Carbon can be found in...

Answer:

10⁰C

Explanation:

10⁰C is equal to 50⁰F

Answer:

18 moles of H₂.

Explanation:

The balanced equation for the reaction is given below:

2Al + 6HCl –> 2AlCl₃ + 3H₂

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Finally, we shall determine the number of mole of H₂ produced by the reaction of 12 moles of Al. This can be obtained as follow:

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Therefore, 12 moles of Al will react to produce = (12 × 3)/2 = 18 moles of H₂.

Thus, 18 moles of H₂ were obtained from the reaction.

Answer:

407 pm

Explanation:

For any elemental face-centered cubic structure, the relationship between the edge length of the unit cell and the atomic radius of its element is:

Where L is the edge length and r is the atomic radius.

With that in mind we can calculate the edge length:

Answer:

decrease by a factor of 1.5

Answer:

Explanation:

So,at STP or NTP, one mole of any gas occupies 22.4 litres of volume. To find mass,firstly we have to calculate the no. Of moles present in 11.2 litres of O2 gas which can be calculated as ;

No. Of moles = Given Volume ÷ 22.4 Litre (provided that gas is at STP)

= 11.2 Litre / 22.4 Litre

= 0.5 moles

Now, mass can be calculated by;

Mass = no. Of moles × Molecular mass

= 0.5 × 32 (Molecular mass of O2 is 32u or 32 g, if you are calculating in Grams, also called Gram Molecular Mass)

= 16 g

This is the answer

Answer:

c. To facilitate a reaction of one substrate to form two products without the use of water

Explanation:

A lyase is an enzyme that catalyzes - accelerates the chemical reaction - in which a substrate is broken into two molecules. The reaction does not involve hydrolysis or oxidation, so the water molecule is not included in the chemical reaction. Thus, the enzyme facilitates the reaction in which a molecule (substrate) is decomposed into two molecules with the elimination of chemical bonds.

Answer:909

Explanation:

Explanation:

Proton +1.60 x 10-19 C 1.672 x 10-24 g

Electron -1.60 x 10-19 C 9.05 x 10-28 g

Neutron neutral 1.674 x 10-24 g

Answer:

0.0831 moles of NaOH were in the original mixture

Explanation:

The strontium hydroxide, Sr(OH)2, requires 2 moles of HCl per mole of hydroxide to be neutralized.

The sodium hydroxide, NaOH, requires 1 mol of HCl per mol of hydroxide.

To solve this question we must write 2 equations:

(1) 0.19mol = X + Y

Where X = Moles NaOH; Y = Moles Sr(OH)2

The moles of HCl required are:

0.100L * (2.969mol / L) = 0.2969 moles HCl

0.2969 mol = X + 2Y(2)

Replacing (1) in (2):

0.19mol - Y = X

0.2969 mol = (0.19mol - Y) + 2Y

0.1069mol = Y

Moles X = Moles NaOH:

0.19mol = X + 0.1069mol

X = 0.0831 moles of NaOH were in the original mixture

Answer:

Ionic Bond

Explanation:

The atom with the higher electronegativity wants to fill its valence electron shell (meaning it wants 8 electrons in this shell). The atom with lower electronegativity will want to empty or donate an electron so that it can have an empty valence shell.

Answer:

A) 3.6 x 10^-5.

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to write the equilibrium expression for the dissociation of strontium chromate:

[tex]Ksp=[Sr^{2+}][CrO_4^{2-}][/tex]

Thus, since strontium and chromate ions are in a 1:1 mole ratio, we can tell the concentration of both ions as the same; and therefore, the Ksp is:

[tex]Ksp=(6.0x10^{-3}M)(6.0x10^{-3}M)\\\\Ksp=3.6x10^{-5}[/tex]

Or option A) 3.6 x 10^-5.

Regards!

Answer:

false

Explanation:

It is because the pH for Hydroxide ions is 7

Answer:

True

Explanation:

Acids have a low concentration of hydroxide ions and a pH of 1-6, while bases have a high concentration of hydroxide ions and a pH of 8-14

Answer: The increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:

Explanation:

When agitation is increased then there will occur an increase in kinetic energy of the molecules of a substance. As a result, more number of collisions will take place due to which more amount of solute will dissolve into the solvent.

Similarly, increasing the temperature will further increase the kinetic energy of molecules. Hence, this will lead to more solubility of gaseous solute into the liquid solvent.

As solubility of a gas is directly proportional to the pressure of the gas above surface of the solution. So, an increase in solute's partial pressure over solvent will also lead to an increase in solubility of gaseous solute into liquid solvent.

When surface area of solute is increased then there will be more solute particles available for reaction. Hence, more collisions will take place. As a result, rate of reaction is more due to which there will be an increase in solubility.

Thus, we can conclude that the increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:

Answer:

OH- is 1x 10^ + 3

Explanation:

- and - = +

Answer:

3.1621 × 10²⁵ molecules

Explanation:

From the given information:

Moles of C2H8 = 52.5 moles

number of moles = mass/molar mass

molar mass of C2H8 = (6 *2) + (1*8)

= 12 + 8

= 20 g/mol

∴

52.5 moles = mass of C2H8 / 20 g/mol

mass of C2H8 = 52.5 moles × 20 g/mol

mass of C2H8 = 1050 grams

Recall that;

1 mole = 6.023 × 10²³ molecules

∴ 52.5 moles of C2H8 = (52.5 × 6.023 × 10²³) molecules

=3.1621 × 10²⁵ molecules

Answer:

1.10 g/L

Explanation:

Step 1: Calculate Henry's constant (k)

The solubility of a gas (C) is 0.890 g/L at a pressure (P) of 121 kPa. Solubility and pressure are related through Henry's law.

C = k × P

k = C / P

k = (0.890 g/L) / 121 kPa = 7.36 × 10⁻³ g/L.kPa

Step 2: Calculate the solubility of the gas if the pressure is increased to 150 kPa

We will use Henry's law.

C = k × P

C = (7.36 × 10⁻³ g/L.kPa) × 150 kPa = 1.10 g/L

Solubility of the gas, if the temperature is held constant and pressure is increased to 150 kPa from 121 kPa, is 1.10 g/L.

Henry's law of gas states at solubility (C) of the dissolved gas is directly proportional to the partial pressure (P) of the gas.

C ∝ P

C = kP, where

k = Henry's constant

Let first we calculate the Henry's constant, when the solubility of a gas is 0.890 g/L at a pressure of 121 kPa is:

k = (0.890 g/L) / (121 kPa)

k = 7.36 × 10⁻³ g/L.kPa

Now we calculate the solubility of the gas, if the pressure is increased to 150 kPa as:

C = (7.36 × 10⁻³ g/L.kPa) (150 kPa)

C = 1.10 g/L

Hence, required solubility is 1.10 g/L.

To know more about Henry's constant, visit the below link:

https://brainly.com/question/7007748

Answer:

because they were thought in college

Explanation:

hope that helps

Answer:

Celsius + 273 = Kelvin

Explanation:

Answer:

See explanation and image attached

Explanation:

During alpha decay, the mass number of the daughter nucleus is less than that of the parent nucleus by 4 units while the atomic number of the daughter nucleus is less than that of the parent nucleus by two units.

Hence, the daughter nucleus is found two places before the parent in the periodic table.

The alpha decay of the species shown in the question are described in the image attached to this answer.

Answer:

33.4 °C

Explanation:

The final temperature of water will be the equilibrium temperature. This can be obtained as follow:

Mass of copper (M꜀) = 300 g

Initial temperature of copper (T꜀) = 285 °C

Specific heat capacity of copper (C꜀) = 0.385 J/gºC

Mass of water (Mᵥᵥ) = 1000 g

Initial temperature of water (Tᵥᵥ) = 26.5 °C

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Equilibrium temperature (Tₑ) =?

Heat lost by copper = Heat gained by water

M꜀C꜀(T꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

300 × 0.385 (285 – Tₑ) = 1000 × 4.184 (Tₑ – 26.5)

115.5(285 – Tₑ) = 4184(Tₑ – 26.5)

Clear the bracket

32917.5 – 115.5Tₑ = 4184Tₑ – 110876

Collect like terms

32917.5 + 110876 = 4184Tₑ + 115.5Tₑ

143793.5 = 4299.5Tₑ

Divide both side by 4299.5

Tₑ = 143793.5 / 4299.5

Tₑ = 33.4 °C

Therefore, the final temperature of water is 33.4 °C.

Answer:

Un río aluvial es aquel en el que el lecho y las riberas están formados por sedimentos móviles y / o suelo.

Explanation:

Answer: 100.000%

Explanation:

.

Answer:

Answer:Cu

Explanation

First letter is usually capital then the other letters are usually in small letters

Answer:

6.05 × 10⁴ cal

Explanation:

Step 1: Given and required data

Mass of water (m): 112 g

Enthalpy of vaporization of water (ΔHvap): 540 cal/g

Step 2: Calculate how much energy is required to vaporize 112 g of water

Vaporization is a physical change in which a substance goes from the liquid state to the gaseous state. We can calculate the energy required (Q) using the following expression.

Q = ΔHvap × m

Q = 540 cal/g × 112 g = 6.05 × 10⁴ cal

Answer:

Explanation:

ANCHOR ANCHOR ANCHOR ANCHOR

Answer:

See explanation and image attached

Explanation:

During beta emission, neutrons are converted into protons and electrons. The anti neutrino balances the spins.

When a nucleus undergoes beta emission, the mass number of the daughter nucleus produced in the process is the same as that of the parent nucleus but the atomic number of the daughter nucleus increases by one unit.

The product of the beta decay of the nuclides shown in the question is described in the image attached to this answer.

Answer: 0.0285 moles of HCl is present in given amount of solution.

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(1)

Given values:

Molarity of HCl = 0.453 M

Volume of solution = 62.85 mL

Putting values in equation 1, we get:

[tex]0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles[/tex]

Hence, 0.0285 moles of HCl is present in given amount of solution.

Solution :

In the field of chemistry, the cationic polymerization is a kind of the chain growth polymerization where the cation initiator transfers the charge to the monomer and makes it more reactive. This kind of polymerization reaction is very sensitive to the temperature. With increase in temperature, the molecular weight as well as the reaction rate decreases rapidly.

Thus in the cationic polymerization of the 3,3-dimethyl-1-butene, the carbonation intermediate is formed and it rearranges itself. The attack o the 2nd alkene ca take place both the carbonations, so that random copolymer is formed.

im missing something though