Computers And Technology High School

Computers help eliminate the repetitiveness of manual task how can this benefit you in your overall career?

Answers

Answer 1

Answer:

Explanation:

When I went to high school, our next door neighbor had a pet dinosaur. We used to have to do math problems that were incredibly long and tedious. Things like the gas laws. They involve 5 numbers with 2 decimal places and we were asked to find the 6th number.

Eventually we were taught to use log tables but by then we were too numb to care.

Computers however take repetitiveness in their stride. They don't gag at how many times they have to repeat an operation. They don't mind if they do it a thousand times or a million or 100 million times. Some algorithms like the Monte Carlo method depend on trying an operation a million times. Humans would go crazy if they had to do that. Computers can do simple algorithms a million times while the mouse is on the go command.

If you pick a job like a tax consultant, you will be glad not to do any more than knowing where the numbers that make up your data go.

Same with banks and insurance jobs. I'll bet there are many jobs in medicine that require repetitive calculations.

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PODARDSRTH?HOW SPELLING

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sorry, I d0nt understand

A brick has a weight of 23N. The brick is flat and smooth on the side in contact with the floor having measurements ( height= 5cm, length =20cm, width=10cm).
A)Calculate the area of the brick in contact with the floor. Give your answer in cm2.
B)Calculate the pressure of the brick on the floor.​

Answers

Answer:

A)Area = 200[tex]cm^{2}[/tex]

B) Pressure = 0.115 N/[tex]cm^{2}[/tex]

Explanation:

Assuming that the brick is flat on the floor with its largest face towards the floor and not on its side, then we can calculate the area of that face by multiplying the length by the width like so...

Area = length * width

Area = 20cm * 10cm

Area = 200[tex]cm^{2}[/tex]

The formula for calculating pressure is force divided by area. Therefore, since we just finished calculating the area and the force is given to us in the question (23N) we can simply plug in these values and solve for the pressure.

Pressure = Force / Area

Pressure = 23N / 200[tex]cm^{2}[/tex]

Pressure = 0.115 N/[tex]cm^{2}[/tex]

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