What's the most unreactive metal?
Answer:
gold and platinum
Explanation:
Very unreactive metals, such as gold and platinum, are found in the Earth's crust as pure metals. These are called native metals.
please help me! ASAP
Answer:
(1) 4- ethyl -6 methyl -2 octyne
Please i need help with this it is Which of the following is not a property of matter that you could use to distinguish one substance from another.
Answer:
I believe it's mass? I may be wrong though...
. A 300 kg Blue car is moving rightward at 3 m/s, about to collide with a 100 kg Red car. Adjust the
velocity of the Red car so that the total momentum of the system is 800 kg m/s. (Adjust the velocity
of the Red car so that the sum of the momentum of the Blue car and the momentum of the Red car
equal 800 kg m/s.) What happened?
Answer:
The velocity of the red car is 1 m/s.
Explanation:
Given that,
The mass of blue car, m₁ = 300 kg
The mass of red car, m₂ = 100 kg
The velocity of Blue car, v₁ = 300 kg
The total momentum of the system, p = 800 kg-m/s
The momentum of an object is given by :
p = mv
So,
[tex]m_1v_1+m_2v_2=p[/tex]
Where
v₂ is the velocity of red car. So,
[tex]v_2=\dfrac{p-m_1v_1}{m_2}\\\\v_2=\dfrac{800-300\times 3}{100}\\\\v_2=-1\ m/s[/tex]
So, the velocity of the red car is 1 m/s.
2 attempts len
Check my work
The density of sucrose, table sugar, is 1.56 g/ec. What volume (in cubic centimeters) does 19.0 g of
sucrose occupy?
cc
Answer:
12.18 cc
Explanation:
From the question given above, the following data were obtained:
Density = 1.56 g/cc
Mass = 19 g
Volume =?
The density of a substance can be defined as the mass per unit volume of the substance. Mathematically, it can be expressed as:
Density = mass / volume
With the above formula, we can obtain the volume of the sucrose as follow:
Density = 1.56 g/cc
Mass = 19 g
Volume =?
Density = mass / volume
1.56 = 19 / volume
Cross multiply
1.56 × volume = 19
Divide both side by 1.56
Volume = 19 / 1.56
Volume = 12.18 cc
Therefore, the volume occupied by the sucrose is 12.18 cc
What is the percent composition of a copper chloride compound if a 269 g sample contains 127 g of copper and 142 grams of chlorine.
Answer:
Explanation:
The whole sample is 269
%copper = 127/269 * 100 = 47.2%
%chlorine = 142/269 * 100 = 52.8%
That's all you are asking. Is there more?
Which animal is a primary consumer?
brown lemming
short tailed weasel
snowy owl
lichen
Snowy Owl i Think or weasel
How many moles are in 18.3 grams of Carbon?
Answer:
1.5236414197340638
Identify the Precipitation Reaction Below:
A) CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g)
B) H2SO4(aq) + 2 LiOH(aq) → 2 H2O(l) + Li2SO4(aq)
C) Mg(s) + Cu(NO3)2(aq) → Mg(NO3)2(aq) + Cu(s)
D) HCl(aq) + (NH4)2S(aq) → H2S(g) + 2 NH4Cl(aq)
E) NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq)
Answer:
(E)
Explanation:
When aqueous solutions are added together, one of the products is s solid.
What are the similarities and differences between ionic and covalent bonds?
Answer:
Explanation:
Similarities.
Both Ionic and covalents bond produce exothermic reactions.
They are both neutral.in Ionic bonds, the two opposite charge will terminate each other and in covalent, the neutral molecules tend to share electrons.
Difference
Ionic bonds have high polarity while covalent have low.
Ionic bonds have no definite shape, covalent have.
Ionic have high melting points, covalent have low.
Io ic have high boiling point, covalents have low.
Compute the concentration (count per volume) of vacancies in copper at room temperature if the lattice parameter of FCC copper is 0.3615 nm at room temperature (25oC, 298 K), and the activation energy to form a single vacancy is 0.9 eV. Use 8.617x10-5 eV/(atom-K), exactly, as Boltzmann's Constant.
Note: You could look up the density and atomic weight of copper to compute room temperature atom concentration you need for this problem.
Answer:
5.1044844 x 10^7/cm^3 = 5E7
Explanation:
The atomic weight and density (at 25 ° C) for copper are 63.5 g/mol or 0.0635 kg/mol and 8,960 kg/m^3
First lets find the value of N, number of atomic sites per cubic meter for copper, from its atomic weight Acu, its density, and Avogadro’s number NA
N = NA x ρ / Acu = 6.023 x 10^23 x 8,960 kg/m^3 / 0.0635 kg/mol = 8.4985953 x 10^28 atoms / m3
Temperature dependency can be given as :
Arrhenius equation
Nv = N e^(-EA/KT)
N = no. of atoms initially
Ev = activation energy
Nv = 8.4985953 x 10^28 atoms / m^3 exp^-(0.9ev/atom /8.617x10-5 eV/(atom-K) x 298 K
Nv = 5.1044844 x 10^13 /m3
vacancies per cm^3 = 5.1044844 x 10^7/cm^3 = 5E7
To make a solution for an experiment, Gunther needs to add 40 g of a solute to 100 g of water. When making the solution at room temperature, he could only add 34 grams before the solute settled out.
What could he do to dissolve the remaining 6 grams of the solute?
Answer:
B. Heat the solution, dissolve the solute, and let the solution cool verifying nothing settled out.
Explanation:
To dissolve more solute, the solution has been heated at a high temperature, and the cooling has been observed to verify proper dissolution.
The solubility of the compound has been the ability of the solvent to dissolve the solute molecules. For the solution formation, the intermolecular forces between the solute molecules have been broken in order to sustain the interaction between the solute and the solvent molecules,
The interaction between solute and solvent molecules results in the dissolution of the solute in the solvent.
When Gunther dissolves the 34 grams, of solute, the energy of the solvent molecules has been enough to break the solute interactions and dissolve the solute molecules.
However, in order to dissolve more molecules, the solvent molecules are provided with the energy that has been able to increase the kinetic energy of the solvent for the dissolution of more solute.
The kinetic energy of the solvent has been increased with the increase in the temperature, thereby adding to the more dissolution of the solute.
Thus, to dissolve more solute in the solvent, the solution has been heated at a high temperature, and the cooling has been observed to verify the absence of precipitate thereby proper dissolution.
For more information about the dissolution of solute into solvent, refer to the link:
https://brainly.com/question/14281527
How many joules would be released when 256 grams of zinc at 96 c were cooled to 28 c
Answer:
–6562.816 J
Explanation:
From the question given above, the following data were obtained:
Msss (M) = 256 g
Initial temperature (T₁) = 96 °C
Final temperature (T₂) = 28 °C
Heat (Q) released =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial temperature (T₁) = 96 °C
Final temperature (T₂) = 28 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 28 – 96
ΔT = –68 °C
Finally, we shall determine the heat released. This can be obtained as follow:
Msss (M) = 256 g
Change in temperature (ΔT) = –68 °C
Specific heat capacity (C) of Zn = 0.377 J/gºC
Heat (Q) released =?
Q = MCΔT
Q = 256 × 0.377 × –68
Q = –6562.816 J
Thus, –6562.816 J of heat energy is released.
why is carbon IV oxide and water removed before liquefication of air?
Answer:
Because when they unfreeze and are cooled they would block pipes of the air liquefaction plant and make the air colder, hope this helps!!
[tex] \sf { \fcolorbox{green}{g}{What is \: the diffrence between alkali and base in simple defination}} [/tex]
Answer:
All alkalies are bases but all bases are not alkaliesall alkalies are soluble in water but all bases are not alkalies .hope it is helpful to you
Answer:
[tex] \sf { \fcolorbox{green}{g}{\: the diffrence between alkali and base in simple defination are:}} [/tex]
[tex] \sf { \fcolorbox{green}{g}{\:All alkalies are bases but all bases are not alkalies }} [/tex][tex] \sf { \fcolorbox{green}{g}{\:all alkalies are soluble in water but all bases are not alkalies. }} [/tex]Which of these outcomes is a positive effect of ecotourism on the
environment?
A. Ecotourism can harm delicate ecosystems.
O B. Ecotourism takes money away from conservation.
C. Ecotourism can exploit local peoples and increase crime.
D. Ecotourism helps pay for conservation efforts.
Answer: D- ecotourism helps pay for conservation efforts
Explanation:
says help and the others exploit and harm
pls help
1. write the complete chemical symbol for the ion with 14 protons 15 neutrons and 18 electrons
2. write the complete chemical symbol for the ion with 27 protons 32 neutrons and 25 electrons
Answer:
Particle Symbol Mass
electron e- 0.0005486 amu
proton p+ 1.007276 amu
neutron no 1.008665
What is the final temperature of the metal?
What is the temperature change of the water?
What is the temperature change of the metal?
"C
Answer:
1. The final temperature of the metal is 111 °C.
2. The change in the temperature of the water is 6.2 °C
3. The change in the temperature of the metal is 40.6 °C.
Explanation:
From the question given above, the following data were obtained:
Initial temperature of metal (Tₘ₁) = 70.4 °C
Initial temperature of water (Tᵥᵥ₁) = 23.6 °C
Equilibrium temperature (Tₑ) = 29.8 °C
1. Determination of the final temperature of metal.
We'll begin by calculating the change in temperature of the metal. This can be obtained as follow:
Initial temperature of metal (Tₘ₁) = 70.4 °C
Equilibrium temperature (Tₑ) = 29.8 °C
Change in temperature of metal (ΔTₘ) =?
ΔTₘ = Tₘ₁ – Tₑ
ΔTₘ = 70.4 – 29.8
ΔTₘ = 40.6 °C
Finally, we shall determine the final temperature of the metal. This can be obtained as follow:
Initial temperature of metal (Tₘ₁) = 70.4 °C
Change in temperature of water (ΔTₘ) = 40.6 °C
Final temperature of metal (Tₘ₂) =?
40.6 = Tₘ₂ – 70.4
Collect like terms
40.6 + 70.4 = Tₘ₂
111 = Tₘ₂
Tₘ₂ = 111 °C
Thus, the final temperature of the metal is 111 °C
2. Determination of the change in the temperature of the water.
Initial temperature of water (Tᵥᵥ₁) = 23.6 °C
Equilibrium temperature (Tₑ) = 29.8 °C
Change in temperature of water (ΔTᵥᵥ) =?
ΔTᵥᵥ = Tₑ – Tᵥᵥ₁
ΔTᵥᵥ = 29.8 – 23.6
ΔTᵥᵥ = 6.2 °C
Therefore, the change in the temperature of the water is 6.2 °C
3. Determination of the change in the temperature of the metal.
The change in the temperature of the metal is 40.6 °C.
Please solution 1 above for explanation.
Answer:
29.8 C
6.2 C
-40.6 C
:)
Explanation:
What is the pH of a 4.5 x 10 M HI solution?
Answer:
ik ppl sy no links but https://courses.lumenlearning.com/cheminter/chapter/the-ph-scale/
Explanation: it should help you
9. a) What is an isotope?
Answer:
Each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element. Hope this helps, have a good day! :)
Answer:
atoms with the same number of protons and electrons but different numbers of neutrons
Explanation:
The ratio of the elements in a binary ionic compound are based on the element's _______________.
A. oxidation number
B. mass number
C. total number of neutrons
state types of environment pollution?
Answer:
Air Pollution.
Water Pollution.
Soil/Land Pollution.
Noise Pollution.
Radioactive Pollution.
Explanation:
4. The formation of an ionic bond involves the
a. transfer of electrons.
b. transfer of neutrons.
c.
transfer of protons.
d. sharing of electrons.
[tex] \huge \mathrm{Answer࿐ }[/tex]
The formation of Ionic bond involves Transfer of electrons.
Correct answer is A.) transfer of electrons
_____________________________
[tex]\mathrm{ \#TeeNForeveR}[/tex]
Arrange the species according to the oxidation state of nitrogen in each. Note that highest refers to the most positive oxidation state of nitrogen, whereas lowest refers to the most negative oxidation state.
A. NO3-
B. NO4+
C. N2
D. NH2OH
E. NO2-
1. Highest oxidation state
2. Lowest oxidation state
Answer:
A. NO₃⁻ ⇒ +5
B. NO₄⁺ ⇒ +9
C. N₂ ⇒ 0
D. NH₂OH ⇒ -1
E. NO₂⁻ ⇒ +3
Explanation:
To calculate the oxidation number of an element in a compound, we have to know the oxidation number of the other elements. Then, we have to consider that the sum of the oxidation number of each atom multiplied by the subscripts is equal to the net charge of the compound.
A. NO₃⁻
This is the ion nitrate. Oxygen atoms (O) has an oxidation number of -2 because it derives from an oxide. In this case, the net charge of the ion is -1. Thus, we calculate the oxidation number of N as follows:
N + (3 x (-2)) = -1
N - 6 = -1 ⇒ N= -1 + 6 = +5
B. NO₄⁺
In this case, the sum of the oxidation numbers of O and N multiplied by the subscripts is equal to +1:
N + (4 x (-2)) = +1
N - 8 = +1 ⇒ N = +1 +8 = +9
C. N₂
The oxidation number of N is 0 because N₂ is an elemental substance.
D. NH₂OH
The oxidation number of H is +1 and -2 for O. The net charge of the molecule is 0.
N + (H x 3) + (O) = 0
N + (+1 x 3) + (-2) = 0
N + 3 -2 = 0 ⇒ N = 2 - 3 = -1
E. NO₂⁻
The net charge of the ion nitrite is -1.
N + (2 x O) = -1
N + (2 x (-2)) = -1 ⇒ N = -1 + 4 = +3
Therefore:
Highest oxidation number = B. NO₄⁺ (+9)
Lowest oxidation number = D. NH₂OH (-1)
__PbSO4 → __ PbSO3 +__O2
Balance the equation and indicate the type of reaction
an object can be considered in motion when it changes only it's direction. true or false?
Answer:
Its false Because it does'snt only show directions and changes there are others too.
Explanation:
hope it helps!!
Answer:
false
Explanation:
it's false because it's in motion
Name the only Australian mammal who is restricted to the alpine environment? ...
What is the age of the Sun? ...
What happens when lightening hit the tree? ...
What is the name of the tallest grass of the world? ...
What is the average height of Bamboo?
A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place
over the next few minutes?
Molecules in both the metal and the surrounding air will start moving at lower speeds.
Molecules in both the metal and the surrounding air will start moving at higher speeds.
The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up.
The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Answer:
Molecules in both the metal and the surrounding air will start moving at higher speeds.
Explanation:
Temperature is defined as a measure of the average kinetic energy of the molecules of a body.
The greater the temperature of a body, the greater the average kinetic energy of the molecules of the body and the greater the speed of the particles of the body.
A metal at 150°C will witness an increase in the average kinetic energy of its molecules, the molecules will speed up as temperature increases.
Similarly, the hot metal plate releases heat to the surrounding air molecules by radiation causing the surrounding air molecules to experience an increase in temperature and average kinetic energy. Thus the air molecules surrounding the metal hot plate also speed up.
In a cycle of copper experiment, a student first reacts a piece of copper metal with nitric acid to produce copper(II) nitrate (Cu(NO3)2) solution. The student then performs various reactions which transform the copper ions into a series of different copper compounds and complexes. Finally, the last reaction reduces the copper ions back to elemental copper metal. Copper atoms are conserved throughout the process. If the initial step of the experiment produces 4.12 mL of 2.41 M Cu(NO3)2, what is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Answer:
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Explanation:
The concentration of the solution is given by :
[tex][C]=\frac{\text{Moles of compound}}{\text{Volume of solution in Liters}}[/tex]
We have:
Concentration of copper (II) nitrate solution = [tex][Cu(NO_3)_2]=2.41 M[/tex]
The volume of solution = 4.12 mL
1 mL= 0.001 L
[tex]4.12 mL= 4.12\times 0.001 L= 0.00412 L[/tex]
Moles of copper (II) nitrate in solution = n
[tex]2.41=\frac{n}{0.00412 L}=0.0099292 mol[/tex]
Moles of copper (II) nitrate in solution = 0.0099292 mol
1 Mole of copper(II) nitrate has 1 mole of copper then 0.0099292 moles of copper(II) nitrate will have :
[tex]1\times 0.0099292 mol= 0.0099292 \text{ mol of Cu}[/tex]
Mass of 0.0099292 moles of copper:
[tex]=0.0099292 mol\times 63.55 g/mol=0.63100 g\approx 0.631 g[/tex]
This mass of copper present in the solution is the theoretical mass of copper present in the given copper(II) nitrate solution.
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Which is considered a fruit?
acorn
squash
orange
beet
carrot
Answer:
an orange would be considered a fruit
Explanation:
fruits have seeds while vegetables do not