Calculate the concentration of H3O+ ions present in a solution of HCl that has a measured pH of 1.510 .
_____M
HCl, the acid in Part 1, is a strong acid. The concentration of H3O+ ions in this solution is the same as the initial concentration of the acid.
A solution of the weak acid CH3COOH with the same initial concentration of acid will have a pH that is (Higer, lower, the same) the pH of the HCl solution.
Rank the following solutions in order of increasing acidity, placing the most acidic solution at the left. (CH3COOH is approximately 1.0% ionized at this concentration.)
pH= 0.00, pH= 7.45, [HCl]= .15M, [CH3COOH]= .15M
order of acidity
most acidic -----> least acidic

Answers

Answer 1

Solution :

The relationship between pH and [tex]$[H_3O^+]$[/tex]  is pH = [tex]$- \log [H_3O^+]$[/tex]

The concentration of [tex]$[H_3O^+]$[/tex] is given as

pH = [tex]$- \log [H_3O^+]$[/tex]

[tex]$[H_3O^+]=10^{-pH}$[/tex]

           [tex]$=10^{-1.510}$[/tex]

          [tex]$=3.09 \times 10^{-2}$[/tex]

Therefore, the concentration of [tex]$[H_3O^+]$[/tex] is [tex]$=3.09 \times 10^{-2}$[/tex]

The relationship between pH and [tex]$[H_3O^+]$[/tex]  is pH = [tex]$- \log [H_3O^+]$[/tex]

The concentration of [tex]$[H_3O^+]$[/tex] is given as

pH = [tex]$- \log [H_3O^+]$[/tex]

     [tex]$=- \log[0.15]$[/tex]

    = 0.82

Therefore, the pH of the solution is 0.82

Now updating the ICE table for 0.15 M [tex]$CH_3COOH$[/tex] is as follows :

              [tex]$CH_3COOH \ \ \ + \ \ \ H_2O \ \ \rightleftharpoons \ \ CH_3COO^- \ \ + \ \ H_3O^+$[/tex]

[tex]$I\ (M)$[/tex]           0.15                                         0                      0

[tex]$C\ (M)$[/tex]            -x                                           +x                    +x

[tex]$E\ (M)$[/tex]          0.15 - x                                      x                      x

∴ Acidionization constant,

[tex]$K_a=\frac{[CH_3COO^-][H_3O^+]}{[CH_3COOH]}$[/tex]

[tex]$1.82 \times 10^{-5}=\frac{(x)(x)}{(0.15-x)}$[/tex]

[tex]$1.82 \times 10^{-5}=\frac{x^2}{(0.15-x)}$[/tex]

We can assume that :  (0.15 - x) M = 0.15 M

[tex]$1.82 \times 10^{-5}=\frac{x^2}{0.15}$[/tex]

[tex]$x^2=1.82 \times 10^{-5} \times 0.15$[/tex]

[tex]$x^2=2.7 \times 10^{-6}$[/tex]

[tex]$x=1.7 \times 10^{-3} \ M$[/tex]

Therefore, from the equilibrium table,  [tex]$[H_3O^+] =x=1.7 \times 10^{-3} \ M$[/tex]

pH = [tex]$- \log [H_3O^+]$[/tex]

     [tex]$=- \log(1.7 \times 10^{-3} \ M)$[/tex]

     = 2.77

Hence the pH of 0.15 M  [tex]$CH_3COOH$[/tex] is 2.77

Stronger acid always have a lower pH value.

The value of pH for the given solution are 0.0, 7.45, 0.82 and 2.77

So the increasing order of the acidity is :

pH = 0.0 > pH = 0.82 (0.15 M HCl) > pH = 2.77 (0.15 M [tex]$CH_3COOH$[/tex]) > pH =7.45

Answer 2

Hydronium ion concentration can be calculated to know the pH of the solution. The increasing order of acidity is 0, 0.82, 2.77, and 7.45.

What is pH?

pH is the negative logarithm of the hydronium ion concentration. The hydronium ion concentration can be calculated as:

[tex]\begin{aligned}\rm pH &= \rm - log [H_{3}O^{+}]\\\\&= 10^{-1.510}\\\\&= 3.09 \times 10^{-2}\end{aligned}[/tex]

Thus, the hydronium ion concentration is 0.0309.

The pH when the hydronium ion concentration is 0.15, can be calculated as,

[tex]\begin{aligned}\rm pH &= \rm - log [H_{3}O^{+}]\\\\&= \rm -log (0.15)\\\\&= 0.82\end{aligned}[/tex]

Thus, the pH of the solution is 0.82.

Now the acid ionization constant is calculated using the ICE table as,

[tex]\begin{aligned}\rm K_{a} &= \rm \dfrac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}\\\\1.82 \times 10^{-5} &= \rm \dfrac{(x)(x)}{(0.15-x)}\end{aligned}[/tex]

Assuming that (0.15- x) = 0.15 M then,

[tex]\begin{aligned} 1.82 \times 10^{-5} &= \dfrac{x^{2}}{(0.15-x)}\\\\\rm x^{2} &= 2.7 \times 10^{-6}\\\\&= 1.7 \times 10^{-3}\;\rm M\end{aligned}[/tex]

Now, calculating pH of 0.15 M acetic acid is calculated as:

[tex]\begin{aligned}\rm pH &= \rm - log [H_{3}O^{+}]\\\\&= \rm -log (1.7 \times 10^{-3})\\\\&= 2.77\end{aligned}[/tex]

The stronger the acid lower will be the pH value. The pH of the solutions is 0.0, 7.45, 0.82, and 2.77.

Therefore, the correct order of the increasing acidity is 0.0 > 0.82 > 2.77 > 7.45.

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Related Questions

Water can break down to form hydrogen and oxygen gas. Balance the
equation below (hint, always balance oxygen last). What coefficients go in
the blank spaces? *

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Answer:

its 2,2,1

Explanation:

TRUE or FALSE: recessive alleles of the same gene are named with a
DIFFERENT letter than dominant alleles.

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Answer: I think it’s true

An inflated balloon is left
outside overnight.
Initially, it has a volume
of 1.74 L when the
temperature is 20.2°C and
the pressure is 1.02 atm.
At what temperature will
the balloon have a volume
of 1.56 L if the pressure
falls to 0.980 atm?
*Show all of your work*

Answers

Answer:

4.2 L

Explanation:

The final temperature of the system can be determined using combined gas law. The temperature at which the balloon has a volume of 1.56 L and pressure of 0.980 atm is 17.4 ° C.

What is combined gas law?

Combined gas law is combination of Charles's law, Boyle's law and Gay-Lussac's law. It states the relation between temperature, pressure and volume of a gas .

Thus, P V/T = a constant

Let P1, V1 and T1 be the initial pressure,volume and temperature of the gas and P2, V2 and T2 be the final values, then

P1 V1/T1 = P2 V2 /T2

Given that, P1 = 1.02 atm

V1 = 1.74 l

T1 = 20.2° C

P2 = 0.98 atm

V2 = 1.56 L

T2 = (P2 V2 T1)/ (P1 V1)

    = (0.98 × 1.56 × 20.2) /(1.74 × 1.02)

    = 17.4 ° C

Therefore, the final temperature of the system will be 17.4 ° C.

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From a cross between a short-haired guinea pig (hh) and a long-haired guinea pig (Hh), what would be the possible phenotypes of the offspring?
A. 100% will have long hair.
OB. 75% will have long hair; 25% will have short hair.
OC. 50% will have long hair; 50% will have short hair.
O D. 25% will have long hair; 75% will have short hair.

Answers

Answer:

C

Explanation:

There will be a two long hair and two short hair

For the decomposition of dinitrogen pentoxide in carbon tetrachloride solution at 30 °C , the average rate of disappearance of N2O5 over the time period from t = 0 min to t = 112 min is found to be 5.80×10^-4 M min^-1. The average rate of formation of O2 over the same time period is:__________ M min-1

Answers

Answer:

1.45 × 10⁻³ M min⁻¹

Explanation:

Step 1: Write the balanced reaction for the decomposition of dinitrogen pentoxide

2 N₂O₅(g) ⇒ 2 N₂(g) + 5 O₂(g)

Step 2: Calculate the average rate of formation of oxygen

The average rate of disappearance of N₂O₅ over the time period from t = 0 min to t = 112 min is found to be 5.80 × 10⁻⁴ M min⁻¹ (5.80 × 10⁻⁴ molN₂O₅ L⁻¹  min⁻¹). Given that the molar ratio of N₂O₅ to O₂ is 2:5, the average rate of formation of O₂ is:

5.80 × 10⁻⁴ molN₂O₅ L⁻¹  min⁻¹ × 5 molO₂/ 2 molN₂O₅ = 1.45 × 10⁻³ molO₂ L⁻¹  min⁻¹ = 1.45 × 10⁻³ M min⁻¹

Consider two bonds, A and B. Both bonds presently are selling at their par value of $1,000. Each pays interest of $120 annually. Bond A will mature in five years, while bond B will mature in eight years. If the yields to maturity on the two bonds change from 12% to 10%
a. Both bonds will decrease in value but bond B will decrease more than bond A
b. Both bonds will increase in value but bond B will increase more than bond A
c. Bond A will increase in value, but Bond B will decrease in value.
d. Both bonds will increase in value but bond B will increase more than bond A
e. Both bonds will increase in value but bond A will increase more than bond B

Answers

Answer:

The answer is "Option b"

Explanation:

The longer its maturity, therefore higher the rise in prices as the interest rate changes, therefore higher the value from both bonds, but bond B is greater than bond A.

 

What is the molarity of a solution that contains 33.5 g of CaCl, in 600.0 mL of water.
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O 0.0558 M
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Answers

I think it’s the second one

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Answer:

sever and over

Please hurry!
*URGENT* *URGENT*

Best answer gets Brainliest!!

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Consider the following container with particles of a substance within it:

Lucas likes this model to use in a report but decided to add more molecules shorten the arrows and have the particles closer together. What type of matter does Lucas actually want his graphic to portray?

A) plasma

B) gas

C) liquid

D) solid

Answers

Answer:

c. liquid

Explanation:

because the are not very close if the said very closely packed together it would have been a solid

Find the mass of 250mL of gatorade if the density of gatorade is 0.9g/mL.

Answers

Answer:

225g

Explanation:

250mL x 0.9g/mL = 225g

Answer:

225g

Explanation:

d=m/ml

m= d.ml

m=0,9g/ml.250ml

m=225g

A compound has the empirical formula CH. A sample of this
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Select one:
O
a. C6H6
b. C2H2
0
c. C3H3
O
d. C4H4

Answers

Answer: C6H6

Since we have the mass and number of Moles we can calculate the molecular weight.
n = m/M so M = m/n = 30.19/ 0.387 = 78 g/mol
For C6H6 the molecular weight is :
6 x 12 + 6 x 1= 72 + 6 = 78 g/mol
Which corresponds

Draw the mechanism for the first step in the reaction of resorcinol with ethyl acetoacetate including all proper electron pushing arrows. Use the back of this page for space as needed.

Answers

Answer:

Attached below is the required diagram .

Explanation:

During the reaction of resorcinol and ethyl acetoacetate there is the production of a transesterification product, and this transesterification product is produced in other to increase the electrophicilty of the carbonyl center.

Attached below is the required diagram .

match the vocabulary with the definitions.

1. a single compound breaks apart from two or more elements or compounds
2. two or more elements or compounds combine to form one compound.
3. a substance formed as a result of a chemical reaction.
4. one of the starting substances involved in a chemical reaction.

combination reaction
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decomposition reaction
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Answers


1: Decomposition reaction
2: Combination reaction
3: product
4: Reactant

Which structure is the naturally occurring form of glucose?

six-sided ring


multiple ring


five-sided ring


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Answers

Answer: A. Six-Sided Ring

Mixed Practice:

For questions 6-9, you may not have to use your entire flow chart. Decide where to start and end using your flow chart.



4NH3 + 5O2 → 4NO + 6H2O


MM NH3 = 17.04 g/mol; MM O2 = 32 g/mol; MM NO = 30.01 g/mol; MM H2O = 18.02 g/mol



In the above reaction, how many moles of NO are formed if 824 g of NH3 react?



27.5 mol
3510 mol
48.4 mol
774 mol

Answers

Given

Mass of NO - 824 g

Molar mass of NO - 30.01g/mol

No of moles of NO = Given mass/Molar mass

No of moles of NO = 824/30.01= 27.45 mole

Hence 27.5 moles of NO are formed!

Balanced equation: K2S(aq) + BaCl2(aq) =

Answers

Answer:

K2S(aq) + BaCl2(aq) = 2KCl(aq) + BaS(s)

In the image attached, it is explained how the solution is balanced.

The number of atoms of any element in the given chemical formula is the number that is written on the foot of the symbol of that element. The   balanced equation is

K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq)[tex]\rightarrow[/tex]2KCl(aq) + BaS(s)

What is Balanced equation?

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side.

The unbalanced equation is

K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq) [tex]\rightarrow[/tex]KCl(aq) + BaS(s)

The number of atoms of K on reactant side is 2 while on product side it is 1, so to balance K we need to multiply KCl by 2

K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq) [tex]\rightarrow[/tex]2KCl(aq) + BaS(s)

The atoms of sulfur on reactant and product side is 1, so it is balanced.

The atoms of Ba on reactant and product side is 1, so it is balanced.

The atoms of Cl on reactant and product side is 2, so it is balanced.

Therefore the balanced equation is

K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq)[tex]\rightarrow[/tex]2KCl(aq) + BaS(s)

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What is the empirical formula of a compound containing 12 g of carbon, 2 g of hydrogen, and 16 g of oxygen only

Answers

Answer:

The empirical formula=CHO. To explain it is C1H1O1 but we don't put the one that's why it is CHO

Explanation:

What is the name for a compound that forms between one Nitrogen and 3 Chlorines

Answers

in the picture below

How many formula units (particles of AgNO3) are in 5.50 grams of AgNO3?

(picture for answer choices)

Answers

Answer:

No of molcules(N)= 1.98×10^22

Explanation:

m=5.5, Mm= 167, NA= 6.02×10^23

Moles(n)= m/M= N/NA

5.5/167 = N/6.02×10^23

SIMPLIFY

N=1.98×10^22molecules

The more bonds an atom can make, the more likely it is to combine with other atoms in different ways.
Which element is most likely able to make the greatest variety of bonds?
O nitrogen
O hydrogen
O oxygen
O carbon

Answers

Answer:

carbon

Explanation:

for it has got an ideal size, neither too small nor too big

In an oxoacid such as H2SO4, ionizable hydrogen atoms are those bonded to oxygen

a. True
b. False

Answers

Answer:

true

Explanation:

Oxoacids are oxygen containing acids .The ionizable hydrogens in sulphuric acid are those bonded to the oxygen atoms. Hence, the statement is correct.

What are oxoacids?

According to Bronsted-Lowry concept acids are substances which can furnish  H+ ions when dissolved in water or on ionization. Oxoacids contains oxygen along with hydrogen atoms.

Some elements have a number of oxoacids mainly for group 15 and 16 elements. Phosphorus and sulphur have 4-5 oxoacids which differ in the number of oxygen and hydrogens.Oxoacids contains the hydroxyl group OH and the naming of oxoacids is based on the number of OH groups.

Sulphuric acid is an oxoacid of Sulphur containing 2 OH groups and two double bonded oxygens. Where the hydrogen atoms can be donated to a base to form its ionizable form .

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How many molecules are there in 0.565 moles of C6H14?

Answers

Answer:

3.4 × 10^23 molecules

Explanation:

To find the number of molecules present in C6H14, we multiply the number of moles in the compound by Avagadro's number (6.02 × 10^23 atoms).

number of molecules = number of moles (mol) × 6.02 × 10^23?

Number of molecules = 0.565 × 6.02 × 10^23

3.4 × 10^23 molecules

What type of physical weathering is caused by the expansion of water?

Answers

Answer:

Its frost wedging

Explanation:

In chemistry class, a student conducted an investigation on the factors that affect the solubility of copper (II) sulfate (CUSO) in water. The data were recorded in the following table.

Answers

Answer:

See Explanation

Explanation:

The rate of a chemical reaction depends on certain factors. Some of these factors include; surface area, temperature, nature of reactants etc.

The trial that exhibits the slowest rate of dissolution of CuSO4 crystals is trial 2 because the crystals have a small surface area since the crystals were large. Also, the solution was not agitated or stirred to increase the rate of collision between the water and the CuSO4 crystals.

Increase in temperature, agitation of the reaction solution and high surface area increases the rate of collision between the water and CuSO4 crystals leading to a faster rate of dissolution. This occurs in trial 3.

James measured the humidity of the air on his backyard each morning for four days His data is recorded below On which day did it most likely rain

Answers

Answer:

hdbdjsjsj

Explanation:

hdhshshe

How much heat is released for 98g of steam to condense?

A. -221480 J
B. +32732J
C. 35980 J
D. -32732J

Answers

The answer to this question is D

What happens to light as it passes through a convex lens?
A.The light rays bend inward
B. The light scattered
C.The light magnified
D.The light bend outward

Answers

Answer:

the answer is D

Explanation:

Rays of light that pass through the lens are brought closer together (they converge). A convex lens is a converging lens. When parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus.

A sample of liquid water at 30 c is heated until half of it boils away

Answers

Answer:

b. decreases

Explanation:

the answer is deceases

A sample of argon gas has a volume of 698.7l. The temp is decreased to 24.8c and the volume also decreases to 499.1l. What was the original temp

Answers

ASsfh 977. Hoon mein

A mixture contains 21.7 g NaCl,
3.74 g KCI, and 9.76 g Lici.
How many total moles are in this
mixture?
Molar Mass
NaCl: 58.44 g/mol
KCI: 74.55 g/mol
LiCl: 42.39 g/mol

Answers

Answer:

[tex]n_{tot}=0.652mol[/tex]

Explanation:

Hello there!

In this case, according to the given problem, it is possible to use the given molar masses of NaCl, KCl and LiCl in order to calculate the total moles, yet we calculate the moles of each salt first as shown below:

[tex]n_{NaCl}=21.7gNaCl*\frac{1molNaCl}{58.44gNaCl}=0.371molNaCl\\\\ n_{KCl}=3.74gKCl*\frac{1molKCl}{74.55KCl}=0.0502molNaCl\\\\ n_{LiCl}=9.76gLiCl*\frac{1molLiCl}{42.39gLiCl}=0.230molLiCl[/tex]

Then, we add them all together to obtain:

[tex]n_{tot}=0.371mol+0.0502mol+0.230mol\\\\n_{tot}=0.652mol[/tex]

Regards!

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