Calculate the relative molecular mass of aspartame.

Answer: The African savanna ecosystem is a tropical grassland with warm temperatures year-round and seasonal rainfall. The savanna is characterized by grasses and small or dispersed trees, along with a diverse community of organisms that interact to form a complex food web.

Answer: A coefficient

Explanation:

Example of a coefficient - 2H₂O

The 2 is the coefficient

Answer:a type of cell division in sexually reproducing organisms that reduces the number of chromosomes in gametes

Explanation:

Answer:

Its a type of cell division that reduces chromosomes.

Explanation:

I believe not 100% sure tho.

Answer:

C. cell --> tissue --> organ --> organ system --> organism

Explanation:

Cells are the building blocks of life (Ex: skin cells)

A group of cells for a tissue (Ex: epithelial tissue)

Tissues working together form an organ (Ex: the stomach)

Organs working together create organ systems (Ex: the digestive system)

Organ systems create organisms (Ex: a human)

Explanation:

The final volume will be 100 mL. This is because when you dilute a solution, the molarity of the solution decreases while the volume increases. Since the molarity of the original solution is 11.5 M and the desired molarity is 1.10 M, the volume must increase by a factor of 10.5 (11.5/1.10). Therefore, the final volume will be 10.0 mL x 10.5 = 100 mL.

answer: what

explanation: what

Answer: Best way is Electronegativity.

Explanation:

Comparing the electronegativities of the two elements is one method of predicting the type of bond that will form between them. Ionic bonds typically result from significant differences in electronegativity, whereas covalent bonds typically result from smaller differences.

The kind of covalent bond that forms between two atoms depends on how many pairs of electrons are shared by them. There are some factors that determine the type of bonds.

Simply how they share electrons makes a difference between different binding kinds. Ionic bonds don't share at all, polar bonds share unevenly, and covalent bonds share equally. Following are the variables that affect the kind of bond that will form between two atoms:

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The radioactive element plutonium  undergo radioactive bombardment producing stable isotope curium. The balanced nuclear reaction is written below:

[tex]_{94}^{239}\textrm{Pu} + _{2}^{4}\textrm{He}\rightarrow _{96}^{241}\textrm{Cm} + 2_{0}^{1}\textrm{n}[/tex]

Atomic nucleus undergoes reaction with charged particles producing either its isotope or a new atom. Heavy unstable atoms such as actinides undergo radioactive decay by emitting or bombarding charged species such as alpha particles to form stable species.

Plutonium is 94th element in periodic table. It is used as nuclear fuel because it releases energy during nuclear reactions. Bombardment of an alpha particle produces a curium (Z = 96, A =241) with two neutrons as side products.

Therefore the balanced nuclear reaction of Pu-239 to produce Cm-241 is written as below:

[tex]_{94}^{239}\textrm{Pu} + _{2}^{4}\textrm{He}\rightarrow _{96}^{241}\textrm{Cm} + 2_{0}^{1}\textrm{n}[/tex]

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The chirality of the enzyme ensures that a chiral product is obtained.

The term chirality could be simplified to mean "handedness". This idea comes from the fact that a compound could be handed. The handed of aa molecule has to do with the direction to which it rotates plane polarized. As such a compound could be left handed or right handed.

Now, we are told that the product of the enzyme is chiral. This is because the enzyme is also chiral and its shape can only lock into the particular chiral reactant and this is what does give rise to the chiral product.

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In the given reaction, the limiting reactant is hydrogen gas. 3 moles of hydrogen gas produces 2 moles of ammonia, thus 9 moles will produce 6 moles of ammonia that is equal to 102 g.

Ammonia is an inorganic gas formed by the combination of nitrogen gas and hydrogen gas. The balanced chemical equation for the reaction is written below:

[tex]\rm N _{2} + 3 H_{2} \rightarrow 2 NH_{3}[/tex]

As per the given reaction, hydrogen gas is needed more in this reaction, and it is the limiting reactant which determines the product yield. Here, 3 moles of hydrogen gas produces 2 moles of ammonia. Thus, 9 moles of hydrogen gas produces:

(9 × 2) / 3 = 6 moles.

Molar mass of ammonia = 17 g/mol

Thus mass of 6 moles = 17 g/mol × 6 moles = 102 g.

Therefore, the largest amount of ammonia that can be produced from 9 moles of hydrogen gas is 102 g.

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Answer:

0.0878 moles CaCl₂

Explanation:

To find the amount of moles of CaCl₂, you need to

(1) convert the volume from mL to L (1,000 mL = 1 L)

(2) calculate the amount of moles (M = moles / L)

It is important to arrange the conversions in a way that allows for the cancellation of units.

(Step 1)
   

  42 mL CaCl₂                    1 L
------------------------  x  ----------------------  =  0.042 L CaCl₂
                                       1,000 mL

(Step 2)

Molarity (M) = moles / volume (L)                <----- Molarity ratio

2.09 M = moles / 0.042 L                            <----- Insert values

0.0878 = moles                                           <----- Multiply both sides by 0.042 L

The mass of [tex]H_2[/tex] that will be formed when 35.25 g Al reacts with excess hydrochloric acid would be 3.93 g.

The equation of the reaction of aluminum metal with hydrochloric acid to produce hydrogen gas is represented below:

[tex]2Al + 6HCl -- > 2AlCl_3 + 3H_2[/tex]

From the equation, one would see that the mole ratio of aluminum to the hydrogen gas produced is 2:3.

Now, with 35.25 g of aluminum, recall that: mole = mass/molar mass.

The molar weight of aluminum is 27 g/mol.

Thus:

Mole of 35.25 g Al = 35.25/27

                                = 1.31 mol

From the mole ratio, the mole of hydrogen that will be produced would be:

3/2 x 1.31 =1.97 mol

The molar mass of [tex]H_2[/tex] is 2 g/mol, the mass of 1.97 mol hydrogen gas can be calculated as:

Mass = mole x molar mass

         = 1.97 x 2

        = 3.93 grams

In other words, the amount of [tex]H_2[/tex] that would be formed when 35.25 g All reacts with excess hydrochloric acid would be 3.93 g.

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The temperature of the gas when the volume increase from 0.67 L to 1.37 L is  471.29 °C.

Temperature is the hotness or coldness of a thing or place.

To calculate the temperature in Celsius when the volume increase, we use the formula below.

Formula:

Where:

From the questuion,

Given:

Substitute these values into equation 1

Hence, the final temperature of the gas is 471.29 °C.

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Answer:

[tex] \huge{ \boxed{2.0468 \times {10}^{22} \: \text{atoms} }}[/tex]

Explanation:

To find the number of entities in a given substance we use the formula

[tex] \bold{N = n \times L} [/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 0.034 moles

N = 0.034 × 6.02 × 10²³ = 2.0468 × 10²²

We have the final answer as

[tex] \bold{2.0468 \times {10}^{22} \: \text{atoms}}[/tex]

the coefficient in front of H2O and so that you have an even number of oxygen

to balance H2O = H2 + O2 you will need to be sure to count all of H and O atoms on each side of the chemical

The rate of effusion of CO at 2.00 atm in the same container would be 1.74 mL/min.

According to Graham's law of effusion of gases, at constant pressure, the rate of effusion of gases is inversely proportional to the square root of their molar masses.  

Graham's law of effusion of gases can be mathematically represented as:

[tex]r_1/r_2[/tex] = [tex]\sqrt\frac{Mm_2}{Mm_1}[/tex]

Where [tex]r_1[/tex] and [tex]r_2[/tex] are effusion rates of gas 1 and gas 2, and [tex]Mm_1[/tex] and [tex]Mm_2[/tex] are their molar masses respectively.

In this case:

Gas 1 = CH

Molar mass of CH = 12 + 1 = 13 g/mol

[tex]r_1[/tex] = 2.55

Gas 2 = CO

Molar mass = 12 + 16 = 28 g/mol

[tex]r_2[/tex] = ?

Making [tex]r_2[/tex] the subject of the formula and substituting the values into the equation:

2.55/[tex]r_2[/tex] = [tex]\sqrt\frac{28}{13}[/tex]

2.55/[tex]r_2[/tex] = 1.4676

[tex]r_2[/tex]        = 2.55/1.4676

          = 1.74 mL/min

In other words, the rate of effusion of CO at 2.00 atm in the same container would be 1.74 mL/min.

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The molality of the solution is  -11.34 m/kg. The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality.

The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality. The definition of molarity, on the other hand, is based on a certain volume of solution. Mol/kg is a typical molality measurement unit in chemistry.

While a solution's molarity is determined by the moles of solute divided by the volume of the solution in litres, a solution's molality is determined by the moles of solute divided by the mass of the solvent in kilogrammes.

Colligative property:  freezing point depression.

ΔT = Kf. m

ΔT = T°fussion pure solvent - T° fussion solution

Kf = depression constant for water

0°C - (21.1°C) = 1.86 °C/m . m

-21.1°C = 1.86°C/m . m

-21.1°C / 1.86° m/°C = m  → -11.34 m/kg

The molality of the solution is -11.34 m/kg

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Answer:

Explanation:

Answer:

Explanation:

Smoking a cigarette, snorting cocaine, or drinking yourself into oblivion are all easy habits to adopt because they light up your brain with the neurotransmitter …

There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the the IUPAC name for N[tex]_2[/tex]O is nitrous oxide.

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.

N[tex]_2[/tex]O, also known as laughing gas, is commonly used by dentists as a sedative and pain reliever during dental procedures. The IUPAC name for N[tex]_2[/tex]O is nitrous oxide.

Therefore, the the IUPAC name for N[tex]_2[/tex]O is nitrous oxide.

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Answer: 1. dinitrogen monoxide ( iupac name for N2O)

              2.nitrous oxide (common name for N3O)

Explanation:

Answer: 0.375L

Explanation: Using M1V1=M2V2, we can solve for V1.

12M*V1=1.5M*3.0L

V1 = [tex]\frac{1.5M*3.0L}{12M}[/tex]

V1 = 0.375L.

0.375 L volume of the solution she needed to prepare 3.0 L of a 1.5 M HCl solution.

A homogenous mixture of one or more solutes that have been dissolved in a solvent is known as a solution. The material that a solute dissolves in to create a homogenous mixture is known as a solvent.

The component that dissolves in a solvent to create a homogenous mixture is known as a solute.

M₁ is the initial concentration of HCl solution = 12.0 M

V₁ is the volume of initial HCl solution that is needed

M₂ is the final concentration of HCl solution = 1.5 M

V₂  is the final volume of HCl solution to be prepared = 3.0 L

To find V₁, we get

V₁ = (M₂ V₂) / M₁

calculating the values, we will get:

V₁ = 1.5 M x 3.0 L / 12.0 M

= 0.375 L

Therefore, tech required to take 0.375 L of the 12.0 M HCl solution and dilute it to  3.0 L to make a 1.5 M HCl solution.

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Answer:

the water freezes at a lower temperature.

Answer:

Explanation:

1,2,4,

The equations that show combustion are equations A, B and D.

When we talk about combustion, the idea is that the substance would be burnt in oxygen. In other words, the combustion can be taken to be an oxidation reaction. It is an oxidation reaction in the sense that the oxidation number of the substance that is reacting with the oxygen would become increased.

When we look at the equations that we have, it is quite easy to pick out among the balanced reaction equations that are shown here the ones that has to do with the burning of the substance in oxygen and a consequent rise in the oxidation number.

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When [tex]O_2[/tex] is converted to [tex]O_3[/tex], the kind of reaction that takes place is oxidation.

Oxidation is a type of reaction that can be defined in several ways. These include:

Oxidation is the reverse of reduction, which can be defined as:

The conversion of [tex]O_2[/tex] to [tex]O_3[/tex] requires the addition of oxygen. Thus, it is an oxidation reaction.

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Stars form in large, dense regions of gas and dust known as molecular clouds. These clouds are located primarily in the spiral arms of galaxies, where they are exposed to intense radiation from nearby stars. As the gas and dust in these clouds are subjected to this radiation, they begin to collapse under their own gravity. As the collapse continues, the cloud becomes denser and denser, and eventually a protostar forms at its center. Over time, this protostar continues to contract and heat up, eventually reaching the point where nuclear fusion can begin in its core. At this point, the protostar becomes a fully-fledged star, and the process of star formation is complete.

TL;DR: Within the clouds of dust and scattered throughout most galaxies.

A. The limiting reactant would be oxygen.

B. The mole of excess reactant ([tex]CS_2[/tex]) would be 0.67 mol.

C. 0.33 mol [tex]CO_2[/tex] and 0.67 mol [tex]SO_3[/tex]  would be formed.

Carbon disulfide burns in oxygen to produce carbon dioxide and sulfur dioxide according to the balanced equation below:

[tex]CS_2(l) + 3O_2(g) -- > CO_2(g) + 2SO_2(g)[/tex]

The mole ratio of the carbon disulfide and the oxygen gas is 1:3. In other words, every mole of [tex]CS_2[/tex] requires 3 moles of [tex]O_2[/tex] for complete combustion.

A. From the established mole ratio, if 1.00 mol of [tex]CS_2[/tex] reacts with 1.00 mol of [tex]O_2[/tex], the limiting reactant would be [tex]O_2[/tex] because 3 moles of it are required for every mole of [tex]CS_2[/tex].

B. The excess reactant is, thus, [tex]CS_2[/tex]. 1.00 mol of [tex]O_2[/tex] would require:

3 mol [tex]O_2[/tex] = 1 mol [tex]CS_2[/tex]

1 mol [tex]O_2[/tex] = 1 x 1/3

               = 0.33 mol of [tex]CS_2[/tex]

But 1 mole of [tex]CS_2[/tex] reacted. The excess mole of [tex]CS_2[/tex] would be: 1 - 0.33 = 0.67 mol.

C. From the equation of the reaction, 3 mole of oxygen produces 1 mole of [tex]CO_2[/tex]. Thus, 1 mole of oxygen would produce:

3 mol [tex]O_2[/tex] = 1 mol [tex]CO_2[/tex]

1 mol [tex]O_2[/tex] = 1 x 1/3

              = 0.33 mol [tex]CO_2[/tex]

Also, 3 mol oxygen produces 2 moles [tex]SO_2[/tex]. Then 1 mol oxygen will produce:

2 x 1/3 = 0.67 mol

Thus, 0.33 mol [tex]CO_2[/tex] and 0.67 mol [tex]SO_3[/tex] will be formed from 1 mol of [tex]O_2[/tex].

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Carbon disulfide burns in oxygen to yield carbon dioxide and sulfur dioxide according to the following chemical equation. CS2(l) + 3O2(g) → CO2(g) + 2SO2(g)

a. If 1.00 mol CS2 reacts with 1.00 mol O2, identify the limiting reactant.

b. How many moles of excess reactant remain?

c. How many moles of each product are formed?

The final mass concentration of salt in the solution in g/l is 36.06 g/L.

The mass concentration of the mixture of the two salt solutions is calculated as follows:

Concentration of solution 1 = 15 g/l

mass of salt in the 250 mL solution = 15 g/l * 250 mL * 1 L/1000 mL

mass of salt in the 250 mL solution = 3.75 g

Concentration of solution = 6% (m/v)

This means that in 100 mL solution, 6 g of salt in present.

In 1000 mL or 1 L solution, 60 g of salt will be present.

Hence, the concentration of solution = 60 g/L

mass of salt in the 220 mL solution = 60 g/l * 220 mL * 1 L/1000 mL

mass of salt in the 220 mL solution = 13.2 g

Total mass of salt in the mixture = 16.95 g

Total volume of solution = 470 mL

Final mass concentration of solution = 16.95 g / 470 mL * 1000 mL/L

Final mass concentration of solution = 36.06 g/L

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