Answer:
This is a geometric sequence.
I NEED HELP PLEASE, THANKS! :)
A gear of radius 6.1 cm turns at 11 revolutions per second. What is the linear velocity of the gear in meters per second?
v = linear velocity, d = distance traveled, and t = time.
Answer:
Velocity = 4.22 m/s
Step-by-step explanation:
Time = 1 second
Radius = 6.1 cm
Diameter = 12.2 cm = 0.122 m
Displacement = Revolution × π × Diameter
Displacement = 11 × 3.14 × 0.122
Displacement = 4.22 m
Now, Linear velocity:
Velocity = displacement / Time
Velocity = 4.22 / 1
Velocity = 4.22 m/s
Answer: 4.216 meters per second
Step-by-step explanation:
Notes: Use the following conversions:
1 revolution = 2π
100 cm = 1 meter
and the following formula: v = ωr/t where v is in meters per second
[tex]\dfrac{11\ revolutions\times 6.1\ cm}{1\ second}\times \dfrac{2\pi}{1\ revolution}\times \dfrac{1\ meter}{100\ cm}=\dfrac{1.342\pi\ meters}{second}\\\\\\=\large\boxed{\dfrac{4.216\ meters}{second}}}[/tex]
EXCELLENT VOTE!! (only if u give the CORRECT answer)
Answer:
Option C
Step-by-step explanation:
Answer:
B.
You need to subtract 1 term because you don't include the starting 5
4^10 - 1 = 4^9
You multiply 5 by 4 each time for 9 times so it is 5 x 4^9
Hope this helps
Step-by-step explanation:
Line A has an x-intercept of -4 and a y-intercept of 8. What is its slope?
Answer:
Step-by-step explanation:
We can use the intercept form of the equation of a line, then solve for y.
Intercept form
x/(x-intercept) +y/(y-intercept) = 1
x/-4 +y/8 = 1
__
Solving for y, we have ...
-2x +y = 8 . . . . multiply by 8
y = 2x +8 . . . . add 2x
The coefficient of x is 2, so the slope is 2.
__
The graph shows you the rise is 8 for a run of 4, so ...
slope = rise/run = 8/4
slope = 2
One number is 10 times as large as another, and their difference is 81. Find the numbers. If x represents the smaller number, then the larger number is x + 10 10x
Answer:
value of x=9
so value of large number is 90 and smaller number is 9
The table below shows the average attendance of school events by the day of the week on which they are held. Average Attendance at School Events Thursday Friday School Play 300 x Band Concert 184 250 Which values of x will indicate an association between the two variables in the two-way table? Check all that apply. 250 304 407 422 714
Answer:
A , B, E 1,2,5
Your the welcome my audience
Step-by-step explanation:
Answer:
a b e
Step-by-step explanation:
just believe me you $exy hunky man
How many distinct triangles can be formed for which mzA
= 75°, a = 2, and b = 3?
O No triangles can be formed.
One triangle can be formed where angle B is about 15°.
One triangle can be formed where angle B is about 40°.
Two triangles can be formed where angle B is 40° or
140°
We are given
m∠A = 75 deg
a = 2
b = 3
Apply the Law of Sines.
sin(B)/b = sin(A)/a
sin(B)/3 = sin(75)/2
sin(B) = (3*sin(75))/2 = 1.45
The value of the sin function cannot exceed 1.
This means that the triangle cannot exist.
Answer: No distinct triangles
Answer: A no triangles can be formed
Step-by-step explanation:
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the circle equations in general form with their corresponding equations in standard form. x2 + y2 − 4x + 12y − 20 = 0
(x − 6)2 + (y − 4)2 = 56
x2 + y2 + 6x − 8y − 10 = 0
(x − 2)2 + (y + 6)2 = 60
3x2 + 3y2 + 12x + 18y − 15 = 0
(x + 2)2 + (y + 3)2 = 18
5x2 + 5y2 − 10x + 20y − 30 = 0
(x + 1)2 + (y − 6)2 = 46
2x2 + 2y2 − 24x − 16y − 8 = 0
x2 + y2 + 2x − 12y − 9 = 0
Answer:
1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]
2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]
3) For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex], the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]
4) For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex], the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]
5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex], the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]
6) For[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]
Step-by-step explanation:
This can be done using the completing the square method.
The standard equation of a circle is given by [tex](x - a)^2 + (y-b)^2 = r^2[/tex]
1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex]
[tex]x^2 - 4x + y^2 + 12y = 20\\x^2 - 4x + 2^2 + y^2 + 12y + 6^2 = 20 + 4 + 36\\(x-2)^2 + (y+6)^2 = 60\\[/tex]
Therefore, for [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]
2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex]
[tex]x^2 + 6x + y^2 - 8y = 10\\x^2 + 6x + 3^2 + y^2 - 8y + 4^2 = 10 + 9 + 16\\(x + 3)^2 + (y- 4)^2 = 35\\[/tex]
Therefore, for [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]
3) For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex]
Divide through by 3
[tex]x^2 + y^2 + 4x + 6y = 5[/tex]
[tex]x^2 + y^2 + 4x + 6y = 5\\x^2 + 4x + 2^2 + y^2 + 6y + 3^2 = 5 + 4 + 9\\(x + 2)^2 + (y+ 3)^2 = 18\\[/tex]
Therefore, for [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex], the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]
4) For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex]
Divide through by 5
[tex]x^2 + y^2 - 2x + 4y = 6[/tex]
[tex]x^2 + y^2 -2x + 4y = 6\\x^2 - 2x + 1^2 + y^2 + 4y + 2^2 = 6 + 1 + 4\\(x - 1)^2 + (y+ 2)^2 = 11\\[/tex]
Therefore, for [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex], the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]
5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex]
Divide through by 2
[tex]x^2 + y^2 - 12x - 8y = 4[/tex]
[tex]x^2 + y^2 - 12x - 8y = 4\\x^2 - 12x + 6^2 + y^2 - 8y + 4^2 = 4 + 36 + 16\\(x - 6)^2 + (y+ 4)^2 = 56\\[/tex]
Therefore, for [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex], the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]
6) For [tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex]
[tex]x^2 + 2x + y^2 - 12y = 9\\x^2 + 2x + 1^2 + y^2 - 12y + 6^2 = 9 + 1 + 36\\(x+1)^2 + (y-6)^2 = 46\\[/tex]
Therefore, for[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]
For Plato / Edmentum
Just to the test and got it right ✅
Find the total surface area of this cylinder. Give your answer to one decimal place PLEASE HELP THANK YOUUUU
Answer:
Step-by-step explanation:
surface area of cylinder=2 πr²+2πrh
=2πr(r+h)
=2π×12(12+18)
=24π×30
=720π
≈2261.9 cm²
Find w please help me
Answer:
w = 77°
Step-by-step explanation:
From the picture attached,
WXYZ is a quadrilateral having 4 interior angles,
m∠y = 90°
Therefore, (2x - 10) = 90°
2x = 90 + 10
2x = 100
x = 50
Now, m∠z = (x + 15)° = 65°
m∠x = (3x - 22)° = 150 - 22
= 128°
Sum of interior angles of a polygon = (n - 2)×180°
where n = Number of sides of the polygon
If n = 4,
m∠u + m∠x + m∠y + m∠z = (4 - 2) × 180°
w + 128 + 90 + 65 = 360
w = 360 - 283
w = 77°
Therefore, measure of w = 77°
Which triangle results from a reflection across the line x = 1?
Answer:
Correct answer is option D.
Step-by-step explanation:
Given that [tex]\triangle ABC[/tex] in the image 1 attached.
If we have a look at the image attached, the coordinates are:
[tex]A(1,1)\\B(2,5)\ and\\C(4,1)[/tex]
To find reflection of a point across any line, the distance of points from the line must be same.
Point A(1,1) lies on the line x = 1, so its reflection A' will be at the same point A'(1,1).
Point C(2,5) is at a distance 1 from x = 1 on right side, so C' will be 1 distance on the left side of x = 1 i.e. 1 will be subtracted from its x coordinate.
i.e. C'(1 - 1, 5)
C'(0, 5)
Point B(4, 1) is at a distance 3 from x = 1 on right side, so B' will be 3 distance on the left side of x = 1 i.e. 3 will be subtracted from its x coordinate.
i.e. B'(1 - 3, 1)
B'(-2, 1)
When we plot the above point A', B' and C', we get the option D as correct.
The vertices of the triangle after reflection across the line x = 1 are:
A'(1, 1),
B'(-2, 1),
and C'(0, 6).
The correct option is D.
Given information:
As per the diagram,
The vertices of the triangle are:
A(1, 1),
B(4, 1),
and C(2, 6).
To find the reflection of the triangle across the line x = 1, we can apply the reflection transformation.
The line x = 1 acts as the mirror or reflection axis. To reflect a point across this line, we can imagine folding the image over the line so that the distance between the point and the line is preserved, but the point is now on the other side of the line.
Let's reflect each vertex of the triangle across the line x = 1:
Reflecting point A(1, 1):
The distance between point A and the line x = 1 is 0 since A lies on the line itself. Therefore, the reflection of point A will also be (1, 1).
Reflecting point B(4, 1):
The distance between point B and the line x = 1 is 3 units. Reflecting across the line x = 1 will place B 3 units to the left of the line, resulting in the point (1 - 3, 1), which simplifies to (-2, 1).
Reflecting point C(2, 6):
The distance between point C and the line x = 1 is 1 unit. Reflecting across the line x = 1 will place C 1 unit to the right of the line, resulting in the point (1 - 1, 6), which simplifies to (0, 6).
Therefore, the vertices of the triangle after reflection across the line x = 1 are:
A'(1, 1),
B'(-2, 1),
and C'(0, 6).
To learn more about the reflection;
https://brainly.com/question/11232423
#SPJ6
A large stand of fir trees occupies 24 hectares. The trees have an average density of 1 tree per 20m squared. A forester estimates that each tree will yield 300 board-feet. Estimate the yield of the stand if one-tenth of the trees are cut.
Answer:
The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.
Step-by-step explanation:
First, let is find the total amount of fir trees that occupies the area of 24 hectares. (1 hectare = 10000 square meters)
[tex]n = \sigma \cdot A[/tex]
Where:
[tex]\sigma[/tex] - Surface density, measured in trees per square meter.
[tex]A[/tex] - Total area, measured in square meters.
Given that [tex]\sigma = \frac{1}{20}\,\frac{tree}{m^{2}}[/tex] and [tex]A = 24\,h[/tex], the total amount of fir trees is:
[tex]n = \left(\frac{1}{20}\,\frac{trees}{m^{2}} \right)\cdot (24\,h)\cdot \left(10000\,\frac{m^{2}}{h} \right)[/tex]
[tex]n = 12000\,trees[/tex]
It is known that one-tenth of the tress are cut, whose amount is:
[tex]n_{c} = 0.1 \cdot n[/tex]
[tex]n_{c} = 0.1 \cdot (12000\,trees)[/tex]
[tex]n_{c} = 1200\,trees[/tex]
If each tree will yield 300 board-feet, then the yield related to the trees that are cut is:
[tex]y = S\cdot n_{c}[/tex]
Where:
[tex]S[/tex] - Yield of the tress, measured in board-feet per tree.
[tex]n_{c}[/tex] - Amount of trees that will be cut, measured in trees.
If [tex]n_{c} = 1200\,trees[/tex] and [tex]S = 300\,\frac{b-ft}{tree}[/tex], then:
[tex]y = \left(300\,\frac{b-ft}{tree} \right)\cdot (1200\,trees)[/tex]
[tex]y = 360000\,b-ft[/tex]
The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.
how many millimeters are in a meter
Answer:
There are 1000 millimeters in a meter.
Step-by-step explanation:
I really hope this helps in any way.
Answer:
1,000
Step-by-step explanation:
The word millimeter has the prefix of 'milli-'.
'Milli-' means a thousand.
Applying the prefix meaning to the word, a millimeter would be a thousandth of a meter.
There are 1,000 millimeters in a meter.
Brainilest Appreciated.
convert the decimal to a simplified fraction 0.8=
Answer:
4/5
Step-by-step explanation:
You know 0.8 x 10 = 8, so 8/10 is the fraction.
Now, simplify 8/10.
8/10 = 4/5
Answer:
4/5
Step-by-step explanation:
Step 1: Convert decimal to fraction
0.8= 8/10
Step 2:Simplify
8/10=4/5
Write a two-column proof. Given: <2 is congruent to <5; Segment AB is congruent to Segment DE Prove: Segment BC is congruent to Segment EC
Answer:
proof
Step-by-step explanation:
Statements
Reasons
<2 is congruent to <5; Segment AB is congruent to Segment DE
Given
<3≅<4
Vertical angle theorem
ΔCDB≅ΔCAE
AAS
Segment BC is congruent to Segment EC
CPCTC
The segment BC is congruent to segment EC and this can be proven by using the properties of a triangle and the given data.
Given :
Angle 2 is congruent to angle 5.Segment AB is congruent to Segment DE.The following steps can be used in order to prove that segment BC is congruent to segment EC:
Step 1 - Using the triangle properties it can be proven that segment BC is congruent to segment EC.
Step 2 - According to the vertical angle theorem, angle 3 is congruent to angle 4.
Step 3 - Now, according to the AAS (Angle Angle Side) postulate, triangle CDB is similar to triangle CAE.
Step 4 - So, according to the CPCTC, segment BC is congruent to segment EC.
For more information, refer to the link given below:
https://brainly.com/question/25813512
PLEASE HELP ME Im confused!!!! Kinah works in a bakery and is making peach pies. She makes 40 pies and uses 6 peaches for each pie. The number of peaches that she uses to make the pies is a function of the number of pies that she makes. Which of these statements describe the domain or range of this function? Select two that apply.
Answer:
b
Step-by-step explanation:
Juan hiked to the top of a 3,000-foot mountain and back down without taking a break. Which graph best represents Juan's distance from the top of the mountain during the entire hike?
Answer:
Top left graph.
Step-by-step explanation:
If Juan didn't take a break, there is no plateau/flat line. And if he started hiking up and then down, then the graph should be an upside-down V shape.
Answer:
Graph A is the most acuurate
There is a bag filled with 5 blue, 6 red and 2 green marbles. A marble is taken at random from the bag, the colour is noted and then it is not replaced. Another marble is taken at random. What is the probability of getting 2 blues?
Answer:
Step-by-step explanation:
Total marbles = 5 + 6 + 2 = 13
P( getting blue ball from first draw) = 5/13
The marble is not replaced. So, Now total marbles will be 12 & number blue marbles will be 4
P( getting blue ball from second draw) = 4/12 = 1/3
P(getting two blues) = [tex]\frac{5}{13}*\frac{1}{3}\\[/tex]
= 5/39
A winter recreational rental company is fencing in a new storage area. They have two options. They can set it up at the back corner of the property and fence it in on four sides. Or, they can attach it to the back of their building and fence it in on three sides. The rental company has decided that the storage area needs to be 100 m2 if it is in the back corner or 98 m2 if it is attached to the back of the building. Determine the optimal design for each situation.
Answer:
Rectangular area attached to the back of the building
two sides of legth 7 m and one side of 14 m
Step-by-step explanation:
We need to compare quantity of fencing material to be used in both cases
1.Option
A = 100 m² dimensions of storage area "x" and "y"
x*y = 100 y = 100/x
The perimeter of the storage area is
p = 2*x + 2*y ⇒ p = 2*x + 2*100/x
p(x) = 2*x + 200/x
Taking drivatives on both sides of the equation
p´(x) = 2 - 200/x²
p´(x) = 0 ⇒ 2 - 200/x² = 0
2*x² - 200 = 0 x² = 100
x = 10 m
and y = 100/10
y = 10 m
Required fencing material in first option
2*10 + 2*10 = 40 m
2.-Option
Following the same procedure
A = 98 m² y = A/x y = 98/x
p = 2*x + y p(x) = 2*x + 98/x
p´(x) = 2 - 98/x² p ´(x) = 0
2 - 98/x² = 0
2*x² = 98 x² = 49
x = 7 m and y = 98/ 7 y = 14 m
Total quantity of fencing material
p = 2* 7 + 14 p = 28
Therefore option 2 is more convinient from economic point of view
Optimal design rectangular storage area with two sides of 7 m and one side of 14 m
Pls ppl answer dis question PLS PLS PLS No scaming pls
4√3 x^2+5x-2√3
Answer:
\the zeroes are (2√3)/ 3, (√3)/4,
or -1.15, 0.43 to the nearest hundredth.
Step-by-step explanation:
I am assuming you want to find the zeroes of this function:
4√3 x^2+5x-2√3 = 0
Using the quadratic formula:
x = [ -5 +/- √((5)^2 - 4 * 4√3 * -2√3) ] / (2 * 4√3 )
= ( - 5 +/- √(25 - (-32*3)) / 8√3
= (-5 +/- √ 121) / 8√3
= (-5 - 11) / 8√3 or (-5 + 11) / 8√3
= -16/8√3 or 6/8√3
= -16√3/ 24 or 6√3 / 24
= -2√3/ 3 or √3/4.
Francis surveyed a random sample of 70 students at Franklin High School about their favorite season. Of the students surveyed, 18 chose fall as their favorite season. There are 1816 students at Franklin High School.
Complete question is;
Francis surveyed a random sample of 70 students at Franklin High School about their favorite season. Of the students surveyed, 18 chose fall as their favorite season. There are 1816 students at Franklin High School. Based on the data, what is the most reasonable estimate for the number of students at Franklin High School whose favorite season is fall?
Answer:
467
Step-by-step explanation:
We are told that 18 out of 70 of the surveyed students' favorite season is fall. This when expressed in fraction, gives; 18/70.
Now we need to multiply this fraction by the total number of Franklin High School students in order to get the estimate for the number of students at Franklin High School whose favorite season is fall. Total number of students = 1816. Thus, estimate is;
1816 × 18/70 = 467
Thus, the most reasonable estimate for the number of students at Franklin High School whose favorite season is fall would be 467.
Please answer it in two minutes
Answer:
2,700 degrees.
Step-by-step explanation:
17 gon is a heptadecagon.
The formula for the sum of interior angles is [tex](n-2)*180[/tex] degrees.
[tex](17-2)*180=\\15*180=\\2700[/tex]
Write equation Derek will get a bonus if he sells at least 50 sets of knives in a month use k to represent the number of knives he can sell to receive his bonus
Answer: k ≥ 50
Step-by-step explanation:
From the question, we are informed that Derek will get a bonus if he sells at least 50 sets of knives in a month. We are further told to us k to represent the number of knives he can sell to receive his bonus.
Since we are told that Derek will get a bonus if he sells at least 50 sets of knives in a month, this means that k will be greater than or equal to 50. Therefore,
k ≥ 50
please solve it 90 POINTS please help- PLEASE HELP its Identify the following for the quadratic relations please slove it all please if you can save the picture and do it on the page -
i Will give brainliest
Answer:
[tex]\boxed{\mathrm{view \: explanation}}[/tex]
Step-by-step explanation:
2)
a) elimination method
b) substitution method
c) substitution method
For the first part we can elimate the y variable by subtracting the equations. We can then find the value of x.
For the second part we can substitute y as 2x+5 in the second equation and solve for x.
For the third part we can substitute y as 4x+3 in the first equation and solve for x.
3)
[tex]\boxed{\mathrm{view \: attachment}}[/tex]
Please answer this....
Answer:
c) [tex]2\frac{23}{30}[/tex] d)[tex]1\frac{23}{24}[/tex]
7) a. [tex]6\frac{3}{11}[/tex] kg b. [tex]6 \frac{2}{3}[/tex] cm c. 20 cm
d. [tex]9\frac{9}{10}[/tex] kg e. 10 g f. [tex]23 \frac{1}{4}[/tex] kg
Step-by-step explanation:
c) [tex]8\frac{2}{3}[/tex] - [tex]5\frac{9}{10}[/tex]
First we will change to improper fraction and then solve
[tex]\frac{26}{3} - \frac{59}{10}[/tex]
= [tex]\frac{260 - 177}{30}[/tex]
= [tex]\frac{83}{30}[/tex]
we will now change to mixed number
= [tex]2\frac{23}{30}[/tex]
d) [tex]8\frac{1}{8} - 6\frac{1}{6}[/tex]
we will first change it to improper fraction and then solve
= [tex]\frac{65}{8} - \frac{37}{6}[/tex]
= [tex]\frac{390 - 296}{48}[/tex]
= [tex]\frac{94}{48}[/tex]
we can reduce the fraction
=[tex]\frac{47}{24}[/tex]
we will change it mixed number
=[tex]1\frac{23}{24}[/tex]
7)
a. [tex]\frac{3}{11}[/tex] of 23
= [tex]\frac{3}{11}[/tex] × 23
= [tex]\frac{69}{11}[/tex]
=[tex]6\frac{3}{11}[/tex] kg
b. [tex]\frac{2}{3}[/tex] of 10 cm
= [tex]\frac{2}{3}[/tex] × 10 cm
= [tex]\frac{20}{3}[/tex] cm
=[tex]6 \frac{2}{3}[/tex] cm
c. [tex]\frac{5}{6}[/tex] of 24cm
= [tex]\frac{5}{6}[/tex] × 24 cm
6 will divide 24
=5 × 4 cm
= 20 cm
d. [tex]\frac{3}{10}[/tex] of 33 kg
= [tex]\frac{3}{10}[/tex] × 33 kg
=[tex]\frac{99}{10}[/tex] kg
=[tex]9\frac{9}{10}[/tex] kg
e. [tex]\frac{2}{7}[/tex] of 35 g
= [tex]\frac{2}{7}[/tex] × 35 g
7 will go into 35
=2×5 g
=10 g
f. [tex]\frac{3}{4}[/tex] of 31 kg
= [tex]\frac{3}{4}[/tex] × 31 kg
=[tex]\frac{93}{4}[/tex] kg
=[tex]23 \frac{1}{4}[/tex] kg
Consider the graph with four lines below. On a coordinate plane, line a has a positive slope and goes through points (negative 1, 0) and (1, 2), line b has a negative slope and goes through (negative 2, 2) and (negative 1, negative 1), line c has a negative slope and goes through (0, 3) and (1, 0), and line d is horizontal at y = 1. By inspection, which system would have no solution? line a and line b line a and line c line b and line c line b and line d
Answer:
C) line b and line c
Step-by-step explanation:
On edge
A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The system of equations that do not have any solution is line b and line c. Hence, the correct option is C.
What is the equation of a line?A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,
y =mx + c
where,
x is the coordinate of the x-axis,
y is the coordinate of the y-axis,
m is the slope of the line, and
c is the y-intercept.
The equation of line a passing through (-1,0) and (1,2) are,
m = (0-2)/(-1-1) = -2/-2 = 1
y= x + c
0 = -1 + c
c = 1
Equation of line 1, y=x+1
The equation of line b passing through (-2,2) and (-1,-1) are,
m = (2+1)/(-2+1) = 3/-1 = -3
y= -3x + c
-1 = -3(-1) + c
c = -4
Equation of line 1, y=-3x-4
The equation of line c passing through (0,3) and (1,0) are,
m = (3-0)/(0-1) = 3/-1 = -3
y= -3x + c
3 = -3(0) + c
c = 3
Equation of line 1, y=-3x+3
Also, the equation of line d is y=1
The solution of two-equation is the point at which the two equations are not intersecting. Therefore, the system of equations that do not have any solution is line b and line c.
Hence, the correct option is C.
Learn more about Equation of Line:
https://brainly.com/question/21511618
#SPJ2
which of the following angles is coterminal with 5pi/3? pi/3, 2pi/3, 4pi/3, 5pi/3
Answer:
5pi/3
Step-by-step explanation:
For two angles to be co-terminal, one must differ from the other by a multiple of 2pi.
The angle of consideration is 5pi/3
Let us consider the options one by one and see if they differ from the angle of consideration by a multiple of 2pi.
5pi/3 - pi/3 = 4pi/3
5pi/3 - 2pi/3 = 3pi/3 = pi
5pi/3 - 4pi/3 = pi/3
5pi/3 - 5pi/3 = 0 = 0(2pi)
5pi/3 is co-terminal with itself
Which of the following is the correct factored form of the given equation? 6x^2 -13x - 8 = 0
Answer:
the 2nd
Step-by-step explanation:
PLEASE HELP Which of the sets of ordered pairs represents a function? A = {(2, −2), (5, −5), (−2, 2), (−5, 5)} B = {(4, 2), (4, −2), (9, 3), (9, −3)} a. Only A b. Only B c. Both A and B Incorrect d. Neither A nor B
Answer: A. Only A
Step-by-step explanation:
A has exactly one output for every input but B has different outputs for an input.
A car is traveling at x feet per second. The driver sees a red light ahead, and
after 1,5 seconds reaction time, the driver applies the brake. After the brake is
applied, the car takes seconds to stop, during which time the average speed
24
of the car is feet per second. If the car travels 165 feet from the time the
driver saw the red light to the time it comes to a complete stop, which of the
following equations can be used to find the value of x?
A) x2 + 48x - 3,960 = 0
B) x2 + 48x - 7,920 = 0
C) x2 + 72x - 3,960 = 0
D) x2 + 72x - 7,920 = 0
Answer:
The correct option is;
D) x² + 72·x - 7920 = 0
Step-by-step explanation:
The time it takes the car to stop = x/24 seconds
the average speed during stopping = x/2 feet per second
Given that the car was initially travelling at x feet per second and it takes the car 165 feet to stop after the driver takes 1.5 seconds at the initial speed x before the break is applied, we have;
Total distance traveled = (x/24)×(x/2) + x×1.5 = 165
= x²/48 + 1.5·x = 165
Multiply through by 48, we have;
x² + 72·x = 7920
Which gives the equation as follows;
x² + 72·x - 7920 = 0.
The graph below shows the price of different numbers of beach balls at a store: Which equation can be used to determine p, the cost of b beach balls? b = 5.50p p = 5.50b p = 11b b = 11p
Answer:
p = 5.50b
Step-by-step explanation:
2 beach balls cost 11
4 beach balls cost 22
6 beach balls cost 33
So each (1) ball b costs 5.50 ($) p