Answer:
R = 45.05 ft, θ = -29º
Explanation:
Let's analyze your problem, two cars collide that get stuck, then this collide with a third car and they get stuck and the whole collides with a wall stopping, this problem has several parts
We define a form system for all the cars, so that during the crashes the forces have been internal and the moment can be preserved
Let's slow down to the English system
vₐ₀ = 63 mi / h (5280 ft / 1 mile) (1 h / 3600 s) = 92.4 ft / s
v_{bo] = 76.8757 mi / h = 112.7 ft / s
v_{c0} = 45 mi / h = 66 ft / s
Let's start by looking for the velocity in the first collision, let's set a reference system with the x-axis in the eastern direction
X axis
initial instant. Before crash
p₀ = mₐ vₐ₀
final instant. Right after the crash
p_f = (mₐ + m_b) v₁ₓ
the moment will be preserved
p₀ = p_f
mₐ vₐ₀ = (mₐ + m_b) v₁ₓ
v₁ₓ = [tex]\frac{m_a}{m_a+m_b} \ v_{ao}[/tex]
let's look for speed
note that the unit of free is the weight (W = mg), but since it is in the numerator and denominator the value of gravity is eliminated, so we do not have to reduce this unit
v₁ₓ = [tex]\frac{3000}{3000+3600} \ 92.4[/tex]
v₁ₓ = 42 ft / s
Y axis
initial
p₀ = -m_b v_{bo}
the negative sign is because it travels south (negative of the y-axis)
final
p_f = (mₐ + m_b) v_{1y}
conservation moment
p₀ = p_f
-m_b v_{bo} = (mₐ + m_b) v_{1y}
v_{1y} = [tex]- \frac{m_a}{m_a+m_b} \ v_{1y}[/tex]
we look for the value
v_{1y} = [tex]- \frac{3000}{3000+3600} \ 112.7[/tex]
v_{1y} = -51.227 ft / s
Now let's solve the second clash
X axis
initial
p₀ = (mₐ + m_b) v₁ₓ
final
p_f = (mₐ + m_b + m_c) v₂ₓ
conservation moment
(mₐ + m_b) v₁ₓ = (mₐ + m_b + m_c) v₂ₓ
M = mₐ + m_b + m_c
v₂ₓ = [tex]\frac{m_a+m_b}{M} \ v_{1x}[/tex]
we calculate
M = 3000 + 3600 + 3000 = 9600
v₂ₓ = [tex]\frac{ 3000+3600}{9600} \ 42[/tex]
v₂ₓ = 26.25 ft / s
Y axis
initial
p₀ = (mₐ + m_b) v_{1y} + m_c v_{co}
final
m_f = M v_{2y}
conservation moment
(mₐ + m_b) v_[1y} + m_c v_{co} = M v_{2y}
v_{2y} = [tex]\frac{m_a+m_b}{M } \ v_{1y} + \frac{m_c}{M} \ v_{co}[/tex]
we calculate
v_{2y} = [tex]- \frac{3000+3600}{9600} \ 51.227 + \frac{3000}{9600} \ 66[/tex]
v_{2y} = - 35.22 + 20.625
v_{2y} = - 14.594 ft / s
We already have the velocity of the set of vehicles, now we can use the kinematics relations to find the diastase at point D
For this last part we must make some assumptions
* we despise collision times
* we find the distance that the given time advances (t = 1.5 s) using the equations of uniform motion
X axis
x = v₂ₓ t
x = 26.25 1.5
x = 39.375 ft
Axis y
y = v_{2y} t
y = -14.594 1.5
y = -21.89 ft
We can give the answer in two ways
* the position is 39.375 ft to the East and 21.89 ft to the South
* In the form of module and angle
Let's use the Pythagorean theorem
R = [tex]\sqrt{x^2+ y^2}[/tex]
R = [tex]\sqrt{39.375^2 + 21.89^2}[/tex]
R = 45.05 ft
let's use trigonometry
tan θ = y / x
θ = tan⁻¹ y / x
θ = tan⁻¹ (-21.89 / 39.375)
θ = -29º
this angle is measured clockwise from the x axis
Describe what happens to the magnitude of the net electrostatic force on the electron as the electron
is moved toward the positive plate. [1]
When the electron is moved toward the positive plate, the electrostatic force increases causing the electron to be attracted to the positive plate.
What is the electrostatic force?The electrostatic force is the force tat acts between two charges. The nature of this force is described by the Coulumb law.
When the electron is moved toward the positive plate, the electrostatic force increases causing the electron to be attracted to the positive plate.
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1. What is the ideal mechanical advantage of a wedge that is 12 cm long
and 4 cm wide?
A. 16
B. 48
C. 3
D. 8
Which DOES NOT happen during the phase change from liquid to solid?
Kinetic energy decreases
Particles move slower
Freezing occurs
Temperature increases
Answer:
Temperature increases
During the phase transition from liquid to solid, kinetic energy diminishes, particles move slower, and freezing occurs.
Phase change:Extreme heat is more likely to occur as a result of rising temperatures, and it will last longer. Heatwaves can indeed be deadly, resulting in manifestations including heat kinks and heat exhaustion, as well as death.
Warmer temperatures have the potential to trigger a cascade of other changes around the world.The greenhouse effect is worsened by these gas emissions, which cause the earth's crust temperature to rise. Burning fossil fuels has the greatest impact on climate change of any human activity.Since in changement from liquid to solid the temperature will decrease.Therefore, the final answer is "Temperature increases".
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A bar magnet has
a. one magnetic pole.
b. two magnetic poles.
c. three magnetic poles.
d. four magnetic poles.
Answer:
b
Explanation:
Bar magnets have two magnetic poles
What are some ways the government can help reduce greenhouse gases?
Answer:
Switching power plants, for example, from coal-burning to gas-burning can significantly reduce emissions. Equip fossil fuel plants with carbon capture and storage technology. ... Although it doesn't exactly reduce emissions, carbon capture technology does prevent emissions from reaching the atmosphere.
The potential energy of an object is 16.0 joules. The object is 145cm high.
What is the mass of the object?
Answer:
I don't know but you got this!!
can someone pls help
Answer:i
Explanation:∩
help meee plisssssssssssssssssssssssssssss
Answer:
Resistance = 0.22 Ohms
Current = 13.63636 A
Explanation:
Total resistance for resistors in parallel is given by:
[tex]\frac{1}{T} =\frac{1}{R1} +\frac{1}{R2} +...+\frac{1}{Rn}[/tex] where n is the number of resistors
[tex]\frac{1}{T} = \frac{1}{1.1} +\frac{1}{1.1} +\frac{1}{1.1} +\frac{1}{1.1} +\frac{1}{1.1}[/tex]
if you solve that you get [tex]\frac{1}{T} = 5/1.1 \\\\T = 1.1/5T = 0.22 Ohms[/tex]
Solve current using V=IR
I=V/R =
I=3/0.22
I = 13.63636 A
A metal pot feels hot to the touch after a short time on the shove. what type of material is the metal pot
What are Heredity and Punnett Squares?
Answer: A Punnett square can be used to predict genotype and phenotypes of offspring from genetic crosses. ... In the P generation, one parent has a dominant yellow phenotype and the genotype YY, and the other parent has the recessive green phenotype and the genotype yy.
Explanation:
A solenoid consists of 4200 turns of copper wire. The wire has a diameter of 0.200 mm. The solenoid has a diameter of 1.00 cm. When the solenoid is connected to a 12.0 V battery, we observe that the current increases over time and is 155 mA after 1.50 milliseconds have passed. Assume that the internal resistance of the battery and connecting wires is negligible.
Required:
a. What is the length of wire needed to form the solenoid?
b. What is the inductance of the solenoid?
c. What is the length of the solenoid?
d. What will be the current after three time constants have elapsed?
Answer:
a. The length of the solenoid wire is approximately 131.95 m
b. The inductance of the solenoid is approximately 2.078 × 10⁻³ H
c. The length of the solenoid is 0.84 m
d. The current after three time constants have elapsed is approximately 456.1 A
Explanation:
The given parameters are;
The number of turns in the solenoid, N = 4,200 turns
The diameter of the wire, d = 0.200 mm
The diameter of the solenoid, D = 1.00 cm
The voltage of the battery connected to the solenoid, V = 12.0 V
The current increase = 155 mA
The time for the increase = 1.50 millisecond
The internal resistance of the battery is negligible
a. The length of wire needed to form the solenoid, l = π·D·N
∴ l = π × 0.01 × 4,200 ≈ 131.95
The length of the solenoid, l ≈ 131.95 m
b. The inductance, 'L', of the solenoid is given as follows;
[tex]L = \dfrac{\mu_0 \cdot N^2 \cdot A}{l}[/tex]
Where;
μ₀ = 12.6 × 10⁻⁷ H/m
N² = 4,200²
A = The cross sectional area of the solenoid = π·D²/4
l = Length of the solenoid = d × N = 0.0002 m × 4,200 = 0.84 m
∴ L = (12.6 × 10⁻⁷ × 4,200² × 0.01² × π/4)/0.84 ≈ 0.002078 = 2.078 × 10⁻³
The inductance, L ≈ 2.078 × 10⁻³ H
c.) The length of the solenoid = d × N = 0.0002 m × 4,200 = 0.84 m
The length of the solenoid = 0.84 m
d. The current after three time constant
We have;
∈ = -L × di/dt
di/dt = 155 mA/1.5 ms = 103.[tex]\overline 3[/tex] A/s
∈ = 103.[tex]\overline 3[/tex] A/s × 2.078 × 10⁻³ H = 0.21472[tex]\overline 6[/tex] V
We have;
[tex]\tau = \dfrac{t}{\left(ln\dfrac{1}{1-\dfrac{Change}{Final-Start} } \right)}[/tex]
The change in voltage = 0.21472[tex]\overline 6[/tex] V
The start voltage = 0 V
The final voltage = 12.0 V
t = 1.5 ms = 0.0015 s
We get;
[tex]\tau = \dfrac{0.0015}{\left(ln\dfrac{1}{1-\dfrac{0.21472\overline 6}{12-0} } \right)} \approx 8.3076\times 10^{-2}[/tex]
τ = L/R
Therefore,
R = L/τ =
The resistance = 2.078 × 10⁻³/(8.3076×10⁻²) = 0.0250
The resistance = 0.0250 Ω
[tex]I= \dfrac{V}{R} \cdot \left(1 - e^{-\dfrac{t}{\tau} }\right)[/tex]
Therefore, after three time constants, we have;
∴ I = (12.0/(0.0250)) × (1 - e⁻³) ≈ 456.1
The current after three time constants have elapsed, I ≈ 456.1 A.
Because of surface tension, it is possible, with care, to support an object heavier than water on the water surface. The maximum thickness, h, of a square material that can be supported is assumed to be a function of the length of the side of the square, the density of the material, the acceleration of gravity, and the surface tension of the liquid. Develop a suitable set of dimensionless parameters for this problem.
Answer:
[tex]\pi 1 = \frac{h}{l}[/tex]
[tex]\pi 2 =[/tex] б / [tex]l^2gp[/tex]
[tex]\frac{h}{l} =[/tex] Ф ( б / [tex]l^2gp[/tex] )
Explanation:
Develop a suitable set of dimensionless parameters for this problem
The set of dimensionless parameters for this problem is :
[tex]\pi 1 = \frac{h}{l}[/tex]
[tex]\pi 2 =[/tex] б / [tex]l^2gp[/tex]
[tex]\frac{h}{l} =[/tex] Ф ( б / [tex]l^2gp[/tex] )
and they are using the pi theorem, MLT systems
attached below is a detailed solution
Which of the following can be studied by science?
O A. Value judgments
O B. Matters of opinion
O C. Questions of right and wrong
O D. Natural phenomena.
In the “Elastic Collision" part of this activity, what happened to the momentum of the red cart after the collision? What happened to the momentum of the blue cart after the collision?
Explanation:
Elastic collision between balls of equal mass viimis 1.5 mys 1.5m/s 1! mis ... Make a data table for the following: mass, velocity and momentum of each ball before ... Part 2 moving faster. ... Summary: Describe the main ideas learned in this activity regarding initial and ... Collision 2: Blue Cart Moving Slower than the Red Cart.
2. Predict what will happen if the 80 kg adult was further from the pivot (more right) and explain your reasoning. 3. Predict what will happen if the 30 kg child was closer to the pivot (more right) and explain your reasoning. 4. Test your predictions in the Balance Lab. Make notes about any ideas you have that need to be changed. 5. What are some rules you could use to make predictions for other situations where masses are on a balance
Answer:
2) τ = F x torque increases, 3) troque decreases,
4) man approaches the pivot and the child must move away
5) Σ τ = 0
Explanation:
2) when the man moves away from the pivot his torque increases significantly, since his distance increases
τ = F x
τ = m g x
therefore the system rotates faster
3) when the child approaches the pivot, his troque decreases, because the distance decreases
τ = f x
therefore the system must spin slower
4) If we place the man and the child on the side of a scale, the movement must be the man approaches the pivot and the child must move away, so that the torque is the same and the system can reach a balance
5) the rotational equilibrium expression
Σ τ = 0
is the one that describes the equilibrium of a system with several forces
Following are the solution to the given points:
For question 2:
If the guy was further to the right, say the [tex]5^{th}[/tex] unit,[tex]\to W_2\times d_2=80\times 5=300\ units[/tex]
Since this value is larger than [tex]W_1\times d_1=30\times 8=240\ units[/tex]As just a result, the boards will lean towards the guy, and will tumble to the right.For question 3:
If the girl was [tex]6^{th}[/tex] units closer to a pivot,[tex]\to W_1\times d_1=30\times 6=180 \ units[/tex]
This value is once again less than [tex]W_2\times d_2=80\times 3=240\ units[/tex]As just a result, the boards will tilt towards the guy, and will fall to the right.For questions 4 and 5:
Whenever experimenting, verify that the mass you utilize and the distance you travel are carefully measured. Since even a tiny quantity of ambiguity in such measures can produce unexpected results.Learn more:
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Part A
n
Rank the light intensity, from largest to smallest, at the point P in the figures.
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E
D
C
B
A
2 bulbs
3 bulbs
00
4 bulbs
XOXO
1 bulb
2 bulbs
co
T0.5 m
1.0 m
1.5 m
个
1.0 m
p
2.0 m
P
P
OP
Largest
Smallest
The light intensity from largest to smallest ranking will be :
B > D > A=C > E
What is intensity ?
In physics, the intensity is the power transferred per unit area, where the area is measured on the plane perpendicular to the direction of propagation of the energy
equation to find intensity is I = P/ 4π(d^2)
where P = Power
I = intensity
d = distance where the intensity need to be found
let power of 1 bulb be = P
case A = I = P / (1)^2 = P / 1 =P
case B = I = 2P/ (0.5)^2 = 8P
case C = I = 4P / (2)^2 = P
case D = I = 3P / (1)^2 = 3P
case E = I = 2P /(1.5)^2 = 0.8 P
The light intensity from largest to smallest ranking will be :
B > D > A=C > E
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Which of the following is the tendency of a system to become more
disordered?
A. Energy
B. Heat
C. Entropy
D. Efficiency
Answer:
b
Explanation:
the more heat the hotel it get which cause more heat
Answer: C. Entropy
Explanation: a pex :)
A researcher plans to release a weather balloon from ground level, to be used for high-altitude atmospheric measurements. The balloon is spherical, with a radius of 2.00 m, and filled with hydrogen. The total mass of the balloon (including the hydrogen within it) and the instruments it carries is 20.0 kg. The density of air at ground level is 1.29 kg/m3. (a) What is the magnitude of the buoyant force (in N) acting on the balloon, just after it is released from ground level
Answer:
B = 423.64 N
Explanation:
The thrust force in a fluid is equal to the weight of the displaced fluid,
B = ρ g V
where the density is that of air ρ=1.29 kg / m³ and the volume of the spherical balloon is
V = [tex]\frac{4}{3} \pi r^3[/tex]
v = 4/3 π 2³
V = 33.51 m³
let's calculate the thrust
B = 1.29 9.8 33.51
B = 423.64 N
1. Is it possible for the ball to move so quickly that the angle between the cable and vertical post stays at ninety degrees?
2. When the ball is moving in a horizontal circle, what vertical force (or component) balances gravity?
3. What happens to the centripetal force as the length of the cord increases?
Answer:
Tetherball is an interesting game in which two players tries to hit the ball hard so that it goes around the
pole.Each time the player hits the ball, it's orbit rises higher off the ground.Let's understand the physics
behind this.The motion of a tetherball is governed by two forces.These two forces combine to generate a
net force, i.e. centripetal force.If the ball is moving more quickly, it requires a greater centripetal force,
which in turn requires a greater tension force.Since the ball's weight hasn't changed, the angle of the
tension force changes until the ball is in vertical equilibrium.
To access this physics simulation visit: http://goo.gl/xVdwgO Page 02Exploration Series www.ck12.org
Ball Mass : This slider controls the mass of the ball. A ball with more mass will have more inertia, requiring
a greater net force to accelerate it. A ball with more mass will ALSO have a greater gravitational force
acting on it. Watch both of these effects occur when you manipulate this slider.
Cable Length : This slider controls the length of the cable. A longer cable is capable of allowing a greater
circular radius of motion for the ball. It is important to remember that the radius of the circular motion is
NOT equal to the length of the cable. Instead, if you want to understand the size of the circle of the ball's
motion, ignore the cable and just imagine the path of the ball.
Ball Speed : This slider controls the speed of the ball - imagine a kid just hit the ball and it sped up. A ball
moving more quickly is also accelerating more quickly because its velocity is changing as it moves in a
circle (remember that changes in DIRECTION of velocity 'count' as changes to velocity).
Force Diagram : This allows you to turn on or off the diagram of the forces acting on the ball. Look for the
ball to be in vertical force balance, which means the vertical component of tension is canceled by the
gravitational force. The ball should NOT be in horizontal force balance - it is accelerating towards the center
of the circle! It is important to note that this free body diagram should really be moving with the ball so that
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the tension force always points along the cord - we are just showing the forces at the moment the ball is at
the furthest-right on this screen.
Centripetal force vs Tetherball speed : This is a plot of centripetal force required to keep the ball in
circular orbit about the pole as a function of its speed. As expected, a more quickly-moving ball is changing
in velocity more often in a given amount of time, and so is accelerating more. This greater (centripetal, or
center-pointing) acceleration requires a greater net force.
Explanation:
he inductance of a tuning circuit of an AM radio is 4 mH. Find the capacitance of the circuit required for reception at 1200 kHz.
Answer:
4.4pF
Explanation:
the capacitance of the circuit required for reception is given:
wL = [tex]\frac{1}{wC}[/tex]
w = 2π [tex]f[/tex]
Using both equation
Capacitance is given
C = 1 - 4π2 f2 L
1- 4×9.8969×144×10 10 ×0.004
=4.4pF
)) What do these two changes have in common?
mixing chocolate syrup into milk
rain forming in a cloud
) Select all that apply.
Both involve chemical bonds breaking.
Both are changes of state.
Both are only physical changes.
Both are chemical changes.
Answer:
Both are only physical changes
Explanation:
A physical change is a change that does not involve or alter the chemical composition of the substances involved. Physical changes form no new substance and can be easily separated into individual constituents. Example of physical changes are change in state, boiling, melting etc.
According to this question, two processes were given as follows:
1. mixing chocolate syrup into milk
2. rain forming in a cloud
These two processes are similar in the sense that they are both examples of physical changes.
The new roller coaster at Carowinds flies along at 80 m/s. How long does it take to
travel 16000 meters of track?
A child falls sideways off the sled while sledding on frictionless ice. What happens to the velocity of the sled
Answer:
Same as before.
Explanation:
we can use momentum conservation to solve the problem.
Let mass of child be m and of the sled be M. Also let both have initial velocity u.
since, child fells off on the sled it will still have same velocity of ''u''.
By momentum conservation we have,
(M + m) x u = m x u + M x v
⇒ Mu=Mv
⇒ u=v
Hence, velocity of the sled remains the same.
PLEASE HELP!
what would the answer be?
Answer:
Tie aluminium foil on each end of the battery using rubber band, then use copper wire to attach the led to the aluminium foil...... probably would work
A metal cube 1.0 cm on each side is sandwiched between two electrodes. The electrodes create a 0.0050N/C electric field in the metal. A current of 9.0 A passes through the cube, from the positive electrode to the negative electrode. Identify the metal.
a-Tungsten
b-gold
c-silver
d-copper
Answer:
This is Tungsten .
Explanation:
Electrical field E = V / l , V is potential diff and l is length
.005 = V / .01
V = .005 X .01 = 5 X 10⁻³ volts
I current = 9A
Resistance R = V / I
= 5 x 10⁻³ / 9
= 5.55 x 10⁻⁶ ohm .
To calculate resistivity :
R = ρ l / S , l is length , S is cross sectional area
5.55 x 10⁻⁶ = ρ x .01 / .01 x .01
ρ = 5.5 x 10⁻⁸
This is Tungsten .
Can atoms go bad?, not in the reversible way like ionization and isotopes but really malfunction our die.
Answer:
atoms cannot go bad
Explanation:
Because they stay alive and get good nutriants
8. A weight lifter lifts a set of weights a vertical distance of 2 m. If a constant net force of 350 N is exerted on the weights, what is the net work done on the weights? Please show full working out ( not in words)
Answer: Work = change in energy which can be calculated by force * displacement so taking this we can multiply 350n by *2m and we can come out with 700 joules
Explanation: I Hope This Helps I'm new at this.
You dip your finger into a pan of water twice each second, producing waves with crests that are separated by 0.19 m. (a) Determine the frequency of the water waves. Hz (b) Determine the period of the water waves. s (c) Determine the speed of the water waves.
Answer:
a) The frequency of the waves are = 2 Hz (since you are making two pulses every second)
b)The period of the waves is 0.19 m (as the consecutive crests are separated by 0.19 m)
c) V = L x f
v = 0.19 m x 2 S-1 (Hz is actually per second)
v = 0.38 ms-1
pe nis
A 2000-kg elevator is at rest when its cable breaks. The elevator falls 26 m before it encounters a giant spring at the bottom of the elevator shaft. As the elevator falls, its safety clamp applies a constant frictional force of 17,000 N. 1. List all the forces acting on the elevator after the cable breaks but before it hits the spring. Determine the work done by each force on the elevator. Make sure these work terms have the appropriate signs (positive or negative). 2. Calculate the net work done on the elevator. 3. Use the work-kinetic-energy theorem to determine the speed of the elevator right before it encounters the spring. 4. After the elevator encounters the spring, the spring compresses by 0.6 m before the elevator comes to rest. The safety clamp continues to apply a constant 17,000 N force. List all the forces acting on the elevator while it falls this final 0.6 m. 5. For each force listed in question F4, determine an expression for the work it does on the elevator. Make sure each work term has the appropriate sign (positive or negative). 6. Use the work-kinetic-energy theorem to determine the value of the spring constant k.
Explanation:
work done =force *distance
work done =17000*26
work done=442,000 joules.
A uniform electric field of magnitude 106 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.48 T perpendicular to the electric field also exists in this region. A beam of positively charged particles travels into the region. Determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (Assume the beam of particles travels perpendicularly to both fields.) m/s
Answer:
[tex]220833.33\ \text{m/s}[/tex]
Explanation:
[tex]E[/tex] = Electric field = [tex]106\ \text{kV/m}[/tex]
[tex]B[/tex] = Magnetic field = [tex]0.48\ \text{T}[/tex]
Velocity is given by
[tex]v=\dfrac{E}{B}[/tex]
[tex]\Rightarrow v=\dfrac{106\times 10^3}{0.48}[/tex]
[tex]\Rightarrow v=220833.33\ \text{m/s}[/tex]
The velocity of the particle is [tex]220833.33\ \text{m/s}[/tex].