Consider W=4(cos(pi/2)+ isin(pi/2)) and Z=3(cos(3 pi/2) + isin(3 pi/2)). What is W + Z expressed in polar form?

Answer: 5

Step-by-step explanation:

Answer: I don't see the amount per football

Step-by-step explanation:

Answer:

sorry if im wrong but im pretty sure -5/3

Step-by-step explanation:

Answer:

2/1

Step-by-step explanation:

A calculator showed me that this was the answer. I would give you the link but I would probably get deleted. I already got warned so yeah.

Hope this helps!

Answer:

1

Step-by-step explanation:

The discriminant of the quadratic equation 2x2+4x-7=0 is 1

Answer:

-2

Step-by-step explanation:

It would be =

-2(-2 + 5) = -6

4 - 10 = -6

-10 and a positive four is a -6

Answer:

you just see whats on the side and write it down so its 16-20

Step-by-step explanation:

Answer:

22

Step-by-step explanation:

Answer:

up

Step-by-step explanation:

postive, up!

Answer:

..........UP..........

Answer:

27

Step-by-step explanation:

6/10=12/20 because when you cross multiply, 120=120, so then you can do wither 6/10=x/45 and when you cross multiply you get 270=10x and 270/10=27.

Answer:

1.9 degrees above the normal temperture

Step-by-step explanation:

Normal temperture: 98.6 degrees Fahrenheit

100.5 - 98.6 =  1.9  

Answer:

The answer is C because you have to multiply them both:)

Answer:

The answer is C

Step-by-step explanation:

What I'm about to write is overkill for this question, but it works for any common denominator. Factor the denominators.

10: 2 * 5

5 : 1 * 5

You need 1 five and 1 two. The answer is 10

The correct way to go about doing the question is to multiply the 5 by 2 and the 2 on top by 2

2*2/5*2 = 4/10

1/10        1 / 10

4/10 + 1/10

Answer:

y = 3x + 10

Step-by-step explanation:

Answer:

im pretty sure it is (0,5) or (10,0)

Step-by-step explanation:

Answer:

A. Elimination; a coefficient in Equation I is an integer multiple of a coefficient

in Equation II.

Step-by-step explanation:

4 is a multiple of 2. Therefore, the answer would be A.

y=0.625x+1.75 is the equation for your problem.

Answer:

150

Step-by-step explanation:

x/5=30

x=30*5

x=150

Hoped this helped!

Step-by-step explanation:

x/5 = 30

5 × x/5 = 5 × 30

x = 5 × 30

x = 150

Answer:

x= 3d/k +8b/k i think

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

Median is the Middle number in the sequence.

Hope this Helps!!

:D

Answer:

The correct option is C) 12.00%.

Step-by-step explanation:

This can be calculated using the formula for calculating the effective annual rate (EAR) as follows:

EAR = ((1 + (i / n))^n) - 1 .............................(1)

Where;

EAR = effective annual rate =  12.682%, or 0.12682

i = annual percentage rate (APR) = ?

n = Number of compounding periods or months = 12

Substituting the values into equation (1) and solve for i, we have:

0.12682 = ((1 + (i / 12))^12) - 1

0.12682 + 1 = (1 + (i / 12))^12

1.12682 = (1 + (i / 12))^12

(1.12682)^(1/12) = (1 + (i / 12))^(12/12)

1.12682^0.0833333333333333 = 1 + (i / 12)

1.00999962428035 - 1 = i / 12

0.00999962428035 = i / 12

i = 0.00999962428035 * 12

i = 0.119995491364199, or 11.9995491364199%

Approximating to 2 decimal places, we have:

i = 12.00%

Therefore, the correct option is C) 12.00%.

Answer:

(-5,-5)

Step-by-step explanation:

Answer:

0.8809

Step-by-step explanation:

Given that:

The population proportion p = 4% = 4/100 = 0.04

Sample mean x = 16

The sample size n = 300

The sample proportion [tex]\hat p =\dfrac{x}{n}[/tex]

= 16/300

= 0.0533

∴

[tex]P(\hat p \leq 0.0533) = P\bigg ( \dfrac{\hat p - p}{\sqrt{\dfrac{P(1-P)}{n}}}\leq\dfrac{0.0533 - 0.04}{\sqrt{\dfrac{0.04(1-0.04)}{300}}}\bigg )[/tex]

[tex]P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.04(0.96)}{300}}}\bigg )[/tex]

[tex]P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.0384}{300}}}\bigg )[/tex]

[tex]P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{1.28 \times 10^{-4}}}\bigg )[/tex]

[tex]P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{0.0113}}\bigg )[/tex]

[tex]P(\hat p \leq 0.0533) = P\bigg ( Z\leq1.18}\bigg )[/tex]

From the z tables;

= 0.8809

OR

Let X be the random variation that follows a normal distribution;

Then;

population mean [tex]\mu[/tex] = n × p

population mean [tex]\mu[/tex] = 300 × 0.04

population mean [tex]\mu[/tex] = 12

The standard deviation [tex]\sigma = \sqrt{np(1-p)}[/tex]

The standard deviation  [tex]\sigma = \sqrt{300 \times 0.04(1-0.04)}[/tex]

The standard deviation [tex]\sigma = \sqrt{11.52}[/tex]

The standard deviation  [tex]\sigma = 3.39[/tex]

The z -score can be computed as:

[tex]z = \dfrac{x - \mu}{\sigma}[/tex]

[tex]z = \dfrac{16 -12}{3.39}[/tex]

[tex]z = \dfrac{4}{3.39}[/tex]

z = 1.18

The required probability is:

P(X ≤ 10) = Pr (z  ≤ 1.18)

= 0.8809

Answer:

Following are the solution to the given point:

Step-by-step explanation:

Please find the comp[lete question in the attached file.

Given:

[tex]\bold{ \lim_{n \to \ \infty} (1+ \frac{r}{n})^{nt} =e^{rt}}[/tex]

In point 1:

[tex]\to y = (1+ \frac{r}{n})^{nt}[/tex]

In point 2:

[tex]\to \ln (y)= nt \ln(1+ \frac{r}{n})[/tex]

In point 3:

Its key thing to understand, which would be that you consider the limit n to[tex]\infty[/tex],  in which r and t were constants!  

[tex]=lim_{n \to \ \infty} \ln (y) = lim_{n \to \ \infty} nt \ln(1+\frac{r}{n})\\\\= lim_{n \to \ \infty} \frac{\ln(1+\frac{r}{n})}{\frac{1}{nt}}\\\\= lim_{n \to \ \infty} \frac{\frac{-r}{\frac{n^2}{(1+\frac{r}{n})}}}{- \frac{1}{n^2t}}\\\\= lim_{n \to \ \infty} \frac{\frac{rn^2t}{n^2}}{(1+\frac{r}{n})}\\\\= lim_{n \to \ \infty} \frac{rt}{(1+\frac{r}{n})}\\\\= \frac{rt}{(1+\frac{r}{0})}\\\\=rt[/tex]

In point 4:

[tex]\to \lim_{n \to \ \infty} = (1+\frac{r}{n})^{nt}[/tex] and

[tex]\to \lim_{n \to \ \infty} = A_0e^{rt}[/tex]

tom will have his key 10

Answer:

40,320.. took the test on USA test prep

Step-by-step explanation:

Answer:

123

Step-by-step explanation:

3 + (16 - 1)8

3 + (15)8

3 + 120

123

Answer:

2.56

Step-by-step explanation:

8% of 32 is 2.56

Answer:

A.

Step-by-step explanation:

That is a translation of 3 units left and 6 units down.

Answer:

a

The 95% confidence interval is [tex] 0.2474 < p < 0.3188 [/tex]

b

  The result obtained does not contradict expectation

Step-by-step explanation:

From the question we are told that

   The number of green peas is  k =  438

   The number of yellow peas is u =  173

Generally the sample size is mathematically represented as

       [tex]n = k + u[/tex]

=>    [tex]n = 438 + 173[/tex]

=>    [tex]n = 611[/tex]

Generally the sample proportion for yellow peas is

      [tex]\^ p = \frac{u}{n}[/tex]

=>   [tex]\^ p = \frac{173}{611 }[/tex]

=>   [tex]\^ p = 0.2831[/tex]

From the question we are told the confidence level is  95% , hence the level of significance is    

      [tex]\alpha = (100 - 95 ) \%[/tex]

=>   [tex]\alpha = 0.05[/tex]

Generally from the normal distribution table the critical value  of  [tex]\frac{\alpha }{2}[/tex] is  

   [tex]Z_{\frac{\alpha }{2} } =  1.96[/tex]

Generally the margin of error is mathematically represented as  

     [tex]E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} } [/tex]

=>  [tex]E =  1.96 * \sqrt{\frac{ 0.2831 (1- 0.2831)}{611} } [/tex]

=>  [tex]E =  0.0357 [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\^ p -E <  p <  \^ p +E[/tex]

=>     [tex] 0.2831  -0.0357 <p< 0.2831  + 0.0357[/tex]

=>     [tex] 0.2474 < p < 0.3188 [/tex]

From the question we are told that it was expected that 25% of the offspring peas will be yellow

   Now from the 95% confidence interval obtained we see that the expected sample proportion(25% ) falls within it so  it means that the result obtained does not contradict expectation