can't quite figure out the limit problem ​

Answer:

1143

Step-by-step explanation:

Answer:

x=-9/7

Step-by-step explanation:

Answer:-12(x - 3) - (2x - 6) = 60

= -12 OJHORZHOEHFOSDHSKDKCDEZIAIFDNSQDKFFFFFFFFFFFFZIDJAZIFJOIJF

Step-by-step explanation:

EFKJNDOIDNOIEFJOAIZFOUJFNJBVJFNVJNZJCN

Question 7

Exponential functions have a variable degree.

Answer is 3^x + 6.

Question 8

Changing 15.3% to a decimal, we get 0.153.

Answer: Choice (4)

Answer:

The answer is 20/3

Step-by-step explanation:

(5 x 1 ) + ( 5 x 1/3)

5 + ( 5 × 1/3 )

5 + 5/3 = 20/3

Answer:

Step-by-step explanation:

[tex]r_1(t) = < t^2 , 8t-15,t^2> \\ \\ r_2(t) = < 11t-30, \ t^2 , \ 13t-40> \\ \\ at \ r_1 = r_2 \\ \\ t^2 = 11t - 30 , \ \ \ \ \ \ \ \ \ \ \ \ 8t - 15 = t^2 , \ \ \ \ \ \ \ \ \ t^2 = 13t -40 \\ \\ t^2 - 11t + 30\ \ \ \ \ \ \ \ \ \ \ \ t^2 -8t + 15 , \ \ \ \ \ \ \ \ \ \ \ \ t^2 -13t + 40 \\ \\ t^2 -8t-3t + 30=0 \ \ \ \ \ \ t^2 - 2t -4t + 15=0 \ \ \ \ \ \ t^2 - 1t - 13t + 40 =0[/tex]

[tex](t-6)(t-5) \ \ \ \ \ \ \ \ \ \ \ (t-5)(t-3) \ \ \ \ \ \ \ \ \ \ \ (t-5)(t-8)[/tex]

[tex]\mathbf{The \ common \ value \ of \ t \ = \ 5}[/tex]

Answer:

C

Step-by-step explanation:

Answer:

-1 and -5

Step-by-step explanation:

Answer:

the slope is 2/3 bcoz u do 2-0/3-0

Answer:

The equation of the line that has a slope of 3/2 and a y-intercept of -4 is:

y=3/2x-4.

Step-by-step explanation:

You want to find the equation for a line that has a slope of 3/2 and a y-intercept of -4.  First of all, remember what the equation of a line is:

y = mx+b  Where:  m is the slope, and  b is the y-intercept

All you really have to do here is  replace m with 3/2, which is the slope you gave, and  replace b with -4, the y-intercept you gave,  in the equation y=mx+b.

Answer:

[tex]y = x-7[/tex]    

Step-by-step explanation:

To write the equation of the line in slope-intercept form, use the slope-intercept formula, [tex]y = mx +b[/tex]. Find real values for the [tex]m[/tex] and [tex]b[/tex] and substitute them into the formula.  

1) We know that [tex]m[/tex] represents the slope, so substitute 1 in its place.  However, we still need to find [tex]b[/tex], or the y-intercept. So, along with substituting that 1 in for [tex]m[/tex], substitute the x and y values for (7,0) for the x and y in the formula as well. Then, isolate [tex]b[/tex] to find its value:

[tex]y = mx + b\\0 = (1)(7)+b\\0 = 7 + b\\-7 = b[/tex]

So, [tex]b[/tex] = -7.  

2) Now, just substitute the found values for [tex]m[/tex] and [tex]b[/tex] into the slope-intercept formula. Remember that the slope is [tex]m[/tex], so substitute 1 in, and [tex]b[/tex] is -7, so substitute -7 in its place as well. This gives the following equation in slope-intercept form:

[tex]y = 1x -7[/tex] or [tex]y = x-7[/tex]

Answer:

x1=8    x2=-7

Step-by-step explanation:

(x-8)(x+7)

x1=8

x2=-7

Answer:

m = 5/9

Step-by-step explanation:

rise = 5

run = 9

m = rise/run

m = 5/9

Answer:

m = 5/9

Step-by-step explanation:

Use the slope formula to find the slope m.

[tex]m = \frac{5}{9}[/tex]

Answer: 14*x

Step-by-step explanation: I am 99% sure

Answer:

-9 - 10 = -19

Step-by-step explanation:

If both numbers are a negative, then add them together but keep the negative or minus sign

Hope this Helps!!!

Answer:

8

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Answer:

yo sorry I'm dum need points

Answer:

[tex]Area = 2m^8 - 6m^4 + 4.5[/tex]

Step-by-step explanation:

Given

[tex]Base = 2m^4 - 3[/tex]

[tex]Height = 2m^4 - 3[/tex]

Required

The area

This is calculated as:

[tex]Area = 0.5 * Base * Height[/tex]

[tex]Area = 0.5 * (2m^4 - 3) * (2m^4 - 3)[/tex]

Open brackst

[tex]Area = 0.5 * (4m^8 - 6m^4 - 6m^4 + 9)[/tex]

[tex]Area = 0.5 * (4m^8 - 12m^4 + 9)[/tex]

Open bracket

[tex]Area = 2m^8 - 6m^4 + 4.5[/tex]

Answer:

4/420=105

Step-by-step explanation:

decompose 42 and divide by 4 is 10 and is 20 divided by 4 is 5

This question is incomplete, the missing table is uploaded along this answer below.

Answer:

percentage of age reduction is 40

Option B) 40% is the correct answer

Step-by-step explanation:

Given the data in the question;

from the table in the image below;

sample x = 25.69 , 25.58 , 24.78 , 24.94 , 24.87 , 24.63 , 25.70 , 25.52 , 24.95 , 24.91

mean = ∑x/n

where n is sample size

= (25.69  + 25.58  +24.78  + 24.94  + 24.87  + 24.63  + 25.70  + 25.52  +24.95 ) / 10

= 251.57 / 10

mean u = 25.157

so;

S/N    Sample (X)       Mean (u)       (X-U)²

1            25.69              25.157      0.284089

2           25.58              25.157      0.178929

3           24.78              25.157       0.142129

4           24.94              25.157       0.047089

5           24.87              25.157       0.082369

6           24.63              25.157       0.277729

7           25.7                 25.157       0.294849

8           25.52              25.157       0.131769

9           24.95              25.157        0.042849

10          24.91               25.157       0.061009

Total     251.57                               1.54281

Mean  25.157

Sample Variance = ∑(x-u)²/n-1 = 1.54281 / (10 - 1) = 1.54281 / 9 = 0.1714

Standard deviation STD1 = √ (variance) = √0.1714 = 0.414

now, for 6-sigma capability, Cpk = 2

Cpk = min of ( USL - mean ) / 3×STD), (Mean - LSL) / 3×STD

since our mean is centered between USL and LSL;

Cpk = ( 26.5 - 25 ) / 3×STD2

we substitute

2 = ( 26.5 - 25 ) / 3×STD2

6STD2 = 1.5

STD2 =  1.5 / 6

STD2 = 0.25

so current standard deviation STD1 = 0.414

required standard deviation for 6-sigma process STD2 = 0.25

so percentage of age reduction will be;

⇒ ( 0.414 - 0.25 ) 0.414 = 0.164 / 0.414 = 0.396 ≈ 0.4

⇒ 0.4 × 100 = 40%

Therefore, percentage of age reduction is 40

Option B) 40% is the correct answer

If the 0's are indeed zeroes, then it would appear that you're using degrees, so that the equation

r(θ) = 2 sin(0°) + 3 sin(90°)

describes a circle r = 3 (since sin(0°) = 0 and sin(90°) = 1). In this case, the area would simply be π r ² = 9π.

But I suspect you meant to use θ, so the curve has the far more interesting equation,

r(θ) = 2 sin(θ) + 3 sin(9θ)

Since sin(9θ) has a period of 2π/9 and sin(θ) has a period of 2π, their sum has a period of 2π. (That is, 2π times the LCM of 1 and 1/9, which is 1.) But we observe r(θ) is odd, since

r(-θ) = 2 sin(-θ) + 3 sin(-9θ)

… = -2 sin(θ) - 3 sin(9θ)

… = - r(θ)

which tells us that the curve closes itself over a half-period. So the area bounded by the curve is given by the integral,

[tex]\displaystyle\int_0^\pi\int_0^{r(\theta)}r\,\mathrm dr\,\mathrm d\theta[/tex]

If you're not familiar with double integrals yet, all you need to know is that this reduces to the area formula you may/should be familiar with,

[tex]\displaystyle\frac12\int_0^\pi r(\theta)^2\,\mathrm d\theta[/tex]

Compute the integral:

[tex]=\displaystyle\frac12\int_0^\pi(2\sin(\theta)+3\sin(9\theta))^2\,\mathrm d\theta[/tex]

[tex]=\displaystyle\frac12\int_0^\pi(4\sin^2(\theta)+12\sin(\theta)\sin(9\theta)+9\sin^2(9\theta))\,\mathrm d\theta[/tex]

Apply some identities:

sin²(θ) = (1 - cos(2θ)) / 2

sin(θ) sin(9θ) = (cos(9θ - θ) - cos(9θ + θ)) / 2 = (cos(8θ) - cos(10θ)) / 2

sin²(9θ) = (1 - cos(18θ)) / 2

[tex]=\displaystyle\frac14\int_0^\pi(4(1-\cos(2\theta))+12(\cos(8\theta)-\cos(10\theta))+9(1-\cos(18\theta))\,\mathrm d\theta[/tex]

[tex]=\displaystyle\frac14\int_0^\pi(13 - 4\cos(2\theta) + 12\cos(8\theta) - 12\cos(10\theta) - 9\cos(18\theta))\,\mathrm d\theta[/tex]

[tex]=\dfrac14 \left(13\theta-2\sin(2\theta)+\dfrac32\sin(8\theta)-\dfrac65\sin(10\theta)-\dfrac12\sin(18\theta)\right)\bigg|_0^\pi[/tex]

[tex]=\dfrac1{40} \left(130\theta-20\sin(2\theta)+15\sin(8\theta)-12\sin(10\theta)-5\sin(18\theta)\right)\bigg|_0^\pi[/tex]

[tex]=\dfrac{130\pi-20\sin(2\pi)+15\sin(8\pi)-12\sin(10\pi)-5\sin(18\pi)}{40}[/tex]

= 13π/4

Answer:

40 choices of combinations can be made.

Step-by-step explanation:

Given that Brian wants to buy a shirt, and he can choose an XL, L, M, S, or XS long-sleeve or short-sleeve in white, black, pink, or blue, to determine how many choices of combinations does he have, the following calculation must be performed:

XL + L + M + S + XS = 5

LS + SS = 2

W + B + P + B = 4

5 x 2 x 4 = X

10 x 4 = X

40 = X

Thus, 40 choices of combinations can be made.

Answer:

a) 83.099% of the club members had watched Naruto or Death Note.

b) 15.493% of the club members had watched only Naruto

c) 33.803% of the club members had watched only Death Note.

Step-by-step explanation:

First we find the number of students which each habit, treating the habits as Venn sets.

I am going to say that:

Set A: Watched an episode of Naruto.

Set B: Watched an episode of Death Note.

24 had watched both an episode of Naruto and an episode of Death Note:

This means that [tex](A \cap B) = 24[/tex]

48 had watched an episode of Death Note

This means that [tex]B = 48[/tex].

We have that:

[tex]B = (B-A) + (A \cap B)[/tex]

In which B - A are those who watched only Death Note. So

[tex]48 = (B-A) + 24[/tex]

[tex](B-A) = 24[/tex]

35 members had watched an episode of Naruto

This means that [tex]A = 35[/tex].

[tex]A = (A-B) + (A \cap B)[/tex]

[tex]35 = (A-B) + 24[/tex]

[tex](A-B) = 11[/tex]

At least one:

This is

[tex](A \cup B) = A + B - (A \cap B)[/tex]

So

[tex](A \cup B) = 35 + 48 - 24[/tex]

[tex](A \cup B) = 59[/tex]

Total number of students:

59 at least one, 12 none, so 71 total.

(a) What percent of the club members had watched Naruto or Death Note?

At least one, so 59 out of 71

59*100/71 = 83.099

83.099% of the club members had watched Naruto or Death Note.

(b) What percent of the club members had watched only Naruto?

11 out of 71. So

11*100/71 = 15.493

15.493% of the club members had watched only Naruto.

(c) What percent of the club members had watched only Death Note?

24 out of 71. So

24*100/71 = 33.803

33.803% of the club members had watched only Death Note.

Answer:

i think it is (b) What percent of the club members had watched only Naruto?

Step-by-step explanation:

Answer:

[tex]C = (\frac{33}{5},\frac{19}{5})[/tex]

Step-by-step explanation:

Given

[tex]A = (1,3)[/tex]

[tex]B = (8,4)[/tex]

[tex]AC : BC = 4 : 1[/tex]

Required

Determine the coordinates of C

To do this, we make use of:

[tex]C = (\frac{nx_1 + mx_2}{n+m},\frac{ny_1 + my_2}{n+m})[/tex]

Where:

[tex]A = (1,3)[/tex] ---- [tex](x_1,y_1)[/tex]

[tex]B = (8,4)[/tex] ---- [tex](x_2,y_2)[/tex]

[tex]m:n = 4 : 1[/tex]

So:

[tex]C = (\frac{1 * 1 + 4*8}{1+4},\frac{1*3 + 4*4}{1+4})[/tex]

[tex]C = (\frac{33}{5},\frac{19}{5})[/tex]

Answer:

Options A and C are correct answers

Step-by-step explanation:

A) [tex] \angle 5\: and \:\angle 1[/tex] are complementary.

C) [tex] \angle 3\: and \:\angle 4[/tex] form a linear pair.

Hope it helps you in your learning process.

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Answer:

Carlotta needs 24 orange beads for her necklace.

Step-by-step explanation:

For each necklace, the ratio of blue beads to orange beads is 3 to 2. or 3:2

Total beads given to make a necklace is = 60

Let the number of orange beads be = x

The ratio is 2 orange beads out of 5 total beads

So, we can represent the ratio as:

x=24

Hence, Carlotta needs 24 orange beads for her necklace.

Blue beads needed =  

We can also check the ratio for blue beads to orange beads:

Divide by 4, we get

Divide by 3, we get

 ...... (the given ratio)

Therefore, Carlotta needs 24 orange beads for her necklace