Answer:
x = 2, [tex]CH_{4} + 2O_{2} = CO_{2} + 2H_{2}O\\[/tex]
Explanation:
This question is related to balancing chemical equations.
[tex]CH_{4} + xO_{2} = CO_{2} + 2H_{2}O\\[/tex]
- There must be the same amount of carbons (C), hydrogens (H), and oxygens (O) on each side of the equals sign.
- There is already 1 carbon and 4 hydrogens on each side of the equals sign. The big number in front of the chemical compound multiplies into the individual elements and can be multiplied by the subscripts to get the total number of each element.
- On the right side of the equation, there are 4 oxygens (O), and on the left side, there are 2. In order for there to be 4 oxygens (O) on the left side, there must be a 2 in front of [tex]O_{2}[/tex].
Therefore, x = 2.
[tex]CH_{4} + 2O_{2} = CO_{2} + 2H_{2}O\\[/tex]
Which of the following must be
TRUE if a solution is to be
considered acidic?
A. [H^+] < [OH)
B. [H^+] > [OH ]
C. KW= [H^+] /[OH]
D. [H^+] =[OH)
Answer:
c
Explanation:
kw=h+bls
Carbon dioxide and water are produced when pentane (C5H12) reacts with oxygen. What is the balanced equation for this reaction?
○C5H12(g) + O29) - CO2(g) + H2O(g) ○C5H12(g) + O2(g) - 5CO2(g) + H2O(g)
○C5H12(g) +802(g) - 5CO2(g) + 6H2O(g) ○5CO2(g) + 6H2009) - C5H12(g) + 802(g)
○C5H12(g) +502(g) - 5CO2(g) + 6H2(g)
○CH2(g) +O2(g) + CO2(g) + H2(g)
Answer:
C
Explanation:
C5H12(g) +802(g) - 5CO2(g) + 6H2O(g)
The balanced chemical equation of pentane (C5H12) which reacts with oxygen is
C5H12(g) +802(g) - 5CO2(g) + 6H2O(g)
What is balanced chemical equation?It is the chemical equation in which the atom or molecules or moles of elements on both side reactant and product.
Our reactants are pentane and oxygen. Since, fourth and sixth reaction do not contain pentane. Therefore, fourth and sixth reaction are wrong.
Now, our next step is to compare product.
As we know that, Carbon dioxide and water are produced when pentane (C5H12) reacts with oxygen. So, we get to the conclusion that carbon dioxide and water are the product.
Since, rest of the equation have carbon dioxide and water as product.
On reactant side, there are 5 carbon atoms and 12 hydrogen atom. So, on product side there must be 5 carbon atoms and 12 hydrogen atom. Now we balance the oxygen atom on both side.
Thus, we concluded that the balanced chemical equation of pentane (C5H12) which reacts with oxygen is
C5H12(g) +802(g) - 5CO2(g) + 6H2O(g).
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Explain the method to decrease friction?
Answer:
having a smooth or lubricated surface may help decrease friction.
Explanation:
2Cr^3 + 3Zn(s) -> 2Cr(s) + 3Zn^2 + (aq) which reactant is reduced and which is oxidicided
Answer:
Cr is oxidised
and
Zn is reduced
[ Reduced reactant ] :
Cr^( + 3 ) + 3 e^( - 1 ) ===》 Cr^( 0 )
_____________________________
[ Oxidicided reactant ] :
Zn^(0) ===》Zn^( + 2 ) + 2 e^( - 1 )
El petróleo crudo, es decir, en estado natural,
se encuentra embebido en las rocas porosas de
la corteza terrestre, semejante al agua en una
esponja, y no a manera de lagos subterráneos,
como se cree. Por lo general, el pozo petrolero
contiene en su parte superior una gran masa de
gas. Responde:
a) ¿Qué precauciones se deben tener en la explo-
tación del petróleo?
b) ¿Cuál es el impacto ambiental de la explotación
del petróleo?
c) ¿Qué compromisos debe cumplir una em-
presa que explota el petróleo en relación con el
medio ambiente?
A gas has an initial pressure of 120 kPa, a volume of 23 liters, and a temperature of 20°C. If the pressure is raised to 150 kPa the new volume is 17 liters, what is the new temperature of the gas? *
A.100 K
B.0.003 K
C.270.7 K
D.18.4 K
Water can keep engines operating at low temperatures. Which property of water most likely gives it this ability?
A. it boils at around 100°C
B. it has a high heat capacity
C. it is a good lubricant
D. it can change from water to ice
Answer:
B: it has a high heat capacity
Explanation:
When any material has a high specific heat capacity/ heat capacity, it doesn't heat or cool very fast. So water can absorb more heat from the engine and can keep the engine cool or at low temperature for a longer period of time.
Please help me I will give brainliest to the first correct answer
Answer:
OPTIC B) HEPT-HOPE IT IS HELPFUL
2. How did the Activator affect the mixture?
Answer:
Activator effects a mixture if you put to much of the activator your using into a product or thing you are using.
Explanation:
For ex.
If you poor to much activator into slime it will make the slime hard and very wet it will ruin your slime completely so you will have to do it just right but start off pouring it slowly and mix and then more if it needs more.
Gas particles that are at low temperature and high pressure and are close to changing phases are considered:
a)Real Gases
b)Ideal Gases
c)Both Ideal and Real Gases
Can someone please help, 20 points
Draw 3-ethyl-2,4-dimethyl octanoic acid
3-ethyl-2.4-dimethyl-octanoic acid
Which of the following are acid formulas? (Choose 2)
NH3
CH3OH
NaOH
HNO3
H2SO4
CH4
Answer:
HNO3 & H2SO4
Explanation:
HNO3 is Nitric acid and H2SO4 is Sulphuric acid
Teresa has taken three tests worth 100 points each. Her scores are 85, 93, and 88. She has one test left to take.
To get an average score of 90, what must the sum of all her test scores be?
a.
400
c.
600
b.
360
d.
300
Answer:
SOrry it makes me writer sotufjksankdn
Explanation:
CAN SOMEONE PLEASE HELP ME WITH THIS I REALLY NEED HELP
Answer:
B
Explanation:
There's a three in front of the CH3COOH. But let's figure it out without that 3.
1 mol of CH3COOH has 3 H from CH3 and 1 hydrogen at the end. In all 4 hydrogens.
Now put the 3 in front 3CH3COOH multiplies everything by 3. So you had 4 before and with the 3 in front you must have 12.
Try it. Draw it out.
CH3COOH has 4
CH3COOH has 4
CH3COOH has 4
Total 12
That's B
Does heat flow out of the atmosphere (HQ)
change during the day?
Answer:
The heat flow into Earth's atmosphere varies as the Sun rises and sets, gradually increasing during the day and falling to zero at night.
Explanation:
Heat radiates from the ground into the lower atmosphere. In conduction, heat moves from areas of more heat to areas of less heat by direct contact. Warmer molecules vibrate rapidly and collide with other nearby molecules, transferring their energy.
please answer cansend to me
PLEASE QUICKLY. I'll give BRAINLIEST. A sample contains 25% parent isotope and 75% daughter isotopes. If the half-life of the parent isotope is 72 years, how old is the sample?
144 years old
216 years old
288 years old
360 years old
From the calculations and the principles of radioactivity, the age of the parent isotope is 144 years
What is radioactivity?The term radioactivity has to do with the spontaneous decay of a substance.
We know that we have about 25% parent isotope still remaining hence;
[tex]0.693/t1/2 =2.303/t log No/N\\When N =0.25 No and t1/2 = 72 years\\0.693/72 =2.303/t log No/0.25No\\0.0096 = 2.303/t *0.60206\\0.0096 = 1.3865/t\\t = 1.3865/0.0096\\t =144 years[/tex]
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Answer:
A. 144 years old
Explanation:
Balance the following equation:
Cr + __02 +_Cr203
Answer:
4Cr + __302 -->_2Cr203.....
How many moles of aluminum sulfide will be produced if 12 moles of Sg react?
Answer:
Molar mass = [9(12.0)+8(1.01)+4(16.0)] = 180.1 g/mol Moles = 112 g 1 mol x 180.1 g = 0.622 mol (3 sig figs)
Explanation:
why metal in the middle of metal activity series can't be obtained by heating ors in air
Answer:
See Explanation
Explanation:
The way by which a metal is obtained from its ore is determined by the chemical reactivity of the metal.
Metals that are highly reactive are chiefly obtained by electrolysis of the metal salt. These metals are found high up in the metal activity series.
Metals that are at the middle of the series are moderately reactive and are obtained by electrolysis or by reduction since they still form ionic salts.
Metals that are far lower in the series can only be obtained by heating them in air because they are mostly unreactive.
Hence, moderately reactive metals at the middle of the series are not obtained by roasting in air.
112 g of aluminum carbide react with 174 g water to produce methane and aluminum hydroxide in the reaction shown below.
2 Al4C3(s) + 12 H2O(l) → 3 CH4(g) + 4 Al(OH)3(s)
If aluminum carbide is the limiting reactant, how many moles of the excess reactant are left over
a
37.3 mol
b
4.68 mol
c
7.33 mol
d
131.94 mol
Answer: 4.999 moles of excess reactant will be left over.
Explanation:
Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.
Excess reagent is defined as the reagent which is left behind after the completion of the reaction.
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of aluminium carbide = 112 g
Molar mass of aluminium carbide = 143.96 g/mol
Putting values in equation 1:
[tex]\text{Moles of aluminium carbide}=\frac{112g}{143.96g/mol}=0.778mol[/tex]
For the given chemical reaction:
[tex]2Al_4C_3(s)+12H_2O(l)\rightarrow 3CH_4(g)+4Al(OH)_3(s)[/tex]
By the stoichiometry of the reaction:
2 moles of aluminium carbide reacts with 12 moles of water
So, 0.778 moles of aluminium carbide will react with = [tex]\frac{12}{2}\times 0.778=4.668 mol[/tex] of water
Given mass of water = 174 g
Molar mass of water = 18 g/mol
Putting values in equation 1:
[tex]\text{Moles of water}=\frac{174g}{18g/mol}=9.667mol[/tex]
Moles of excess reactant (water) left = 9.667 - 4.668 = 4.999 moles
Hence, 4.999 moles of excess reactant will be left over.
URGENT! PLEASE HELP ASAP
A sample of Argon gas at a pressure of 813 mm Hg and a temperature of 54°C, occupies a volume of 10.4 liters. If the gas is heated at a constant pressure to a temperature of 74°C, the volume of the gas sample will be _____ L?
How many moles of H2O are in 12.00 kg of water?
Use the equation below:
2Na + Cl2 ==> 2NaCl
+ O
How many grams of NaCl are produced when 1.25 moles of Cl2 reacts with Na?
Explanation:
2/1×1.25
=2.5 mole of NaCl are produced
weight of NaCl produced = moles × molar mass of NaCl
weight of NaCl produced = 2.5×58.5
weight of NaCl produced =146.5 grams
What is the pH of a solution with an H3O+ concentration of 5.67 x 10-4 M?
a. 1.00
b. 3.25
C. -1.00
d. -3.25
Answer:
3.25Explanation:
The pH of a solution can be found by using the formula
[tex]pH = - log [ { H_3O}^{+}][/tex]
From the question we have
[tex]ph = - log(5.67 \times {10}^{ - 4} ) \\ = 3.2464[/tex]
We have the final answer as
3.25Hope this helps you
How many formula units are there in 14.50 moles of any compound?
___X 10^___formula units
Answer:
8.73 × 10²⁴ formula units
Explanation:
To calculate the number of formula units a substance contain, we multiply the number of moles by Avagadro number (6.02 × 10²³)
number of formula units = 14.50 moles × 6.02 × 10²³
= 87.29 × 10²³
= 8.73 × 10²⁴ formula units.
I’d appreciate the help! :)
Here is the reaction:
3 NO2 (g) + H2O (l) = 2HNO3 (l) + NO (g)
Answer: 300g
Explanation:
first we write the given values on top
224L. x
3 NO2 (g) + H2O (l) = 2HNO3 (l) + NO (g)
22.4L 30g
then we form a formula
224L/22.4L= x/30g
224*30/22.4
6720/22.4= 300g
Balance the following equation: _H2+ __02 - __ H20
Answer:
2
H
2
+
O
2
=
2
H
2
O
Explanation:
From the original equation, you first need to write each component separately.
H
2
+
O
2
=
H
2
O
Left side: H = 2 ; O = 2 (number based on the subscript)
Right side: H = 2 ; O = 1 (number based on the subscripts; no subscript means that the element is just 1)
Notice that the number of H is already balance but the number of O is not. In order to balance the O, you need to multiply the element by 2, but you CANNOT do this by simply changing the subscript.
Hence,
H
2
+
O
2
=
2
H
2
O
Left side: H = 2 ; O = 2
Right side: H = 2 x 2 = 4 ; O = 1 x 2 = 2
Now, notice that the number of O is now balance (both are 2) but the number of H is not (since
H
2
O
is a substance and not an element, you need to multiply everything by 2). So, what to do?
You also multiply the left side H by 2. Hence,
2
H
2
+
O
2
=
2
H
2
O
Left side: H = 2 x 2 = 4 ; O = 2
Right side: H = 2 x 2 = 4 ; O = 1 x 2 = 2
The equation is now balanced.
How many ml of a 6.00M HNO would be required to prepare 200ml of a 2.50M
solution?
83.33ml
72.98ml
86.23ml
64.98ml
Answer:
83.33ml
Explanation:
Firstly, let's notice that 200ml are equal to 0.2L
M=number of moles of the solute ÷ number of liters. Let's call the number of liter by x:
2.5=x÷0.2
x=2.5×0.2
x=0.5
It means you'll need 0.5 mol of HNO. But your solution have 6 moles per liter, so how much do you need? Divide the moles by 12 to have 0.5, so now you need to divide the liter per 12 too. The liter is equal to 1000ml, so:
1000ml÷12=83.33ml
PLEASE HELP!
The specific heat of octane, C8H18(l), is 2.22 J/(g⋅K).
How much heat is needed to raise the temperature of 76.0 g of octane from 10.6 ∘C to 26.0 ∘C?
Express your answer in joules to three significant figures.
Answer:
Q = 2.60 • [tex]10^{3}[/tex] J
Explanation:
Our specific heat capacity equation is:
Q = mC∆T
Q is the energy in joules.
m is the mass of the substance.
∆T is the temperature chance.
Let's plug in what we know.
We have 76.0 g of octaneThe specific heat capacity of octane is 2.22 J/(g•K)The temperature increases from 10.6º to 26.0º (a 15.4º increase)Q = 76.0(2.22)(15.4)
Multiply.
Q = 2598.288
We want three significant figures.
Q = 2.60 • [tex]10^{3}[/tex]
or
Q = 2590 J
Hope this helps!
Answer:6,985.008
Explanation:
so the hear formula is mass times specific heat times change in temperature (kelvin) so what i did was got the change in temperature (41.4 K) and multiplied that times 2.22 J/(g•K)and multiplied that by 76 grams of Octane to get the Answer (not in scientific notation)