Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction takes place using all of the Cl2 gas. When the reaction is complete, the yield of PCl5 is measured at 118 grams. Calculate the Volume of the flask (in Liters): g

Answers

Answer 1

Answer:

The volume of the flask is 20.245 litres .

Explanation:

We are given with following information-

[tex]PV=nRT[/tex] -------- 1

where R =[tex]0.0821L.atom/mole.K[/tex]

Molar mass of [tex]PCl_5=208.22g/mole[/tex]

The given chemical equation is -

[tex]2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5 _(_s_)[/tex] --------- 2

Now , calculation -

Mass of [tex]PCl_5[/tex] formed = 118g

Molar mass of [tex]PCl_5[/tex] = [tex]208.22g/mole[/tex]

      Mole = [tex]\frac{mass (g)}{molar mass}[/tex]

Therefore , moles of [tex]PCl_5[/tex] formed = [tex]\frac{118}{208.22}[/tex]

     From equation 2 , we get to know that ,

 2mole [tex]PCl_5[/tex] formed from 5 mole [tex]Cl_2 _(_g_)[/tex]

Therefore , [tex]\frac{118}{208.22}[/tex] mole [tex]PCl_5[/tex] formed from [tex]\frac{5}{2} \times\frac{118}{208.22}[/tex] mole [tex]Cl_2 _(_g_)[/tex]

Moles of [tex]Cl_2 _(_g_)[/tex] used =[tex]\frac{5\times118}{2\times208.22} mole[/tex]

R= [tex]0.0821L.atom/mole.K[/tex]

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of  [tex]Cl_2 _(_g_)[/tex] (n)= [tex]\frac{5}{2} \times\frac{118}{208.22}[/tex] moles

Applying  the formula above in 1 equation , that is

PV = nRT

putting the given values -

[tex]1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322[/tex]

 V = 20.245 litres.

Hence , the volume of the flask is 20.245 litres .

 


Related Questions


Which property of a star is closely related to its temperature?
omposition
brightness
Color
size

Answers

Answer:

color

Explanation:

An 80g sample of 3 1 H decays, leaving 2.5g of 3 1 H.
1. How long would this take?
2. What percentage of this sample would be left?
3. What fraction of this sample would be left?

3 1 H -> 3 2 He + 0 -1 /3 t1/2= 12.3 years

Answers

Here is the link to the answer:

Alkenes can isomerize under aqueous acidic conditions to form a more stable alkene. Draw the more stable alkene isomer and give the curved arrow mechanism to show its formation. g

Answers

Answer:

See explanation below

Explanation:

You are not providing the alkene you want to stabilize, however, I manage to find a similar question with an alkene. All you have to do is follow the same procedure, cause its pretty similar the steps.

According to the below picture, we have an alkene between carbon 1 and 2, where carbon 2 is less stable than carbon 3 which have another methyl group.

In order to do this, in a first step, the alkene is converted into a alkane by the addition of a hydrogen atom that the hydronium has. Then, in the next step, we have a substraction of the hydrogen in carbon 3 to form the double bond between carbon 1 and 3.

Why vitamin A(retinol) transported by chylomicrons ?

Answers

Answer:

from the small intestine (RE = retinyl ester; ROH = ret- inol. CM = chylomicron remnant). is split at least one intact molecule of retinol, retinal.

Atmospheric pressure decreases as altitude increases. In other words, there is more air pushing down on you at sea level, and there is less air pressure pushing down on you when you are on a mountain.If pentane (C5H12), hexane (C6H14), and hexanol (C6H13OH) are heated evenly at different altitudes, rank them according to the order in which you would expect them to begin boiling.
Rank from first to last. To rank items as equivalent, overlap them.
1. Hexane high altitude.
2. Pentane high altitude.
3. Hexane sea level.
4. Hexanol sea level

Answers

Answer:

Boils first >Pentane at high altitude> Hexane at high altitude>hexane at sea level> hexanol at sea level> boils last.

Explanation:

Step 1: To boil, a liquid must overcome the attractive forces between molecules and the outside pressure pushing down on the liquid's surface.

(Hexanol> Hexane> Pentane)

Step 2: Identify which situation is most conducive to boiling

To boil, a liquid must overcome the attractive forces between molecules and the outside pressure pushing down on the liquid's surface.

In which situation would you expect the liquid to boil first, assuming equal heating.

(weak intermolecular attraction and low atmospheric pressure)  

Two substances, A and B, initially at different temperatures, come into contact and reach thermal equilibrium. The mass of substance A is 6.27 g and its initial temperature is 20.9 ∘C . The mass of substance B is 26.1 g and its initial temperature is 52.7 ∘C. The final temperature of both substances at thermal equilibrium is 46.3 ∘C.

If the specific heat capacity of substance B is 1.17 J/(g⋅∘C), what is the specific heat capacity of substance A?

Answers

Answer:

It would be 6.9420. Thank me later

PLS HELP ASAP. list 5 chemicals that contribute to ozone layer depletion?​

Answers

Answer:chlorofluorocarbons (CFCs)

halon.

carbon tetrachloride (CCl4)

methyl chloroform (CH3CCl3)

hydrobromofluorocarbons (HBFCs)

hydrochlorofluorocarbons (HCFCs)

methyl bromide (CH3Br)

bromochloromethane (CH2BrCl)

Explanation:

BRAINLIEST pls

Question 5 In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce gaseous ammonia. This reaction is now the first step taken to make most of the world's fertilizer. Suppose a chemical engineer studying a new catalyst for the Haber reaction finds that liters per second of dinitrogen are consumed when the reaction is run at and the dinitrogen is supplied at . Calculate the rate at which ammonia is being produced. Give your answer in kilograms per second. Round your answer to significant digits. Clears your work. Undoes your last action. Provides information about entering answers.

Answers

Answer:

0.41kg/s

Explanation:

Question 5 In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce gaseous ammonia. This reaction is now the first step taken to make most of the world's fertilizer. Suppose a chemical engineer studying a new catalyst for the Haber reaction finds that 505. liters per second of dinitrogen are consumed when the reaction is run at 172 °C and the dinitrogen is supplied at 0.88 atm. Calculate the rate at which ammonia is being produced. Give your answer in kilograms per second. Round your answer to 2 significant digits. Clears your work. Undoes your last action. Provides information about entering answers.

Step 1: Convert 172 °C to Kelvin

We will use the following expression.

K = °C + 273.15

K = 172°C + 273.15 = 445 K

Step 2: Calculate the moles of N₂ consumed every second

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 0.88 atm × 505. L/(0.0821 atm.L/mol.K) × 445 K = 12 mol

Step 3: Calculate the rate of production of ammonia

Let's consider the balanced equation for the synthesis of ammonia.

N₂ + 3 H₂ ⇒ 2 NH₃

The molar ratio of N₂ to NH₃ is 1:2. The rate of production of ammonia is:

12 mol N₂/s × 2 mol NH₃/1 mol N₂ = 24 mol NH₃/s

Step 4: Convert the rate from mol/s to kg/s

We will use the following conversion factors:

The molar mass of NH₃ is 17.03 g/mol.1 kg = 1000 g

[tex]\frac{24mol}{s} \times \frac{17.03 g}{1mol} \times \frac{1kg}{1000g} = 0.41kg/s[/tex]

How many miles of O2 are needed to burn 1.45 mil of C8H18

Answers

Answer:

[tex]n_{O_2}=18.1molO_2[/tex]

Explanation:

Hello there!

In this case, according to the combustion of octane:

[tex]C_8H_1_8+25/2O_2\rightarrow 8CO_2+9H_2O[/tex]

We can see there is a 1:25/2 mole ratio of octane to oxygen; therefore, we can calculate the moles of oxygen via the following stoichiometric factor:

[tex]n_{O_2}=1.45molC_8H_1_8*\frac{25/2molO_2}{1molC_8H_1_8} \\\\n_{O_2}=18.1molO_2[/tex]

Best regards!

100 kg of a mixture that is 28% solids with the remainder water is put into a centrifuge to remove part of the water. The centrifuge runs for a half hour. A mixture that is now 60% solids is removed from the centrifuge and placed in a dryer for an additional hour. The product coming out of the dryer is 98% solids. Determine the following:

a. What is the mass of the mixture added to the dryer?
b. What is the mass of the product removed from the dryer?
c. How much water is removed from the original mixture by the centrifuge?
d. How much water is removed by the dryer?

Answers

Answer:

a. 46.7kg is the mass of the mixture added to the dryer.

b. 28.57kg is the mass removed  from the dyer

c. 53.3kg are removed by the centrifuge.

d. 18.13kg are removed by the dryer

Explanation:

As the 28% of the mixture is solids in 100kg, initially we have 28kg of solids.

a. Assuming in the supernatant there is no remaining solid and as the mixture is now 60% (60/100) solids:

2k8g solids *( 100 / 60) = 46.7kg is the mass of the mixture added to the dryer.

b. As the mass removed from the dyer is 98% of solids:

28kg Solids * (100 / 98) = 28.57kg is the mass removed  from the dryer

c. As the original mass is 100kg and the mass removed 46.7kg:

100 - 46.7  =

53.3kg are removed by the centrifuge

d. The difference in mass between mass removed by the dryer and the added is:

46.7kg - 28.57kg =

18.13kg are removed by the dryer

An X-ray photon with a wavelength of 0.954 nm strikes a surface. The emitted electron has a kinetic energy of 959 eV.

Part A:

What is the binding energy of the electron in kJ/mol? [Note that KE = = mv2 and 1 electron volt (eV) = 1.602 x 10-19 J.] ​

Answers

Answer:

An X-ray photon of wave length 0.989 nm strikes a surface. The emitted electron has a kinetic energy of 969 eV. What is the binding energy of the electron in kJ/mol? [KE=

1

2

mv2;1 electron volt (eV)=1.602×10−19J][KE=

2

1

mv

2

;1 electron volt (eV)=1.602

The binding energy of the emitted electron is  5.48 x 10⁻²⁰ kJ/mol.

The given parameters;

wavelength of the photon, λ = 0.954 nm = 0.954 x 10⁻⁹ m.kinetic energy of emitted photon, K.E = 959 eV

The binding energy of the electron is calculated as follows;

from Einstein's mass defect equation

[tex]\Delta E = \Delta mc^2\\\\[/tex]

Also, from Einstein's photo-electric equation;

E = φ + K.E

where;

φ is the binding energy of the electron on the metal surface

The energy of one mole of electron the emitted is calculated as;

[tex]E = hf = h\frac{c}{\lambda} \\\\E = \frac{(6.626 \times 10^{-34}) \times (3\times 10^8)}{0.954 \times 10^{-9}} \\\\E = 2.084 \times 10^{-16} \ J[/tex]

The kinetic energy of the emitted electron in Joules is calculated as;

K.E = 959 x 1.602 x 10⁻¹⁹ J

K.E = 1.536 x 10⁻¹⁶ J

The binding energy of the electron is calculated as;

φ = E - K.E

φ = 2.084 x 10⁻¹⁶ J  -   1.536 x 10⁻¹⁶ J

φ = 5.48 x 10⁻¹⁷ J

φ = 5.48 x 10⁻²⁰ kJ/mol

Thus, the binding energy of the emitted electron is  5.48 x 10⁻²⁰ kJ/mol

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In a lab, a student mixes 25.0 ml of 0.115 M aluminum sulfate with 34.0 ml of 0.0975 M Lead (III) nitrate. Calculate the grams of the precipitate that is formed.

Answers

Answer:

In a lab, a student mixes 25.0 ml of 0.115 M aluminum sulfate with 34.0 ml of 0.0975 M Lead (III) nitrate. Calculate the grams of the precipitate that is formed.

Explanation:

Archeologists can determine the age of artifacts made of wood or bone by measuring the amount of the radioactive isotope 14C present in the object. The amount of isotope decreases in a first-order process. If 15.5% of the original amount of 14C is present in a wooden tool at the time of analysis, what is the age of the tool? The half-life of 14C is 5730 yr.

Answers

Answer: The age of the tool is 15539 years

Explanation:

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant = 100

a - x = amount left after decay process = [tex]\frac{15.5}{100}\times 100=15.5[/tex]  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.  

[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]

[tex]k=\frac{0.693}{5730yr}=0.00012yr^{-1}[/tex]

b) for 15.5 % of original amount

[tex]t=\frac{2.303}{0.00012}\log\frac{100}{15.5}[/tex]

[tex]t=15539years[/tex]

Thus age of the tool is 15539 years

Suppose you have 11.0 mol of (CH4) and 9.0 mol of (O2) in a reactor. Calculate the largest amount of CO2 that could be produced

Answers

Hi just a reminder don’t click the links, and 11.0 is correct

What is the volume of CO2 (acting as an ideal gas) if 64.0 mL of 1.261 M HCl reacts with excess
CaCO3 at 28 °C and 0.987 atm? Show your work and box your answer
2HCl + CaCO3 + H2O + CO2 + CaCl2

Answers

Answer:

1.01 L

Explanation:

Step 1: Write the balanced equation

2 HCl + CaCO₃ ⇒ H₂O + CO₂ + CaCl₂

Step 2: Calculate the reacting moles of HCl

64.0 mL (0.0640 L) of 1.261 M (1.261 mol/L) HCl react. The reacting moles are:

0.0640 L × 1.261 mol/L = 0.0807 mol

Step 3: Calculate the moles of CO₂ produced from 0.0807 moles of HCl

The molar ratio of HCl to CO₂ is 2:1. The moles of CO₂ produced are 1/2 × 0.0807 mol = 0.0404 mol.

Step 4: Calculate the volume occupied by 0.0404 moles of CO₂

0.0404 moles of CO₂ are at 28 °C (301 K) and 0.987 atm. We can calculate the volume occupied using the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 0.0404 mol × (0.0821 atm.L/mol.K) × 301 K / 0.987 atm = 1.01 L

Combustion, or __________, is an example of one of the most familiar chemical changes. Melting of ice, likewise, is one of the most common examples of physical changes. When a piece of coal burns, combines with the carbon in the coal. The products are carbon dioxide gas, water vapor, and a lot of ash. After careful measurements are taken, the of the reactants (coal and oxygen) is to the mass of the products (carbon dioxide, water vapor, and ash). During the_________ reaction, the quantity of matter is unchanged. Similarly, when 10 grams of ice__________ , grams of water is obtained. Mass is_________ in this change as well.

Answers

Answer:

a) Burning

b) physical

c) 10

d) constant

Explanation:

Mass remains same in a physical reaction. It changes only in chemical reactions where some of the mass is lost as energy /heat.

Thus, during combustion mass changes while during melting mass of water do not changes.

What is the maximum amount of energy that could be produced from the reaction of 85.0 grams of Aluminum with 95.0 grams of oxygen, according to the following reaction?
4 Al + 3 O2 = 2 Al2O3 AHH = -3352 kJ

Answers

Answer:

47 kj

Explanation:

Temperature measures
a. the internal energy of an object
b. how much heat is in a substance
c. the average kinetic energy of atoms and molecules in a substance
d. the average speed of atoms and molecules in a substance

Answers

i believe the answer is C. sorry if im wrong

Enter the correct letter sequence (no
spaces) Use all capital letters *

Answers

Not enough to go off of.

Please who knows ?

Which is not a conjugate acid-base pair?

A. HNO3and NO3-
B. CH3COOH and CH3COO
C. H3O+ and OH-
D. HSO4-and SO4/2-

Answers

Answer:C

conjugate of H3O+ is H2O

Which of the following chemical substances has diatomic molecules? a) carbon dioxide b) nitrogen c) ozone d) nitrogen dioxide​

Answers

Answer:

C I think

Explanation:

Thermosetting polymers are less likely to be recycled than thermoplastic polymers because: Thermosetting polymers are less likely to be recycled than thermoplastic polymers because: Some other reason. They are so cheap that it is not worthwhile to recycle them. They cannot be re-melted by heating to form into new shapes. They are so durable that there are not enough thermosetting polymers in the waste stream to set up a recycling program.

Answers

Answer:

They cannot be re-melted by heating to form into new shapes.

Explanation:

Recycling refers to the process of melting a plastic and making it into another shape or size.

Thermoplastics can be softened repeatedly, melted and remoulded. Thermosetting polymers can not be softened, melted and remoulded once they are formed.

Hence, thermosetting polymers cannot be re-melted by heating to form into new shapes therefore they can't be recycled.

Consider the following gas phase reaction:

2NO(g) + O2(g) --> 2NO2(g)

400. mL of NO at STP is reacted with 500. mL of O2 at STP. Calculate the volume of the reaction mixture at STP after the reaction goes to completion.

A.700 mL
B.800 mL
C.900 mL
D.1300 mL
E.100 mL

The answer is A. 700 mL, can someone please explain how they arrived at that answer.

Answers

Answer:

2NO(g) + O2(g) --> 2NO2(g)

now 400 ml of NO × 2 mol of NO2/2 mol of NO

= 400 ml of NO2

now 500 ml of O2 × 2 mol of NO2/1 mol of O2

= 1000 ml of NO2

now 400 ml of NO2 × 1 mol of O2/2 mol of NO

= 200 ml

subtract that from 500 ml of total i.e. 500-200 =300 ml

The total volume of the reaction mixture is 1000 ml -300ml = 700 ml

How does one calculate the pH of a solution? O A. The pH is the product of [H+] and [OH-]. O B. The pH is the negative log of [OH-]. O c. The pH is the log of [H+). D. The pH is the negative log of [ht].​

Answers

One can calculate the pH of a solution by knowing that the pH is the log of [H+). The correct option is c.

What is pH?

pH is potential hydrogen. It is the measurement of the acidity and basicity of any solution.

To calculate the pH, we first know the concentration of hydronium ion, then by using the following formula

[tex]\rm pH = -log [H_3O^+][/tex]

Thus, the correct option is c. The pH is the log of [H+).

Learn more about pH

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Answer:

pH is the negative log of H+

Explanation:

I just did it and got it wrong. The answer is D!!!

How many moles is 34.4 g of Oxygen gas (O2)?

Answers

Answer:

n = 1.075  moles

Explanation:

Given that,

Mass of oxygen = 34.4 gram

The molar mass of oxygen gas = 32 g/mol

We need to find the number of moles of oxygen. We know that,

No. of moles = given mass/molar mass

So,

[tex]n=\dfrac{34.4\ g}{32\ g/mol}\\\\=1.075\ mol[/tex]

So, there are 1.075  moles in 34.4 g of Oxygen gas.

For a particular reaction, Δ=−111.4 kJ and Δ=−25.0 J/K.
Calculate Δ for this reaction at 298 K.
Δ= ?

Answers

Answer:

[tex]\Delta G =-103.95kJ[/tex]

Explanation:

Hello there!

In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:

[tex]\Delta G =\Delta H-T\Delta S[/tex]

It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:

[tex]\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ[/tex]

Best regards!

What is the ph of 0.45m solution of the strong chloric acid HCIO3?​

Answers

Answer:

pH = 0.35

Explanation:

For a strong acid, all of the acid dissociates into H3O+, and pH = -log[H3O+], where [H3O+] = [HClO3] = 0.45 M.

Which of the following is an example of an anion that contains a metal?
A. Sulfate
B. Phosphate
C. Chromate
D. Nitrate
.

Answers

I think sulphate is answer.

Chromate from the following given list is an example of an anion that contains metal, therefore the correct answer is option C.

What is a Chemical compound?

The chemical compound is a combination of two or more  either similar or dissimilar chemical elements

Sulphate is an anion in which  both sulfur and oxygen are  non-metals.

Phosphate is an anion in which both phosphorus and oxygen are non-metals.

Chromate is an anion in which chromium is metal and oxygen is a non-metal.

Nitrate is an anion in which both nitrogen and oxygen are non-metals.

Thus, Chromate is an anion in which chromium is metal, therefore the correct answer is option C.

To learn more about a chemical compound, refer to the link;

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While eating dinner with her family, Tina's mother starts to cough. When Tina
asks her mother if she is okay, her mother is unable to speak or make any
other noise. What is happening to Tina's monther, and what should she do
next to provide aid?
A. Tina's mother has mild FBAO. Tina should begin administering
abdominal thrusts, followed by back blows if the problem persists.
B. Tina's mother has mild FBAO. Tina should begin administering
back blows, followed by abdominal thrusts if the problem persists.
C. Tina's mother has severe FBAO. Tina should begin administering
back blows, followed by abdominal thrusts if the problem persists.
D. Tina's mother has severe FBAO. Tina should begin administering
abdominal thrusts, followed by back blows if the problem persists.

Answers

The correct answer is: C. “Tina’s mother has severe FBAO. Tina should begin administering back blows followed by abdominal thrusts if the problem persists.”

Explanation: I did my study and took the test, this was right. :)

What body parts are involved in this injury? (e.g., limbs, muscles, tendons, tissue, bones, blood flow, etc.)

Now that you know more about how injuries happen and how to treat them, what can you do differently that will help you prevent an injury?


What are some ways this injury can happen? (e.g., falling, playing with matches, etc.)
How common is this injury? (Look on the Internet to find at least one statistical fact.)
What is the process for treating the injury? (Include all the steps and be detailed.)
Have you ever had this injury? If so, was your injury treated properly?

Answers

Answer:

An abrasion or scrape. Spray or pour hydrogen peroxide on the womb. Then apply a patch wrapped to it with an adhesive tape.

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