Answer:
i gtg soon baby ok?
Explanation:
Can someone help with these questions please???
When lava cools outside the Earth, ____ igneous rocks are formed
Answer:The rock forms large crystals
Explanation:
Hello! Please help :((
Find the distance from point B to point C. Enter as a decimal rounded to the nearest tenth. А 61° 5.7 mi B С BC = [?] mi Enter
Answer:
BC = 10.28 ≈ 10.3 mi to the nearest tenth
Explanation:
Using the trigonometry rules; SOH CAH TOA,
TOA would be more suitable in this question.
Tan ∅ = Opposite / Adjacent
Tan 61 = BC / AB
1.8040 = BC / 5.7
BC = 5.7 * 1.8040
BC = 10.28 ≈ 10.3 mi
the answer is 10.3, i already rounded it.
CH3CH3C(CH3)2CH2I classification and name
Answer:
1,2 di methyl 5 ene tri chloro hexane
What group of elements on the periodic table is not usually found in nature?
Answer:
Halogens
Explanation:
they they are never found free in nature.
Can someone please rephrase this question, I dont understand what it is asking for.
Which disease might have cures developed as a result of their understanding of structure and function of protein?
Answer:
Which infection may have fixes created because of their comprehension of construction and capacity of protein?
How many moles of "02" are in a 192g sample of O2? *
1
2
3
4
5
6
7
Answer: The number of moles of [tex]O_2[/tex] are 6.
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
Given mass = 192 g
Molar mass = 32 g/mol
[tex]\text{Number of moles}=\frac{192g}{32g/mol}=6mol[/tex]
The number of moles of [tex]O_2[/tex] are 6.
What happens when sodium and chlorine react to make table salt
Please help
What are mand n in the rate law equation?
Rate = k[A]”[B]"
A (they are experimentally determined exponents)
Just like cans of soup, atoms of the same element often have different masses. These different varieties are called isotopes. In the Average Atomic Mass Gizmo, you will learn how to find the average mass of an element using an instrument called a mass s
Answer:
ions are deflected and the lighter the ions the more the deflection.
Placing magnetic field in the path of the ions cause them to move in a curved path.
Explanation:
This question is all about the way in which mass spectroscopy works. Mass spectroscopy Is one of the techniques in spectroscopy which is used in the identification of chemical compounds.
Mass spectroscopy works based on the principle of ionization. For a mass spectroscopy to start ionization must first occur that is to say this is the first step in the identification of compound in mass spectroscopy.
The following steps are involve in mass spectroscopy;
=> Ionization: the molecules of the sample are first ionized. The ions formed here are positive ions.
=> Acceleration: the ions in step one are accelerated.
=> Deflection: the smaller ions get deflected more than the bigger ions. The magnetic field is used in the deflection of this ions.
=> Detection: the ions are then detected.
Therefore, to answer the question, the ions are deflected and the lighter the ions the more the deflection.
Placing magnetic field in the path of the ions cause them to move in a curved path.
Ionic compounds form between two metals true
Answer (TL;DR):
False, ionic compounds form between a metal and a nonmetal. This is because metals are looking to lose electrons to get a full outer shell while nonmetals are looking to gain electrons to get a full outer shell.
Explanation:
Atoms have a full outer shell when their outermost shell holds the maximum number of electrons. For example, if the outermost shell is the first shell of the atom, it can hold up to 2 atoms. When this shell holds 2 atoms, it is considered full. If the outermost shell is the second shell of the atom, it can hold up to 8 atoms. When this shell holds 8 atoms, it is considered full. This can also be referred to as an atom "gaining a complete octet." The reason that atoms want a complete octet is to become stable and less reactive.
Let's say an atom with 3 shells has only 1 electron on the third shell. It doesn't have a complete octet and it wants to gain one. The third shell can hold up to 8 electrons. So, to gain a complete octet, the atom can either gain 7 electrons or just lose the 1 that it already has, which is the easier option. This is the case with metals and the opposite goes for nonmetals.
Because metals want to lose electrons and nonmetals want to gain electrons, they form compounds with each other.
I hope this helps!
After going through a guided tutorial by selecting Run Grams Demonstration, you can create your own experiment by clicking the Run Experiment button at the end or by clicking the Overview tab and returning to the Experiment tab to select Run Experiment. There are nine reactions you can explore on your own. Sulfur dioxide gas (SO2) and oxygen gas (O2) react to form the liquid product of sulfur trioxide (SO3). How much SO2 would you need to completely react with 6.00 g of O2 such that all reactants could be consumed
Answer: Thus 24.0 g of [tex]SO_2[/tex] would be needed.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} O_2=\frac{6.00g}{32g/mol}=0.1875moles[/tex]
[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(l)[/tex]
According to stoichiometry :
1 mole of [tex]O_2[/tex] require = 2 moles of [tex]SO_2[/tex]
Thus 0.1875 moles of [tex]O_2[/tex] will require=[tex]\frac{2}{1}\times 0.1875=0.375moles[/tex] of [tex]SO_2[/tex]
Mass of [tex]SO_2=moles\times {\text {Molar mass}}=0.375moles\times 64g/mol=24.0g[/tex]
Thus 24.0 g of [tex]SO_2[/tex] would be needed to completely react with 6.00 g of [tex]O_2[/tex] such that all reactants could be consumed.
An unknown compound contains only C , H , and O . Combustion of 5.90 g of this compound produced 11.8 g CO2 and 4.83 g H2O . What is the empirical formula of the unknown compound
Answer:
C₂H₄O
Explanation:
In a compound that contains Cabon, hydrogen and oxygen, the combustion produce CO₂ from the carbon, and H₂O from the hydrogens. Using the mass of the products we can solve the moles of Carbon and hydrogen. The empirical formula is the simplest whole-number of atoms present in a molecule.
Moles CO₂ = Moles C:
11.8g CO₂ * (1mol / 44g) = 0.268 moles CO₂ = 0.268 moles C * (12g/mol) =
3.216g C
Moles H₂O = 1/2 moles H:
4.83g H₂O * (1mol / 18g) = 0.268 moles H₂O * (2 mol H / 1 mol H₂O) =
0.537 mol H * (1g/mol) = 0.537g H
Mass O to find moles O:
5.90g Sample - 3.216g C - 0.537g H = 2.147g O * (1mol / 16g) = 0.134 moles O
Ratio of atoms -Dividing in 0.134 moles-:
C = 0.268mol C / 0.134 mol O = 2
H = 0.537mol H / 0.134 mol O = 4
O = 0.134mol O / 0.134 mol O = 1
Empirical formula is:
C₂H₄Otell me how is your life as a youngster
Answer:
ruthless, my style as a juvenile
ran with a gang, slanged in the meanwhile
Explanation:
Which is true about relative dating?
Potassium –Argon dating is used on very old rocks and minerals.
Carbon-14 dating is used on rocks and minerals that are relatively young
Relative dating uses the half-life of isotopes to get the exact age of a rock or mineral
The law of superposition is used to determine a rocks relative age.
it's the last one because it's depended on the rock layers
Answer:
The law of superposition is used to determine a rocks relative age.
Determine the mass of AgCl(s) produced when 0.91 g of AgNO3 in an aqueous solution reacts with excess NaCl aqueous solution as shown below: AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq) i Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 10")
Answer:
0.77 g
Explanation:
Step 1: Write the balanced equation
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
Step 2: Calculate the moles corresponding to 0.91 g of AgNO₃
The molar mass of AgNO₃ is 169.87 g/mol.
0.91 g × 1 mol/169.87 g = 5.4 × 10⁻³ mol
Step 3: Calculate the moles of AgCl produced from 5.4 × 10⁻³ moles of AgNO₃
The molar ratio of AgNO₃ to AgCl is 1:1. The moles of AgCl produced are 1/1 × 5.4 × 10⁻³ mol = 5.4 × 10⁻³ mol.
Step 4: Calculate the mass corresponding to 5.4 × 10⁻³ moles of AgCl
The molar mass of AgCl is 143.32 g/mol.
5.4 × 10⁻³ mol × 143.32 g/mol = 0.77 g
Early chemists, known at the time as alchemists, had a difficult time understanding the Law of Conservation of Mass. Using the burning of wood as an example, what property of matter made this law difficult for early scientists to understand?
The law of conservation of mass states that, for any isolated system, the mass can neither be created nor be destroyed
After burning a log, the remains that are left behind after it burns are lesser than what would initially seem. There is a difference in mass before the burning of the log after the burning of the log. This seems like a violation of the law of conservation of mass, which would have made it difficult for early chemists to understand it. But if we consider the surroundings as a system then we can see that the mass that is lost in burning is actually converted into smoke and energy or forming other forms of substances. Then considering the whole system we can see that the mass and energy are conserved and interrelated.learn more about conservation of mass and energy:
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Surface tension is a force that affects....
A. Gases
B. Plasmas
C. Solids
D. Liquids
Answer:
option A iis the right answer
A continuously stirred tank reactor is designed to remove the hazardous waste compound trichloroethylene (TCE) from industrial wastewater. The tank is 3250 liters. The wastewater flows into the tank at 200 L/min with a TCE concentration of 25 mg/L. The reactor decays TCE at a reaction rate of 0.20 min-1 . What is the steady-state concentration of TCE in the treated water leaving the reactor
Answer:
the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L
Explanation:
Given that;
Tank volume v = 3250 liters
wastewater flows into the tank Q = 200 L/min
TCE concentration Co= 25 mg/L
reactor decays TCE at a reaction rate K = 0.20 min-1
mass balance
we know that;
Accumulation = inflow - outflow ± generation
⇒dc/dt = QCo - Qc ± rc.V
now at a steady state; dc/dt = 0
so
0 = QCo - Qc + rcV
where rc = -kc
0 = QCo - Qc - kcV
Qc + kcV = QCo
c(Q + kV) = QCo
c = QCo / (Q + kV)
so we substitute
c = (200 × 25) / (200 + (0.2×3250))
c = 5000 / 850
c = 5.88 mg/L
Therefore, the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L
Richard sketched models of two different neutral isotopes of oxygen. If the
isotope models are accurate, which statement might be true? (Refer to the
periodic table if necessary.)
A. One shows 7 protons, and one shows 9.
B. One shows 8 neutrons, and one shows 9.
C. One shows 8 electrons, and one shows 9.
D. One shows 8 protons, and one shows 7.
Answer:
its b
Explanation:
just did the test on A P E X
If the isotope models are accurate, One shows 8 neutrons, and one shows 9. Therefore, the correct option is option B.
What is isotope?A chemical element's isotope is one of more than one species of atoms that share the same atomic number, spot on the periodic table, and almost identical chemical activity, but differ in atomic mass and physical characteristics. There are a number of isotopes for each chemical element.
The first step in identifying and labelling an atom is to count the protons within its nucleus. Usually, this nuclear number is denoted by the letter Z. The fact that all atoms possessing the same number of electrons have essentially equal chemical characteristics lends the atomic number its enormous significance. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.
Therefore, the correct option is option B. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.
To know more about isotope, here:
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10-kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.
Answer:
Temperature = 0.605°C
Total enthalpy at 300kpa = 545.2 kJ
Total enthalpy at 600kpa = 846.45 kJ.
Explanation:
Checking the table for 134a pressure table. It is given that the specific volume of saturated liquid and the specific volume of the saturated vapor of 280kpa is 0.0007699 m^3/kg and 0.072352 m^3/kg respectively.
Also, the specific volume of saturated liquid and the specific volume of the saturated vapor of 320kpa is 0.0007772 m^3/kg and 0.063604 m^3/kg respectively.
The first thing to do is to determine the value for the specific volume of saturated liquid.
At 300 kpa, the specific volume of saturated liquid,n is given below as;
300 - 280/ 320 - 280 = (n - 0.0007699)/ 0.0007772 - 0.0007699.
Therefore, n = specific volume of saturated liquid = 0.0007735 m^3/kg.
300 - 280/ 320 - 280 = n - 0.072352/ (0.063604 - 0.072352).
n = 0.0679 m^3/kg.
The second thing to do is to determine the value of the specific volume.
Specific volume = 14 × 10^-3/ 10 = 0.0014 m^3/kg.
Determine the enthalpy of the mixture,b(I). This is given below as;
300 - 280/ 320 - 280 = b(I) - 199.54/ (196.7 - 199.54).
b(I) = 198.125 kJ/Kg.
Hence, b = [ 300 - 280/ 320 - 280 = j - 50.18 / 55.16 - 50.18] + [ ( 0.0014 - 0.00077735) / 0.067978 - 0.00077735] × 198.125.
b = 54.517 KJ/Kg.
Total enthalpy = 10 × 54.517 = 545.17 kJ.
Temperature can be Determine as below;
300 - 280/ 320 - 280 = T + 1.25 / 2.46 - 1.25.
Temperature = 0.605°C.
Hence, at 600kpa, the total enthalpy = [81.51 + ( 0.0014 - 0.0008199/ 0.034295 - 0.0008199) × 180.90] × 10
Total enthalpy at 600kpa = 846.45 kJ.
what is its molar concentration?
Answer:
The correct answer is - the number of moles of solute per liter of solution.
Explanation:
The molar concentration is also known as molarity which is the amount of concentration of a solute is in a chemical solution is the number of moles of solute per unit volume of solution. It is represented as M and can be calculated by:
M = n/v
Where n is the number of moles of the solute and,
v is the volume of solution (in liters normally)
It is worldwide used measurment for the concentration.
A silver nitrate solution contains 14.77 g of primary standard AGNO3 ( Molecular weight 169.87) in 1.00 L. What volume of this solution will be needed to react with 0.2631 g of NaCl ( Molecular weight 58.44) ?
Answer:
[tex]V=5.2 mL=0.052L[/tex]
Explanation:
Hello!
In this case, since the chemical reaction between silver nitrate and sodium chloride is:
[tex]AgNO_3(aq)+NaCl(aq)\rightarrow AgCl(s)+NaNO_3(aq)[/tex]
We can see there is a 1:1 mole ratio between each solution; thus, we first compute the moles of each reactant considering their molar masses:
[tex]n_{AgNO_3}=14.77g*\frac{1mol}{169.87g}=0.087molAgNO_3\\\\ n_{NaCl}=0.2631g*\frac{1mol}{58.44}=0.0045molNaCl[/tex]
Now, since the concentration of the silver chloride solution is 0.087 M, we may assume that the concentration of the NaCl solution is the same, so we can compute the volume as shown below:
[tex]V=\frac{n_{NaCl}}{M}=\frac{0.0045mol}{0.087mol/L}\\\\V=0.052L[/tex]
Or:
[tex]V=5.2 mL[/tex]
Best regards!
The volume of solution needed to react with 0.2631 g of NaCl is 0.052 L.
How we calculate the volume?Volume of the solution will be calculated by using the below formula:
M = n/V, where
M = concentration in terms of molarity
n = no. of moles
V = volume
Given chemical reaction is:
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
First we calculate the moles of given reactants by using the formula:
n = W/M , where
W = given mass
M = molar mass
Moles of AgNO₃ = 14.77g / 169.87g/mole = 0.087 mole
Moles of NaCl = 0.2631g / 58.44g/mole = 0.0045 mole
Concentration of AgNO₃ = 0.087 mole / 1L = 0.087M
From the stoichiometry of the reaction it is clear that mole ration of AgNO₃ & NaCl is 1:1. So, we take the concentration of NaCl is equal to the concentration of AgNO₃ and calculate the volume by using the above formula as:
Volume of NaCl = 0.0045mole / 0.087M = 0.052 L
Hence, 0.052 L is the required volume of NaCl.
To know more about moles, visit the below link:
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3. You can express the density of an object in units of kg/L or in units of
g/mL. How is the density of an object in kg/L related to its density in g/mL?
1. How would you describe what red cabbage juice is?*
(1 Point)
Acid
Neutral
Alkali
Indicator
Salt
I need help please please
Answer:
B should be the answer, and ur low-key valid lol
Explanation:
Can some one help I'm lost iam being timed:( Show using two conversion factors how you would convert from 0.020 kg into mg
Answer:
20000 Mg
Explanation:
list 5 island in the Philippines
Answer:
Coron, Palawan, El Nido, Palawan, Cebu, Boracay, Siargao.
Explanation:
I hope this helps.
coron,palawan,El nidu, Cebu and boracay are 5 island in Philippines.....
In general chemicals enter Ecosystems through which two spears
Answer:
biosphere and lithosphere
Explanation:
The biosphere is described as the zone of life on Earth. It is a sum of all ecosystems. The biosphere is composed of living organisms and non-living factors.
The lithosphere is the outer part of the Earth such that this part is rocky. The lithosphere is made up of the brittle crust.
In general, chemicals enter Ecosystems through the biosphere and lithosphere.
How many grams of silver nitrate are needed to prepare 0.125 M solution in 250.0 mL of water?*
(1 Point)
AgNO₃
Ag
= 107.868 8
mol
N = 14.0078
mol
8
0 = 15.999
mol
0.313 g
169.872 g
0.0849 g
5.31 g
O 31.3 g
Answer:5.3 grams AgNO3
Explanation:
To solve your problem, take a look at the definition of molality (m):
moles of solute/kg of solvent
You are given the grams of solvent (water) to find the grams of silver nitrate.
First, convert 250 grams to kg:
250 g * 1 kg / 1000g = 0.250 kg
Now that you have the kg of solvent, you can solve for the moles of solute:
kg of solvent * molality = moles of solute
0.250 kg * 0.125 m = 0.03125 mol AgNO3
You can convert the number of moles to grams using the molar mass of AgNO3, which is 169.872 g/mol:
moles of solute * molar mass of solute = grams of solute
0.03125 mol AgNO3 * 169.872 g/mol = 5.3085 g
Because your question provides two significant digits, you must round this number to get the final answer:
5.3 grams AgNO3
I hope this helps!