Answer:
17
Step-by-step explanation:
Plot in the points for each variable to find the y-intercept.
1=-4(4)+c
1=-16+c
1+16=c
17=c
9=-4(2)+c
9=-8+c
9+8=c
17=c
Answer:
Step-by-step explanation:
Given:
2 Points
(4,1) and
(2,9)
Slope
m = (y2 - y1)/(x2 - x1)
y2 = 9
y1 = 1
x2 = 2
x1 = 4
m = (9 - 1) / (2 - 4)
m = 8 / - 2
m = - 4
y intercept
y = mx + b
y = -4x + b
Use (9, 1) to find the y intercept
1 = - 4*9 + b
1 = - 36 + b
b = 37
Answer
The equation is y = - 4x + 37
Find the volume of this square
based pyramid.
10 in
12 in
[ ? ]
Answer:
480 in.^3
Step-by-step explanation:
volume of pyramid = (1/3) * (area of base) * height
Since this pyramid has a square for the base, the area of the base is
A = s^2, where s = length of the side of the square
volume = (1/3) * s^2 * h
volume = (1/3)(12 in.)^2 * (10 in.)
volume = (1/3)(144)(10) in.^3
volume = 480 in.^3
The volume of the square-based pyramid is 480 cubic inches as per the concept of the pyramid.
To find the volume of a square-based pyramid, we can use the formula:
Volume = (1/3) x base area x height.
In this case, the base of the pyramid is a square with a side length of 12 inches, and the height of the pyramid is 10 inches.
First, we calculate the base area of the pyramid, which is the area of the square base:
Base area = side length x side length
= 12 in x 12 in
= 144 square inches.
Now, we can substitute the values into the volume formula:
[tex]Volume = \frac{1}{3} \times 144 \times 10[/tex].
Multiplying these values, we get:
[tex]Volume = \frac{1}{3} \times1440 {in}^3[/tex]
Simplifying the expression, we have:
[tex]Volume = 480\ in^3[/tex].
To learn more about the pyramid;
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if y= -6 when x= -2 find y when x= 5
Answer:
Y=15 when x=5
Step-by-step explanation:
if y= -6 when x= -2
So y=? When x=5
Y=15
Hope this helps
Good Luck
A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = –16t^2 + 36t + 10. a. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. b. What is the ball’s maximum height?
Step-by-step explanation:
We have,
A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function :
[tex]h=-16t^2 + 36t + 10[/tex] ......(1)
Part (a) :
The maximum height reached by the ball is given by :
[tex]\dfrac{dh}{dt}=0\\\\\dfrac{d(-16t^2 + 36t + 10)}{dt}=0\\\\-32t+36=0\\\\t=\dfrac{36}{32}\\\\t=1.125\ s[/tex]
Part (b) :
The maximum height of the ball is calculated by putting t = 1.125 in equation (1) such that :
[tex]h=-16(1.125)^2 + 36(1.125)+ 10\\\\h=30.25\ m[/tex]