if f(x)= x/2-3 and g(x)=4x^2+x-4 find (f+g) (x)

Answers

Answer 1

Answer:

(f+g) (x)=4x^2+3x/2-7

Step-by-step explanation:

f(x)= x/2-3 and g(x)=4x^2+x-4

(f+g) (x)=?

(f+g) (x)=f(x)+g(x)

(f+g) (x)=x/2-3+4x^2+x-4

combining like terms

(f+g) (x)=4x^2+x/2+x-3-4

(f+g) (x)=4x^2+3x/2-7

hope it helps. Brainliest please


Related Questions

Can you help me with this question

Answers

Answer:

-1.67

Step-by-step explanation:

Find the volume of this square
based pyramid.
10 in
12 in
[ ? ]

Answers

Answer:

480 in.^3

Step-by-step explanation:

volume of pyramid = (1/3) * (area of base) * height

Since this pyramid has a square for the base, the area of the base is

A = s^2, where s = length of the side of the square

volume = (1/3) * s^2 * h

volume = (1/3)(12 in.)^2 * (10 in.)

volume = (1/3)(144)(10) in.^3

volume = 480 in.^3

The volume of the square-based pyramid is 480 cubic inches as per the concept of the pyramid.

To find the volume of a square-based pyramid, we can use the formula:

Volume = (1/3) x base area x height.

In this case, the base of the pyramid is a square with a side length of 12 inches, and the height of the pyramid is 10 inches.

First, we calculate the base area of the pyramid, which is the area of the square base:

Base area = side length x side length

                = 12 in x 12 in

                = 144 square inches.

Now, we can substitute the values into the volume formula:

[tex]Volume = \frac{1}{3} \times 144 \times 10[/tex].

Multiplying these values, we get:

[tex]Volume = \frac{1}{3} \times1440 {in}^3[/tex]

Simplifying the expression, we have:

[tex]Volume = 480\ in^3[/tex].

To learn more about the pyramid;

https://brainly.com/question/17615619

#SPJ2

if y= -6 when x= -2 find y when x= 5

Answers

Answer:

Y=15 when x=5

Step-by-step explanation:

if y= -6 when x= -2

So y=? When x=5

Y=15

Hope this helps

Good Luck

Can someone help me with the below question???

Answers

Answer:

so 2a+3b=±13

Step-by-step explanation:

4a²+9b²=97

ab=6

2a+3b=?

by using formula

(a+b)²=a²+b²+2ab

(2a+3b)²=(2a)²+(3b)²+2(2a)(3b)

(2a+3b)²=4a²+9b²+12ab

putting values

(2a+3b)²=97+12(6)

(2a+3b)²=97+72

(2a+3b)²=169

taking square root on both sides

√(2a+3b)²=√169

2a+3b=±13

i hope it will help you

Answer:

2a+3b = 13

Step-by-step explanation:

Using this formula

[tex](x+y)^2 = x^2+y^2+2xy[/tex]

Where,

x = 2a and y = 3b

Putting in the above formula

=> [tex](2a+3b)^2=4a^2+9b^2+12ab[/tex]

Putting  4a²+9b² = 97 and ab = 6

=> (2a+3b)² = 97+12(6)

=> (2a+3b)² = 97+72

=> (2a+3b)² = 169

Taking sqrt on both sides

=> 2a+3b = 13

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