calculate the moment of inertia of a thin, uniform rod of length l and mass m that rotates about a pivot at distance l/3 from one end.

Answer: Directional Drilling and Tunneling

Explanation:

The method used by engineers to pierce rock at angles other than just a straight line is known as directional drilling.

Directional drilling is defined as the practice of accessing an underground oil or gas reserve by drilling in a non-vertical direction where directional drilling is also called directional boring. Directional drilling increases the efficiency of oil and gas extraction, and can also reduce the environmental impact of drilling.

Drills are primarily used in woodworking, metalworking, construction, machine tool fabrication, construction, and utility projects. Specially designed versions have been made for miniature applications.

Thus, the method used by engineers to pierce rock at angles other than just a straight line is known as directional drilling.

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The final answer is:

A) momentum = 4.53 kgm/s

B) Force = 2263 J

Given:

mass = 62 g = 0.062 kg

velocity = 73 m/s

Impact lasted = 2 × 10⁻³

A) The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 62 g = 0.062 kg

velocity = 73 m/s

We have

momentum = 0.062 × 73 = 4.526

momentum = 4.53 kgm/s

B) To find the force on the ball,

We can use the formula as:

force= (62/1000) × [73-0/(2 × 10⁻³)]

force = 2263 J

Therefore the momentum of the ball is 4.53 kgm/s and the force is 2263 J.

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The pipe at point b will have the least inner diameter based on the supplied statement.

Any liquid, gas, or substance in general that, while under stress, changes form continuously and is incapable of withstanding tangential or shearing forces.

Pipe size and water pressure are related in a moisture pipeline. Because if a pipe's diameter is reduced, the pressure inside the pipeline will rise. According to Bernoulli equation, pressure may be decreased by decreasing the area on conveyance. As a result, there is a high pressure at B and a low diameter at B.

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The complete question is-

An ideal fluid flows from left to right through this horizontal pipe, whose interior is hidden. A higher fluid level in the vertical pipes indicates a higher pressure inside the horizontal pipe. At which point does the pipe have the smallest inner diameter? (A higher fluid level in the vertical pipes indicates a higher pressure inside the horizontal pipe).

(A). Point a

(B). Point b

(C). Point c

(D). The diameter doesn't change

(E). We can't determine the diameter of the pipe.

Answer:

(D)  From what has been given

For a linear elastic collision the speed of separation equals the speed of approach - if the relative speed of approach  was 4 m/s, the relative speed of separation will be 4 m/s - both KE and momentum are considered conserved

Answer:

Trial 1 is the largest, trial 3 is the smallest

Explanation:

Given:

Trial 1

M₁ = 6·10²² kg

d₁ = 3 500 km = 3.5·10⁶ м

Trial  2

M₂ = 6·10²² kg

d₂ = 7 000 km = 7·10⁶ м

Trial  3

M₃ = 3·10²² kg

d₃ = 7 000 km = 7·10⁶ м

___________

F - ?

Gravitational force:

F₁ = G·m·M₁ / d₁² = m·6.67·10⁻¹¹·6·10²² / (3.5·10⁶)² = 0.37·m  (N)

F₂ = G·m·M₂ / d₂² = m·6.67·10⁻¹¹·6·10²² / (7·10⁶)² = 0.08·m  (N)

F₃ = G·m·M₃ / d₃² = m·6.67·10⁻¹¹·3·10²² / (7·10⁶)² = 0.04·m  (N)

Trial 1 is the largest, trial 3 is the smallest

Since the angle of incidence and reflection are equal (90° - 24° = 66°), the angle that perhaps the reflected beam forms with the surface is 66°.

If two lines meet at a common point, an angle is created. A right angle is one that is 90 degrees, and they can be found within every corner of a square. Angles that are wider are said to as obtuse and those that are more acute.

As illustrated below, the size of the circle that the arcs at two points subtend and its arc length together define the angle, or, that is formed when the lines from those two points meet at the circle's vertex.

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Compared to visible light, radio waves are less energetic and move more slowly.

The speed of light, which is roughly 186,000 miles per second, is what radio waves move at. In other words, light may go farther than the entire globe in the same amount of time that radio waves take to cover the distance of a football field. The speed and energy of radio waves would be slower than those of visible light. Compared to radio waves, visible light would have a shorter wavelength and lesser energy. The speed of radio waves and the speed of light in the visible spectrum are identical. In a vacuum, they both move at a speed of 3 108 3 10 8 metres per second. The visible light that our eyes detect is electromagnetic radiation of this kind. The researchers claim that they can make the wave travel faster than the speed of light by carefully adjusting the frequency of the voltage and the phase displacement. The fastest rate of charge transmission, however, is slower than the speed of light.

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It can hear the two speakers' beats because of the frequency of 30 Hz. Consider driving one speaker at 590 Hz and another at 560 Hz.

The quantity of observations that take place during a specific predetermined timeframe is the frequency of the a class interval. Therefore, if 20 individuals between the ages of 5 and 9 are found in the data from our study, the frequency again for 5–9 age range is 20.

The temporal rate of evolution seen in oscillatory & periodic events, such as vibrations, speech recordings (sound), radio frequencies, and light, is specified by the frequency, an essential parameter in science and engineering.

Beat frequency f = f₂ - f₁

F₂ = 590 Hz

F₁ = 560 Hz

f = 590 - 560

f = 30 Hz

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If a glacier has a smooth bedrock-glacier interface and/or that interface contains water from melting ice, that glacier is likely to move more rapidly than one that has an irregular interface and is frozen at its base is true.

Isotope geochemistry is a key technique for studying long-term climate change. The most common type of oxygen has 8 protons and 8 neutrons, giving it an atomic weight of 16 (¹⁶O), which is referred to as "light" oxygen. Because only a tiny percentage of oxygen atoms contain two additional neutrons, giving them an atomic weight of 18 (¹⁸O), or "heavy" oxygen, the rest of oxygen is referred to as "light" oxygen. Only roughly 1 in 500 oxygen atoms contain the uncommon form ¹⁸O.

Although the amount of heavy oxygen in ice varies with temperature, it has less ¹⁸O than saltwater. We need to consider the process of glacier formation in order to comprehend why this may be the case. The water-ice in glaciers began as mist in the seas, fell as snow, and then solidified into ice. When water vaporizes, the light water ([tex]H_{2}[/tex]O) enriches the water vapor while the heavy water ([tex]H_{2}[/tex]¹⁸O) is left behind ([tex]H_{2}[/tex]¹⁶O). This is only a result of the heavier molecules finding it more difficult to get past the evaporation barriers. So, although the oceans are considerably richer in ¹⁸O, glaciers are relatively enhanced in ¹⁶O. In contrast to warmer regions, this imbalance is more pronounced in colder climates.

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Two metres of rope must be raised in order to move the burden every metre.

Explain why two metres of rope should be raised.

Assuming no dissipative forces are at work over the rope.

The effort is used to draw upward on the rope's free end while the load is hung from the pulley block. The effort required is just half the amount of the load because the load is now suspended from two ropes, each of which is bearing half of the weight.

Hence, two metres of rope must be raised in order to move the burden every metre.

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The required time need to fire the rockets to achieve the desired condition is by the relationship of centripetal acceleration by angular acceleration and angular velocity, t = [tex]\sqrt{gR}\frac{M}{2T}[/tex]

What is Centripetal Acceleration?

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center. In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the Earth. Centripetal refers to being in the middle.

Radius of the spaceship in the form of a wheel = R

Mass of the spaceship concentrated at its rim = M

Radial acceleration of any object placed on the spaceship = g

Thrust exerted by the rocket = T

Time needed to fire the rockets = t

I understand the question you are looking for

"A crew of scientists has built a new space station. The space station is shaped like a wheel of radius R with essentially all its mass M at the rim. When the crew arrives the station will be set rotating at a rate that causes an object at the rim to have radial acceleration g thereby simulating Earth's surface gravity. This is accomplished by two small rockets each with thrust T newtons mounted on the station's rim. How long a time t does one need to fire the rockets to achieve the desired condition?"

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Answer:

T = 2 π (L / g)^1/2

T = 6.28 (5 m / 9.80 m/s^2)^1/2

T = 4.49 sec     (the period is not dependent on mass)

In an oscillator consisting of a spring and a block, the amount of kinetic energy reaches maximum when: A. The block passes over the equilibrium point.

In Science, kinetic energy can be defined as a type of energy that's possessed by a physical object or body, especially due to its motion or a change in velocity (acceleration).

This ultimately implies that, a physical object or body would gain more of kinetic energy as it falls back toward the Earth because it is in motion.

In an experiment that is based on an oscillator using both a spring and a block, the amount of kinetic energy that is possessed by the block would reach maximum when it passes over the equilibrium point.

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Complete Question:

In an oscillator consisting of a spring and a block, the amount of kinetic energy reaches maximum when:

The block passes over the equilibrium point.

The block is at maximum positive displacement from the equilibrium point.

The spring's extension is half of the amplitude of oscillation.

The spring is at maximum compression.

None of these.

the spring constant, k for a 12 cm length attached to the ceiling with 2.5 kg mass is 612.5.

what is spring constant ?

The stiffness of the spring is how we determine spring constant. In other words, we can define the spring constant as the force used to produce the specified displacement when the spring's displacement is one unit. It follows that a spring's spring constant will increase with increasing spring stiffness.

from the given information -

length of spring before attaching mass = 12 cm

length after attaching mass = 16 cm

mass attached = 2,5 kg

Force = k.x

k= Force/x = 2.5 x 9.8 / 0.04 = 612.5

Thus the spring constant, k for a 12 cm length attached to the ceiling with 2.5 kg mass is 612.5.

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Only one genuine zero exists, and it is found at x = 1.359. newton's method to approximate the zero(s) of the function

The first three decimal places were repeated in the solution after the fourth iteration. I began by assuming that x = 1 was the answer to the Newton's Method formula.

When I entered 1 for x, I received a zero of 5/3.

I entered 5/3 and repeated the process to get 997/687.

I was able to get 1.36976 by plugging in 997/687 and repeating the process.

I entered 1.36976 and repeated the process to get 1.359454.

I entered 1.359454 and repeated the process to get 1.359304.

There was no need to go any further because we are only interested in accuracy to three decimal places.

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While changing direction, the object will continue to move at the same speed.

In way of comparison to kinetic energy, which defines the course and speed of an object's moving, velocity is the amount of mobility along one journey. Alternatively, velocity is a vector and speed is a scalar quantity.

The rate and direction of motion are measured by a vector known as velocity. The speed that something moves in one direction is known as its velocity. Velocity can be used to gauge both the speed of an oncoming car on a busy freeway and the speed of a rocket being launched into space.

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It is false to say that a ground wire is an essential component for a circuit breaker. So, given statement is false.

The reason for why it is off-base on the grounds is  that the seriousness of an electric shock relies upon how much flow streaming in it, not on the sort of material by which it is made. An electrical switch is an electrical wellbeing gadget intended to shield an electrical circuit from harm brought about by an overcurrent or cut off. Its essential capability is to hinder current stream to safeguard hardware and to forestall the gamble of fire.

Dissimilar to a wire, which works once and afterward should be supplanted, an electrical switch can be reset (either physically or naturally) to continue typical activity.

Circuit breakers are made in changing sizes, from little gadgets that safeguard low-current circuits or individual domestic devices, to huge switchgear intended to safeguard high voltage circuits taking care of a whole city. The conventional capability of an electrical switch, or circuit, as a programmed method for eliminating power from a broken framework, is frequently truncated as OCPD (Over Flow Insurance Gadget).

Hence, given statement is false.

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90 J work must Denise do to drag her basket of laundry of mass 8.0 kg a distance of 6.0 m along a floor if the force she exerts is a constant 30.0 N at an angle of [tex]60^0[/tex] with the horizontal.

It is given that,

Mass of the basket = 8.0 Kg.

Distance from where it needs to be dragged = 6.0 m

Constant force = 30.0 N = F

Value of angle = [tex]\theta[/tex]= [tex]60^\circ[/tex]

As we know, the value of work done can be determined by using the formula:

[tex]w=\mathrm{Fscos}(\theta)[/tex]

So, putting the value of F, s and value of angle in above formula:

We will get, the value of work done as:

[tex]\mathrm{w}=30 \times 6 \times \cos (60) \\& =180 \times \frac{1}{2} \\& =90 \text { joule }[/tex]

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A person can see objects clearly only if they are between 0.6 m and 4 m from her eyes. Her optometrist prescribes bifocals that enable her to see distant objects through the top half of the lenses and read papers at a distance of 0.25 m through the lower half. What are the respective powers of the top and bottom lenses?a. -0.25 dB (top lens); +5.7 dB (bottom lens)b. +2.3 dB (top lens); -3.3 dB (bottom lens)c. +4 dB (top lens); -1.7 dB (bottom lens)d. -5.7 dB (top lens); +0.25 dB (bottom lens)e. -0.25 dB (top lens); +2.3 dB (bottom lens).

e. -0.25 dB (top lens); +2.3 dB (bottom lens)

docs of optometry (O.D.s/optometrists), the usa's number one eye health care carriers, are the frontline of eye and vision care. doctors of optometry are essential fitness care companies and are diagnosed as physicians underneath Medicare. They study, diagnose, treat and control illnesses and issues of the attention.

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If his near point is a typical 25cm, he must hold the gem that he is inspecting at 4.17cm in front of the magnifying lens that the jeweler is wearing.

It is a convex lens that is used to produce a magnified image of an object. The lens is usually mounted in a frame with a handle or wear it like an eyeglasses in front of our eye.

How to calculate, how close can he hold a gem that he is inspecting?
First, let's calculate the focal length of the lens.

f = 1 / P

= 1 / 20D

= 0.05m * ( 10^2 cm / 1m)

= 5cm

Convex lens will create a virtual image of a nearby object. Therefore, the image distance is taken as negative, di = -25cm

The position where the gem can be held is calculated with this formula :

1 / f = 1 / do + 1 / di

1 / do = 1 / f - 1 / di

= (1 / 5cm) - (1 / -25cm)

do = 4.17cm

Therefore, the jeweler needs to hold the gem at 4.17cm.  

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Parabolic Up. Since the force is in the y-direction, the particle will continue to move at a constant speed in the x-direction and accelerate in the y-direction. This creates a parabolic path around y-axis.

Force is the power that changes the motion of an item. A force can purpose an object with mass to alternate its pace. Pressure also can be described intuitively as a push or a pull. A force has both value and path, making it a vector quantity.

Pressure is a push or a pull and it affects us in our daily lives because, without force, people might not be capable of open and near stuff or lifting up their arms or legs.

Variety of Forces :

* Muscular Forces, muscular tissues feature to produce an ensuing force which is referred to as 'muscular force'.

* Frictional Forces, while an item modifications its national motion, 'frictional pressure' acts upon it.

* Carried out pressure.

* Tension force.

* Spring force.

* Gravitational pressure.

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The temperature of an object is 172°c. what is the peak wavelength (in µm) of the radiation emitted by the object at this temperature is 6.5101 μm.

The link between a blackbody's temperature and the wavelength at which it emits the most light is known as Wien's law, commonly referred to as Wien's displacement law.

According to Weins Equation spectral radiance of black-body radiation per unit wavelength, peaks at the wavelength λpeak given by:

λ(peak) = b/T

where T is the absolute temperature. b is a constant of proportionality. So the higher the temperature, the shorter or smaller the wavelength of the thermal radiation. The lower the temperature, the longer or larger the wavelength of the thermal radiation.

Now, T= 172+ 273.15 = 445.15 K
λ(peak)= 2898 μm⋅K/445.15 K    (As value of b is 2898 μm)

λ(peak) = 6.5101 μm

Therefore, peak wavelength of the radiation is 6.5101 μm.

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The Power power, in watts, is supplied by the force pushing up on the man is 1165.44 W.

a) Power P = Work done(W)/time taken(t)

= [tex]\frac{mgh}{t}[/tex]

= [tex]\frac{(74.7)(9.8)(19.9)}{12.5}[/tex]

= 1165.44 W

b) Let the Power expended by his body be P'

We have (0.412)P' = P

⇒ P' = [tex]\frac{P}{0.412}[/tex] = ([tex]\frac{1165.44}{0.412}[/tex]) = 2828.74 W

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The Radius loop of 34.88m that coaster could go around with speed of 18.5m/s.

Mass of rollercoaster =2800kg

Speed is 18.5m/s

[tex]V=\sqrt{gR}\\ \\V=speed=18.5m/s\\\\g=gravity=9.81m/s^2\\\\R=radius[/tex]

Calculation- squaring both sides of equation.

[tex]V^2=gR\\\\R=V^2/g\\\\R=18.5^2/9.81\\\\R=342.25/9.81\\\\R=34.88m[/tex]

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Neptune and Uranus are similar in terms of size, mass, composition, and internal structure. The largest moon of Neptune, Triton, appears to have been captured because of its retrograde orbit.

Triton has a thin atmosphere and could be experiencing geological activity. Neptune's location was anticipated before it was ever discovered. Neptune is one of just two ice giants in the outer solar system (the other is Uranus). The planet's bulk, which is composed of a hot, dense fluid floating atop a tiny, rocky core, is primarily made up of water, methane, and ammonia (80% or more). Uranus is Neptune's identical twin. Their mass and chemical contents are equivalent. They are composed of an exterior layer of rocks and a mantle that is a mixture of water, ammonia, and methane ices.

Therefore, a physical body's mass is its total amount of matter. Inertia, or the body's resistance to acceleration (change of velocity) when a net force is applied, is also measured by this property. The gravitational pull an object has on other bodies is also influenced by its mass. The kilograms is the fundamental mass unit of SI (kg).

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The small explosive charge produces only internal forces between the two stages of the rocket, so no external forces. Momentum is conserved.

=

( + )( ⁄) − ( )( ⁄)/

=

. / − . //

= . / /

=. / / = /s

Since this is positive the lower stage is moving in the same direction as the upper stage and both are in the same as the original direction.

Therefore, The small explosive charge produces only internal forces between the two stages of the rocket, so no external forces. Momentum is conserved.

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Two students are playing paper football. The x-component of the velocity vector is 10.97 m/s.

Given that,

Initial velocity of the football is, u = 15 m/s

Angle of projection, θ = 43°

The x-component of the velocity which is also known as horizontal component is given as:

Vx = V cos(43°) = 15* 0.731 = 10.965 ≈ 10.97 m/s

The y-component of the velocity which is also known as vertical component is given as:

Vy = V sin(43°) = 15* 0.682 = 10.23 m/s

Thus, x-component of the velocity is 10.97 m/s, y-component of the velocity is 10.23 m/s.

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The multiple of earth's radius which gives the radial distance is 4/3 or 1.33.

Initial speed = 0.745

However,

We know that escape velocity = V = √ (GM/2Rₓ)

So, using the property of energy conservation,

= (1/2)mv² - GMm/2Rₓ

= - GMm/r

The escape velocity, in astronomy and space exploration, is the velocity needed for a body to escape from a gravitational centre of attraction without undergoing any further acceleration. It is the minimum velocity required by a body to be projected to overcome the gravitational pull of the earth.

Thus,

= r = 4Rₓ / 3

Hence the multiple of Rₓ is 4/3 or 1.33.

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