[tex]x^{2}[/tex] - 55 = 26
Answer: [tex]x=9,\:x=-9[/tex]
Steps:
[tex]x^2-55=26[/tex]
[tex]\mathrm{Add\:}55\mathrm{\:to\:both\:sides}[/tex]
[tex]x^2-55+55=26+55[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]x^2=81[/tex]
[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]
[tex]x=\sqrt{81},\:x=-\sqrt{81}[/tex]
[tex]\sqrt{81}[/tex]= 9
[tex]-\sqrt{81}=-9[/tex]
So That Equals:
[tex]x=9,\:x=-9[/tex]
#[tex]Hardnessed To Perfection[/tex]
Describe the overall shape of this distribution. Explain your answer in complete sentences.
Answer: The histogram is skewered to the right (right-skewered)
Step-by-step explanation:
The peak veers to the left and the tail is towards the right.
The histogram given is right-skewed.
What is a histogram?
A histogram is a representation of the distribution of data with intervals.
We have,
Right-skewed and left-skewed are terms used to describe the shape of a data distribution.
A right-skewed (or positively skewed) distribution is one in which the tail on the right-hand side of the graph is longer or fatter than the tail on the left-hand side.
A left-skewed (or negatively skewed) distribution is the opposite of a right-skewed distribution.
In this case, the tail on the left-hand side of the graph is longer or fatter than the tail on the right-hand side.
Now,
We see that the histogram given is right-skewed because the tail on the right-hand side of the graph is longer or fatter than the tail on the left-hand side.
Thus,
The histogram given is right-skewed.
Learn more about histograms here:
https://brainly.com/question/16819077
#SPJ3
what is 75 as a fraction of 125? give your answer in its simplest form.
75 as a fraction of 125 would be 75/125
Now Lets simplify
75/25=3
125/25=5
We get 3/5
We can not reduce 3/5 anymore, so the answer is 3/5
A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25. 75 is 3/5 fraction of 125.
What is a Fraction?A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.
Let 75 be x fraction of 125. Therefore, we can write the statement as,
x × 125 = 75
x = 75/125
x = 3 /5
Hence, 75 is 3/5 fraction of 125.
Learn more about Fraction:
https://brainly.com/question/1301963
#SPJ2
1 1/4×-1 1/3 is equals to?
Answer: [tex]-\frac{5}{12}[/tex]
Steps:
[tex]1\frac{1}{4}\times \left(-1\right)\frac{1}{3}[/tex]
Convert mixed numbers to improper fractions: [tex]1\frac{1}{4}[/tex][tex]=\frac{5}{4}[/tex]
[tex]=\frac{5}{4}\times \left(-1\right)\frac{1}{3}[/tex]
[tex]\mathrm{Apply\:the\:rule}:\quad \:a\left(-b\right)=-ab[/tex]
[tex]\frac{5}{4}\left(-1\right)=-\frac{5}{4}\times \:1[/tex]
[tex]=-\frac{5}{4}\times \:1\times \frac{1}{3}[/tex]
[tex]\mathrm{Apply\:rule}\:a\times 1=a[/tex]
[tex]=-\frac{5}{4}\times \frac{1}{3}[/tex]
[tex]\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}[/tex]
[tex]\frac{5}{4}\times \frac{1}{3}=\frac{5\times \:1}{4\times \:3}[/tex]
[tex]=-\frac{5\times \:1}{4\times \:3}[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:5\times \:1=5[/tex]
[tex]=-\frac{5}{4\times \:3}[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:4\times \:3=12[/tex]
[tex]=-\frac{5}{12}[/tex]
Hope This Helps!
What is the area of this cross section of this rectangular prism? Enter your answer in the box.
10 in.
6 in.
16 in.
Answer:
16.
Step-by-step explanation:
Is there a picture?
HELP!!! WILL GIVE BRAINLIEST +LIKE AND 5 STARS ANSWER THE QUESTION IN THE PICTURE
Answer:
b, c , a
Step-by-step explanation:
I am guessing
Answer:
B, C, D
Step-by-step explanation:
2. How many squares are in figure 10? Explain how you know.
Answer:
We determined that the 10th figure will have 45 shaded squares. That means 100 – 45 = 55 squares will be unshaded
Step-by-step explanation:
hope this helps
Which of the following numbers is not a perfect square?
49 124 169 361
Answer: 124
Step-by-step explanation: 7^2=49; 13^2=169; 19^2=361. Only 124 cannot be expressed as a square of an integer.
Answer:
124
Step-by-step explanation:
3. 8.F.1.3
Which of the following equations represents
a linear function?
A. y = 3x2
B. y = 2-
C. y = 4x+6
D. y = -x + 3
The sample average unrestrained compressive strength for 50 specimens of a particular type of brick was computed to be 3120 psi, and the sample standard deviation was 180. The distribution of unrestrained compressive strength may be somewhat skewed. We want to determine whether the data indicate that the true average unrestrained compressive strength is less than the design value of 3200. Test using α = 0.01.
Answer:
The p-value of the test is 0.0014 < 0.01, meaning that the data indicates that the true average unrestrained compressive strength is less than the design value of 3200.
Step-by-step explanation:
We want to determine whether the data indicate that the true average unrestrained compressive strength is less than the design value of 3200.
At the null hypothesis, we test if the mean is at the design value of 3200, so:
[tex]H_0: \mu = 3200[/tex]
At the alternate hypothesis, we test if it is less than the design value of 3200, so:
[tex]H_a: \mu < 3200[/tex]
The test statistic is:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.
3200 is tested at the null hypothesis:
This means that [tex]\mu = 3200[/tex]
The sample average unrestrained compressive strength for 50 specimens of a particular type of brick was computed to be 3120 psi, and the sample standard deviation was 180.
This means that [tex]n = 50, X = 3120, s = 180[/tex]
Test statistic:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{3120 - 3200}{\frac{180}{\sqrt{50}}}[/tex]
[tex]t = -3.14[/tex]
P-value of the test and decision:
The p-value of the test is the probability of finding a sample mean below 3120, which is the p-value of t = -3.14, using a one-tailed test, with 50 - 1 = 49 degrees of freedom.
With the help of a calculator, the p-value of the test is 0.0014
The p-value of the test is 0.0014 < 0.01, meaning that the data indicates that the true average unrestrained compressive strength is less than the design value of 3200.
A projectile is launched at a height of h feet above the ground at an angle of θ with the horizontal. The initial velocity is v0 feet per second, and the path of the projectile is modeled by the parametric equations
x=(v0cosθ)t and y=h+(v0sinθ)t-16t^2
Write the parametric equations to model the path of a projectile launched from ground level (h = 0) at the given values of θ and v0. Use your equations to answer the following questions.
θ=40∘ , v0=128 feet per second
Determine the maximum height
Give the time the object reaches this height (to one decimal place).
Give the approximate horizontal distance the objects is at this point (to one decimal place).
Determine the time the object will hit the ground after it is launched (to one decimal place).
Using the equation, the time the object will hit the ground after it is launched is 3.4 seconds.
To model the path of a projectile launched from ground level (h = 0), we can set h = 0 in the equation for y:
[tex]y = (v_0sin \theta)t - 16t^2[/tex]
Therefore, the parametric equations for the path of the projectile are:
[tex]x = (v_0cos\theta)t \\y = (v_0sin \theta)t - 16t^2[/tex]
Substituting θ = 40∘ and v0 = 128 feet per second, we get:
[tex]x = (128 cos 40^o)t\\y = (128 sin 40^o)t - 16t^2[/tex]
To determine the maximum height, we need to find the vertex of the parabolic path, which is given by:
t = -b/2a
where a = -16, b = 128 sin 40∘, and c = 0 (since the projectile starts and ends at ground level). Substituting the values, we get:
t = -128 sin 40∘ / (2*(-16)) = 2.3 seconds (approx)
The maximum height can be found by substituting this value of t into the equation for y:
y = (128 sin 40∘)(2.3) - 16(2.3)^2 = 230.3 feet (approx)
Therefore, the maximum height is 230.3 feet and it is reached at 2.3 seconds.
To find the horizontal distance at this point, we can substitute the value of t into the equation for x:
x = (128 cos 40∘)(2.3) = 172.8 feet (approx)
Therefore, the approximate horizontal distance the object is at this point is 172.8 feet.
To determine the time the object will hit the ground after it is launched, we need to find the time when y = 0:
[tex]0 = (128 sin 40)t - 16t^2[/tex]
Solving for t using the quadratic formula, we get:
t = 0 or t = 8 sin 40∘ / 2 = 3.4 seconds (approx)
Therefore, the time the object will hit the ground after it is launched is 3.4 seconds.
To know more about equation visit:
brainly.com/question/649785
#SPJ1
what is the angle of d
Answer:
115°
Step-by-step explanation:
65 +65 = 130
360-130= 230
230÷2= 115
GIVING BRAINLIEST !!!!!
Find the expected value of the winnings
from a game that has the following
payout probability distribution:
Payout ($)
2
4
6
8
10
Probability 0.35 0.2 0.1 0.2 0.15
Expected Value = [?]
Round to the nearest hundredth.
Enter
Answer:
Expected value: $5.20
Step-by-step explanation:
2(0.35)+4(0.2)+6(0.1)+8(0.2)+10(0.15)=5.2, so you can expect to win $5.20 in this game.
Answer:
5.20 is the answer for Acellus it works
Step-by-step explanation:
Someone help me pls!!!!????
Answer:
Greatest would be Chlorine Krypton Argon Fluorine and least Hydrogen
Answer:
J, I, G, K, H.
Step-by-step explanation:
The elements go from least to greatest, and since they are negatives, we sort them from the highest negative to the lowest negative.
Which equation represents the data in this function table?
A. y = x - 8
B. x= y + 8
C. y = 3x
D. y = x + 3
Answer: The answer is B. Because 3 multiplied by x and add it by 3 equates to y. example: (x=2) 3x2+3= y. y=9 .
The answer is not b
Step-by-step explanation:
PLZZZZZZZZZZZZZZZZZ help
Answer:
true
Step-by-step explanation:
[tex]\frac{x}{2} <20[/tex]
* substitute 30 for x *
[tex]\frac{30}{2} <20\\\frac{30}{2} =15\\[/tex]
we're left with 15 < 20 which is true
Write a sine function that has an amplitude of 5, a midline of 2 and a period of 8pi/5.
Answer:
f(x) = 5*sin( (5/4)*x) + 2
Step-by-step explanation:
A general sine function can be written as:
f(x) = A*sin(w*x) + M
Where:
A is the amplitude
w is the frequency of the function
M is the midline
Here we know that we want to have:
An amplitude of 5. Then, A = 5
A midline of 2, then M = 2
And a period of (8/5)*pi
For now, we can write our function as:
f(x) = 5*sin(w*x) + 2
Now, we know that for a function of period T, is always true that:
f(x) = f(x + T)
here, the period is T = (8/5)*pi
knowing that sin(0) = sin(2*pi)
Then we must have:
sin(0) = sin(w*0) = sin(w*( 0 + (8/5)*pi)) = sin(2*pi)
Then the arguments of the third and fourt parts must be the same, thus:
w*(8/5)*pi = 2*pi
We can solve this for w now:
w*(8/5) = 2
w = 2*(5/8) = (5/4)
Then the function is:
f(x) = 5*sin( (5/4)*x) + 2
What is the value of y in the equation 4+ y = -3? (1 point)
07
0 1
O-1
0 -7
What is the value of x helppp
Answer:
The angles are vertical and x = 128*.
Step-by-step explanation:
x is the same angle as 128, because the angles are vertical.
Have a nice day! :-)
calculate the surface area of the net
[tex]\red {incomplete \: question}[/tex]
help me on this plz and thank you
By solving for x you get x=6
Answer:
x = 6
Step-by-step explanation:
12x = 72
72/12 = 6
x = 6
Chris drops an egg with a parachute from the top of a building. The height, h, in feet, of the egg above the ground after t seconds is given
by h (t) = 100 - 16t2
After how many seconds does the egg hit the ground?
I
Answer:
The egg hits the ground after 2.5 seconds.
Step-by-step explanation:
Height of the egg:
The height of the egg after t seconds is given by:
[tex]h(t) = 100 - 16t^2[/tex]
After how many seconds does the egg hit the ground?
This is t for which [tex]h(t) = 0[/tex]. So
[tex]h(t) = 100 - 16t^2[/tex]
[tex]16t^2 - 100 = 0[/tex]
[tex]16t^2 = 100[/tex]
[tex]t^2 = \frac{100}{16}[/tex]
[tex]t = \sqrt{\frac{100}{16}}[/tex]
[tex]t = \frac{10}{4}[/tex]
[tex]t = 2.5[/tex]
The egg hits the ground after 2.5 seconds.
The circumference of the tire of Melvin’s cycle is 2.5m. He took part in a race of 2km. When
he had covered 1.2km, the tire burst. To finish the race, how many more times should the wheel go
round?
Answer:
320
Step-by-step explanation:
Distance to go
2km - 1.2 km = 0.8km = 800m
Revolutions needed
800/2.5 = 320
If p is inversely proportional to the square of q, and pis 24 when q is 11,
determine p when q is equal to 2.
Answer:
726
Step-by-step explanation:
Here p = k / q², and 24 = k / 121, or k = 2904
Then p = 2904 / q²
If q = 2, p = 2904 /4 = 726
Answer:
p = 12 × 11²
Step-by-step explanation:
By question,
=> p ∝ 1/q²
=> p = k/q²
When p is 24 and q is 11=> 24 = k/11²
=> k = 24 * 11²
When q is 2 ,=> p = k/q²
=> p = 24*11²/2
=> p = 12 × 11²
A sphere shaped orange has a diameter of 7 centimeters. Find the volume of the orange to the nearest tenth.
22cm^3
Step-by-step explanation:
My education system is different so I dont know what nearest tenth would mean in this .
But going mathematically:
Its diameter is 7 centimetres.
So to find its volume we can use the formula pi/d or pi/r^2
Now, 22/7÷7 would be 22cm³.
PLS, NO FILES, OR LINKS, JUST ANSWERS, AND EXPLANATIONS..... What is the combined area of the two bases of the following cylinder? 43.96 in. 2 87.92 in. 2 25.12 in. 2 12.56 in. 2
The combined area of the circular bases of the cylinder is of 25.12 squared inches.
What is the area of a circle?
The area of a circle of radius r is given by:
[tex]A = \pi r^2[/tex]
In this problem, there are two bases, and each base is a circle of r = 2 in, hence the combined area in inches squared of the two bases is given by:
[tex]A_c = 2 \times \pi \times 2^2 = 8\pi = 25.12[/tex]
More can be learned about the area of a circle at https://brainly.com/question/17326298
#SPJ1
Answer:
25.12 squared inches.
Hope this helps!
4. You bought 765 shares $45.23 and you sold it the next day for $46.01. What is your gross capital
I honestly don't know the answer. Hope this helps..
Review the graph of function g(x).
For which value of a does lim g(x) not exist?
X-
O-6
0-3
0 0
2-
Answer:
0-6 de correct answer okay.
At x→ -3 the value of the limit of function g(x) does not exist because the left-hand limit and right-hand limit are not equal an option second is correct.
What is the limit?A limit is a value at which a function approaches the output for the given values in mathematics. Limits are used to determine integrals, derivatives, and continuity in calculus and mathematics.
We have a graph of function g(x)
[tex]\rm \lim_{x \to a}g(x)[/tex]
Let's check at x = -3
Finding the left-hand limit and right-hand limit.
[tex]\rm \lim_{x \to -3^{-1}}g(x) = -2[/tex]
[tex]\rm \lim_{x \to -3^{+1}}g(x) = -4[/tex]
Since the left-hand limit and right-hand limit are not equal then at x = -3 the limit does not exist.
Thus, at x→ -3 the value of the limit of function g(x) does not exist because the left-hand limit and right-hand limit are not equal an option second is correct.
Learn more about the limit here:
brainly.com/question/8533149
#SPJ2
8 Mangoes = 30 bananas
5 banana= 2 oranges
15 oranges=? mangoes
Answer:
it would only be 8, unless you need to go down to the decimal point then it would be 8.25
Step-by-step explanation:
it would be 8 because if you need to find how many bananas you have, to do this you would divide 15 by 2 and get 7.5 then you multiply those by 5 to get the number of bananas which would be 37.5, and then if 8 mangos = 30 bananas you only have 8 mangos.
(sorry if this is very jumbled and hard to understand, also getting brainliest would help, thank you)
There are 6 blue marbles, 7 black marbles, 4 orange marbles, and 3 green marbles in a bag. Once a marble is drawn, it is replaced. Find
the probability of the outcome.
Find P(Blue, Orange, and then Green)
which one is the right answer:
9/1000
3/500
6/35
0
Answer:
Hello! answer 9/1000
Step-by-step explanation:
All you have to do is multiply the probability of each then you will get your answer so...
6/20 × 4/20 × 3/20 = 9/1000 So thats your probability. Hope that helps!