Answer:
a) pH = 11.5
b) pH= 3
Explanation:
a) lets calculate the number of moles of each reactant
moles of HCl = 32/1000 * 0.32 = 0.01024 mole
moles of NaOH = 42/1000 * 0.32 = 0.01344 moles
1 moles of HCl reacts with 1 moles of NaOH , so 0.01024 mole of HCl should react with 0.01024 moles of NaOH , but there is some excess NaOH.
excess NaOH= 0.01344 -0.01024 = 0.0032 moles
[H+]= [tex]\frac{10^{-14} }{0.0032} = 3.125 *10^{-12}[/tex]
pH= -log [3.125*10^-12) = 11.5
b) moles of NaOH = 0.00924
excess HCl present = 0.01024 - 0.00924 =.001
so excess [H+] = 0.001
pH= -log( 0.001) = 3
Diazomethane has the following composition by mass: 28.57% C, 4.80% H, and 66.64% N. The molar mass of diazomethane is 42.04 g/mol. Find the molecular formula of diazomethane.
Answer:
CH2N2
Explanation:
To find the molecular formula, we must first find the empirical formula as follows:
28.57% C - 28.57g of Carbon
4.80% H - 4.80g of Hydrogen
66.64% N - 66.64g of Nitrogen
Next, we convert this mass values to mole by dividing by their respective atomic mass.
C = 28.57/12 = 2.38mol
H = 4.80/1 = 4.80mol
N = 66.64/14 = 4.76mol
Next, we divide each mole value by the smallest mole value (2.38mol)
C = 2.38mol ÷ 2.38 = 1
H = 4.80mol ÷ 2.38 = 2.01
N = 4.76mol ÷ 2.38 = 2
The empirical ratio of C, H and N is therefore 1:2:2. Hence, the empirical formula is CH2N2
To calculate the molecular formula;
(CH2N2)n = 42.04 g/mol
{12 + 1(2) + 14(2)}n = 42.04
{12 + 2 + 28}n = 42.04
{42}n = 42.04
n = 42.04/42
n = 1.00009
Since n = 1, molecular formula is CH2N2
How many moles of carbon (C) are there in 92.5 g of C?
Answer:
c are there 93.5 of c yan siguro
Whatss the answer giving brainliest:)
Answer:
A.
Explanation:
I just know.
Answer:
a.
Explanation: