Answer:
E. None of the above
A bicycle racer is going downhill at 11.0 m/s when, to his horror, one of his 2.25 kg wheels comes off when he is 75.0 m above the foot of the hill. We can model the wheel as a thin-walled cylinder 85.0 cm in diameter and neglect the small mass of the spokes. (a) How fast is the wheel moving when it reaches the bottom of hill if it rolled without slipping all the way down
Answer: The wheel is moving 29.26 m/s fast
Explanation: Please see the attachments below
Use the slider to apply a force of about 400 N. After 2 s have elapsed in the simulation, decrease the Applied Force (force exerted) slowly back to zero. Try to do this adjustment in roughly 2 s . While the Applied Force (force exerted) is decreasing, the velocity is:______.
a. constant.
b. increasing.
c. decreasing.
Answer:
c. decreasing.
Explanation:
Force produces acceleration or deceleration. Force is the product of a body's mass and its acceleration. When a force is applied to an object, the force tends to cause the body to move if the body was originally stagnant, cause the body to accelerate if applied in the direction of the body's velocity, or decelerate the body if applied in opposite direction to the velocity of the body. When the force that is exerted on a moving body is slowly reduced to zero, frictional forces between the body and the floor surface gradually decelerates the body. When this deceleration occurs, the velocity of the body gradually decreases t a stop.
Why do some astronomers object to the new definition of a planet that was adopted in 2006?
A. New space missions show that Pluto is much larger than originally thought.
B. By this definition, Earth, Jupiter, and other planets should not be considered planets.
C. There was never a vote on whether to adopt the new definition or not.
D. It means that we now technically have over 100 planets.
Answer:
A. New space missions show that Pluto is much larger than originally thought.
Explanation:
The new definition of a planet that was adopted in 2006, defined planet as an object that orbits the sun, with sufficient mass to be round, not a satellite of another object, and has removed debris and small objects from the area around its orbit.
This new definition of a planet that was adopted in 2006, classified Pluto as "dwarf planet", because Pluto meets planetary criteria except that it has not cleared debris from its orbital neighborhood.
However, new Horizons spacecraft flew by Pluto in 2015, revealed that Pluto is much larger than originally thought
Therefore, the correct option is "A"
A. New space missions show that Pluto is much larger than originally thought.
Answer: it means that we now technically have over 100 planets
Explanation:
it’s not New space missions show that Pluto is much larger than originally thought!!!
what is meaning of convection
Answer:
Convection is heat transfer through the movement of liquids and gases.
Air bags greatly reduces the chance of injury in a car accident.explain how they do so in terms of energy transfer
Answer:
Airbags reduce chances of injury by absorbing most of the impact force from the body during a car crash
Explanation:
In a car collision, the speed of the vehicle is suddenly bought to rest. All the kinetic energy is suddenly converted into other forms of energy.
The body of the driver keeps travelling forward under his inertia force due to his mass until he is slammed against the steering wheel. The steering wheel is a very rigid component, and so when the body slams against it, the body takes the deformation, absorbing some of the energy of the moving car. This sudden impact of energy can be fatal enough to gravely injure the driver because the body does not undergo much deformation. When an airbag is used, the crash automatically triggers the release of the airbag. Instead of the body colliding against the rigid steering wheel, it is now collided against the soft air bag. The airbag is very collapsible, and some of the kinetic energy of the car on the driver is converted into the deformation energy used to deform the airbag when they collide. In the process of deformation, the time of impact is extended, reducing the force impacted on the driver, reducing the fatality of the impact.
The electron beam inside an old television picture tube is 0.40 mm in diameter and carries a current of 50 μA. This electron beam impinges on the inside of the picture tube screen.
Requried:
a. How many electrons strike the screen each second?
b. The electrons move with a velocity of 4.0m/s. What electric field strength is needed to accelerate electrons from rest to this velocity in a distance of 5.0 m?
c. Each electron transfers its kinetic energy to the picture tube screen upon impact. What is the power delivered to the screen by the electron beam?
Answer:
a) # _electron = 31 10¹³ electrons, b) E = 9.1 10⁻¹² N / C , c) P = 7.22 10⁻¹⁶ J
Explanation:
In this exercise we must examine the movement of electrons in an electric field.
a) they ask us for the number of electrons.
The electric current is
i = q / t
q = i t
let's calculate
q = 50 10⁻⁶ 1
q = 50 10⁻⁶ C
For this we can use a rule of direct proportions, if the charge of an electron is 1.6 10⁻¹⁹ C, the number of electrons for the charge of 50 10⁻⁶ C
#_electron = 50 10⁻⁶ C 1 / 1.6 10⁻¹⁹ C
# _electron = 31.25 10¹³ electrons
b) For this part we use kinematics to find the acceleration
v² = v₀² + 2 a x
electrons start from rest, so vo = 0
a = v² / 2x
let's calculate
a = 4²/2 5
a = 1.6 m / s²
Having the acceleration we can use Newton's second law where the force is electric
F = ma
e E = m a
E = m / e a
let's calculate
e = 9.1 10⁻³¹ / 1.6 10⁻¹⁹ 1.6
E = 9.1 10⁻¹² N / C
c) what the power on the screen
for this we must add the kinetic energy of all the electrons in the given time
P = # _electron Km / y
P = # _electron (½ m v²) / t
let's calculate
P = 31 10 13 (½ 9.1 10-31 1.6²) / 1
P = 7.22 10⁻¹⁶ J
PLEASE! PLEASE! PLEASE! HELP! I need this by Monday! It's a project DUE on Monday! I'm giving 75 points for the Brainiest :-)
Answer:
Please see below for all the numbers to be entered in the table:
Explanation:
Coaster World: F = 160 N; D = 40 m; T = 10 s; W = 160 * 40 = 6400 J; V = 40/10 = 4 m/s
Wally: F = 800 N; D = 10 m; T = 3.5 s W = 800*10 = 8000 J; V = 10/3.5 = 2.86 m/s
Elijah: F = 1400 N; D = 800 m; T = 40 m = 2400 s; W = 1400*800 = 112000 J; V = 800/2400 = 0.33 m/s
George: F = 600 N; D = 80 m; T = 50 m = 3000 s; W = 600 * 80 = 48000 j so he should get paid: 48,000/1000= $48; V = 80/3000 = 0.027 m/s
Answer:
Down below
Explanation:
Coaster World: F = 160 N; D = 40 m; T = 10 s; W = 160 * 40 = 6400 J; V = 40/10 = 4 m/s
Wally: F = 800 N; D = 10 m; T = 3.5 s W = 800*10 = 8000 J; V = 10/3.5 = 2.86 m/s
Elijah: F = 1400 N; D = 800 m; T = 40 m = 2400 s; W = 1400*800 = 112000 J; V = 800/2400 = 0.33 m/s
George: F = 600 N; D = 80 m; T = 50 m = 3000 s; W = 600 * 80 = 48000 j so he should get paid: 48,000/1000= $48; V = 80/3000 = 0.027 m/s
A neutral metal ball is suspended by a string. A positively charged insulating rod is placed near the ball, which is observed to be attracted to the rod. This is because:____________.
a. the ball becomes negatively charged by induction
b. the ball becomes positively charged by induction
c. the string is not a perfect insulator
d. there is a rearrangement of the electrons in the ball
e. the number of electrons in the ball is more than the number in the rod
Answer:
d. there is a rearrangement of the electrons in the ball
Explanation:
Inside the neutral metal ball, there are equal no. of positive charges (protons) and negative charges (electrons). Normally, the charges are distributed evenly throughout the ball.
However, when the positively charged insulating rod is brought near, since positive charges and negative charges attract each other, the electrons (-ve charges) in the metal ball moves towards the side nearest to the rod. The metal ball gets attracted to the rod.
a and b are not correct because the rod is insulating, so electrons cannot be transferred between them to induce a net charge in the metal ball. the no. of electrons is unrelated to the attraction between opposite charges , so e is incorrect as well.
A spherical balloon contains a charge +Q uniformly distributed over its surface. When it has a diameter D, the electric field at its surface has magnitude E. If the balloon is not blown up to thrice this diameter without changing the charge, the electric field at its surface is?
Answer:
E = 1/9 E₀
Explanation:
In this exercise we are told that the electric field is Eo when the diameter of the balloon is D, the expression
we are asked to shorten the electric field when the diameter is 3D with the same eclectic charge
For this we can use the gauss law to find the field in the new diameter, for this we create a Gaussian surface in the form of a sphere
Ф = ∫ E. dA = [tex]q_{int}[/tex] /ε₀
In this case the lines of the electric field and the radii of the sphere are parallel, therefore the scalar product is reduced to the algebraic product and the charge inside the sphere is the initial charge Q
A = 4π r²
E 4π r² = Q /ε₀
E = 1 /4πε₀ Q / r²
the value of the indicated distance is 3 times the initial diamete
r = 3 D / 2
we substitute
E = 1/4 πε₀ Q (2/ 3D)²
for the initial conditions
E₀ = 1 / 4πε₀ Q (2/D)²
subtitled in the equation above
E = 1/9 E₀
What is the role of the part in the diagram labeled Y?
modulate, amplify, and send out waves
O capture, amplify, and demodulate waves
change the amplitude and frequency of waves
O change the pulse and phase of waves
Question is incomplete and image is not attached ti the question. The required image is attached below, so the complete question is:
The diagram shows a device that uses radio waves.
What is the role of the part in the diagram labeled Y?
modulate, amplify, and send out waves capture, amplify, and demodulate waves change the amplitude and frequency of waves change the pulse and phase of wavesAnswer:
2. capture, amplify, and demodulate waves
Explanation:
The part Y labeled in the diagram refers to radio receiver which capture, amplify and demodulate the radio waves.
The radio receiver seperates required radio frequency signals through antenna and consist of an amplifier that amplify or increase the power of receiving signal. At the end, demodulators present in receivers recover the information from the modulated wave.
Hence, the correct option is 2.
Answer:
B
Explanation:
edge 2020
1. A current of 0.001 A can be felt by the human body. 0.005 A can produce a pain response. 0.015 A can cause a loss of muscle control. In the procedures of this lesson, over 0.030 A of current traveled in the three-battery circuit. Why was this circuit safe to handle with dry hands?
Answer:
It was safe to handle the circuit with dry hands because dry skin body resistance is very high, measuring up to 500,000 ohms.
Explanation:
Given;
Current of 0.001 A to be felt
Current of 0.005 A can produce a pain response
Current of 0.015 A can cause a loss of muscle control
Total current that traveled in the three-battery circuit = 0.03 A
Thus, we can conclude that, it was safe to handle the above mentioned circuit with dry hands because dry skin body resistance is very high, measuring up to 500,000 ohms.
A car travels 120 mi averaging a certain speed. If the car had gone 10 mph faster, the trip would have taken 1 hr less. Find the car's average speed.
Answer:
The average speed of a car will be "30 mph".
Explanation:
The given values are:
Distance = 120 mi
Let the speed be "x".
As we know,
[tex]Time = \frac{Distance}{Speed}[/tex]
[tex]=\frac{120}{x}[/tex]
According to the question,
If the speed of a car = x + 10
then the time will be:
= [tex]\frac{120}{x} -1[/tex]
Now,
⇒ [tex]Speed\times Time=(x+10)(\frac{120}{x}-1)[/tex]
⇒ [tex]120=120+\frac{1200}{x} -x-10[/tex]
On multiplying "x" both sides, we get
⇒ [tex]120x=120x+1200-x^2-10x[/tex]
⇒ [tex]x^2+10x-1200[/tex]
⇒ [tex]x^2+40x-30x-1200=0[/tex]
⇒ [tex]x(x+40)-30(x+40)=0[/tex]
⇒ [tex](x+40)(x-30)=0[/tex]
[tex]x+40=0[/tex]
[tex]x=-40[/tex]
Or,
[tex]x-30=0[/tex]
[tex]x=30[/tex]
So that the average speed will be "30 mph".
A mass on a spring vibrates in simple harmonic motion at a frequency of 3.26 Hz and an amplitude of 5.76 cm. If the mass of the object of 0.218 kg, what is the spring constant
Answer:
91.48N/m
Explanation:
In a spring-mass system undergoing a simple harmonic motion, the inverse of the frequency f, of oscillation is proportional to the square root of the mass m, and inversely proportional to the square root of the spring constant, k. This can be expressed mathematically as follows;
[tex]\frac{1}{f}[/tex] = [tex]2\pi\sqrt{\frac{m}{k} }[/tex] -----------(i)
From the question;
f = 3.26 Hz
m = 0.218kg
Substitute these values into equation (i) as follows;
[tex]\frac{1}{3.26}[/tex] = [tex]2\pi\sqrt{\frac{0.218}{k} }[/tex] [Square both sides]
([tex]\frac{1}{3.26}[/tex])² = ([tex]2\pi[/tex])²([tex]\frac{0.218}{k}[/tex])
([tex]\frac{1}{10.6276}[/tex]) = [tex]4\pi[/tex]²([tex]\frac{0.218}{k}[/tex]) [Take [tex]\pi[/tex] to be 3.142]
([tex]\frac{1}{10.6276}[/tex]) = [tex]4(3.142)[/tex]²([tex]\frac{0.218}{k}[/tex])
([tex]\frac{1}{10.6276}[/tex]) = [tex]39.488[/tex]([tex]\frac{0.218}{k}[/tex])
([tex]\frac{1}{10.6276}[/tex]) = ([tex]\frac{8.608}{k}[/tex]) [Switch sides]
([tex]\frac{8.608}{k}[/tex]) = ([tex]\frac{1}{10.6276}[/tex]) [Re-arrange]
([tex]\frac{k}{8.608}[/tex]) = ([tex]\frac{10.6276}{1}[/tex]) [Cross-multiply]
k = 8.608 x 10.6276
k = 91.48N/m
Therefore, the spring constant of the spring is 91.48N/m
4. How would the magnetic field lines appear for a bar magnet cut at the midpoint, with the two pieces placed end to end with a space in between such that the cut edges are closest to each other
Answer:
Explanation:
Pls see diagram in attached file
A flare is dropped from an airplane flying horizontally at uniform velocity (constant speed in a straight line). Neglecting air resistance, the flare will:_______. A) quickly lag behind the plane B) remain vertically under the plane C) move ahead of the plane explain
Answer:
Option B (remain vertically under the plane) is the correct option.
Explanation:
A flare would follow a particle trajectory with horizontal direction somewhat like airplane velocity as well as initial maximum motion as null but instead, gravity will induce acceleration. It would be lowered vertically underneath the plane before flare had already sunk to something like the surface.There is no different movement in the airplane nor even the flash. And none of them can change its horizontal level.Some other alternatives are given really aren't linked to the specified scenario. So choice B is the perfect solution to that.
A 1.97-pF capacitor is connected to a 9.0-V battery and fully charged. How many electrons did the battery transfer from one capacitor plate to the other
Answer:
1.11×10⁸ Electrons.
Explanation:
Applying,
Q = CV..................... Equation 1
Where Q = Total charge on the capacitor, C = Capacitance of the capacitor, V = Voltage of the battery.
Given: C = 1.97 pF = 1.97×10⁻¹² F, V = 9.0 V
Substitute this value into equation 1
Q = 1.97×9×10⁻¹²
Q = 1.773×10⁻¹¹ C.
If the charge on one electron = 1.602×10⁻¹⁹ C.
Therefore number of electron = 1.773×10⁻¹¹ /1.602×10⁻¹⁹
Number of electron = 1.11×10⁸
Answer:
The battery transferred 1.107 x 10⁸ electrons from one capacitor plate to the other.
Explanation:
Given;
capacitance of the capacitor, C = 1.97 pF = 1.97 x 10⁻¹² F
the battery potential, V = 9 V
The charge on each capacitor is calculated as;
Q = CV
Q = 1.97 x 10⁻¹² x 9
Q = 1.773 x 10⁻¹¹ C
1 electron has 1.602 x 10⁻¹⁹ Coulomb's charge
⇒1.602 x 10⁻¹⁹ C = 1 electron
⇒1.773 x 10⁻¹¹ C = ?
= (1.773 x 10⁻¹¹ C x electron) / (1.602 x 10⁻¹⁹ C)
= 1.107 x 10⁸ electrons
Therefore, the battery transferred 1.107 x 10⁸ electrons from one capacitor plate to the other.
What is the electric potential (relative to infinity) due to these charges at the center of this square
Answer:
Zero
Explanation:
See attached file pls
A convex meniscus thin lens is made with the radius of curvature of the first convex surface being 25.0 cm and the second convex (towards object) surface 45.0 cm. If the glass used has index of refraction 1.500, what is the focal length of this lens?
Answer:
112.5cm
Explanation:
Using the formula
1/f = (n-1)(1/R1 + 1/R2)
1/f = (1.5 - 1)(1/25 - 1/45)
1/f = 0.5 x (4/225) = 2/225
f = 225/2
= 112.5cm
Ohm's Law for electrical circuits is stated VequalsRI, where V is a constant voltage, R is the resistance in ohms and I is the current in amperes. Your firm has been asked to supply the resistors for a circuit in which V will be 9 volts and I is to be 5 plus or minus 0.1 amperes. In what interval does R have to lie for I to be within 0.1 amps of the target value Upper I 0 equals 5 question mark
Answer:
The resistance interval is [tex]R = 1.8 \pm 0.037[/tex]
Explanation:
From the question we are told that
The voltage is V = 9 V
The current is [tex]I = 5 \pm 0.1[/tex]
The maximum current would be
[tex]I_{max} = 5 + 0.1 = 5.1 \ A[/tex]
The minimum current would be
[tex]I_{min} = 5 - 0.1 = 4.9 \ A[/tex]
The maximum resistance is
[tex]R_max = \frac{V}{I_{min}}[/tex]
[tex]R_max = \frac{9}{4.9}[/tex]
[tex]R_max = 1.837 \Omega[/tex]
The minimum resistance is
[tex]R_{min} = \frac{V}{I_{max}}[/tex]
[tex]R_{min} = \frac{9}{5.1}[/tex]
[tex]R_{min} = 1.765 \Omega[/tex]
and [tex]R = \frac{9}{5} = 1.8 \Omega[/tex]
The interval R lies is
[tex]R = 1.8 \pm 0.037[/tex]
A 75kg passenger at the bottom of a roller coaster loop that has a radius of 20m. If the roller coaster car is moving 10m/s, what is the apparent weight of the passenger? g
Answer:
The apparent weight of the passenger is 360 N
Explanation:
Given;
The mass of the passenger, m = 75 kg
radius of the loop, r = 20 m
velocity of the roller coaster, v = 10 m/s
Centripetal force acting on this passenger is given as;
[tex]F = \frac{mv^2}{r}[/tex]
where;
F is the centripetal force acting on the passenger
m is the mass of the passenger
v is the velocity of the passenger
r is the radius of the track
[tex]F = \frac{mv^2}{r} \\\\F = \frac{75*10^2}{20} \\\\F = 375 \ N[/tex]
Real weight of the passenger,
W = mg
where;
g is acceleration due to gravity
W = 75 x 9.8
W = 735 N
Apparent weight of the passenger = Real weight - Centripetal force
Apparent weight of the passenger = 735 N - 375 N
Apparent weight of the passenger = 360 N
Therefore, the apparent weight of the passenger is 360 N
If a capacitor is being charged by 1.0 A of current flowing onto its plates, the displacement current between the plates will be
Answer is given below
Explanation:
When current occurs due to charge flow, it is called conduction. Since there are no conductors between the plates of the capacitor, there is no charge transfer between them and the conduction current becomes zero. However, when the capacitor is charged, the charges accumulate on the plates and, therefore, the electric field across the plates E increases with time. This variation of the electric field in the plates of the capacitor is called the displacement current, so in the displacement current, there is no electric current due to the movement of the charges, but due to the variation of the electric field between the two points.so I ∝ Rate of accumulations of the charge across plate capacitorI = [tex]\frac{dQ}{dt}[/tex] I = i (cond)I = 1 ASamantha is refinishing her rusty wheelbarrow. She moves her sandpaper back and forth 45 times over a rusty area, each time moving with a total distance of 0.12 m. Samantha pushes the sandpaper against the surface with a normal force of 2.6 N. The coefficient of friction for the metal/sandpaper interface is 0.92. How much work is done by the normal force during the sanding process
Answer:
W = 12.96 J
Explanation:
The force acting in the direction of motion of the sand paper is the frictional force. So, we first calculate the frictional force:
F = μR
where,
F = Friction Force = ?
μ = 0.92
R = Normal Force = 2.6 N
Therefore,
F = (0.92)(2.6 N)
F = 2.4 N
Now, the displacement is given as:
d = (0.12 m)(45)
d = 5.4 m
So, the work done will be:
W = F d
W = (2.4 N)(5.4 m)
W = 12.96 J
A 25-kilogram object is placed on a compression spring, and it creates a displacement of 0.15 meters. What is the weight of an object that creates a displacement of 0.23 m on the same spring? Enter your answer as a number rounded to the nearest tenth, such as: 42.5
Answer:
I hope it is correct ✌️
A woman who weighs 500 N stands on an 8 m long board that weighs 100 N. The board is supported at each end. The support force at the right end is 3 times bigger than the support force at the left end. How far from the right end is the woman standing
Answer:
[tex]1.6\; \rm m[/tex].
Explanation:
Let [tex]x[/tex] denote the distance (in meters) between the person and the right end of the board.
To keep the calculations simple, consider another unknown: let [tex]y[/tex] denote the support force (in Newtons) on the left end. The support force on the right end of this board would be [tex]3 \, y[/tex] (also in Newtons.)
Now there are two unknowns. At least two equations will be required for finding the exact solutions. For that, consider this board as a lever, but with two possible fulcrums. Refer to the two diagrams attached. (Not to scale.)
In the first diagram, the support at the left end of the board is considered as the fulcrum. In the second diagram, the support at the right end of the board is considered as the fulcrum.Calculate the torque in each situation. Note that are four external forces acting on this board at the same time. (Two support forces and two weights.) Why does each of the two diagrams show only three? In particular, why is the support force at each "fulcrum" missing? The reason is that any force acting on the lever at the fulcrum will have no direct impact on the balance between torques elsewhere on the lever. Keep in mind that the torque of each force on a lever is proportional to [tex]r[/tex], the distance between the starting point and the fulcrum. Since that missing support force starts right at the fulcrum, its [tex]r[/tex] will be zero, and it will have no torque in this context.
Hence, there are three (non-zero) torques acting on the "lever" in each diagram. For example, in the first diagram:
The weight of the board acts at the center of the board, [tex](1/2) \times 8\; \rm m = 4\; \rm m[/tex] from the fulcrum. This force will exert a torque of [tex]\tau(\text{weight of board}) = 4\; \rm m \times (-100\; \rm N) = (-400\; \rm N \cdot m)[/tex] on this "lever". The negative sign indicates that this torque points downwards.The weight of the person acts at [tex]x\;\rm m[/tex] from the right end of the board, which is [tex](8 - x)\; \rm m[/tex] from the fulcrum at the other end of this board. This force will exert a torque of [tex]\tau(\text{weight of person}) = (8 - x)\; {\rm m \times (-500\; \rm N)} = (-500\, \mathnormal{(8 - x)})\; \rm N \cdot m[/tex] on this "lever". This torque also points downwards.The support on the right end of the board acts at [tex]8\; \rm m[/tex] from the fulcrum (i.e., the left end of this board.) This force will exert a torque of [tex]\tau(\text{support, right}) = 8\; {\rm m} \times (3\, \mathnormal{y})\; {\rm N} = (24\, y)\; \rm N \cdot m[/tex] on the "lever". This torque points upwards.If the value of [tex]x[/tex] and [tex]y[/tex] are correct, these three torques should add up to zero. That is:
[tex]\underbrace{(-400)}_{\text{board}} + \underbrace{(-500\, (8 - x))}_{\text{person}} + \underbrace{24\, y}_{\text{support}} = 0[/tex].
That gives the first equation of this system. Similarly, a different equation can be obtained using the second diagram:
[tex]\underbrace{(-400)}_{\text{board}} + \underbrace{(-500\,x)}_{\text{person}} + \underbrace{8\, y}_{\text{support}} = 0[/tex].
Combine these two equations into a two-by-two system. Solve the system for [tex]x[/tex] and [tex]y[/tex]:
[tex]\left\lbrace\begin{aligned}&x = 1.6\\ &y = 150\end{aligned}\right.[/tex].
In other words, the person is standing at about [tex]1.6\; \rm m[/tex] from the right end of the board. The support force at the left end of the board is [tex]150\; \rm N[/tex].
A noisy channel needs to transfer 87 kbps, but has a SNR of 11 dB (decibels). Calculate the minimum Bandwidth required , in kHz, according to Shannon.
Answer:
24KHz
Explanation:
See attached file
Cass is walking her dog (Oreo) around the neighborhood. Upon arriving at Calina's house (a friend of Oreo's), Oreo turns part mule and refuses to continue on the walk. Cass yanks on the chain with a 67 N force at an angle of 30° above the horizontal. Determine the horizontal and vertical components of the tension force.
Answer:
Horizontal component: [tex]F_x = 58\ N[/tex]
Vertical component: [tex]F_y = 33.5\ N[/tex]
Explanation:
To find the horizontal and vertical components of the force, we just need to multiply the magnitude of the force by the cosine and sine of the angle with the horizontal, respectively.
Therefore, for the horizontal component, we have:
[tex]F_x = F * cos(angle)[/tex]
[tex]F_x = 67 * cos(30)[/tex]
[tex]F_x = 58\ N[/tex]
For the vertical component, we have:
[tex]F_y = F * sin(angle)[/tex]
[tex]F_y = 67 * sin(30)[/tex]
[tex]F_y = 33.5\ N[/tex]
So the horizontal component of the tension force is 58 N and the vertical component is 33.5 N.
A 60-watt light bulb carries a current of 0.5 ampere. The total charge passing through it in one hour is:
Answer:
Total charge = 1800C
Explanation:
Q= IT
I = currentt = timeQ = chargeHooke's law states that the force, F, in a spring extended by a length x is given by
F=-kx. According to Newton's second law F = ma, where m is the mass and a is
the acceleration. Calculate the dimension of the spring constant k.
Answer:
dimensions of k are kg / s^2
Explanation:
F=ma (Newton's second law)
F=-kx (Hooke's law)
so equate both
-kx = ma
k = -ma/x
= mass * acceleration / distance (dimensions, -1 has no dimension)
= kg * m/s^2 / m
= kg / s^2
A diver wants to jump from a board, the initial height is 10 meters and he wants to reach a horizontal distance of 2 meters. What minimum speed must he have when jumping from the board to achieve his goal?
Answer:
1.4 m/s
Explanation:
The minimum speed will be when the diver's initial velocity is horizontal.
First, find the time it takes for the diver to fall 10 meters.
Given:
Δy = 10 m
v₀ᵧ = 0 m/s
aᵧ = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
10 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 1.43 s
Now find the initial horizontal velocity.
v = (2 m) / (1.43 s)
v = 1.4 m/s
A student in her physics lab measures the standing-wave modes of a tube. The lowest frequency that makes a resonance is 30 Hz. As the frequency is increased, the next resonance is at 90 Hz.
What will be the next resonance after this?
Answer:
The next resonance will be 150 Hz.
Explanation:
The frequency of the sound produced by a tube, both open and closed, is directly proportional to the speed of propagation. Hence, to produce the different harmonics of a tube, the wave propagation speed must be increased.
The frequency of the sound produced by a tube, both open and closed, is inversely proportional to the length of the tube. The greater the length of the tube, the frequency is lower.
Frecuency of the standing sound wave modes in a open-closed tube is:
fₙ=n*f₁ where m is an integer and f₁ is the first frecuency (30 Hz)
The next resonance is at 90 Hz. This means that it occurs when n = 3:
f₃=3*30 Hz= 90 Hz
This means that the next resonance occurs when n = 5:
f₅=5*30 Hz= 150 Hz
The next resonance will be 150 Hz.