be the adjacent, therefore the hypotenuse will be the dog's total displacement.
So, suppose hypotenuse is represented by a
the opposite represented by b, and the adjacent represented by c
Then;
a² = b² + c²
a² = 8² + 6²
a² = 64 + 46
a² = 100
a =[tex]\sqrt{100[/tex]
a = 10.0 m
However, the magnitude of the dog's total displacement is calculated by taking the tangent of the system.
tan θ = opposite / adjacent
tan θ = b/c
tan θ = 8/6
tan θ = 4/3
tan θ = 1.333
θ = tan⁻¹ (1.333)
θ = 53.12
the magnitude of the dog's total displacement to the nearest tenths = 53.12°