Calculate the energy change for the below reaction in kJ per pound.

Answer:

Moles of NaOH = 0.5 M x 0.0076 L = 0.0038 mol

Moles of HA = 0.0038 mol

Concentration of HA = 0.0038 mol/0.01 L = 0.38 M

AVI: Supports various raw data coding. Microsoft Inc. created the audio visual interleave protocol, or AVI.

Coding is defined as the practice of using computer programming languages to provide instructions to machines and computers.  Computers can obey a set of instructions created through coding.

WAV: A common audio format that Windows PCs can play. It stands for Waveform Audio File Format, which was created by IBM and Microsoft Inc.

Sun, Unix, and Java all employ the standard audio format known as AU.

The most common format for music downloads is MP3.

Real audio, or RA.

AIFF: a common audio file format for Macs.

Thus, AVI: Supports various raw data coding. Microsoft Inc. created the audio visual interleave protocol, or AVI.

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Answer:

Explanation:

1,2,4,

The equations that show combustion are equations A, B and D.

When we talk about combustion, the idea is that the substance would be burnt in oxygen. In other words, the combustion can be taken to be an oxidation reaction. It is an oxidation reaction in the sense that the oxidation number of the substance that is reacting with the oxygen would become increased.

When we look at the equations that we have, it is quite easy to pick out among the balanced reaction equations that are shown here the ones that has to do with the burning of the substance in oxygen and a consequent rise in the oxidation number.

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answer: what

explanation: what

Answer:

Explanation:

In the given reaction, the limiting reactant is hydrogen gas. 3 moles of hydrogen gas produces 2 moles of ammonia, thus 9 moles will produce 6 moles of ammonia that is equal to 102 g.

Ammonia is an inorganic gas formed by the combination of nitrogen gas and hydrogen gas. The balanced chemical equation for the reaction is written below:

[tex]\rm N _{2} + 3 H_{2} \rightarrow 2 NH_{3}[/tex]

As per the given reaction, hydrogen gas is needed more in this reaction, and it is the limiting reactant which determines the product yield. Here, 3 moles of hydrogen gas produces 2 moles of ammonia. Thus, 9 moles of hydrogen gas produces:

(9 × 2) / 3 = 6 moles.

Molar mass of ammonia = 17 g/mol

Thus mass of 6 moles = 17 g/mol × 6 moles = 102 g.

Therefore, the largest amount of ammonia that can be produced from 9 moles of hydrogen gas is 102 g.

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Answer:a type of cell division in sexually reproducing organisms that reduces the number of chromosomes in gametes

Explanation:

Answer:

Its a type of cell division that reduces chromosomes.

Explanation:

I believe not 100% sure tho.

Answer: A coefficient

Explanation:

Example of a coefficient - 2H₂O

The 2 is the coefficient

Answer:

C. cell --> tissue --> organ --> organ system --> organism

Explanation:

Cells are the building blocks of life (Ex: skin cells)

A group of cells for a tissue (Ex: epithelial tissue)

Tissues working together form an organ (Ex: the stomach)

Organs working together create organ systems (Ex: the digestive system)

Organ systems create organisms (Ex: a human)

The chemical formula of aspartame is C₁₄H₁₈N₂O₅ and it's relative molecular mass is 294.30 g/mol which is calculated as (12×14)+(1×18)+(14×2)+(16×5).

Molecular  mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molecular mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.

The molar mass and formula mass are used as synonym for the molecular mass.It does not depend on the amount of substance which is present in the sample.It has units of gram/mole.

Molecular masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.In case of aspartame it is calculated as,(12×14)+(1×18)+(14×2)+(16×5)=294.30 g/mol.

Thus , relative molecular mass or molecular mass of aspartame is 294.30 g/mol.

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Answer: Substances can change phase — often because of a temperature change. At low temperatures, most substances are solid; as the temperature increases, they become liquid; at higher temperatures still, they become gaseous.

Explanation:

Reagents are primary standards that can be used in chemical processes. These substances are frequently employed to figure out the concentration of a solution that can interact chemically with the primary standard but whose concentration is unknown. The term "secondary standard solution" refers to a solution developed expressly for a given analysis.

A reagent with a high degree of purity is called a primary standard solution. It has a highly accurate concentration that mirrors the solute's molar concentration. Because of its purity, it may be used to accurately determine the mass to volume ratio.

The term "secondary standard solution" refers to a solution developed expressly for a given analysis. A secondary standard is a substance whose active agent content was discovered by comparison with a primary standard. This means that it is frequently bench marked against a major standard.

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Ideal gas law is valid only for ideal gas not for vanderwaal gas. To solve such, we need to know the relation between rate of effusion and molar mass of gases. Therefore, the new volume V₂ is 18L.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature. an ideal gas on the walls of the container is inversely proportional to the volume occupied that gas.

Mathematically, Boyle's law can be written as

P₁V₁ = P₂V₂

P₁=initial pressure=342 torr

P₂=final pressure=1710 torr

V₁ = initial volume= 29.0 L

V₂=final pressure=?

Substituting all the given values in the above equation, we get

V₂ = P₁V₁/P₂

V₂ = (342 × 29.0)/1710

V₂ = 18L

Therefore, the new volume V₂ is  18L.

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Answer: 0.375L

Explanation: Using M1V1=M2V2, we can solve for V1.

12M*V1=1.5M*3.0L

V1 = [tex]\frac{1.5M*3.0L}{12M}[/tex]

V1 = 0.375L.

0.375 L volume of the solution she needed to prepare 3.0 L of a 1.5 M HCl solution.

A homogenous mixture of one or more solutes that have been dissolved in a solvent is known as a solution. The material that a solute dissolves in to create a homogenous mixture is known as a solvent.

The component that dissolves in a solvent to create a homogenous mixture is known as a solute.

M₁ is the initial concentration of HCl solution = 12.0 M

V₁ is the volume of initial HCl solution that is needed

M₂ is the final concentration of HCl solution = 1.5 M

V₂  is the final volume of HCl solution to be prepared = 3.0 L

To find V₁, we get

V₁ = (M₂ V₂) / M₁

calculating the values, we will get:

V₁ = 1.5 M x 3.0 L / 12.0 M

= 0.375 L

Therefore, tech required to take 0.375 L of the 12.0 M HCl solution and dilute it to  3.0 L to make a 1.5 M HCl solution.

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The mass of [tex]H_2[/tex] that will be formed when 35.25 g Al reacts with excess hydrochloric acid would be 3.93 g.

The equation of the reaction of aluminum metal with hydrochloric acid to produce hydrogen gas is represented below:

[tex]2Al + 6HCl -- > 2AlCl_3 + 3H_2[/tex]

From the equation, one would see that the mole ratio of aluminum to the hydrogen gas produced is 2:3.

Now, with 35.25 g of aluminum, recall that: mole = mass/molar mass.

The molar weight of aluminum is 27 g/mol.

Thus:

Mole of 35.25 g Al = 35.25/27

                                = 1.31 mol

From the mole ratio, the mole of hydrogen that will be produced would be:

3/2 x 1.31 =1.97 mol

The molar mass of [tex]H_2[/tex] is 2 g/mol, the mass of 1.97 mol hydrogen gas can be calculated as:

Mass = mole x molar mass

         = 1.97 x 2

        = 3.93 grams

In other words, the amount of [tex]H_2[/tex] that would be formed when 35.25 g All reacts with excess hydrochloric acid would be 3.93 g.

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The reaction between water and ammonium nitrate results in increase in a temperature.

Hence, Option C is the correct answer.

When ammonium nitrate is dipped in a beaker which contains the water, the beaker becomes cold because it is an endothermic reaction. The endothermic reaction is a reaction that it absorbs energy from the outside in the form of heat.

Thus we can say that hydrating ammonium nitrate is an endothermic reaction, because of that the beaker becomes cold.

We feels cold when ammonium nitrate is mixed in water that shows an endothermic reaction. In an endothermic reaction, the ammonium nitrate mixed in water, a chemical reaction occurs which absorbs heat rather than releases it.

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The final mass concentration of salt in the solution in g/l is 36.06 g/L.

The mass concentration of the mixture of the two salt solutions is calculated as follows:

Concentration of solution 1 = 15 g/l

mass of salt in the 250 mL solution = 15 g/l * 250 mL * 1 L/1000 mL

mass of salt in the 250 mL solution = 3.75 g

Concentration of solution = 6% (m/v)

This means that in 100 mL solution, 6 g of salt in present.

In 1000 mL or 1 L solution, 60 g of salt will be present.

Hence, the concentration of solution = 60 g/L

mass of salt in the 220 mL solution = 60 g/l * 220 mL * 1 L/1000 mL

mass of salt in the 220 mL solution = 13.2 g

Total mass of salt in the mixture = 16.95 g

Total volume of solution = 470 mL

Final mass concentration of solution = 16.95 g / 470 mL * 1000 mL/L

Final mass concentration of solution = 36.06 g/L

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Answer: The African savanna ecosystem is a tropical grassland with warm temperatures year-round and seasonal rainfall. The savanna is characterized by grasses and small or dispersed trees, along with a diverse community of organisms that interact to form a complex food web.

Answer:

the water freezes at a lower temperature.

Answer:

Pipes direct water from Lake Mead down to the bottom of the dam. The water picks up speed as it falls; gravitational energy turns the turbines.

Explanation:

Answer

When [tex]O_2[/tex] is converted to [tex]O_3[/tex], the kind of reaction that takes place is oxidation.

Oxidation is a type of reaction that can be defined in several ways. These include:

Oxidation is the reverse of reduction, which can be defined as:

The conversion of [tex]O_2[/tex] to [tex]O_3[/tex] requires the addition of oxygen. Thus, it is an oxidation reaction.

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Answer:

0.0878 moles CaCl₂

Explanation:

To find the amount of moles of CaCl₂, you need to

(1) convert the volume from mL to L (1,000 mL = 1 L)

(2) calculate the amount of moles (M = moles / L)

It is important to arrange the conversions in a way that allows for the cancellation of units.

(Step 1)
   

  42 mL CaCl₂                    1 L
------------------------  x  ----------------------  =  0.042 L CaCl₂
                                       1,000 mL

(Step 2)

Molarity (M) = moles / volume (L)                <----- Molarity ratio

2.09 M = moles / 0.042 L                            <----- Insert values

0.0878 = moles                                           <----- Multiply both sides by 0.042 L

A. The limiting reactant would be oxygen.

B. The mole of excess reactant ([tex]CS_2[/tex]) would be 0.67 mol.

C. 0.33 mol [tex]CO_2[/tex] and 0.67 mol [tex]SO_3[/tex]  would be formed.

Carbon disulfide burns in oxygen to produce carbon dioxide and sulfur dioxide according to the balanced equation below:

[tex]CS_2(l) + 3O_2(g) -- > CO_2(g) + 2SO_2(g)[/tex]

The mole ratio of the carbon disulfide and the oxygen gas is 1:3. In other words, every mole of [tex]CS_2[/tex] requires 3 moles of [tex]O_2[/tex] for complete combustion.

A. From the established mole ratio, if 1.00 mol of [tex]CS_2[/tex] reacts with 1.00 mol of [tex]O_2[/tex], the limiting reactant would be [tex]O_2[/tex] because 3 moles of it are required for every mole of [tex]CS_2[/tex].

B. The excess reactant is, thus, [tex]CS_2[/tex]. 1.00 mol of [tex]O_2[/tex] would require:

3 mol [tex]O_2[/tex] = 1 mol [tex]CS_2[/tex]

1 mol [tex]O_2[/tex] = 1 x 1/3

               = 0.33 mol of [tex]CS_2[/tex]

But 1 mole of [tex]CS_2[/tex] reacted. The excess mole of [tex]CS_2[/tex] would be: 1 - 0.33 = 0.67 mol.

C. From the equation of the reaction, 3 mole of oxygen produces 1 mole of [tex]CO_2[/tex]. Thus, 1 mole of oxygen would produce:

3 mol [tex]O_2[/tex] = 1 mol [tex]CO_2[/tex]

1 mol [tex]O_2[/tex] = 1 x 1/3

              = 0.33 mol [tex]CO_2[/tex]

Also, 3 mol oxygen produces 2 moles [tex]SO_2[/tex]. Then 1 mol oxygen will produce:

2 x 1/3 = 0.67 mol

Thus, 0.33 mol [tex]CO_2[/tex] and 0.67 mol [tex]SO_3[/tex] will be formed from 1 mol of [tex]O_2[/tex].

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Carbon disulfide burns in oxygen to yield carbon dioxide and sulfur dioxide according to the following chemical equation. CS2(l) + 3O2(g) → CO2(g) + 2SO2(g)

a. If 1.00 mol CS2 reacts with 1.00 mol O2, identify the limiting reactant.

b. How many moles of excess reactant remain?

c. How many moles of each product are formed?

the coefficient in front of H2O and so that you have an even number of oxygen

to balance H2O = H2 + O2 you will need to be sure to count all of H and O atoms on each side of the chemical

Answer:

Below

Explanation:

Oxygen     negative   positive    hydration

The oxygen atom in a water molecule points toward the sodium ion because its partial negative charge is attracted to the sodium ion's positive charge. This is called hydration.

In a water molecule, the oxygen atom is more electronegative than the hydrogen atoms, causing it to pull the shared electrons in the covalent bonds closer to itself. As a result, the oxygen atom gains a partial negative charge (δ-) due to the presence of these electron-rich lone pairs.

On the other hand, when sodium chloride (NaCl) or any other ionic compound dissolves in water, it dissociates into its constituent ions (Na⁺ and Cl⁻). The positively charged sodium ion (Na⁺) attracts the partial negative charge on the oxygen atom of the neighboring water molecules.

This electrostatic attraction between the partial negative charge on the oxygen atom and the positive charge on the sodium ion is called an ion-dipole interaction. It is one of the primary forces that drive the dissolution of ionic compounds in polar solvents like water.

When many water molecules surround the sodium ion, with their oxygen atoms pointing toward it and forming ion-dipole interactions, the process is called solvation or hydration. The water molecules effectively surround the sodium ion, separating it from the rest of the sodium chloride crystal and keeping it in solution. This is a crucial process in dissolving ionic compounds in water and making them available for various chemical reactions and biological processes.

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The temperature of the gas when the volume increase from 0.67 L to 1.37 L is  471.29 °C.

Temperature is the hotness or coldness of a thing or place.

To calculate the temperature in Celsius when the volume increase, we use the formula below.

Formula:

Where:

From the questuion,

Given:

Substitute these values into equation 1

Hence, the final temperature of the gas is 471.29 °C.

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The volume of I₂ gas formed when 21 L of Cl₂ gas reacts at STP is 21 L

We'll begin by writing the balanced equation for the reaction. This is shown below:

2KI(aq) + Cl₂(g) -> 2KCl(aq) + I₂ (g)

From the balanced equation above,

1 L of Cl₂ reacted to produce 1 L of I₂

With the above information, we can obtain the volume of I₂ formed when 21 L of Cl₂ react at STP as follow: :

From the balanced equation above,

1 L of Cl₂ reacted to produce 1 L of I₂

Therefore

21 L of Cl₂ will also react to produce 21 L of I₂

Thus, the volume of I₂ formed is 21 L

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Explanation:

The final volume will be 100 mL. This is because when you dilute a solution, the molarity of the solution decreases while the volume increases. Since the molarity of the original solution is 11.5 M and the desired molarity is 1.10 M, the volume must increase by a factor of 10.5 (11.5/1.10). Therefore, the final volume will be 10.0 mL x 10.5 = 100 mL.