Answer:
[tex]M_{C_9H_{13}NO_3}=183.23g/mol[/tex]
Explanation:
Hello!
In this case, since the molar mass of a chemical compound is computed by averaging the atomic mass of each element in the molecule and the amount of atoms; which in this case there are 9 carbon atoms, 13 hydrogen atoms, 1 nitrogen atom and 3 oxygen atoms; thus, we compute the average as shown below:
[tex]M_{C_9H_{13}NO_3}=m_C*9+m_H*13+m_N+m_O*3[/tex]
Now, we plug in the atomic masses to obtain:
[tex]M_{C_9H_{13}NO_3}=12.01*9+1.01*13+14.01+16.00*3\\\\M_{C_9H_{13}NO_3}=183.23g/mol[/tex]
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Nitrogen can exist as a solid, a liquid, or a gas. Which of the following lists the
phases of nitrogen in order of increasing density?
1. liquid, gas, solid
2. gas, liquid, solid
3. gas, solid, liquid
4. solid, liquid, gas
The phases of nitrogen in order of increasing density is solid, liquid, and gas.
Nitrogen is known to be odorless and colorless. Nitrogen makes up about 78% of the gases that we've in the atmosphere. It has an atomic number of 7 and is represented with the symbol N.It should be noted that nitrogen can be a solid, a liquid or a gas. When nitrogen is at ordinary pressure, it is known to be a gas. In a case whereby nitrogen is below 77°K, then it's a liquid and it's a solid when it's below 63°K.The density explains the mass per unit volume that nitrogen has when it's either at gaseous, solid or liquid state. It should be noted that the highest density is at its gaseous state.Therefore, the phases of nitrogen in order of increasing density will then be solid, liquid, and gas.In conclusion, the correct option is D.
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Answer:
Batteries hold chemical energy
Explanation:
The battery acid in a battery leads to chemical energy.
What is one way a pathogen can enter the body?
Question 3 options:
Nose
Broken Skin
Mouth
All of the above
The density of gold is 19.3 g/cm³. Which of the following shows the mass of a gold bar that is 4.50 cm × 8.00 cm × 20.00 cm?
Answer:
13896g
Explanation:
volume = 4.50×8.00×20.00 = 720 cm³
mass = density × volume
mass= 19.3 × 720 = 13896g
Identify the most acidic hydrogens in each of the following molecules. Give the structure of the enolate ion arising from deprotonation. (a) Acetaldehyde; (b) propanal; (c) acetone; (d) 4-heptanone; (e) cyclopentanone.
Answer:
See explanation below (Brainlist please)
Explanation:
First of all, we need to understand what is an acidic hydrogen.
An acidic hydrogen, is the atom of hydrogen which is more propense to undergo an acid base reaction, and form a stable ion or molecule in the process.
In other words, is the hydrogen that is more vulnerable to get substracted in an acid base reaction to form another compound.
Knowing this information, gives us an idea of how a molecule can be formed and which kind of compound is formed.
Now, in this question, we have 5 molecules. Each of them is either a ketone or aldehyde, so this mean that we have the carbonile group (C = O), which means that is easier to identify the acidic hydrogen. This is because the Carbonile group is an attractor group, so, it will attract the charges by inductive effect (in some cases by resonance), and the molecule is more stable.
This can be shown by drawing the enolate ion that is formed once the molecule undergo the acid base reaction. As it's an enolate form that we are looking for, then it means that the ketone or aldehyde is undergoing an electrofilic attack with a base. This base will substract the most acidic hydrogen to form a better and stable enolate. The acidic hydrogen and the enolate form can be seen in the attached picture.
a) In the case of acetaldehyde, the most acidic will be the hydrogen of carbon 2, because the hydrogen from the carbonile, once it's substracted, the charge of the carbon cannot be stabilized by resonance. Carbon 2 hydrogens, can do this job easily.
b) Propanal happens something similar to acetaldehyde, the terminal hydrogen cannot be substracted, and carbon 3, once the hydrogen is gone, the negative charge cannot be stabilized by resonance, so hydrogens of carbon 2 can do this.
c) in the case of acetone, is easier to look because we only have the C = O between two methyl group, so you can use either carbon 1 or 3 to do the job.
d) 4 heptanone the most acidic hydrogen would be carbon 3 or 5, because they are closer to the C=O and the ion can be stabilized by resonance.
e) Finally in ciclopentanone, the most acidic hydrogen would be carbon 2 or 5.
See picture for a better understanding.
Hope it helps.