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Answer:

Cddd

Step-by-step explanation:

Answer:

4(x - 3)

Step-by-step explanation:

4x = 4 * x

12 = 4 * 3

GCF = 4

4x - 12 = 4*x - 4*3

           = 4(x - 3)

                                                                                    the second one.

............................

Answer:

[tex]x=\sqrt{14}[/tex]

Step-by-step explanation:

This triangle is a 45-45-90 triangle.

By using the image I posted, we can find x easily.

So, we have [tex]\sqrt{7}[/tex] as one of the sides.

They hypotenuse, which is x is just [tex]\sqrt{7} \sqrt{2}[/tex]

Simplify and we get x = [tex]\sqrt{14}[/tex]

Answer:

30.5x1200=36600

r=el avion vuela a 36.600m de altura

Answer:

24

Step-by-step explanation:

Answer:

I personally don't, but if you search up graph helper you could answer all of them. Hope you find the answer.

Step-by-step explanation:

Answer:

what table? there is no picture attached or answer choices.

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

It must first translate 1 unit to the left because quadrilateral F'G'H'I is one unit away from to y axis. It can then translate across the y-axis.

Answer:

ITS B!

Step-by-step explanation:

Ape x!

Answer:

Step-by-step explanation:

Answer:

530.66 cm squared

Step-by-step Explanation:

Diameter of the circle = 26 cm

Radius of the circle (r) = 26/2 = 13 cm

[tex]A_{circle} = \pi {r}^{2} \\ \\ A_{circle} = 3.14 \times {(13)}^{2} \\ \\ A_{circle} = 3.14 \times 169 \\ \\ A_{circle} =530.66 \: {cm}^{2} [/tex]

Answer:

The area of 530.66 cm squared.

Option (a) 530.66 cm² is the correct answer.

Step-by-step explanation:

Given :

To Find :

Using Formulas :

[tex]\star{\small{\underline{\boxed{\sf{\red{R = \dfrac{D}{2}}}}}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = \pi{r}^{2}}}}}}}[/tex]

Solution :

Finding the radius of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Radius = \dfrac{D}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \dfrac{26}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \cancel{\dfrac{26}{2}}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = 13}}}[/tex]

[tex]\star{\underline{\boxed{\sf{\red{Radius = 13 \: cm}}}}}[/tex]

Hence, the radius of circle is 13 cm.

[tex]\rule{200}2[/tex]

Now, finding the area of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \pi{r}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 3.14 \times {(13)}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times {(13 \times 13)}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times 169}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314 \times 169}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{53066}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 530.66}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = 530.66 \: {cm}^{2}}}}}}}[/tex]

Hence, the area of circle is 530.66 cm².

[tex]\rule{300}{1.5}[/tex]

Answer:

what in the math equations is this???

Step-by-step explanation:

Answer:

Car A: Initial Charge = 20

Car B: Initial Charge = 30

Car A: Rate = 5

Car B: Rate = 0

At 2 miles, their charges will be the same

Step-by-step explanation:

Given

Car A

[tex]Base\ Charge = \$20[/tex]

[tex]Rate = \$5[/tex] per mile

Car B

[tex]Base\ Charge = \$30[/tex]

Solving (a): The initial charge

First, we get the  linear equation that represents both car's charges.

Represent number of miles with m.

So, the charges is:

Car A

[tex]A = Base\ Charge + Rate * m[/tex]

[tex]A = 20 + 5 * m[/tex]

[tex]A = 20 + 5m[/tex]

Set m to 0 to get the initial charge:

[tex]A = 20 + 5*0[/tex]

[tex]A=20[/tex]

and

[tex]Rate = 5[/tex]

Car B:

[tex]B = Base\ Charge + 0 * m[/tex] i.e. Rate is 0

[tex]B = 30+ 0 * m[/tex]

[tex]B = 30[/tex]

So:

[tex]Initial = 30[/tex] and [tex]Rate = 0[/tex]

Solving (b): When their charge wil be equal.

To do this, we set:

[tex]A = B[/tex]

[tex]20 + 5m = 30[/tex]

[tex]5m = 30- 20[/tex]

[tex]5m = 10[/tex]

[tex]m = 2[/tex]

At 2 miles, their charges will be equal

Answer:Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?

Answer:

48

Step-by-step explanation:

round off 3.8 to 4 and 11.9 to 12 and multiply the values

Answer:28

Step-by-step explanation:

hope this helpes

Answer:

the probability of drawing a blue ball from bag A is 1/5 and the probability of drawing a red ball from bag B is 2/3.

The probability of drawing a blue ball from Bag A and a red ball from Bag B will be 2/15.

Probability denotes the likelihood of something happening. It is concerned with the occurrence of an unpredicted event.

Probability can only have a value between 0 and 1. Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of events is known as the favorable event ratio.

The probability of drawing a blue ball from Bag A is, 1/5

The probability of drawing a red ball from Bag B is, 2/3.

P(A)=1/5

P(B)=2/3

The probability of drawing a blue ball from Bag A and a red ball from Bag B will be;

P(A and B)=P(A). P(B)

P(A and B)=(1/5)×(2/3)

P(A and B)=(2/15)

Hence,the probability of drawing a blue ball from Bag A and a red ball from Bag B will be 2/15.

To learn more about the probability refer;

https://brainly.com/question/795909

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Answer:

Step-by-step explanation:

The proportion between the first two and the second two numbers are:

Simplifying the second fraction:

Comparing the fractions:

The answer is no

Answer:

- Discount car rentals charges less daily

- After 3 days

Step-by-step explanation:

Required

Which charges less per day

When is the total cost the same

First, calculate the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

From the table, we have:

[tex](x_1,y_1) = (2,185)[/tex]

[tex](x_2,y_2) = (6,345)[/tex]

So, we have:

[tex]m = \frac{345 - 185}{6 - 2}[/tex]

[tex]m = \frac{160}{4}[/tex]

[tex]m = 40[/tex]

The equation is then calculated as:

[tex]y = m(x - x_1) + y_1[/tex]

[tex]y = 40(x - 2) + 185[/tex]

[tex]y = 40x - 80 + 185[/tex]

[tex]y = 40x + 105[/tex]

So, the equation of the table (i.e. Discount Car rental) is: [tex]y = 40x + 105[/tex]

While the equation of Pay Less is: [tex]y = 55x + 60[/tex]

The company that charges less per day has the smaller slope and that is: Discount car rental because the slope (40) is less than the slope (55)

For the total cost to be the same, we simply equate both expressions:

i.e.

[tex]y = y[/tex]

[tex]55x + 60 = 40x + 105[/tex]

[tex]55x - 40x = - 60 + 105[/tex]

[tex]15x =45[/tex]

[tex]x = 3[/tex]

Answer:

D

Step-by-step explanation:

(3.25+4.75+15) =23

23- (2.5+2.75+10)

= 7.75

I'm just as confused as you are

Answer:

Square

Step-by-step explanation:

From what it looks like I think it is a square

Answer:

C. Square

Step-by-step explanation:

The cross section is the surface that would be exposed if the shape was cut by that other shape. If that cube was cut like that, then the surface would be a square.

Answer:

a) the probability of (2 < X < 6) is 0.6247

b) the value of c is 3.878

c) the value of E[ x² ] is 13

Step-by-step explanation:

Given that;

mean μ = 3

variance = 4

standard deviation s = √variance  = √4 = 2

(a) Find the probability P(2 < X < 6)

P(2 < X < 6) = p( (x - μ / s ) < z <  (x - μ / s ) )

= p( (2 - 3 / 2 ) < z < (6 - 3 / 2 ) )

= p( -0.5  < z <  1.5)

from z-score table, 1.5; z = 0.9332 and -0.5; z = 0.3085

so

P(2 < X < 6)  = 0.9332 - 0.3085 = 0.6247

Therefore, the probability of (2 < X < 6) is 0.6247

b) Find the value c such that P(X > c) = 0.33

with p-value = 0.33, the corresponding z -score to the right is 0.439

we know that;

z = x - μ / s

we substitute

0.439 = x - 3 / 2

x - 3 = 2 × 0.439

x - 3 = 0.878

x = 0.878 + 3

x = 3.878

Therefore, the value of c is 3.878

c) Find E[ x² ].

Variance = E[ x² ] - [ mean ]²

E[ x² ]  = Variance + [ mean ]²

we substitute

E[ x² ]  = 4 + [ 3 ]²

E[ x² ]  = 4 + 9

E[ x² ]  = 13

Therefore, the value of E[ x² ] is 13

The distribution follows a normal distribution.

The given parameters are:

[tex]\mathbf{\mu = 3}[/tex] --- mean

[tex]\mathbf{\sigma^2= 4}[/tex] --- variance

(a) P(2 < x < 6)

Start by calculating the standard deviation

[tex]\mathbf{\sigma = \sqrt{\sigma^2}}[/tex]

This gives

[tex]\mathbf{\sigma = \sqrt{4}}[/tex]

[tex]\mathbf{\sigma =2}[/tex]

Calculate the z-scores for x = 2 and 6

[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]

So, we have:

[tex]\mathbf{z = \frac{2 - 3}{2} = -0.5}[/tex]

[tex]\mathbf{z = \frac{6 - 3}{2} = 1.5}[/tex]

So, the probability becomes

[tex]\mathbf{P(2 < x < 6) = P(-0.5 < z < 1.5)}[/tex]

Using z table of probabilities, we have:

[tex]\mathbf{P(2 < x < 6) =0.9332 - 0.3085}[/tex]

[tex]\mathbf{P(2 < x < 6) =0.6247}[/tex]

(b) Calculate c if P(X > c) = 0.33

Start by calculating the z-score for p-value = 0.33

From the z table, z = 0.439 when p-value = 0.33

Recall that:

[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]

So, we have:

[tex]\mathbf{0.439 = \frac{x - 3}{2}}[/tex]

Multiply both sides by 2

[tex]\mathbf{0.878= x - 3}[/tex]

Add 3 to both sides

[tex]\mathbf{3.878= x}[/tex]

Rewrite as:

[tex]\mathbf{x = 3.878}[/tex]

Replace x with c

[tex]\mathbf{c = 3.878}[/tex]

The value of c is 3.878

(c) Calculate E[x²]

The variance of a dataset is:

[tex]\mathbf{\sigma^2 =E(x^2) - \mu^2}[/tex]

Substitute known values

[tex]\mathbf{4 =E(x^2) - 3^2}[/tex]

[tex]\mathbf{4 =E(x^2) - 9}[/tex]

Add 9 to both sides

[tex]\mathbf{13 =E(x^2) }[/tex]

Rewrite as:

[tex]\mathbf{E(x^2) = 13 }[/tex]

Hence, the value of [tex]\mathbf{E(x^2) }[/tex] is 13

Read more about normal random variables at:

https://brainly.com/question/11395972

Answer:

1001/1500

Step-by-step explanation:

The easiest method for doing this is to just average the two numbers.

e.g. to find a number x between the two numbers ab and cd

x=12[ab+cd]

=12[adbd+bcbd]

=ad+bc2bd

In this case…

x=(2×5)+(3×4)2×2×5=10+1230=2230=1115

You can easily see where that came from.

23=1015 and 45=1215

and the ‘common denominator’ means you just have to pick a value between 10 and 12 . i.e. 11

But you can also say…

23=100150 and 45=120150

and choose any of 101150,102150,...,119150

or

23=10001500 and 45=12001500

and choose any of 10011500,10021500,...,11991500

Answer:4/5 and 2/3 each have a common bottom of 15 so 4/5 is

12/15 and 2/3 will be 10/15

Step-by-step explanation:So than 12/15 forget the bottom don't subtract the bottom just look at it like [12-10] then you got 2 then you go back to the bottom and put it together so your answer is [2/15]

Answer:

they all went to the stairs

Step-by-step explanation:

67.90 I don't know u tell me

Answer:

The answer is D slope = -3 y-intercept = -2

Step-by-step explanation:

Answer

D.

Step-by-step explanation:

The first part of the equation is -3 and the second part is -2. The number attached to the variable is the "slope" and the number coming after the variable is the y intercept.

Answer:

The answer is 5.07%, I just did this :)

Answer:

he is 36 months old or 3 years old, and he ways 82 kilograms.

Step-by-step explanation:

quick mafs

The point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.

In a graph, the line which is horizontal is known as the x-axis of the graph. The vertical line in the graph is called the y-axis of it. These axis helps to read the data from graph in following way-

In the given graph, the x-axis is labeled with age in months and y-axis is labeled with weight of panda.

The point with coordinates (36,82) tells that the age of panda is 36 months and the weight of the panda is 82 kilograms.

Hence, the point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.

Learn more about the graph here;

https://brainly.com/question/24696306

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