Answer:

Yes at A the mechanical energy is conserved.

Yes at B the part of mechanical energy is conserved potential energy and kinetic energy and some is lost as frictional force.

Explanation:

Ratio = Eb/ Ea= 1058.3 J/2940 J= 0.3599

Ratio = Ec/ Eb= 0J/ 1058.3 J= 0

At point A the skater is at rest or it is the starting point and the whole energy is due to the position of the skater i.e= mgh = 50 *9.8*6= 2940 J

Since there's no movement there is no Kinetic energy = 0 J

Yes at A the mechanical energy is conserved.

At point B the skater has traveled for some of the distance . It has potential energy and kinetic energy.

Yes at B the part of mechanical energy is conserved as potential energy and kinetic energy.

The total Mechanical energy = 1058.3 J

At point B Total Mechanical energy = PE+ KE

1058.3J = 980 J + 78.3 J

1058.3 J = mgh + 1/2mv²

= 50*2*9.8 + 1/2 *50*(8.85)²

= 980 J + 78.3 J

As the total energy of the system must remain the same some of the mechanical energy is lost as frictional force at point B .

2940 J-1058.3 J= 1881.7

At Point C the skater has arrived at the end point and the height , speed, PE, KE and ME all are zero.

(a) The **ratio **of the **mechanical energy** at **B **and mechanical energy at **A **is **0.36.**

(b) The **ratio **of the **mechanical energy** at **C **and mechanical energy at **A **is** 0.**

(c) **mechanical energy** is **conserved **between **a **and **b**.

(d) **mechanical energy** is **not conserved** between **b **and **c**.

The given parameters;

The **ratio **of the **mechanical energy** at **B **and mechanical energy at **A**;

[tex]ratio = \frac{E_b}{E_a} = \frac{1058.3}{2940} = 0.36[/tex]

The **ratio **of the **mechanical energy** at **C **and mechanical energy at **A**;

[tex]ratio = \frac{E_c}{E_a} = \frac{0}{2940} = 0[/tex]

The **change **mechanical energy **between A** and **B **from the given position;

[tex]\Delta E = mg(h_b - h_a) - \frac{1}{2}m(v_b^2 - v_a^2)\\\\ \Delta E = 50\times 9.8(2-6) \ - \ \frac{1}{2} \times 50(8.85^2 - 0)\\\\\Delta E =- 1960 + 1960\\\\\Delta E = 0 \ J[/tex]

Thus, we can conclude that **mechanical energy** is conserved between **a **and **b**.

The change **mechanical energy** between **A **and **B **from the given position;

[tex]\Delta E = mg(h_c - h_b) - \frac{1}{2}m(v_c^2 - v_b^2)\\\\ \Delta E = 50\times 9.8(0-2) \ - \ \frac{1}{2} \times 50(0^2 - 8.85^2)\\\\\Delta E = -980 + 1960 \\\\\Delta E = 980 \ J[/tex]

Thus, we can conclude that **mechanical energy** is **not conserved** between **b **and **c**.

Learn more here:https://brainly.com/question/19969393

how do you Convert 50 g to kg in an equation for physics

**Answer:**

Divide by 1000

**Explanation:**

An airplane, starting at rest, takes off on a 600. m long runway accelerating at a rate of 12 m/s/s. How many seconds does it take to reach the end of the runway?

**Answer:**

10 seconds

**Explanation:**

As it starts from rest, then u=0

and by III rd equation of motion:

Notice that the electromagnet in the virtual simulation is made up of a battery and a wire. What item could you add to the electromagnet to make it even stronger?

**Answer:**

**Explanation:**

Have y’all seen steeleflag19 at all on here?

Matching type. Send help please. ASAP!

**Answer:**

46-D

47-C

48-F

49-A

50-B

I am not very sure I am right about those answers though.

How do I proton and and electron compared

What’s the question?

Determine the electrical force of attraction between two balloons

that are charged with the opposite type of charge but the same

quantity of charge. The charge on the balloons is 6.0 x 10-7 C and they

are separated by a distance of 0.50 m.

**Answer:**

F=1.3x10^-2N

**Explanation:**

Fe= k(6x10^-7C)^2/(0.5)^2

Electrical force of attraction between the balloons is F=1.3x10^-2N

The **electric force** of **attraction** between **two balloons** should be **F=1.3x10^-2N.**

Since The **charge** on the **balloons** is 6.0 x 10-7 C and they are separated by a **distance** of 0.50 m.

So, here the electric force is

Fe= k(6x10^-7C)^2/(0.5)^2

F=1.3x10^-2N

hence, The **electric force** of **attraction** between **two balloons** should be **F=1.3x10^-2N.**

Learn more about **force** here: https://brainly.com/question/19848845

An airplane accelerates down a runway at 4.3 m/s2 for 48 s until it finally lifts off the ground. Determine the distance traveled before takeoff.

I

**Answer:**

x=4953.6m

**Explanation:**

used formula x=xo+vot+1/2at^2

waht is science

wjwissbsskdldmndndnd

**Answer:**

the intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.

**Explanation:**

Calculate the effective charges on the H and F atoms of the HF molecule in units of the electronic charge, e.

**Answer:**

**Explanation:**

Hydrogen fluoride (HF) is an ionic/electrovalent compound that dissociates into ions when dissolved in water. It's dissociation is as seen below

HF ⇄ H⁺ + F⁻

There is a transfer of electron from the hydrogen atom which produces the hydrogen ion (H⁺), while the fluorine atom receives the donated ion to become negatively charged (F⁻). The amount of charge in one electron is generally given as 1.602 × 10⁻¹⁹ coloumbs.

The required value of **effective charge** on **HF** molecule, due to** H** and **F** is **1.602 × 10⁻¹⁹ Coulombs**.

The given problem is based on the concept of **effective charges**. The net positive charge carried out by the electrons of atomic species, after forming a **polyelectronic atom** is known as **Effective charge**.

As per the given problem, the Hydrogen fluoride (HF) is an **ionic/electrovalent** compound that **dissociates** into ions when dissolved in water. It's dissociation is given as,

**HF ⇄ H⁺ + F⁻**

There is a transfer of electron from the **hydrogen** atom which produces the **hydrogen ion (H⁺)**, while the fluorine atom receives the donated ion to become negatively charged (F⁻). The amount of **charge** in one **electron** is generally given as **1.602 × 10⁻¹⁹ Coulombs**.

Thus, we can conclude that the required value of **effective charge** on HF molecule, due to H and F is ** 1.602 × 10⁻¹⁹ Coulombs**.

Learn more about the effective charge here:

https://brainly.com/question/25002720

Six seconds after starting from rest, a car is moving at 15 m/s. What is the car's

average acceleration?

6 m/s2

0-5 m/s?

5 m/s2

2.5 m/s?

-2.5 m/s?

**Answer:**

2.5 m/s²

**Explanation:**

a = ∆v/∆t = (15 m/s)/(6 s) = (15/6) m/s² = **2.5 m/s²**

A 30.0-kgkg box is being pulled across a carpeted floor by a horizontal force of 230 NN , against a friction force of 210 NN . What is the acceleration of the box?

**Answer:**

The acceleration of the box is 0.67 m/s²

**Explanation:**

**Given that,**

Mass of box = 30.0 kg

Horizontal force = 230 N

Friction force = 210 N

**We need to calculate the acceleration of the box**

**Using balance equation**

[tex]F-f_{k}=ma[/tex]

[tex]a=\dfrac{F-f_{k}}{m}[/tex]

Where, F = horizontal force

[tex]f_{k}[/tex] =frictional force

m= mass of box

a = acceleration

Put the value into the formula

[tex]a=\dfrac{230-210}{30}[/tex]

[tex]a=0.67\ m/s^2[/tex]

**Hence, The acceleration of the box is 0.67 m/s²**

Who was the first who traveled to the moon?

NEIL ARMSTRONG WAS THE FIRST MAN WHO TRAVELLED TO THE MOON.

**Answer:**

On July 20, 1969, Neil Armstrong became the first human to step on the moon.

Please provide explanation!!!

Thank you.

**Answer:**

(a) 102 cm/s

(b) 0.490 cm²

**Explanation:**

(a) Use Bernoulli equation.

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

0 + ½ ρ v₁² + ρgh₁ = 0 + ½ ρ v₂² + 0

½ ρ v₁² + ρgh₁ = ½ ρ v₂²

½ v₁² + gh₁ = ½ v₂²

½ (25.0 cm/s)² + (980 cm/s²) (5.00 cm) = ½ v²

v = 102 cm/s

(b) The flow rate is constant.

v₁ A₁ = v₂ A₂

(25.0 cm/s) (2.00 cm²) = (102 cm/s) A

A = 0.490 cm²

3 For this force system the equivalent system at P is ___________ A FRP 40 lb along x dir and MRP 60 ft lbB FRP 0 lb and MRP 30 ft lbC FRP 30 lb along y dir and MRP 30 ft lbS FRP 40 lb along x dir and MRP 30 ft lb

This question is incomplete, the complete question is;

For this force system the equivalent system at P is ___________

A) FRP = 40 lb (along +x-dir.) and MRP = +60 ft.lb

B) FRP = 0 lb and MRP = +30 ft.lb

C) FRP 30 lb (along +y-dir.) and MRP = -30 ft.lb

D) FRP 40 lb (along +x-dir.) and MRP = +30 ft.lb

**Answer:**

**D) FRP 40 lb (along +x-dir.) and MRP = +30 ft.lb**

**Explanation: **

From the figure in the image i uploaded along this answer;

FRP = ( 40 lb i + 30 lb j ) + [30 lb (-j)]

Where i and j are the unit vectors along X & Y axis respectively.

So, FRP = 40 lb i

that is, FRP = 40 lb along +X direction

MRP = [ 30 lb x ( 1 ' + 1' ) ] +( -30 lb x 1 ' )

= (30 lb x 2 ' )- 30 lb ft

= 60 lb ft - 30 lb ft

** = 30 lb ft**

**Therefore option(D) is correct **

A ray is incident at at 50 degrees angle on a plane mirror. What will be the deviation after reflection from the mirror?

**Answer:**

**Explanation:**

If the ray were not deviated, it would travel straight through the mirror. Due to the mirror, the incident ray is reflected at 30°. The ray travels 30° + 30° = 60°. The angle of deviation is 180° - 60° = 120°.

The acceleration of the spacecraft in which the Apollo astronauts took off from the moon was 3.4 m/s2 m / s 2 . On the moon, g g = 1.6 m/s2 m / s 2 . what's the apparent weight

Complete Question

The acceleration of the spacecraft in which the Apollo astronauts took off from the moon was 3.4 m/s2. On the moon, g = 1.6 m/s2. What was the apparent weight of a 75 kg astronaut during takeoff?

Answer:

The value is [tex]N = 375 \ N[/tex]

Explanation:

From the question we are told that

The acceleration is [tex]a = 3.4 \ m/s^2[/tex]

The acceleration due to gravity in the moon is [tex]g = 1.6 m/s^2[/tex]

The mass of the astronaut is [tex]m = 75 \ kg[/tex]

Generally the apparent weight is mathematically represented as

[tex]W = ma + mg[/tex]

=> [tex]W = 3.4 * 75 + 1.6 * 75[/tex]

=> [tex]W = 375 \ N[/tex]

A car moving with an intial velocity of 60m/s is brought to rest in 30 seconds calculate the acceleration

**Answer:**

a = 2 [m/s^2]

**Explanation:**

To solve this problem we must use the expressions of kinematics, we must bear in mind that when a body is at rest its velocity is zero.

[tex]v_{f} = v_{i} - (a*t)[/tex]

where:

Vf = final velocity = 0

Vi = initial velocity = 60 [m/s]

a = desacceleration [m/s^2]

t = time = 30 [s]

**Note: the negative sign of the above equation means that the car is slowing down, i.e. its speed decreases.**

0 = 60 - (a*30)

a = 2 [m/s^2]

What is the speaker’s power output if the sound intensity level is 102 dBdB at a distance of 25 mm ? Express your answer to two significant figures and include the appropriate units.

**Answer:**

**Power = 124.50 W**

**Explanation:**

Given that:

The Sound intensity of a speaker output is 102 dB

and the distance r = 25 m

For the intensity of sound,

[tex]\beta (dB)= 10 \ log_{10 } (\dfrac{I}{I_o})[/tex]

where;

the threshold of hearing [tex]I_o = 10^{-12} (W/m^2)[/tex]

[tex]\dfrac{102 }{10}= log_{10}( \dfrac{I}{10^{-12}})[/tex]

[tex]10^{10.2} = \dfrac{I}{10^{-12}}[/tex]

[tex]I = 10^{10.2} \times 10^{-12}[/tex]

I = 0.01585 W/m²

If we recall, we know remember that ;

Power = Intensity × A rea

Power = 0.01585 W/m² × 4 × 3.142 × (25 m)²

**Power = 124.50 W**

A 0.5 kg basketball moving 5 m/s to the right collides with a 0.05 kg tennis

ball moving 30 m/s to the left. After the collision, the tennis ball is moving 34

m/s to the right. What is the velocity of the basketball after the collision?

Assume an elastic collision occurred.

O A. 11.4 m/s to the left

O B. 11.4 m/s to the right

O C. 1.4 m/s to the right

O D. 1.4 m/s to the left

Answer:

1.4 m/s to the left

Explanation:

just took it c:

(iii) Why do right angle mirrors produce three images of the object?

**Explanation:**

**The two mirrors inclined to each other formed the first two images with are of the same size as the object while the third mirror is produced from the intersection of rays that emanated during the production of the first two images to produce a third image which is smaller than the object and there making the total number of images to be 3.**

**Hence this mirrors produces 3 images due to the third image formed from the intersection of the rays that produces the first two images.**

The formula that relates the image produced by inclined mirror and the angle of inclination is expressed as:

number of images n = 360/θ - 1

θ is the angle of inclination of the two mirrors

n is the number of images

If the mirrors are inclined at right angles, then θ = 90°

Substitute into the formula;

n = 360/90 -1

n = 36/9 -1

n = 4-1

n = 3

100 POINTS.

Please provide explanation.

Thank you

Answer:

(a) 0.829 m/s

(b) 3.27 m/s

(c) 0.000153 m²

55.8%

Explanation:

(a) Flow rate equals velocity times cross-sectional area. (1 L = 0.001 m³)

Q = vA

(0.001 m³ / 2.00 s) = v (48 × π (0.002 m)²)

v = 0.829 m/s

(b) Use Bernoulli equation. Choose point 1 to be the exit of the pump, and point 2 to be exit of the shower head. Choose 0 elevation to be at point 1.

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

(1.50 atm × 1.0×10⁵ Pa/atm) + ½ (1000 kg/m³) v² + 0 = (1 atm × 1.0×10⁵ Pa/atm) + ½ (1000 kg/m³) (0.829 m/s)² + (1000 kg/m³) (10 m/s²) (5.50 m)

1.50×10⁵ Pa + (500 kg/m³) v² = 1×10⁵ Pa + 414.5 Pa + 55000 Pa

v = 3.27 m/s

(c) Flow rate is constant.

Q = vA

(0.001 m³ / 2.00 s) = (3.27 m/s) A

A = 0.000153 m²

Flow rate is proportional to the pressure difference and the radius raised to the fourth power.

Q ∝ ΔP r⁴

Q₂/Q₁ = (ΔP₂/ΔP₁) (r₂/r₁)⁴

Q₂/Q₁ = (1.120) (0.840)⁴

Q₂/Q₁ = 0.558

The flow decreases to 55.8% of the original value.

**Answer:**

**Explanation:**

Regarding the point of "Flow rate is proportional to the pressure difference and the radius raised to the fourth power", flow rate depends on pressure, cross-section area and speed. As speed also depends on cross-section area, flow rate becomes dependent on pressure and cross-section area squared.

In a round pipe like blood vessel, the cross-section area is equal to pi*radius squared. So flow rate is proportional to the pressure difference and (radius squared) squared; i.e. the radius raised to the fourth power.

The new flow rate = (1.12)*(0.84)^4

=0.5576 or 55.76% of the original flow rate

A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much work was done?

**Answer:**

**Explanation:**

The work done by an object can be found by using the formula

workdone = force × distanceFrom the question

distance = 3 meters

force = 15 newtons

We have

workdone = 15 × 3

We have the final answer as

45 JHope this helps you

What cause objects to move? In three to five sentences .

**Answer:**

Gravity can affect the motion of objects as the force pulls objects closer to earth. Kinetic energy also causes movement in objects as that is energy in motion coming from stored energy known as (potential energy). With almost most importantly is needed is a force as without a force acting upon an objects is moving will continue to move and an object at rest will remain at rest as a gravitational pull or kinetic and potential energy for example are forces.

**Explanation:**

Have a great day :)

A solid nonconducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a certain distance rl (r
(A) E/8

(B) E 78.

(C) E/2

(D) 2E

(E) 8E

**Answer:**

**A ) E/8**

**Explanation:**

**If the sphere of radius R carries charge Q, then the volumetric charge density is:**

**ρ₁ = [Q/ (4/3)*π*R³]**

**Therefore the net charge inside r ( r < R ) is:**

**q₁ = ρ * (4/3)*π*r³**

**And E = K * q₁/r K = 9,98 *10⁹ [N*m²/C²]**

**E = K * ρ * (4/3)*π*r³/r**

**E = K * ρ * (4/3)*π*r²**

**If now the charge is distributed over a sphere of radius 2R**

**ρ₂ = [Q/ (4/3)*π*(2R)³]**

**ρ₂ = [Q/ (4/3)*π*8*R³]**

**Then ρ₂ < ρ₁ in fact ρ₂ = (1/8)*ρ₁**

**The electric field depends on the net charge enclosed by a gaussian surface, and the distance between the net charge and the considered point, ( considering the net charge as being at the center of the gaussian surface) In this case, there was no distance change then**

**E₂ = E₁/8**

**The right answer is lyrics A ) E/8**

Please help

A student plans an investigation to determine the refractive index of glass. The student uses this equipments.

- a ray box

- a rectangular glass block

- a protractor

- a pencil

Describe how the student collect her data.

A ray box is the answer I give

On what part of the eye are rods and cones found?

They are located in the retina.

**Answer:**

retina.

**Explanation:**

What measurements would you make (assuming you have the money, time, & equipment) to determine a star’s surface temperature? Explain your answer.

**Answer:**

**use special filters on the telescope**

**Explanation:**

Assuming you have access to a very high-grade telescope you would need to **use special filters on the telescope** that allows you to view the star's color spectrum. The color spectrum represents different levels of heat that a star is generating. This spectrum ranges from red to blue. Therefore in order to calculate the surface temperature, you would need to apply both a blue and red filter onto the telescope. Once you have these measurements you would need to compare them in order to pinpoint the correct variation of color which would give a close enough estimate of the surface temperature of the star.

how are s waves and p waves simuliar?

A.they shake the ground

B.they travel through liquids

C. they arrive at the same time

D.they shake the ground from side to side

**Answer:**

A

**Explanation:**

hope this helps

The answer is A thank me later

I WILL MARK YOU AS BRAINLIEST IF RIGHT

What is the magnitude of the net force acting on this object?

**Answer:**

The net force on an object is the total force applied on the object after adding up all the forces

In the given diagram,

we can see that the 2 forces of 4N and 4N will cancel each other out since they are equal and in the opposite direction

Now, we are left with a force of 2N and 10N,

the net force will be the difference of these forces:

Net force = 10N - 2N

Net force = **8N downwards**

**Another way to do it:**

The two 4N forces will be cancelled out,

and we are left with a 2N and a 10N force

*(notice how we cancelled equal and opposite forces for the 4N)*

We can divide the 10N force into (2N + 8N)

Since the 2N forces are equal and opposite, they will be cancelled out

and we will be left with a net force of **8N downwards**

Which best explains a difference between Einstein’s general theory of relativity and his special theory of relativity?

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

His general theory includes uniform and accelerated motion, but his special theory applies only to accelerated motion.

His general theory applies only to accelerated motion, but his special theory includes uniform and accelerated motion.

His general theory applies only to uniform motion, but his special theory includes uniform and accelerated motion.

**Answer:**

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

**Explanation:**

According to Einstein's 1915 general theory of relativity, the force of gravity arises from the curvature of space and time.

According to theory of special relativity:

1. The laws of physics are the same for all non-accelerating observers

2. The speed of light in a vacuum was independent of the motion of all observers.

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

**Answer:**

for those who dont like to read

the answer is A.

hope i helped

**Explanation:**

Follow the steps and finish the solution.7 (x minus 3) = 28Distributive property: 7 x minus 21 = 28. Addition property of equality: 7 x = 49. Division property of equality: x = blank.What is the value of x?794256
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