Answer:
Following are the code to this question:
#include <iostream>//header file
#include<math.h>//header file
using namespace std;
class Quadratic//defining a class Quadratic
{
private:
double a,b,c;//defining a double variable
public:
Quadratic()//defining default constructor
{
a = 0;//assigning value 0
b = 0;//assigning value 0
c = 0;//assigning value 0
}
Quadratic(double a, double b, double c)//defining a parameterized constructor
{
this->a = a;//use this keyword to hold value in a variable
this->b = b;//use this keyword to hold value in b variable
this->c = c;//use this keyword to hold value in c variable
}
double getA() //defining a get method
{
return a;//return value a
}
void setA(double a)//defining a set method to hold value in parameter
{
this->a = a;//assigning value in a variable
}
double getB() //defining a get method
{
return b;//return value b
}
void setB(double b)//defining a set method to hold value in parameter
{
this->b = b;//assigning value in b variable
}
double getC() //defining a get method
{
return c;//return value c
}
void setC(double c)//defining a set method to hold value in parameter
{
this->c = c;//assigning value in c variable
}
double Evaluate(double x)//defining a method Evaluate to hold value in parameter
{
return ((a*x*x)+(b*x)+c);//return evaluated value
}
double numberOfReal()//defining a method numberOfReal to calculates the real roots
{
return (b*b)-(4*a*c);//return real roots
}
void findroots()//defining a method findroots
{
double d=numberOfReal();//defining double variable to hold numberOfReal method value
if(d<0)//use if block to check value of d less than 0
cout<<"Equation has no real roots"<<endl;//print message
else
{
double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1
double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2
if(r1==r2)//defining if block to check r1 equal to r2
cout<<"Equation has one real root that is "<<r1<<endl;//print message with value
else//else block
cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value
}
}
void print()//defining a method print
{
cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation
}
};
int main()//defining main method
{
Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor
q.print();//calling print method
cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value
q.findroots();//calling method findroots
cout<<q.Evaluate(-1);//calling method Evaluate that prints its value
return 0;
}
Output:
5x^2 + 6x + 1
16
The equation has two real roots that are -0.2 and -1
0
Explanation:
In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.
In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.
In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,
and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.
In the main method, the lass object it calls the parameterized constructor and other methods.
how can you say that a painting is real?
Answer:Know the Artist. Prior to buying an artist's work, become familiar with their oeuvre. ...
Use a Magnifying Glass. Looking at the surface of a painting with a magnifying glass is one of the best ways to spot a print. ...
Turn the Painting Over.
Explanation:brainliest
See from the way they paint. You can see from the picture that its way different. Each artist has different way to paint. see the colour also
Identify at least 6 errors from the following program code. Write all the errors and rewrite the correct program.(11 pts)
1. public E2
2. {
3. Public static void main(String )
4. {
5. System.Out.Println(“hello)
6. }
Answer:The code after rearrange the question segment:
public class Q// Class declaration of Q name.
{// Open the class body.
public static void main(String[] a) // Main function declaration.
{ //Open the main-function body.
System.out.println("Q"); // Print statement which print Q.
} //close the main-function body.
}//close the class body.
Output:
Q
Explanation:
Please read this lab exercise thoroughly, before attempting to write the program.
Write a program that reads the pairs of group number and student count from the text file (user must enter name of file) and:
Displays the number of groups in the file (5 %)
Displays the number of even and odd student count (5%)
Displays the sum of the even student count and the sum of the odd student count as well as the sum of all the student count (5%)
Displays the group numbers of the largest student count and the smallest student count (5 %)
Computes the average of the largest and smallest student count (10 %)
Compute the sum of ALL the digits in the largest student count (i.e. 952 – Sum is 9+5+2 = 16) (15 %)
Assume the contents of the file are as follows but that the pairs of data can change later:
1 25
2 123
3 475
4 61
5 77
6 910
7 234
8 138
9 134
10 95
11 674
12 345
13 31
14 211
15 952
16 873
17 22
18 7
19 876
20 347
21 450
The following is a sample output: User input in red
What is name of the input file? integers.dat
The number of groups in the file is 21
There are 12 odd student count and 9 even student count
The sum of the odd student count is 2645
The sum of the even student count is 4390
The sum of all the student count is 7035
The group number of the largest student count is 15
The group number of the smallest student count is 18
The average of 952 and 7 is 479.5
The sum of all the digits in the largest student count is 16
NOTE:
Use two decimal point precision for the average
To check your code, adjust one of the student count in the file, recompile your code and run again (suggest changing the largest or smallest student count )
Even though there are 21 pairs of numbers in the file, the program should NOT presume there will always be 21 pairs of numbers. In other words, you should not solve this problem by declaring 21 pairs of values. If I choose to use another integers.dat file other than the one provided with the assignment, your program should still work correctly with that file as well. All you can assume is that a series of integers will be read in from the file. Therefore, you need to implement a solution that uses the repetition control structures (for, while, do…while) in the reading and processing of these values to produce your output.
Answer:
filename = input("Enter input file? ")
with open(filename, 'r') as data:
num_groups = []
num_counts = []
for line in data:
cols = line.split()
num_groups.append(int(cols[0]))
num_counts.append(int(cols[1]))
print("The number of num_groups in the file is "+str(len(num_groups)))
c_even = 0; c_odd = 0; s_odd = 0; s_even = 0
for i in num_counts:
if i%2 == 0:
c_even=c_even+1
s_even = s_even + i
else:
c_odd=c_odd+1
s_odd = s_odd + i
print("There are "+str(c_odd)+" odd student and "+str(c_even)+" even student")
print("The sum of odd student is "+str(s_odd))
print("The sum of even student is "+str(s_even))
print("The sum of all student is "+str(s_even+s_odd))
max_count = num_groups[num_counts.index(max(num_counts))]
print("The group number of the largest student is "+str(max_count))
min_count = num_groups[num_counts.index(min(num_counts))]
print("The group number of the smallest student is "+str(min_count))
print("The average of "+str(max(num_counts))+" and "+str(min(num_counts))+" is:",end=" ")
print("%.2f" % ((max(num_counts)+min(num_counts))*0.5))
bigkount = str(max(num_counts))
bigsum = 0
for i in range(len(bigkount)):
bigsum += int(bigkount[i])
print("The sum of all the digits in the largest student is: "+str(bigsum))
Explanation:
The program was written in Python.
Because of the length, I added an attachment where I used comments to explain the lines of the code
In what way, if any, is a model different from a simulation?
Models are types of simulations that transform data sets into scenarios.
Models and simulations are completely different in that they achieve different results.
Models and simulations are essentially identical—they are two terms that describe the same thing.
Models are types of simulations that create ideal workers and members of leadership.
Answer:
Models and Simulations are completely different in that they achieve diffenet results.
Explanation:
Modeling is the act of building a model. A simulation is the process of using a model to study the behavior and performance of an actual or theoretical system. In a simulation, models can be used to study existing or proposed characteristics of a system. ... Simulating is the act of using a model for a simulation.
Answer:
Models are types of simulations that transform data sets into scenarios
Explanation:
Model - computer models take complex data sets and transform them into real-life simulations
design an algorithm to generate the first n terms of sequence 2,6,10,14
Answer:
#Begin
a=2
k=0
temp=0
#Input
k=input()
temp=k
k=0
#Processing
while int(k)<int(temp):
print(a)
a=a+4
k=k+1
In this exercise, using the knowledge of computational language in python, we have that this code will be written as:
The code is in the attached image.
What is range?The Python range function is a function native to the Python language that is used to generate a numerical sequence within a given range. It is normally used as an auxiliary to the for function. In Python, we can repeat an action a specified number of times using a for loop with the range function.
We can write the python as:
a=2
k=0
temp=0
k=input()
temp=k
k=0
while int(k)<int(temp):
print(a)
a=a+4
k=k+1
See more about python at brainly.com/question/13437928
Write a program that reads a list of integers, and outputs the two smallest integers in the list, in ascending order. The input begins with an integer indicating the number of integers that follow. You can assume that the list will have at least 2 integers and fewer than 20 integers. Ex: If the input is: 5 10 5 3 21 2
Answer:
Follows are the code to the given question:
#include <iostream>//header file
using namespace std;
int main() //main method
{
int nums[20];//defining an array
int n,i,k;//defining integer variables
cout<<"Enter total number you want to insert: ";//print message
cin>>n;//input value of n
cout << "Enter array numbers: " << endl;//print message
for (i = 0;i<n;i++) //defining for loop for input values from user-end
{
cin >> nums[i];//input values
}
for (i = 0; i < n;i++) //defining for loop for count array values
{
for (k =i+1;k<n;k++)//defining for loop for arrange value in ascending order
{
if (nums[i] > nums[k])//checking first and second value
{
int t = nums[i];//defining integer variable that hold first element value in t
nums[i] = nums[k];//holding second element value in first element
nums[k] = t;//assign value in t
}
}
}
cout<<"Two smallest number in list are:";//print message
for (i = 0; i <2; ++i)//defining for loop that prints first two smallest value
cout<<nums[i]<<" ";//print value
return 0;
}
Output:
Enter total number you want to insert: 6
Enter array numbers:
5
10
5
3
21
2
Two smallest number in list are:2 3
Explanation:
In this code, an integer array "nums" is defined, and in the next step multiple integer variable is defined, that uses the for loop input value from the user-end, and in the next step, another two for loop is declared, that uses if block to arrange value into the ascending order at which it stores two smallest value in first and second position in the array element, and in the next step, it uses another for loop to print its element value.
Animations
Animations are !
Blank which can be Applied to blank in a presentation?
Traffic flow analysis is classified as which?
Answer:
c. An active attack
d. A passive attack
Explanation:
Traffic flow analysis is a cyber attack method of acquiring information by intercepting and examining messages so as to decode them by analysing patterns in the way the messages are communicated.
Traffic flow analysis can either be active or passive depending on if the attacker alters communication in the case of active analysis or simply extracts information in case of passive analysis.
A computer connected to the internet that ask for data is a
Answer:
Client
Explanation:
When your computer is connected to the internet it is always asking and sending data. Your computer is the client which recieves the data from the sever.
a program execution is called
a program execution is called a process
ExplanationIn the process, they process the data and also execute the data.
What happen in process?
First the data came from input, then go to the memory. The process take the data from the memory and process it and divide it, if there's arithmetic data thingy it will go to ALU and the rest to CU. After the data finish being proceed, the data will be sent to CU and executed there, then send back to the memory and go to the output to be shown.#Sorry my grammar sucks
#Moderators please don't be mean, dont delete my answers just to get approval from your senior or just to get the biggest moderation daily rank.
Consider the declaration of the struct houseType given in this chapter. Suppose firstHouse and secondHouse are variables of houseType. Write C11 statement(s) to compare the style and price of firstHouse and secondHouse. Output true if the corresponding values are the same; false otherwise. (2, 3)
Answer:
See Explanation
Explanation:
The question is incomplete as there is no link pointing to the houseType struct of chapter 1.
So, I've answered the question from scratch
See attachment for explanation where I used comments to explain each line.
The program is as follows:
#include <iostream>
using namespace std;
struct houseType{
int firstHouse, secondHouse;
};
int main() {
houseType hT;
cout << "Enter the price of both house: ";
cin>> hT.firstHouse;
cin>> hT.secondHouse;
if(hT.firstHouse == hT.secondHouse){ cout<<"true"; }
else{ cout<<"false"; }
return 0;
}
Example of vector image format
Answer:
JPEGs, GIFs and PNGs are common raster image types. ...
Vector images, alternatively, allow for more flexibility. Constructed using mathematical formulas rather than individual colored blocks, vector file types such as EPS, AI and PDF* are excellent for creating graphics that frequently require resizing.
Cloud computing security risks
Answer:
Risks:
Network issues or outages caused by attackers can limit or completely deny access to data stored in the cloud
Attackers could find an exploit and steal company data without ever physically touching the company's computer.
That's what I can think of.
Explanation: