Can someone please help me answer this

Answer:

1

Step-by-step explanation:

Answer:

93%.

Step-by-step explanation:

% Decrease = Decrease ÷ Original Number × 100

Divde 11,625 by 12,500 and multiply the answer by 100.

11,625 ÷ 12,500 × 100 = 93  

The percentage reduction is 93%.

Answer:

B. 196πx² + 392πx + 196π

Step-by-step explanation:

Total surface area of a sphere = 4πr²

Radius, r = 7x + 7

Total surface area of a sphere = 4πr²

= 4 * π * (7x + 7)²

= 4π * (7x + 7) * (7x + 7)

= 4π * 49x² + 49x + 49x + 49

= 4π * (49x² + 98x + 49)

= 196πx² + 392πx + 196π

B. 196πx² + 392πx + 196π

Answer:

150℅

Step-by-step explanation:

3/2×100/1

2 in 100=50

so50×3=150℅

Answer:

La²+8La+16 = La²+70

Step-by-step explanation:

8La+16 = 70

8La=70-16

La=54/8

La= 6.75

Area b = (6.75+4)*(6.75+4)

Area b = 10.75*10.75

Area b =115.563

The area of a square is the square of its side lengths

The area of square B is 116 centimeter square

Let the side length of square A be (a), and the side length of square B be (b)

So, we have:

[tex]\mathbf{A_a = a^2}[/tex]

[tex]\mathbf{A_b = b^2}[/tex]

From the question, we have:

[tex]\mathbf{A_b = 70 + a^2}[/tex]

[tex]\mathbf{b = 4 + a}[/tex]

Take square of both sides

[tex]\mathbf{b^2 = (4 + a)^2}[/tex]

[tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex]

Substitute [tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex] in [tex]\mathbf{A_b = b^2}[/tex]

[tex]\mathbf{A_b = 16 + 8a+ a^2}[/tex]

So, we have:

[tex]\mathbf{16 + 8a+ a^2 = 70 + a^2}[/tex]

Subtract a^2 from both sides

[tex]\mathbf{16 + 8a = 70}\\[/tex]

Subtract 16 from both sides

[tex]\mathbf{8a = 54}[/tex]

Divide both sides by 8

[tex]\mathbf{a = 6.75}[/tex]

Recall that:

[tex]\mathbf{A_b = 70 + a^2}[/tex]

So, we have:

[tex]\mathbf{A_b = 70 + 6.75^2}[/tex]

[tex]\mathbf{A_b = 115.5625}[/tex]

Approximate

[tex]\mathbf{A_b = 116}[/tex]

Hence, the area of square B is 116 centimeter square

Read more about areas at:

https://brainly.com/question/1658516

Answer:

0.25 meters is the same as A. 25 centimeters

Explanation:

multiply the length value (0.25) by 100 to get to cm from m

hope this helps chu <3

Answer:

28

Step-by-step explanation:

I'm not sure if this is right

She rode 7 miles in 2 hours, so because she is going at the same speed you times/multiply 7 x 4 in order to determine the miles. I timed it by 4 because 2 hours times 4 = 8 hours.

Hope that helped because I believe it is right :)

Answer:

y=2/7x

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept

y=2/7x+0

y=2/7x

Answer:

I would say that C is the correct answer

Answer:

The 3mm

Step-by-step explanation:

Answer:

3m is the height or altitude.

Answer:

21.42g 21420mg

Step-by-step explanation:

2.142x10=21.42g

2.142x10000=21420mg

Answer:

28.5

Step-by-step explanation:

Plzz mark brainlies thanks!!

9514 1404 393

Answer:

  an = 13 -5(n -1)

Step-by-step explanation:

The "take away 5" rule means the common difference between terms is d=-5. For first term a1=13, the n-th term is ...

  an = a1 +d(n -1)

  an = 13 -5(n -1)

Answer:

Step-by-step explanation:

c

Answer: [tex]16x^{2} - 26xy - 12y^{2}[/tex]

Answer:

[tex]\displaystyle 5[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{32}{39}} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]

OR

[tex]\displaystyle \boxed{y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-1\frac{25}{39}} \hookrightarrow \frac{-\pi}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5cos\:\frac{39}{64}\pi{x} + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between both photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle \frac{32}{39}\:unit[/tex]to the right, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{32}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you get [tex]\displaystyle \boxed{-\frac{32}{39}} = \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1.[/tex]Intermediate, we have two sine graphs [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5sin\:\frac{39}{64}\pi{x} + 1.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle 1\frac{25}{39}\:unit[/tex]to the right, which means that in order to match the leftward sine graph, we need to shift the graph BACKWARD [tex]\displaystyle 1\frac{25}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-1\frac{25}{39}} = \frac{-\pi}{\frac{39}{64}\pi}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-6\frac{22}{39}, 1],[/tex]from there to [tex]\displaystyle [-3\frac{11}{39}, 1],[/tex]they are obviously [tex]\displaystyle 3\frac{11}{39}\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 3\frac{11}{39}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and in case you want to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended five units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. So, overall, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

fafafasda

Step-by-step explanation:

wdwasdsa wr 1+11123121

Answer:

B

Step-by-step explanation:

To determine which point lies on the line, substitute the x- coordinate of the point into the equation and if the value equals the y- coordinate of the point then it lies on the line.

A (4, 8)

y = - 3(4) + 4 = - 12 + 4 = - 8 ≠ 8 ← not on line

B (4, - 8 )

y = - 3(4) + 4 = - 12 + 4 = - 8 ← lies on line

C (- 4, 8 )

y = - 3(- 4) + 4 = 12 + 4 = 16 ≠ 8 ← not on line

D (- 4, - 8 )

y = - 3(- 4) + 4 = 12 + 4 = 16 ≠ - 8 ← not on line

The point lying on the line is (4, - 8 ) → B

Answer:

51.75- 15= 36.75

36.75/3= 12.25 per ticket

Answer:

51.75 - 15 / 3

Step-by-step explanation:

$15 for a bucket of popcorn is separate from the tickets, so you subtract that from the sum.

Then you should have 36.75.

36.75 / 3 = 12.25

I hope this helped!

Stay safe! <3

Answer:

19.47

Step-by-step explanation:

I plugged it into a right triangle trig calculator

Answer:

HERE ARE SOME NOTES ON HOW TO DO these types of geo- problems and some more ! SORRY .

See attachment below!

Step-by-step explanation:

If your in High school Geometry, I could help with that and more!

If your someone who likes to have Notes.. I could send you some PDF's and more for Geometry!!  I took Geometry and have good notes!

Answer:

愚蠢的他媽的

Step-by-step explanation:

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Answer:

D. 63

Step-by-step explanation:

First, add 6 to both sides:

[tex]\frac{x}{7}[/tex] - 6 = 3

[tex]\frac{x}{7}[/tex] = 9

Multiply each side by 7

x = 63

So, the correct answer is D. 63

Simplify 6⋅ (x+3)

Apply the distributive property.

6x+6⋅3=x⋅76x+6⋅3=x⋅7

Multiply 66 by 33.

6x+18=x⋅76x+18=x⋅7

Move 77 to the left of xx.

6x+18=7x

Move all terms containing x to the left side of the equation.

subtract 7x7x from both sides of the equation.

6x+18−7x=06x+18-7x=0

Subtract 7x7x from 6x6x.

−x+18=0-x+18=0

Subtract 1818 from both sides of the equation.

−x=−18-x=-18

Multiply each term in −x=−18-x=-18 by −1

Multiply −1-1 by −1-1.

1x=(−18)⋅−11x=(-18)⋅-1

Multiply xx by 11.

x=(−18)⋅−1x=(-18)⋅-1

Multiply−18-18 by −1-1.

x=18

Answer:

Y intercept is (0,50) or b=50

Step-by-step explanation:

y = 6x-11

substitute y into 2x+3y=7

2x+3(6x-11)=7

2x + 18x-33 = 7

20 x = 7+33

x = 2

y?

y= 6(2)-11

y = 12-11 = 1

so, x = 2 and y = 1

Answer:

√{2545×2545}=√2545²=±2545

Answer:

2.814

Step-by-step explanation:

Answer:

14802

Step-by-step explanation:

Answer:

D.

Explanation:

PEMDAS method. First do the parentheses. Multiply first, then subtract 12 from that number. Once finished with the parentheses, multiply by 8.

Answer:

9/8 of a bag

she doesn't have enough beads.

Step-by-step explanation:

Bag of bead poppy has = 1

Bag of bead needed for necklace 1 = 3/8 of a bag

Bag of bead needed for necklace 2 = 1/8 of a bag

Bag of bead needed for necklace 3 = 5/8 of a bag

Total bag of beads needed = 3/8 + 1/8 + 5/8

= (3+1+5)/8

= 9/8

She needs 9/8 of a bag of bead

9/8 = 1 1/8

Therefore, she doesn't have enough beads.