To calculate the variance of complaints received per week, we first need to find the mean or expected value of the number of complaints. This can be calculated by multiplying the number of complaints in each category by its corresponding probability, and then adding up the results.
Expected value = (0 x 0.13) + (1 x 0.21) + (2 x 0.44) + (3 x 0.07) + (4 x 0.06) + (5 x 0.09) = 2.54
Next, we can use the following formula to calculate the variance:
Variance = Σ[(x - µ)²P(x)]
where Σ = sum, x = number of complaints, µ = expected value, and P(x) = probability.
Using this formula and the probabilities given in the table, we get:
Variance = (0 - 2.54)²(0.13) + (1 - 2.54)²(0.21) + (2 - 2.54)²(0.44) + (3 - 2.54)²(0.07) + (4 - 2.54)²(0.06) + (5 - 2.54)²(0.09) = 1.4856
Rounding this answer to the nearest hundredth, we get a variance of 1.49.
In conclusion, the variance of complaints received per week is 1.49, meaning that the number of complaints is quite spread out around the mean, which is 2.54. This could indicate that the department store has some variability in its service quality, as the number of complaints can vary widely from week to week.
A bag contains 2 gold marbles, 10 silver marbles, and 29 black marbles. The rules of the game are as follows: You randomly select one marble from the bag. If it is gold, you win $6, if it is silver, you win $4. If it costs $1 to play, what is your expected profit or loss if you play this game?
Answer:
33 thats with the 1 dollar subtracted for the entry fee
Step-by-step explanation:
first you add all the number of marbles you have then you get 41 then divide it by 12 because you have 2 gold and 10 silver and you get 3.4 and multiply that by 10 because its 6 and 4 and you get 34 subtract the entry fee
PLEASE HURRY DUE TODAY WILL MARK BRAINLESTIS RIGHT
what is √29 Place a dot on the number line at the BEST approximation
Answer:
5.4
Step-by-step explanation:
square of 29 = 5.385164807
5.385164807 estimated is 5.4
3) Given the formula F=ma where * F represents force, *m represents mass and has units of kilograms (kg), and • a represents acceleration and has units of meters per second squared (). Select an appropriate measurement unit for force.
The appropriate measurement unit for force is kg.m/s²
What is the appropriate measurement unit for force?A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.
From Newton's Second Law, force is expressed as;
F = m × a
Where is mass of object and a is the acceleration
One Newton is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared.
Since F = m × a
Plug in m = kg and a = m/s²
F = kg × m/s²
F = kg.m/s²
Therefore, the unit of measurement is kg.m/s².
Option B is the correct answer.
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HELP ME PLEASE!!! HELPPP!!! A backyard pool is in the shape of a rectangle. The pool has a perimeter of 90 feet and an area of 500 ft2. Which of the following could be the pool's length and width? 15 feet and 30 feet, 10 feet and 35 feet ,50 feet and 10 feet, 25 feet and 20 feet
Answer:
(d) 25 feet and 20 feet
Step-by-step explanation:
You want the possible dimensions of a pool with an area of 500 square feet and a perimeter of 90 feet.
AreaThe area is the product of the length and width. The area of the pools offered in the answer choices are ...
(a) 15·30 = 450 . . . square feet
(b) 10·35 = 350 . . . square feet
(c) 50·10 = 500 . . . square feet
(d) 25·20 = 500 . . . square feet
The area requirement eliminates answer choices A and B.
PerimeterThe perimeter is twice the sum of length and width. The perimeters of the possible pools are ...
(c) 2(50 +10) = 120 . . . feet
(d) 2(25 +20) = 90 . . . feet
The perimeter requirement eliminates answer choice C.
The pool's possible length and width are 25 feet and 20 feet, choice D.
__
Additional comment
You could write a quadratic equation for the pool dimensions, but doing that will generally involve more work than checking the given answer choices.
If x is the width, then 45-x is the length, and the area is ...
x(45 -x) = 500
x² -45x +506.25 = -500 +506.25 . . . multiply by -1, complete the square
x = 22.5 -√6.25 = 20 . . . . take the square root; width is the smaller dimension
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find the area and perimeter of each figure below.
Answer:
finding the perimeter, you sumthe distance all round that is 7+7.5+17.8+6=38.3
38.3 is the perimeter
Which ordered pairs lie on the graph of the exponential function f(x)=−32x+5
?
The ordered pair (0, 2) lies on the graph.
The ordered pair (-1, 0) lies on the graph.
The ordered pair (-1, 0) lies on the graph.
What is function?
In mathematics, a function is a relationship between two sets of elements, called the domain and the range, such that each element in the domain is associated with a unique element in the range.
The exponential function f(x) = -32x+5 can be written in the form of
f(x) = [tex]a(b^{x})+c[/tex], where a, b, and c are constants. Comparing with the given function, we have a = -3, b = 2, and c = 5.
To find the ordered pairs that lie on the graph of the exponential function, we can plug in different values of x and calculate the corresponding values of y using the function. Here are some examples:
When x = 0, we have f(0) = [tex]-3(2^{0})[/tex] + 5 = 2. Therefore, the ordered pair (0, 2) lies on the graph.
When x = 1, we have f(1) = [tex]-3(2^{1})[/tex] + 5 = -1. Therefore, the ordered pair (1, -1) lies on the graph.
When x = -1, we have f(-1) = [tex]-3(2^{-1})[/tex] + 5 = 6/2 - 3 = 0. Therefore, the ordered pair (-1, 0) lies on the graph.
We can continue this process to find more ordered pairs that lie on the graph of the exponential function.
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Solve for x.
A. 7
B. 4
C. 3
D. 5
The correct option -D. 5; Thus, the value of x for the given external secant segment and the tangent on the circle is found as:x = 5.
Explain about the secant of circle:A line that precisely intersects a circle at two points is said to be a secant.
The size of the angle created when two tangents, two secants, or two tangents cross outside of a circle is equal to one-half a positive difference between the sizes of the intercepted arcs.
Using the Theorem:
The square of a length of tangent is equal the the product of such external secant segment and the overall length of the secant if one secant and one tangent both drawn to a circle from a single exterior point:
4(4 + x) = 6²
16 + 4x = 36
4x = 36 - 16
4x = 20
x = 20/4
x = 5
Thus, the value of x for the given external secant segment and the tangent on the circle is found as:x = 5.
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Determine the circumference and approximate area of the
given circle, using 3.14 for pie.
The circumference and approximate area of the given circle is 69.08 inches & 380.14 square inches.
What is circumference?
Circumference is the distance around the edge of a circular object or a round shape. It is the length of the boundary or perimeter of the circle. The formula is given by C = 2πr, where C is the circumference, r is the radius of the circle, and π is a mathematical constant approximately equal to 3.14.
The circumference of a circle is given by the formula:
C = 2πr
where r is the radius of the circle and π (pi) is a mathematical constant approximately equal to 3.14.
Using this formula and plugging in the given value of radius:
C = 2 x 3.14 x 11
C = 69.08 inches (rounded to two decimal places)
So the circumference of the circle with 11 inches radius is approximately 69.08 inches.
The area of a circle is given by the formula:
A = πr²
Again, using the given value of radius and approximating π to 3.14:
A = 3.14 x 11²
A = 3.14 x 121
A = 380.14 square inches (rounded to two decimal places)
So the approximate area of the circle with 11 inches radius is approximately 380.14 square inches.
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Suppose that the functions fand g are defined as follows.
f(x)=2x-1
g(x)=√3x-5
The composite functions (f/g)(x) and (f-g)(x) are (2x-1)/√(3x-5) and (2x-1) -√(3x-5)
Calculating the composite functions (f/g)(x) and (f-g)(x)To calculate (f/g)(x), we need to divide f(x) by g(x):
(f/g)(x) = f(x)/g(x) = (2x-1)/√(3x-5)
The domain of (f/g)(x) is the set of all x-values for which the denominator √(3x-5) is not equal to zero and non-negative
3x-5 ≥ 0, or x ≥ 5/3
Therefore, the domain of (f/g)(x) is x ≥ 5/3.
To calculate (f-g)(x), we need to subtract g(x) from f(x):
(f-g)(x) = f(x) - g(x) = (2x-1) - √(3x-5)
The domain of (f-g)(x) is the set of all x-values for which the expression inside the square root is non-negative:
3x-5 ≥ 0, or x ≥ 5/3
Therefore, the domain of (f-g)(x) is x ≥ 5/3.
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A patient takes 110 mg of a drug at the same time every day: Just before each tablet is taken, 5% of the drug present in th
preceeding time step remains in the body. What quantity of the drug remains in the body in the long run?
Hint: First find the quantity of drug present in the body after the second tablet, third tablet, etc to generalize the sequenc
formula for the nth tablet. Then use that sequence to predict the drug remains in the long run.
The requried quantity of drug that remains in the body, in the long run, is 220 mg.
Let's denote the amount of drug in the body just before taking the nth tablet by [tex]D_n[/tex]. We know that [tex]D_0 = 0[/tex](since the patient hasn't taken any tablets yet) and that 5% of the drug is present in the body just before taking a tablet remains in the body. Therefore, we can write:
[tex]D_1 = 110\\D_2 = 0.95 * D_1 + 110 = 203.5\\D_3 = 0.95 * D_2 + 110 = 292.225\\D_4 = 0.95 * D_3 + 110 = 376.81375[/tex]
We can see that the formula for [tex]D_n[/tex] is:
[tex]D_n = 110 * (1 - 0.05)^n + 110 * (1 - (1 - 0.05)^n) / 0.05[/tex]
Simplifying this formula, we get:
[tex]D_n = 220 * (1 - 0.95^n)[/tex]
Now, we want to find the amount of drug that remains in the body in the long run. This means we want to find the limit of [tex]D_n[/tex] as n goes to infinity. Using the formula above, we can see that:
[tex]lim_ {n- > oo} D_n = lim_ {n- > oo} 220 * (1 - 0.95^n) = 220[/tex]
Therefore, the quantity of drug that remains in the body, in the long run, is 220 mg.
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Write 80cm to 2km as rate
One per 2,500 can be used to represent the rate of 80cm to 2km.
Writing measures as a rate.To write 80cm to 2km as a rate, we need to convert the units to the same system. We can convert 80cm to kilometers by dividing by 100,000 (since there are 100,000 centimeters in a kilometer):
80 cm/100,000 = 0.0008 km
Now we can express the rate as:
0.0008 km per 2 km
Or we can simplify it by dividing both the numerator and denominator by 0.0008:
1 per 2,500
Therefore, 80cm to 2km can be expressed as a rate of 1 per 2,500.
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A researcher is standing in a corner (point c) of a triangler plot. the angle to point a is S76E the angle to point b is N32E The distance between point c and point a is 210 ft and the distance between point c and point b is 150 ft
find the distance between point a and point b
If a researcher is standing in a corner (point c) of a triangle plot. the angle to point a is S76E . the distance between point A and point B is 210 ft.
How to find the distance between point A and point B?To find the distance between points A and B, we can use the Law of Cosines. Let's first label the angles of the triangle:
Angle ACB = 180 - (76 + 32) = 72 degrees
Angle BAC = 76 degrees
Angle ABC = 32 degrees
Using the Law of Cosines, we have:
AB^2 = AC^2 + BC^2 - 2(AC)(BC)cos(ACB)
where;
AB is the distance between points A and B
AC is the distance between points A and C (210 ft
BC is the distance between points B and C (150 ft)
ACB is the angle between AC and BC (72 degrees)
Plugging in the values, we get:
AB^2 = 210^2 + 150^2 - 2(210)(150)cos(72)
AB^2 = 44100
AB = sqrt(44100)
AB = 210 ft
Therefore, the distance between point A and point B is 210 ft.
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solve y''+y=t using laplace inverse with y(0)=1 and y'(0)=-2
The solution of the differential equation y'' + y = t with the initial conditions y(0)=1 and y'(0)=-2 is y(t)= 1-2t+te-t.
What is equation?Equation is a mathematical statement that expresses the equality of two expressions. It shows the relationship between two or more variables and can be written using symbols, numbers, and operations. Equations are used to describe physical laws, to make calculations, and to solve problems. Examples of equations include the Pythagorean theorem, Newton's laws of motion, and linear equations.
We solve this differential equation using Laplace inverse, with the initial conditions y(0)=1 and y'(0)=-2. First, we take the Laplace transform of the equation:
L[y''+y]=L[t]
Using the properties of Laplace transform, we can write this as:
s2Y(s)-sy(0)-y'(0)+Y(s)= (1/s)
Substituting the initial conditions and rearranging terms, we have:
Y(s)= (1/s) + (2/s2) + (1/s2)
We can then invert the Laplace transform to get the solution of the original equation:
y(t)= 1-2t+te-t
Therefore, the solution of the differential equation y'' + y = t with the initial conditions y(0)=1 and y'(0)=-2 is y(t)= 1-2t+te-t.
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What is the area of the trapezoid?
Enter your answer in the box.
The area of given trapezoid whose parallel sides are 8 inches, 16 inches & its perpendicular height is 6 inches is 72 inches².
What is a trapezoid?
Quadrilaterals or four-sided polygons with one pair of parallel sides and one pair of non-parallel sides are known as trapezoids, usually spelt trapezium. It has a perimeter and covers a certain amount of space. The bases of the trapezium are the sides that are parallel to one another. Legs or lateral sides indicates to the non-parallel sides. The altitude or perpendicular height is the separation between the parallel sides. This shape's area is equal to half of the product of its parallel sides times its height.
Given dimensions of trapezoid:
let parallel sides be denoted by a , b & height be 'h'
a= 8 inches (top side)
b= 8+4+4=16 inches (bottom side)
h= 6 inches
Area = [tex]\frac{sum of parallel sides}{2}[/tex] x height
=[tex]\frac{(a+b)h}{2}[/tex]
=[tex]\frac{(8+16)6}{2}[/tex]
=[tex]\frac{24(6)}{2}[/tex]
=24 x 3
=72 sq. inches
The area of given trapezoid is 72 inches²
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Help corrections due in 3 hours! giving 25 points and brainlist
The value of GH in the right angle triangle, given FH and Angle FHG is 22.46 inches.
How to find the value of GH ?Since we have the adjacent side (FH) and want to find the hypotenuse (GH), we can use the cosine function.
cos(35°) = adjacent side (FH) / hypotenuse (GH)
We know that FH = 18.4 in. So, we can write the equation as:
cos(35°) = 18.4 / GH
GH = 18.4 / cos(35°)
GH = 18.4 / 0.81915
= 22.46 inches
So, the length of GH, the hypotenuse, is approximately 22.46 inches.
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Rectangle MPAT has vertices M(1,2) , P(1, 3), A(3, 3), and T(3, 2) . Rectangle M’P’A’T . Which coordinates describe the vertices of the image?
The coordinates of the vertices of the image rectangle M'P'A'T' are:
M'(2,1), P'(3,1), A'(3,3), T'(2,3).
What is rectangle?
A rectangle is a geometric shape that has four sides and four right angles (90 degrees) with opposite sides being parallel and equal in length.
To find the coordinates of the vertices of the image rectangle M'P'A'T', we need to apply a transformation to each vertex of the original rectangle MPAT.
We can see that the original rectangle MPAT has sides parallel to the x and y-axes, which suggests that it is aligned with the coordinate axes. We can also see that the length of its sides are equal, which means it is a square.
To transform this square, we can use a combination of translations, rotations, and reflections. However, since we don't have any information about the type of transformation that is being applied, we can assume that the simplest transformation is a reflection across the line y=x.
To reflect a point (x,y) across the line y=x, we swap its x and y coordinates to get the reflected point (y,x). Therefore, the coordinates of the vertices of the image rectangle M'P'A'T' are:
M'(2,1)
P'(3,1)
A'(3,3)
T'(2,3)
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Problem 7: Find the surface area and round to the nearest tenth.
Answer:
1629.24m
Step-by-step explanation:
starting with the easy ones
1) Rectangle 1:
Surface area of rectangle=Length x width
SAR= 24x21
= 504m
2) Rectangle 2:
SAR= 19x21
=399
3) Rectangle 3
SAR= 21x8
=168
4) Rectangle 4:
SAR= 21x11
=231
*because the top and bottom are trapeziums the formular for it is
A=1/2(a+b)h
although those trapeziums don't have h(Height)
it needs to be broken down into two triangles and a rectangle. to find the height*
5) side/height of triangle A:
formula: C squared= a squared + b squared
in this case we already have C and A. meaning we have to rearrange the formula to:
x = c^2 - a^2
x = 8^2 - 2.5^2
x = sqrt 57.75
x = 7.61
6) Trapezium
SA= 1/2(a+b)h
SA= 1/2(19+24)7.61
=163.62
7) add all surface area together
which should equal 1629.24m
complete the equatiotin 3 over 4 x 6 =
PLEASE HELP
Answer:
1/8
Step-by-step explanation:
If "over" refers to (4 * 6) as a whole,
[tex]\frac{3}{4*6}\\\\=\frac{3}{24}\\\\=\frac{1}{8}[/tex]
If "over" refers to division,
[tex]3 \div 4 \times 6\\= 0.75 \times 6\\= 4.5[/tex]
I would suppose it's the first one, so, ignore the second one if you haven't learnt BODMAS yet.
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Find the difference between the median and the mean by using 4.25, 6.25, 8,8,8, 4.25, 6,9,6, 8.25, 9.25
Check the picture below.
I need help
A population of bacteria is growing according to the equation p(t)=800e^0.14t Estimate when the population will exceed 1151.
t= ---------
Answer: t=2.59
Step-by-step explanation:
This is a matter of clearing out the equation
set 1151=800e^0.14t
1151/800=e^0.14t
ln(1151/800)/0.14=t
t=2.59
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According to the information, we know that the term 125x^5y^4 appears in the expansion when n = 6 and the coefficient of x^6y^7 in the expansion is zero, and the x^6y^7 term does not appear in the expansion.
How to solve this equation and fin the expansion terms?We know that the binomial expansion of (x-y)^n is given by the formula:
(x-y)^n = nC0 x^n y^0 - nC1 x^(n-1) y^1 + nC2 x^(n-2) y^2 - ... + (-1)^n nCn x^0 y^nwhere nCk represents the binomial coefficient "n choose k".
We are given that the term 125x^5y^4 appears in the expansion, so we can set up an equation using the binomial coefficient for that term:
nC5 (x)^5 (-y)^4 = 125x^5y^4Simplifying this equation, we get:
nC5 = 125 / (-1)^4 = 125We can solve for n by finding the smallest value of n for which nC5 is greater than or equal to 125. We can use the formula for binomial coefficients:
nCk = n! / (k! (n-k)!)to calculate the values of nCk for different values of n and k. However, it is easier to use Pascal's triangle to find the binomial coefficients quickly. The fifth row of Pascal's triangle is:
1 5 10 10 5 1We see that the sixth term of this row is 10C5 = 252, which is greater than 125. Therefore, we know that the term 125x^5y^4 appears in the expansion when n = 6.
To find the x^6y^7 term in the expansion, we need to find the coefficient of x^6y^7 in the expansion. We can use the same formula as before, but with k = 7 instead of k = 5:
nC7 (x)^6 (-y)^7We can simplify this expression using the fact that (-1)^7 = -1:
nC7 x^6 y^7We want to find the value of this expression, so we need to find the value of n. We know that n = 6 because the term 125x^5y^4 appears in the expansion. Therefore, we can substitute n = 6 into the expression:
6C7 x^6 y^7We see that 6C7 is zero because we cannot choose 7 items from a set of 6. Therefore, the coefficient of x^6y^7 in the expansion is zero, and the x^6y^7 term does not appear in the expansion.
To find the x^7y^2 term in the expansion, we can use the same formula as before, but with k = 2:
nC2 (x)^7 (-y)^2We can simplify this expression using the fact that (-1)^2 = 1:
nC2 x^7 y^2We want to find the value of this expression, so we need to find the value of n. We know that n = 6 because the term 125x^5y^4 appears in the expansion. Therefore, we can substitute n = 6 into the expression:
6C2 x^7 y^2We can use Pascal's triangle to find that 6C2 = 15. Therefore, the coefficient of x^7y^2 in the expansion is 15, and the x^7y^2 term appears in the expansion as:
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(a) What is the value of x? Show your work.
(b) What is the measure of angle C? Show your work.
In triangle ABC
a) The value of x = 29⁰
b) The angle c equal to 93⁰
What is a triangle?A triangle is a closed plane figure that is formed by connecting three line segments, also known as sides, at their endpoints. The three endpoints, or vertices, where the sides of the triangle meet are not collinear. Triangles are important in mathematics and geometry because they are the simplest polygon that can exist in two-dimensional space.
According to the given informationIn a triangle, the sum of all interior angles is always 180 degrees. Therefore, we can use this fact to find the value of x and angle c.
We know that:
angle a = 35⁰
angle b = 52⁰
angle c = 3(x+2)⁰
Using the fact that the sum of all interior angles in a triangle is 180 degrees, we can write:
angle a + angle b + angle c = 180
Substituting the values we know, we get:
35 + 52 + 3(x+2) = 180
Simplifying the equation, we get:
87 + 3x + 6 = 180
3x + 93 = 180
3x = 87
x = 29
Therefore, x = 29⁰
To find angle c, we can substitute the value of x into the equation we were given for angle c:
angle c = 3(x+2)
angle c = 3(29+2)
angle c = 3(31)
angle c = 93
Therefore, angle c is equal to 93⁰.
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Help Please...
You have 67 coins consisting of half-dollars and quarters. The number of quarters is 7 more than three times the number of half-dollars.
How many quarters do you have?
How many half -dollars do you have?
There are 52 quarters and 15 half-dollars
To solve this problem
Let's represent the number of half-dollars as "x" and the number of quarters as "y".
From the problem statement, we know that:
x + y = 67 (because there are a total of 67 coins)
y = 3x + 7 (because the number of quarters is 7 more than three times the number of half-dollars)
We can use substitution to solve for x:
x + (3x + 7) = 67
4x + 7 = 67
4x = 60
x = 15
So there are 15 half-dollars. We can use this to find the number of quarters:
y = 3x + 7
y = 3(15) + 7
y = 52
So there are 52 quarters.
Therefore, there are 52 quarters and 15 half-dollars.
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Answer:
[tex]3( {2}^{2} ) - {2}^{2} + 4 = 12[/tex]
[tex] {2}^{3} + b( {2}^{2} ) + 43(2) - 126 = 4b - 204[/tex]
[tex]4b - 32 = 12[/tex]
[tex]4b = 44[/tex]
[tex]b = 11[/tex]
For this value of b, these graphs will intersect at (2, 12). Please use your graphing calculator to confirm that this is the only point of intersection.
help please! state the key features for the graph
Answer:
Axis of symmetry =1
vertex =(1,2)
y intercept =0
min/max= -6,2
domain= 0,1,2
range =y≥1,2
Find an equation of the osculating plane and an equation of the normal
plane of the curve x = sin 2t, y = t, z = cos 2t at the point (0, π, 1).
The equation of the normal plane is 4y = 4π, or equivalently, y = π.
What is osculating plane?The word osculate comes from the Latin osculatus, which is a past participle of the verb osculari, which means "to kiss." Thus, an osculating plane is one that "kisses" a submanifold.
To find the osculating plane and normal plane of the curve x = sin 2t, y = t, z = cos 2t at the point (0, π, 1), we need to follow these steps:
Find the first and second derivatives of the curve with respect to t.Evaluate the derivatives at t = π to get the velocity, acceleration, and curvature vectors at the point (0, π, 1).Use the velocity and acceleration vectors to find the normal vector of the osculating plane.Use the normal vector and the point (0, π, 1) to find the equation of the osculating plane.Use the curvature vector to find the normal vector of the normal plane.Use the normal vector and the point (0, π, 1) to find the equation of the normal plane.Step 1: Find the first and second derivatives of the curve with respect to t.
x' = 2cos2t
y' = 1
z' = -2sin2t
x'' = -4sin2t
y'' = 0
z'' = -4cos2t
Step 2: Evaluate the derivatives at t = π.
x'(π) = 2cos2π = 2
y'(π) = 1
z'(π) = -2sin2π = 0
x''(π) = -4sin2π = 0
y''(π) = 0
z''(π) = -4cos2π = -4
So the velocity vector at the point (0, π, 1) is v = ⟨2, 1, 0⟩, the acceleration vector is a = ⟨0, 0, -4⟩, and the curvature vector is κv = ⟨0, 4, 0⟩.
Step 3: Use the velocity and acceleration vectors to find the normal vector of the osculating plane.
The normal vector of the osculating plane is given by the cross product of the velocity and acceleration vectors:
n = v × a = ⟨2, 1, 0⟩ × ⟨0, 0, -4⟩ = ⟨4, 0, 0⟩
Step 4: Use the normal vector and the point (0, π, 1) to find the equation of the osculating plane.
The equation of the osculating plane is given by:
4(x - 0) + 0(y - π) + 0(z - 1) = 0
Simplifying, we get:
4x - 4 = 0
So the equation of the osculating plane is 4x = 4, or equivalently, x = 1.
Step 5: Use the curvature vector to find the normal vector of the normal plane.
The normal vector of the normal plane is given by the curvature vector:
n' = κv = ⟨0, 4, 0⟩
Step 6: Use the normal vector and the point (0, π, 1) to find the equation of the normal plane.
The equation of the normal plane is given by:
0(x - 0) + 4(y - π) + 0(z - 1) = 0
Simplifying, we get:
4y - 4π = 0
So, the equation of the normal plane is 4y = 4π, or equivalently, y = π.
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A drawer contains 10 blue pens, 12 black pens, and 3 red pens. Without looking, Mr. Lopez is going to take one pen from the drawer, use it, and then put it back into the drawer. Then he is going to take another pen from the drawer to use. What is the probability of Mr. Lopez taking a red pen first and then taking a blue pen?
Answer: 4.8%
Step-by-step explanation: the total amount of pens in the drawer is (10+12+3) = 25
the amount of red pens in the drawer is 3
the probability of picking out a red pen from the drawer = 3/25
the amount of blue pens in the drawer is 10
the probability of picking out a red pen from the drawer = 10/25
the probability of picking out a red pen then a blue pen afterwards = (10/25 x 3/25) = 4.8%
Here are two complex numbers being multiplied: (4 + 2)(6-3) = ?
Without calculating the exact result of the multiplication, how can
you tell that the result will be a real number?
Answer: 18
Step-by-step explanation:
I need help solving this thank you
The negation is the fourth option.
6 + 3 ≠ 9 or 6 - 3 ≠ 9
How to write the negation?The negation of an equation is an inequality such that we just change the equal sign, by the "≠" sign.
Here we start with the two equations.
6 + 3 = 9 or 6 - 3 = 9
Just change the equal signs for different signs:
6 + 3 ≠ 9 or 6 - 3 ≠ 9
That is the negation, fourth option.
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As seen in the diagram below, Austin is building a walkway with a width of x feet to go around a swimming pool that measures 8 feet by 10 feet. If the total area of the pool and the walkway will be 360 square feet, how wide should the walkway be?
Using the total area of the rectangular pool we know that the required width of the pathway is 3.6 ft respectively.
What is a rectangle?In the Euclidean plane, a rectangle is a quadrilateral with four right angles.
A parallelogram with a right angle or an equiangular quadrilateral, where equiangular means that all of its angles are equal, are other ways to define it.
A rectangle with four equal-length sides is a square.
Squares are not always rectangles, but rectangles are always squares.
So, the pool and walkway together have a 360 square foot total space.
Assume that the walkway is w feet in width.
Since the pool has an additional w feet of width on both sides, the total area's measurements can be expressed as (8 + 2w) by (10 + 2w).
Thus, we can construct the following equation:
(8 + 2w) x (10 + 2w) = 360
By enlarging and condensing the left side, we obtain:
4w² + 36w - 80 = 0
Using the quadratic formula, we can find w:
w = (-b ± √(b² - 4ac)) / 2a
Here, an equals 4, b equals 36, and c equals -80. When these values are added to the formula, we obtain:
w = (-36 ± √(36² - 4(4)(-80))) / 8
w = (-36 ± √(1872)) / 8
w ≈ -5.6 or w ≈ 3.6
We can ignore the first option because the width cannot be negative. Consequently, the pathway should be around 3.6 feet wide.
Therefore, using the total area of the rectangular pool we know that the required width of the pathway is 3.6 ft respectively.
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