Answer:
liquefaction
liquefaction is a process when a something turns into a liquid.
Explanation:
what does it mean to count atoms
When you count atoms, remember to multiply the coefficient number and the subscript number to find the number of atoms of that element. Examples: ▪ 2H2O. Number of atoms Number of molecules = 2. H-4.
Information normally shown as a continuous wave is analog or digital. Examples include music cds and smartphones is it analog or digital. Takes up a lot of space and degrades over time is it analog or digital. Examples include dimmer light switches and cameras that use film is it analog or digital. Purer data is more accurate and has more details is it analog or digital. Please help
Answer:
Music CDs and smartphones are digital.
Explanation:
Music CDs and smartphones are digital. Analogue takes up a lot of space and degrades with the [passage of time while on the other hand, digital takes less space and degrades in large piece of time. Dimmer light switches and cameras that use film is it analog not digital. The major difference between both signals is that the analog signals have continuous electronic signals, while digital signals have non-continuous electronic signals.
Please don't give me a wedsite
By what factor does [OH- ] change when the pH increases by 1.7?
When a conditions could exist: liquid is in dynamic equilibrium with its vapor at a given temperature, the following
(I) There is no transfer of molecules between liquid and vapor
(II) The vapor pressure has a unique value
(III) The opposing processes, (liquid to vapor) and (vapor to liquid), proceed at equal rates
(IV) The concentration of vapor is dependent on time
Which of the above choices are applicable?
a. I
b. II and III
c. I, II, and III
d. II and IV
e. none of these combination
In dynamic equilibrium conditions, the vapor pressure is unique, and the rate of vaporization and condensation are at equal rates. Thus, option b is accurate.
What is dynamic equilibrium?A dynamic equilibrium is a reaction state where the rate of the forward and the backward reaction are equal. In the above case, the vapourization and the condensation will occur simultaneously at the same rate.
The vapor pressure of the liquid to gas and vice versa has a distinctive value as the temperatures are different making the pressure change directly.
Therefore, option b. II and III are the correct options.
Learn more about dynamic equilibrium here:
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Which substance is the best oxidizing agent?
A. NaOH
B. H2O
C. Xe
D. HCI
E. O3
Answer:
the answer is A.
Explanation:
Elemental fluorine, for example, is the strongest common oxidizing agent.
A sample of gas at 90 degrees Celsius occupies 15.5 L. This gas is heated to occupy a new volume of 20.3L. What is the new temperature of the gas?
Answer:
202 °C
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T₁) = 90 °C
Initial volume (V₁) = 15.5 L
Final volume (V₂) = 20.3 L
Final temperature (T₂) =?
Next, we shall convert 90 °C to Kelvin temperature. This is illustrated below:
T(K) = T(°C) + 273
Initial temperature (T₁) = 90 °C
Initial temperature (T₁) = 90 °C + 273
Initial temperature (T₁) = 363 K
Next, we shall determine the final temperature.
Initial temperature (T₁) = 363 K
Initial volume (V₁) = 15.5 L
Final volume (V₂) = 20.3 L
Final temperature (T₂) =?
V₁ / T₁ = V₂ / T₂
15.5 / 363 = 20.3 / T₂
Cross multiply
15.5 × T₂ = 363 × 20.3
15.5 × T₂ = 7368.9
Divide both side by 15.5
T₂ = 7368.9 / 15.5
T₂ ≈ 475 K
Finally, we shall convert 475 K to celsius temperature. This is illustrated below:
T(°C) = T(K) – 273
T₂ = 475 – 273
T₂ = 202 °C
Thus, the new temperature of the gas is 202 °C
Cell membranes are selectively permeable. This means that A. only water can move freely across the cell membrane. B. any substance can move across the cell membrane, but chemical energy will always be required. C. some substances can move freely across the cell membrane, while others must be transported. D. no substances can move freely across the cell membrane.
Answer:
C. some substances can move freely across the cell membrane, while others must be transported.
Explanation:
1. How does a virus differ from a common cell?
A. It has no nucleus, cell wall, or organelles.
B. It has two nuclei and no cell wall or organelles.
C. A virus has no cell well, no nucleus, and only organelles for
movement.
D. A virus differs from a cell only in shape.
Why would a doctor most likely restrict a patient’s contact with other people while the patient receives internal radiation?
A. The patient’s stress and anxiety would be eliminated.
B. High levels of radiation can diffuse through the patient’s skin.
C. Social contact would increase the effect of the radiation treatment.
D. Radioactive material can leave the patient’s body through saliva, sweat, and urine.
Answer:
D.......................
The molar mass of water is 18.02 g/mol. A mass of 160.0 grams of water is equivalent to how many moles?
please show work!
Answer:
8.879 moles.
Explanation:
From the question given above, the following data were obtained:
Molar mass of water = 18.02 g/mol
Mass of water = 160.0 g
Mole of water =?
Mole is defined by the following equation:
Mole = mass / molar mass
With the above formula, we can obtain the number of mole present in 160 g of water. This can be obtained as follow:
Molar mass of water = 18.02 g/mol
Mass of water = 160.0 g
Mole of water =?
Mole = mass / molar mass
Mole of water = 160 / 18.02
Mole of water = 8.879 moles.
Therefore, 160 g of water contains 8.879 moles.
How much water, in grams, can be made from 1.84 × 1024 hydrogen molecules?
Answer:
55.0g water can be made
Explanation:
To solve this question, we must convert the molecules of H2 to moles using Avogadro's constant. With the moles, and the reaction:
H2 + 1/2O2 → H2O
We can find the moles of H2O = Moles H2 and its mass of using molar mass of water -H2O = 18.01g/mol-
Moles H2 = Moles H2O:
1.84x10²⁴ molecules * (1mol / 6.022x10²³ molecules) = 3.055 moles H2O
Mass:
3.055 moles H2O * (18.01g / mol) = 55.0g water can be made
1. What are the five symbiotic relationships?
2. What is mutualism? Explain mutualism with an example and a picture.
3. What is commensalism? Explain with an example and a picture.
4. What is predation? Explain with an example and a picture.
5. What is parasitism? Explain with an example and a picture.
6. What is competition? Explain with an example and a picture.
Write a CER paragraph (5- 8 complete sentences) answering the following prompt:
Why are symbiotic relationships important in an ecosystem?
Answer:
1) There are five main symbiotic relationships: mutualism, commensalism, predation, parasitism, and competition.
2) The term mutualism can be simply defined as a relationship in which both species are mutually benefited. This relationship can either be within the species or between the two different species. ... Here ants are the mutualist and acacia trees is the host. The acacia tree provides home and food for the ants.
3) Commensalism is a type of symbiotic relationship in which one species benefits, while the other species is neither harmed nor helped. The species that gains the benefit is called the commensal. ... An example is a golden jackal (the commensal) following a tiger (the host) to feed on leftovers from its kills.
4) Predation is the interaction between organisms in which one organism known as the predator kills another organism which is known as prey. ... Examples of predation are a lion eating deer or a snake eating rats. This results in the transfer of energy from the prey to the predator.
5) Parasitism is generally defined as a relationship between the two living species in which one organism is benefitted at the expense of the other. The organism that is benefitted is called the parasite, while the one that is harmed is called the host. A few examples of parasites are tapeworms, fleas, and barnacles.
6) Competition is a negative interaction that occurs among organisms whenever two or more organisms require the same limited resource. ... For example, animals require food (such as other organisms) and water, whereas plants require soil nutrients (for example, nitrogen), light, and water.
Symbiotic relationships are important because they are a major driving force of evolution. This networking and cooperation among species allows them to survive better than they would as individuals.
A radioactive sample contains two different types of radioactive nuclei: A, with half-life 5.0 days, and B, with half-life 30.0 days. Initially, the decay rate of the A-type nucleus is 64 times that of the B-type nucleus. When will their decay rates be equal
Answer:
t = 39.42 days
Explanation:
To do this, we need to use the general expression for decay rate:
R = R₀ exp(-λt) (1)
According to the problem, decay rate of A initially is 64 times rate of B, so we can say the following:
A₀ = 64B₀ (2)
The value of λ can be determined using:
λ = ln2 / t(1/2) (3)
Let's calculate first the value of λ for each nuclei:
For A: λ₁ = ln2 / 5 = 0.1286 day⁻¹
For B: λ₂ = ln2 / 30 = 0.0231 day⁻¹
Now, let's write an expression using (1) for each nuclei.
A = A₀ exp(-0.1286t)
A = 64B₀ exp(-0.1286t) (3)
B = B₀ exp(-0.0231t) (4)
We want to know the time when A = B , therefore, we can actually equals (3) and (4) and solve for t:
64B₀ exp(-0.1286t) = B₀ exp(-0.0231t)
64 exp(-0.1286t) = exp(-0.0231t)
ln(64 * exp(-0.1286t)) = ln(exp(-0.0231t))
ln64 + ln(exp(-0.1286t))= -0.0231t
4.1589 - 0.1286t = -0.0231t
4.1589 = (0.1286 - 0.0231)t
t = 4.1589 / 0.1055
t = 39.42 daysSo, in 39 days, the decay rates of A and B will be the same.
Hope this helps
When 100 identical steel balls are placed on a
triple beam balance, their mass is determined to
be 1,450 grams. The mass of a single steel ball
would be closest to
Explanation:
thank you for the points
8. In order to find molarity, you must know what two things? *
Answer: - The moles of solute present in the solution.
- The volume of solution (in liters) containing the solute.
Explanation:
Explain what matter is, and all of the states it can have.
Answer:
matter is anything that occupies space
states of matter : solid,liquid, gas,plasma
Answer:
matter can be anything, tables chairs, literally anything. it has volume and takes up space.
Explanation:
Solids, liquids, gases, plasmas, and Bose-Einstein condensates (BEC)
12. An electrolysis reaction is
A. hydrophobic.
B. spontaneous.
C. exothermic.
D. non-spontaneous.
Answer: D.) non-spontaneous.
Explanation:
Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an electrolytic cell. How many hours will it take to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A
Answer: It will take 425 hours to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A.
Explanation:
The half-reaction equation is as follows.
[tex]Cu^{2+} + 2e^{-} \rightarrow Cu[/tex]
According to the standard values, 1 mole of an electron carries 96500 C. Therefore, charge carried by 2 moles of electrons is [tex]2 \times 96500 C[/tex].
Also, atomic mass of Cu is 63.5 g. According to the equation 2 moles of electrons are depositing 63.5 g of Cu.
Hence, charge required to deposit 19.5 kg (1 kg = 1000 g) or 19500 g of Cu is calculated as follows.
[tex]19500 g Cu \times \frac{2 \times 96500 C}{63.5 g Cu}\\= 5.92 \times 10^{7} C[/tex]
Formula used to calculate time is as follows.
[tex]Q = I \times t[/tex]
where,
Q = charge
I = current
t = time
Substitute the values into above formula as follows.
[tex]5.92 \times 10^{7} C = 38.5 \times t\\t = \frac{5.92 \times 10^{7} C}{38.5}\\= 1.53 \times 10^{6} sec[/tex]
As 1 hour contains 3600 seconds. So, converting seconds into hours as follows.
[tex]1.53 \times 10^{6} sec = 1.53 \times 10^{6} sec \times \frac{1 hr}{3600 sec}\\= 425 hr[/tex]
Thus, we can conclude that it will take 425 hours to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A.
please help
A container containing 5.00 L of a gas is collected at 100 K and then allowed to expand to 20.0 L. What must the new temperature be in order to maintain the same pressure (as required by Charles' Law)?
Answer:
[tex]T_2=400K[/tex]
Explanation:
Hello there!
In this case, according to the given information for this question, it turns out possible for us to calculate the final temperature, after the expansion process, by using the well-known Charles' gas law:
[tex]\frac{T_2}{V_2}=\frac{T_1}{V_1}[/tex]
Thus, we solve for the final temperature to obtain:
[tex]T_2=\frac{T_1V_2}{V_1}[/tex]
And plug in the given values:
[tex]T_2=\frac{100K*20.0L}{5.00L}\\\\T_2=400K[/tex]
Regards!
How many atoms are in 6.7 moles of iron?
Answer:
4.034x10^24 atoms
Explanation:
6.7 x 6.023x10^23 = 4.034x10^24 atoms
4.0348348050000003e+24
:|
What type of chemical reaction is represented by this balanced equation? S8(s)+802(g)-->8SO2(g)
Answer: I think it could be Decomposition
Explanation: I think is composition because decomposition starts by being together and ends up as two
Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted
between S and q is the force exerted between S and p.
O 1/2
O 2 times
O 1/4
O 4 times
Answer:1/4
Explanation:
How many moles are in 3.87 x 10 ^24 molecules of carbon?
Answer:
1 mole contains 6.02⋅1023 particles
Explanation:
Explanation:
X×6.02⋅1023=3.75⋅1024→
X=3.75⋅10246.02⋅1023=0.623⋅101=6.23 moles
130 cm of a gas at 20°C exerts a pressure of
750 mm Hg. Calculate its pressure if its volume
is increased to 150 cm3 at 35 °C.
Answer: The pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C
Explanation:
Given: [tex]P_{1}[/tex] = 750 mm Hg, [tex]V_{1} = 130 cm^{3}[/tex], [tex]T_{1} = 20^{o}C[/tex]
[tex]P_{2}[/tex] = ?, [tex]V_{2} = 150 cm^{3}[/tex], [tex]T_{2} = 35^{o}C[/tex]
Formula used to calculate the new pressure is as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{750 mm Hg \times 130 cm^{3}}{20^{o}C} = \frac{P_{2} \times 150 cm^{3}}{35^{o}C}\\P_{2} = 1137.5 mm Hg[/tex]
Thus, we can conclude that the pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C.
differences between diamond and graphite
Answer:
dimond is stronger
Explanation:
Answer:
Graphite and Diamond are different because they have different structures. ... However each carbon atom in Diamond has 4 covalent bonds with other Carbons, making it extremely strong and hard. On the other hand, each carbon in graphite is bonded to three carbons, and therefore graphite is formed in layer
Also:
Each carbon atom in a diamond is linked to four other carbon atoms. Each carbon atom in graphite is linked to three other carbon atoms. Diamond is poor conductor of electricity due to the absence of free electrons. Graphite is good conductor of electricity due to the presence of free electrons in its structure.
Explanation:
Hope this helps
what is the mass spectrom
Answer:
Here's your Answer
Explanation:
the mass spectrum is the graphical representation of the ion abundance versus the mass to charge of the ions separated in mass spectrometer
1. The half-life of Co-60 is 5.3 years. If the initial mass of the sample is 1000g, how much will remain after 15.9 years.
Answer:
125 g
Explanation:
The following data were obtained from the question:
Half-life (t½) = 5.3 years.
Original amount (N₀) = 1000 g
Time (t) = 15.9 years.
Amount remaining (N) =?
Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:
Half-life (t½) = 5.3 years.
Time (t) = 15.9 years.
Number of half-lives (n) =?
n = t / t½
n = 15.9 / 5.3
n = 3
Thus, 3 half-lives has elapsed.
Finally, we shall determine the amount of Co–60 that is remaining. This can be obtained as follow:
Original amount (N₀) = 1000 g
Number of half-lives (n) = 3
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2³ × 1000
N = 1/8 × 1000
N = 0.125 × 1000
N = 125 g
Therefore, the amount of Co–60 that is remaining is 125 g
Which two statements describe organ systems working together to bring
oxygen to cells?
O A. Blood vessels carry oxygen from the lungs to the heart.
B. Cells use oxygen to turn nutrients from food into energy.
C. The lungs allow oxygen from the air to enter the blood.
D. The brain monitors the level of oxygen in arteries.
Answer: A and C are the right answer.
Explanation:
A student reads a barometer in the laboratory and finds the prevailing atmospheric pressure to be 736 mmHg. Express this pressure in torr and in atmospheres.
Answer:
736 mmHg = 0.97 atm (Approx.)
736 mmHg = 736 Torr
Explanation:
Given barometer in the laboratory atmospheric pressure data:
Atmospheric pressure in mmHg = 736 mmHg
Find:
Change given data into Torr
Change given data in atm (atmospheric pressure)
Computation:
We know that;
1 atm = 760 mmHg
So,
736 mmHg = 736 / 760
736 mmHg = 0.97 atm (Approx.)
We know that;
760 mmHg = 760 Torr
So,
736 mmHg = 736 Torr