Answer: D. plant more trees where forests are cut down.
Explanation:
Deforestation has to do with the cutting down of trees. Cutting down the forest reduces the size of animal habitats, increases erosion, and results in an increase in the amount of carbon dioxide in the atmosphere.
Ok order to tackle the above, it is necessary that we should plant more trees where forests are cut down.
Which radio wave technologies would be unaffected by satellites that are not working properly?
space communication and television broadcasting television broadcasting and GPS O MRI and radio telescopes
O radio telescopes and space communication
Answer:
MRI and Radio telescopes
MRI and radio telescopes would be unaffected by satellites that are not working properly.
What is radio wave?The longest wavelengths in the electromagnetic spectrum are found in radio waves, which typically have frequencies of 300 gigahertz (GHz) and lower. The wavelength for 300 GHz is 1 mm, which is shorter than a grain of rice, while the wavelength for 30 Hz is 10,000 km (6,200 miles) (longer than the radius of the Earth).
Radio waves move at the speed of light in a vacuum, as do all electromagnetic waves, and at a nearly identical speed in the Earth's atmosphere.
Among the given options, space communication and television broadcasting television broadcasting and GPS and radio telescopes and space communication are affected by satellites that are not working properly because they are operated by satellite technology.
Hence, only MRI and radio telescopes would be unaffected by satellites that are not working properly.
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Which of the following has the most kinetic energy?
A. stretching a rubber band
B. a jet flying through the air
C. throwing a paper airplane
D. pitching a baseball
Alyssa is taking a walk on a nature path near her neighborhood. She
carries a compass with her. As she walks along the path, she notices
the needle on the compass is occasionally deflected from its original
position. If she has not changed the direction she is walking, what is
most likely causing the occasional shift in the needle? (1 point)
O Changes in pressure
0 Changes in temperature
O Sources of electrical current
O Changes to Earth's magnetic field
Answer:
C. Sources of electrical current!
Hope this helps :)
Answer:
Sources of electrical current
Explanation:
Got it right on the test.
The attaction between magnets is a chemical property.
True
Or
False
Answer:
false its an attraction property
Answer:
True
The attraction is a chemical property.
A force of 3kN acts on a car to make it accelerate by 1.5m/s/s. What is the mass of the car?
Answer:
2
Explanation:
To find force it's force = mass times acceleration so to find mass you would divide force by acceleration
Under constant acceleration, the average velocity of a particle is half the sum of its initial and final
velocities. Is this still true if the acceleration is not constant? Explain.
Answer:
It is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle is not constant
Explanation:
The motion of a particle under constant acceleration, 'a', is be given by the following kinematic equations;
v² = u² + 2·a·s
v = u + a·t
Where;
v = The final velocity of the particle
u = The initial velocity of the particle
a = The acceleration of the particle
s = The distance through which the particle travels
t = The time of motion of the particle
By simplifying the above equation, we have;
v² - u² = 2·a·s
(v² - u²)/(2·a) = s
(v - u) × (v + u)/(2 × a) = s
((v - u)/a) × ((v + u)/2) = s
From v = u + a·t, we have;
t = (v - u)/a
∴ ((v - u)/a) × ((v + u)/2) = t × ((v + u)/2) = s
∴ ((v + u)/2) = s/t
The average velocity = (Total distance traveled by the particle) ÷ (The time of travel of the particle)
∴ The average velocity = s/t = ((v + u)/2) = Half the sum of the initial and final velocity
However, it is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle, 'a', is not constant, as the velocity time graph is no longer a straight line graph and the distance traveled by the particle, 's', which is the area under the velocity time graph, 'A', (given by the sum of area of the triangle and the rectangle given by the area under straight line graph for constant velocity) cannot be given directly by the product of the time and the average velocity.
Draw the position vs. time graph for a person walking at a constant speed of 1m/s for 10 seconds. On the same axes, draw graph for a person running at a constant speed of 4m/s
Plot a graph, constant speed of movements represented as straight lines. Time on X axis (seconds) and position on Y axis (metres) , calculated by moving, e.g 4metres in a second.
Can someone pls help me. WILL MARK U BRAINLIEST!!!
What is the kinetic energy of a 25kg object moving at a velocity of 2.5 m/s
Answer:
78j
Explanation:
78.125J to be exact
what energy change takes place when the cell absorbs sunlight
Answer:
It is called photosynthesis.
Explanation:
What is angle between the vectors 2i -3j +K
and 3i +2j
?
a. 90°
C. 60°
b. 0°
d. 120°
Answer:
the answer is B
Explanation:
edg 2020
A body is at equilibrium under the action of three forces. One force is 10N acting due east and one is 5N in the direction 60° north east. What is the magnitude and direction of the third force?
Answer:
If the body is in equilibrium the two forces add up and the third is the opposite of the resultant.
F(1x)=F(1)=10 N
F(2x)=F(2)cos60=5•0.5=2.5 N
F(2y) =F(2)sin60 = 5•0.866= 4.33 N
F(3x) =- F(x)=- (10+2.5 )= -12.5 N
F(3y) =- F(2y)= - 4.33 N
F(3) = sqrt{ F(3x)²+F(3y)²} =13.23 N
tan φ = F(3y)/F(3x) =4.33/12.5=0.364
φ = 19.1⁰ (south-west)
Explanation:
If you are in a car that is being pulled down a 56 m path with a force of 12.5
N, what is the work being done?
Answer:
answer is 700 joules
Explanation:
work is equal to force into displacement
W=12.5*56
700 joules
Which has a larger acceleration, a car or a person running?
Answer:
A car
Explanation:
5. If an object has an acceleration of 0 m/s2, then one can be sure that the object is not ____.
a. moving
b. changing position
c. changing velocity
6. If car A passes car B, then car A must be ____.
a. accelerating.
b. accelerating at a greater rate than car B.
c. moving faster than car B and accelerating more than car B.
d. moving faster than car B, but not necessarily accelerating.
7. Which one of the following is NOT consistent with a car which is accelerating?
a. A car is moving with an increasing speed.
b. A car is moving with a decreasing speed.
c. A car is moving at a high speed.
d. A car is changing direction.
8. A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that
a. he is accelerating
b. he is covering a greater distance in each consecutive second.
c. he is moving with a constant speed (on average).
Answer: c
Explanation: for #5 it can still be moving, just at a constant speed; therefore, it will be c.
If an object has an acceleration of 0 m/s2, then one can be sure that the object is not changing velocity.
If car A passes car B, then car A must be moving faster than car B, but not necessarily accelerating.
The not consistent with a car that is accelerating is a car is moving at a high speed.
A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that he is moving with a constant speed (on average).
What is Acceleration?Acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities (in that they have magnitude and direction). Speed is the distance covered in a unit of time while acceleration is the rate of change in speed. The unit of speed in the metric system is meters per second (m/s) while that of acceleration is meters per second squared (m/s2). Speed is a scalar quantity while acceleration is a vector quantity.To learn more about acceleration and speed, refer to: https://brainly.com/question/25086037
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Please HELP ME If the motion of an object changes, what must be true about the forces acting on that object?
Answer:
If there is a net force acting on an object, the object will have an acceleration and the object's velocity will change. ... Newton's second law states that for a particular force, the acceleration of an object is proportional to the net force and inversely proportional to the mass of the object.
Explanation:
If the motion of an object changes, the net force on the object is greater than zero or the forces acting on the object is unbalanced.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object. The object will move in the direction of the applied force.
When the net force on an object is zero, the object will be remain at rest.
However, when the net force on object is greater than zero, the object will move in the direction of the greater force.
Thus, we can conclude that if the motion of an object changes, the net force on the object is greater than zero or the forces acting on the object is unbalanced.
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Which is not an Ultimate Frisbee rule?
A phonograph record 0.15 m in its radius rotates 18 times per 90 seconds what is the frequency?
Answer:
The frequency of the phonograph record is 0.2 Hz
Explanation:
The frequency of an object moving in uniform circular motion is the number of completed cycles the object makes in a specified time period
The given parameters of the phonograph record are;
The radius of the record = 0.15 m
The number of times the phonograph record rotates, n = 18 times
The time it takes the phonograph record to rotate the 18 times, t = 90 seconds
The frequency of the phonograph record, f = (The number of times the phonograph record rotates) ÷ (The time it takes the phonograph record to rotate the 18 times)
∴ The frequency of the phonograph record, f = n/t = 18/(90 s) = 0.2 Hz
The frequency of the phonograph record = 0.2 Hz.