Come I need answers

Come I Need Answers

Answers

Answer 1
67, 79, 81, 83, 83, 85, 87, 88, 89 then find the bumber in middle so answer is 83

Related Questions

The average of Aaron's three test scores must be at least 93 to earn an A in the class. Aaron scored 89 on the first
test and 94 on the second test. What scores can Aaron get on his third test to guarantee an A in the class? (The
highest possible score is 100.)
15
Write an inequality that models this situation. Use the variable s to represent his score on his third test.

Answers

Answer:

Aaron must obtain a 96 or higher to achieve the desired score to earn an A in the class.

Step-by-step explanation:

Given that the average of Aaron's three test scores must be at least 93 to earn an A in the class, and Aaron scored 89 on the first test and 94 on the second test, to determine what scores can Aaron get on his third test to guarantee an A in the class, knowing that the highest possible score is 100, the following inequality must be written:

93 x 3 = 279

89 + 94 + S = 279

S = 279 - 89 - 94

S = 96

Thus, at a minimum, Aaron must obtain a 96 to achieve the desired score to earn an A in the class.

Aaron must score atleast 90 marks in third test.

Aaron scores in the first  test = 89

Aaron scores in the second test = 94

And the average of Aaron's three test scores must be at least 93 to earn an A.

Let Aaron scores in the third  test = s

Then,

Average = sum of terms divided by the number of terms.

[tex]\frac{89+94+s}{3} \leq 93\\89+94+s\leq 93\times3\\183+s\leq 279\\s\leq 279-189\\s\leq 90[/tex]

So, Aaron must score atleast 90 marks in third test.

Learn more:https://brainly.com/question/19982277

HELP ME PLEASE I HAVEE 5 MINNS lEft HELP

Answers

Answer:

im going to guess the last answer. theone that i can't see

Step-by-step explanation:

I'll give points and brainalist for answer / explanation

Answers

Answer:

D. 8

Step-by-step explanation:

C= 2πr

π= 3.14

C= 25.12

25.12 = 2 * 3.14 * r

r= 4

d= 2r

d= 8

answer fast plz sjsjzjz​

Answers

Answer:

104

Step-by-step explanation:

Just separate the whole thing into two shapes. Multiply the first shape: 12 x 7 = 84

Multiply the second shape: 5 x 4 = 20

3 |a| +5 |b| if a = −2; b = −1
WILL AWARD BRAINLIEST

Answers

Answer:

-11

Step-by-step explanation:

[tex]3( - 2) + 5( - 1)[/tex]

[tex] - 6 + ( - 5)[/tex]

[tex] - 11[/tex]

A number greater than or equal to 41.

Answers

Answer:

42

Step-by-step explanation:

¯\_(ツ)_/¯

Need Help (WILL GIVE BRAINLIEST)

Answers

Answer:

A

Step-by-step explanation:

(y-5) / (7-5) = (x-1) / (2-1)

(y-5) / 2 = x-1

y-5 = 2x -2

y = 2x +3

For the following right triangle, find the side length x.
15

Answers

Answer: 17

Step-by-step explanation:

Pythagorean Theorem

a^2+b^2=c^2

8^2+15^2=c^2

64+225=c^2

289=c^2

Now square both sides

x=17

Answer:

x = 17

Step-by-step explanation:

[tex]c^{2} = a^{2} + b^{2}[/tex]

[tex]c^{2} = 8^{2} + 15^{2}[/tex]

[tex]c^{2} = 64 + 225[/tex]

[tex]c^{2} = 289[/tex]

[tex]\sqrt{c^2} = \sqrt{289}[/tex]

[tex]c = 17[/tex]

Broccoli cost 1.50 at a store. How much does 32 ounces of broccoli cost?

Answers

Answer:

48.00

Step-by-step explanation:

Answer:

48.0 hope it helps you out

Find the annual percentage rate of change for the population of Oregon. In 2000, there were 4.8
million people, and in 2010, there were 8.7 million people.

Answers

Answer:

The annual percentage rate of change for the population of Oregon is of 8.125%.

Step-by-step explanation:

Total percentage change:

Change multiplied by 100 and divided by the initial value.

Change: 8.7 - 4.8 = 3.9 million

Initial value: 4.8

Percentage change: 3.9*100/4.8 = 81.25%

Annual percentage rate of change

81.25% during 10 years(from 2000 to 2010).

So, per year

81.25%/10 = 8.125%

The annual percentage rate of change for the population of Oregon is of 8.125%.

HELP ME PLS ITS URGENT .. !❗❗❗❗❗❗❗❗❗❗❗❗❗
The commuting distances, in miles, of 10 employees were used to make the box plot shown above. Which of the sets of distances below matches the given box plot?
A.
Commuting Distances: 10, 15, 15, 20, 20, 20, 30, 30, 45, 45

B.
Commuting Distances: 10, 15, 15, 20, 20, 30, 30, 30, 45, 45

C.
Commuting Distances: 10, 15, 20, 20, 20, 20, 30, 30, 45, 45

D.
Commuting Distances: 10, 15, 15, 20, 20, 20, 30, 45, 45, 45

Answers

Answer:

A the answer is A ^w^ hope this helps

Calculate the SQRT485 Express answer to nearest hundredth.

Answers

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 22.02

Explanation:

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Ms. Annand baked an apple pie. The boys in the house ate ⅛ of it and the girls ate 3/5. What fraction of the pie did the boys and girls eat altogether? Please answer

Answers

Answer:

29/40

Step-by-step explanation:

1/8 + 3/5 =

We need a common denominator.

8 = 2^3

5 = 5

8 and 5 have no common factors, so the LCD is their product.

LCD = 5 * 8 = 40

1/8 + 3/5 =

= 5/40 + 24/40

= 29/40

Select all the expressions that have the same value

Answers

so what was the question again?

Answer:

Step-by-step explanation:

What is the lateral surface area of this net



Help!!!

Answers

9514 1404 393

Answer:

  720 square feet

Step-by-step explanation:

The lateral area is the area of the central rectangle of the net. It is 12+12+12 = 36 feet long and 20 ft wide.

The lateral area is (36 ft)(20 ft) = 720 ft².


Asha is tiling the lobby of the school with one-foot square tiles. She has 6 bags
of tiles with 50 tiles in each. The lobby is a 30-foot by 8-foot rectangle. How
many tiles will Asha have left over after she tiles the lobby?

Answers

Answer:

60 tiles left over

Step-by-step explanation:

the lobby needs 30 x 8 = 240 tiles.

she has 6 x 50 = 300 tiles

300 - 240 = 60 left over

6) Supplementary Exercise 5.51

A consumer advocate claims that 80 percent of cable television subscribers are not satisfied with their cable service. In an attempt to justify this claim, a randomly selected sample of cable subscribers will be polled on this issue.

(a)

Suppose that the advocate's claim is true, and suppose that a random sample of five cable subscribers is selected. Assuming independence, use an appropriate formula to compute the probability that four or more subscribers in the sample are not satisfied with their service. (Do not round intermediate calculations. Round final answer of p to 1 decimal place. Round other final answers to 4 decimal places.)

The answer for 6(a) is P( Xâ¥4) = P ( x = 4) + P (x = 5) = 5/4 * 0.84 * 0.21 + 5/5 * 0.85 * 0.20 = 0.737

(b)

Suppose that the advocate's claim is true, and suppose that a random sample of 25 cable subscribers is selected. Assuming independence, find each of the following: (Do not round intermediate calculations. Round final answer of p to 1 decimal place. Round other final answers to 4 decimal places.)

1.

The probability that 15 or fewer subscribers in the sample are not satisfied with their service.

The answer for 6(b)1 is P(Yâ¤15) = 1 - P( Y > 20) - X20, i = 16 P ( Y = i) = 1- 0.421 - 0.562 = 0.017

2.

The probability that more than 20 subscribers in the sample are not satisfied with their service.

The answer for 6(b)2 is

3.

The probability that between 20 and 24 (inclusive) subscribers in the sample are not satisfied with their service.

The answer for 6(b)3 is P(20 > Y < 24) = 1 - 0.421 - 0.1867 - 0.1358 - 0.0708 - 0.0236 = 0.1621

4.

The probability that exactly 24 subscribers in the sample are not satisfied with their service.

The answer for 6(b)4 is P( Y = 24) = 0.0236

(c)

Suppose that when we survey 25 randomly selected cable television subscribers, we find that 15 are actually not satisfied with their service. Using a probability you found in this exercise as the basis for your answer, do you believe the consumer advocate's claim? Explain. (Round your answer to 4 decimal places.)

Answers

Answer:

[tex]P(X \le 4) = 0.7373[/tex]

[tex]P(x \le 15) = 0.0173[/tex]

[tex]P(x > 20) = 0.4207[/tex]

[tex]P(20\ge x \le 24)= 0.6129[/tex]

[tex]P(x = 24) = 0.0236[/tex]

[tex]P(x = 15) = 1.18\%[/tex]

Step-by-step explanation:

Given

[tex]p = 80\% = 0.8[/tex]

The question illustrates binomial distribution and will be solved using:

[tex]P(X = x) = ^nC_xp^x(1 - p)^{n-x}[/tex]

Solving (a):

Given

[tex]n =5[/tex]

Required

[tex]P(X\ge 4)[/tex]

This is calculated using

[tex]P(X \le 4) = P(x = 4) +P(x=5)[/tex]

This gives:

[tex]P(X \le 4) = ^5C_4 * (0.8)^4*(1 - 0.8)^{5-4} + ^5C_5*0.8^5*(1 - 0.8)^{5-5}[/tex]

[tex]P(X \le 4) = 5 * (0.8)^4*(0.2)^1 + 1*0.8^5*(0.2)^0[/tex]

[tex]P(X \le 4) = 0.4096 + 0.32768[/tex]

[tex]P(X \le 4) = 0.73728[/tex]

[tex]P(X \le 4) = 0.7373[/tex] --- approximated

Solving (b):

Given

[tex]n =25[/tex]

i)

Required

[tex]P(X\le 15)[/tex]

This is calculated as:

[tex]P(X\le 15) = 1 - P(x>15)[/tex] --- Complement rule

[tex]P(x>15) = P(x=16) + P(x=17) + P(x =18) + P(x = 19) + P(x = 20) + P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)[/tex]

[tex]P(x > 15) = {25}^C_{16} * p^{16}*(1-p)^{25-16} +{25}^C_{17} * p^{17}*(1-p)^{25-17} +{25}^C_{18} * p^{18}*(1-p)^{25-18} +{25}^C_{19} * p^{19}*(1-p)^{25-19} +{25}^C_{20} * p^{20}*(1-p)^{25-20} +{25}^C_{21} * p^{21}*(1-p)^{25-21} +{25}^C_{22} * p^{22}*(1-p)^{25-22} +{25}^C_{23} * p^{23}*(1-p)^{25-23} +{25}^C_{24} * p^{24}*(1-p)^{25-24} +{25}^C_{25} * p^{25}*(1-p)^{25-25}[/tex]

[tex]P(x > 15) = 2042975 * 0.8^{16}*0.2^9 +1081575* 0.8^{17}*0.2^8 +480700 * 0.8^{18}*0.2^7 +177100 * 0.8^{19}*0.2^6 +53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0[/tex]  

[tex]P(x > 15) = 0.98266813045[/tex]

So:

[tex]P(X\le 15) = 1 - P(x>15)[/tex]

[tex]P(x \le 15) = 1 - 0.98266813045[/tex]

[tex]P(x \le 15) = 0.01733186955[/tex]

[tex]P(x \le 15) = 0.0173[/tex]

ii)

[tex]P(x>20)[/tex]

This is calculated as:

[tex]P(x>20) = P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)[/tex]

[tex]P(x > 20) = 12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0[/tex]

[tex]P(x > 20) = 0.42067430925[/tex]

[tex]P(x > 20) = 0.4207[/tex]

iii)

[tex]P(20\ge x \le 24)[/tex]

This is calculated as:

[tex]P(20\ge x \le 24) = P(x = 20) + P(x = 21) + P(x = 22) + P(x =23) + P(x = 24)[/tex]

[tex]P(20\ge x \le 24)= 53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1[/tex]

[tex]P(20\ge x \le 24)= 0.61291151859[/tex]

[tex]P(20\ge x \le 24)= 0.6129[/tex]

iv)

[tex]P(x = 24)[/tex]

This is calculated as:

[tex]P(x = 24) = 25* 0.8^{24}*0.2^1[/tex]

[tex]P(x = 24) = 0.0236[/tex]

Solving (c):

[tex]P(x = 15)[/tex]

This is calculated as:

[tex]P(x = 15) = {25}^C_{15} * 0.8^{15} * 0.2^{10}[/tex]

[tex]P(x = 15) = 3268760 * 0.8^{15} * 0.2^{10}[/tex]

[tex]P(x = 15) = 0.01177694905[/tex]

[tex]P(x = 15) = 0.0118[/tex]

Express as percentage

[tex]P(x = 15) = 1.18\%[/tex]

The calculated probability (1.18%) is way less than the advocate's claim.

Hence, we do not believe the claim.

Cart 1 (500 g) moves to the right at 0.40 m/s. Cart 2 (250g) moves to the left at 0.50 m/s. a. If the carts stick after the collision, what will be their velocity?

Answers

Answer:

after the collision cart 1 will stop and cart 2 will keep moving will 0.1.m/s after stop.

WILL MARK B!
Please I need help I have a quiz

Answers

Answer:

a) 2x² - x + 3 = x(2x + 1) - 2x

<=> 2x² - x + 3 = 2x² + x - 2x

<=> 3 - x = - x

<=> 3 = 0

=> no solution

b) x/2 - x/3 - x/4 = 1/12

[tex] \frac{6x}{12} - \frac{4x}{12} - \frac{3x}{12} = \frac{1}{12} \\ \\ \frac{ - x}{12} = \frac{1}{12} \\ \\ = > - x = 1 \\ \\ \\ < = > x = 1[/tex]

=> the euqation has the solution x = 1

c) |x - 5| = 2|x|

=> x - 5 = 2x

or x - 5 = -2x

<=> x = -5

or 3x = 5

<=> x = -5

x = -5or x = 5/3

d) defined conditions: 2 - x 》 0

<=> x 《 2

we have:

[tex] \sqrt{x + 4} = 2 - x \\ < = > x + 4 = (2 - x) {}^{2} \\ < = > x + 4 = {x}^{2} - 4x + 4 \\ < = > {x}^{2} - 5x = 0 \\ < = > x(x - 5) = 0 \\ [/tex]

<=> x = 0 (because x 《 2)

e)

[tex] \sqrt{5} = \frac{1}{25 {}^{x} } \\ = > 5 = \frac{1}{25 {}^{2x} } \\ < = > 5.25 {}^{2x} = 1 \\ < = > 5.5 {}^{4x} = 1 \\ < = > 5 {}^{4x + 1} = 1 \\ = > 4x + 1 = 0[/tex]

<=> x = -1/4

Answer:

[tex]a) [x: - \infty < x < \infty ][/tex]

[tex]b)[x: - 1][/tex]

[tex]c) [x:- \frac{5}{3} ][/tex]

[tex]d) [x: 3, 0][/tex]

[tex]e) [x: - \frac{1}{4} ][/tex]

How do you find the x-intercept of a parabola?

Answers

you look on the graph and then you see if there is a x on the bottom or wherever it’s written

Write each product using an exponent. 9 x 9 x 9 x 9 x9
(Will be giving brainliest)

Answers

Answer: 9^ 5

Step-by-step explanation: since there is 5 9’s multiplied by each other, it would be 9 to the 5th power.

[tex]\huge\text{Hey there!}[/tex]


[tex]\mathtt{9\times9\times9\times9\times9}\\\mathtt{= 81\times 81\times9}\\\mathtt{= 6,561\times9}\\\mathtt{= 59,049}\\\mathtt{= 9\times 9\times 9 \times 9 \times 9 \rightarrow 9^5}[/tex]


[tex]\huge\text{Therefore your answer should be:}[/tex]

[tex]\huge\boxed{\mathtt{9^5}}\huge\checkmark[/tex]


[tex]\huge\boxed{\mathtt{Good \ luck \ on \ your \ assignment\ \& \ enjoy}}\\\huge\boxed{\mathtt{your \ day!}}[/tex]



~[tex]\frak{Amphitritr1040:)}[/tex]

A recipe calls for 2 cups flour and 1 1/2 cup milk to make seven servings. Ming has plenty of​ flour, but only 5 cups of milk. How many servings can he​ make? Ming can make (answer) servings with 5 cups of milk.

Answers

Answer:

21 or 23 servings.

Step-by-step explanation:

find the area of the figure use 3.14

Answers

Answer:

466.08 m²

Step-by-step explanation:

The figure is composed of a triangle and a semicircle.

Therefore,

Area of the figure = area of the triangle + area of the semicircle

= ½*b*h + ½*πr²

Where,

b = 24 m

h = 20 m

π = 3.14

r = ½ of 24 m = 12 m

Substitute each value into the equation

Area of the figure = ½*24*20 + ½*3.14*12²

= 240 + 226.08

= 466.08 m²

What is the slope of the line below?
(1-2)
(
4-2)
A. negative
B. undefined
C. positive
D. Zero

Answers

Answer: D. Zero

Step-by-step explanation:

It’s a flat line. Flat horizontal lines are ALWAYS zero

Need someone to help me with my maths tutorial ASP!!​

Answers

Answer:

hi! how can i help? <3

Step-by-step explanation:

okay i can stand in for you

Help..................

Answers

Triangle has 180 degrees:
180=2m-3+m+4+3m+5
Combine like terms
180 = 6m+6
Subtract 6 from 180
174=6m
Divide by 6
m=29

Brainliest if that helped, please :)
The sum of all the angles in a triangle is 180°.

(m+4) + (3m+5) + (2m-3) = 180°

m + 4 + 3m + 5 + 2m - 3 = 180°

6m + 6 = 180°

6m = 180° - 6

6m = 174

m = 29°

If John gets paid $45.00 an hour and works 10 hours, how much does he earn?

Answers

10 times 45 equals 450 so he would’ve made 450 if he worked for 10 hours

SOMEONE HELP ME PLEASE!!!!?

Answers

Answer:

139

Step-by-step explanation:

supplementary angles add up to equal 180

so to find the measure of angle ABC we subtract the given angle from 180

180-41=139

so we can conclude that angle ABC=  139

Step-by-step explanation:

< ABC and < CBD are supplementary angles.

< CBD = 41°

< ABC + < CBD = 180° ( Being supplementary angles)

< ABC + 41° = 180°

< ABC = 180° - 41°

< ABC = 139°

Hope it will help :)❤

I will mark you brainalist

Answers

Answer:

the answer is X=-7

,,,,,

Answer:

it would be x=7

Step-by-step explanation:

brainliest pls

8. Determine the area of a sector
with a central angle of 42° in a
circle with radius 3 inches.

NEED IT ASAP

Answers

Answer:

[tex]\boxed {\boxed {\sf A \approx 3.3 \ in^2}}[/tex]

Step-by-step explanation:

Since we are given the central angle in degrees, we should use the following formula for sector area.

[tex]A= \frac {\theta}{360}* \pi r^2[/tex]

The angle is 42 degrees and the radius is 3 inches. Therefore,

[tex]\theta= 42 \\r=3 \ in[/tex]

[tex]A=\frac {42}{360} * \pi (3 \ in)^2[/tex]

Solve the exponent.

(3 in)²= 3 in*3in = 9 in²

[tex]A=\frac {42}{360} * \pi (9 \ in^2)[/tex]

Multiply all three numbers together.

[tex]A= 0.116666666667* 3.14159265359 * 9 \ in^2[/tex]

[tex]A=3.29867228627 \ in^2[/tex]

Let's round to the tenth place. The 9 in the hundredth place tells us to round the 2 up to a 3.

[tex]A \approx 3.3 \ in^2[/tex]

The area of the sector is approximately 3.3 square inches.

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