Calculate the amount of torque of an object being pushed by 6 N force along a circular path of a radius of 1x10^-2 mat 30 degree angle.

Answers

Answer 1

Answer:

The amount of torque is 0.03 N.m.

Explanation:

To find the amount of torque we need to use the following equation:

[tex] \tau = \vec {r} \times \vec{F} = rFsin(\theta) [/tex]   (1)

Where:

r: is the radius = 1x10⁻² m

F: is the force = 6 N

θ: is the angle = 30°

By entering the above values into equation (1) we have:

[tex]\tau = 1 \cdot 10^{-2} m*6 N*sin(30) = 0.03 N.m[/tex]  

Therefore, the amount of torque is 0.03 N.m.

I hope it helps you!


Related Questions

At the end of the previous experiment, aclumsy scientist drops the coil, while still in the magnetic field, and still oriented with its plane perpendicular to the magnetic field, denting it and changing its shape to a semi-circle. The new shape has the same perimeter, but a different area, and it takes 0.036s to deform. What isthe average induced EMF during this mishap

Answers

Answer:

hello your question has some missing parts below are the missing parts

A Circular, 10-turn coil has a radius of 10.7 cm and is oriented with its plane perpendicular to a 0.2-T magnetic field.

answer : 1 volt

Explanation:

Determine the Average induced EMF during this mishap

A' = A/2  ( for a semi circle )

where A = [tex]\frac{\pi r^2}{2}[/tex]

To determine the Average induced EMF apply the relation below

| E | =  η * [tex]\frac{\beta A}{T}[/tex]   ----- ( 1 )

Replace A in equation 1 with  A = [tex]\frac{\pi r^2}{2}[/tex]

hence equation becomes : | E | =  η * βπr^2 / 2T'

where : T' = 0.0365 ,  β = 0.2 , η = 10 , r = 0.107

∴| E |  = 0.999 ≈ 1volts

Fill in the graph for 50 points

Answers

Answer:

Speed: 3, 4, 5, 6. Distance: 1, 2, 3, 4, 5

Answer:

Speed: 3, 4, 5, 6. Distance: 1, 2, 3, 4, 5

Explanation:

Which of the following would produce the most power?
b
ОООО
A mass of 10 kilograms lifted 10 meters in 10 seconds
A mass of 5 kilograms lifted 10 meters in 5 seconds
A mass of 10 kilograms lifted 10 meters in 5 seconds
A mass of 5 kilograms lifted 5 meters in 10 seconds
d

Answers

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

[tex] Power = \frac {Energy}{time} [/tex]

But Energy = mgh

Substituting into the equation, we have

[tex] Power = \frac {mgh}{time} [/tex]

Given the following data;

Mass = 10kg

Height = 10m

Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

[tex] Power = \frac {10*9.8*10}{5} = 490 Watts [/tex]

Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.

BRAINLEST FOR CORRECT ANSWER PLEASE

Which has more momentum: a 3 kg sledgehammer swung at 1.5 m/s OR a 4 kg sledgehammer swung at 0.9 m/s? SHOW YOUR WORK

Answers

Answer:

Sledgehammer A has more momentum

Explanation:

Given:

Mass of Sledgehammer A = 3 Kg

Swing speed = 1.5 m/s

Mass of Sledgehammer B = 4 Kg

Swing speed = 0.9 m/s

Find:

More momentum

Computation:

Momentum = mv

Momentum sledgehammer A = 3 x 1.5

Momentum sledgehammer A = 4.5 kg⋅m/s

Momentum sledgehammer B = 4 x 0.9

Momentum sledgehammer B = 3.6 kg⋅m/s

Sledgehammer A has more momentum

Tom has a mass of 50,000 g and runs up a flight of stairs 4 m high in 12.5 seconds.
Calculate Tom’s power. (g = 10 m/s2)

Answers

Answer:

160 watts.

Explanation:

Remark

Power = Work / Time

Work = F * d

Note: Since he is running up stairs he is doing work against gravity.

Givens

m = 50000 g   kg / 1000 grmsm = 50000 / 1000 = 50 kgh = 4 mtime = 12.5 secondsg = 10 m/s^2

Formula

P = W * d/tW = m*g *d / t

Solution

P = 50kg * 10 m/s^2 * 4 m / 12.5 P = 160 watts.

A cyclist traveling at 5m/s uniformly accelerates up to 10 m/s in 2 seconds. Each tire of the bike has a 35 cm radius, and a small pebble is caught in the tread of one of them. (A) What is the angular acceleration of the pebble during those two seconds

Answers

Answer:

[tex]a=2.5\ m/s^2[/tex]

Explanation:

Given that,

Initial speed, u = 5 m/s

Final speed, v = 10 m/s

Time, t = 2 s

The radius of the tire of the bike, r = 35 cm

We need to find the angular acceleration of the pebble during those two seconds. It can be calculated as follows.

[tex]a=\dfrac{v-u}t{}\\\\a=\dfrac{10-5}{2}\\\\a=2.5\ m/s^2[/tex]

So, the required angular acceleration of the pebble is equal to [tex]2.5\ m/s^2[/tex].

A5 N object at a height has gravitational potential energy of 30 J. What is the height of the object?​

Answers

30=5×h then divide both sides by 5 you will get h=6m

If a 5 N object at a height has a gravitational potential energy of 30 J , then the height of the object would be  6 meters.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.

As given in the problem a 5 N object at a height has gravitational potential energy of 30 J, then we have to find the height of the object.

Similarly, the total gravitational  potential energy of the object,

PE = m × g × h

30  = 5 × h

h  = 30 / 5

h  = 6 meters

Thus, if a 5 N object at a height has a gravitational potential energy of 30 J, then the height of the object would be  6 meters.

To learn more about mechanical energy from here, refer to the link given below  ;

brainly.com/question/12319302

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a forward horizontal force of 50 N is applied to crate a second horizontal force of 180 N is applied to crate in the opposite direction determine the magnitude and direction of the resultant force acting on the crate

Answers

Answer:

130n on the 2nd horizontal

Explanation:

A 744 N force is applied to an object to reach an acceleration of 24 m/s2. What is the objects mass?

Answers

31kg

Explanation:

F = ma

m = F/a

m = 744N/24m/s^2

m = 31kg

(*Newton's Second Law*)

Constructive interference occurs when the crest of 2 waves meet. This can occur when 2 troughs meet as well. When this occurs, water waves look


A- the same (no change)


B- larger


C- invisible


D- smaller

Answers

Answer:

B; Larger

Explanation:

I took the K-12 quiz, and that was the correct answer. Hope this helped!

ocean currents are always cold true or false

Answers

false, since ocean currents act as conveyer belts of warm and cold water.

Which of the following parallel plate diagrams would have the greatest electric fields between them?

Answers

The greatest electric field between them is Option B.

An electric field is the physical subject that surrounds electrically charged particles and exerts a force on all other charged debris inside the area, either attracting or repelling them. It also refers back to the bodily field of a machine of charged particles.

Reasoning:-

Electric field = Kq/r²

Since the distance is inversely proportional to the square root of the distance between them. therefore decreasing the distance electric field will be the greatest. Hence Option B.

The electrical field is defined mathematically as a vector discipline that can be related to each point in space, the force in step with unit charge exerted on a fine take a look at the price at rest at that factor. the electric field is generated by the electrical rate or through time-varying magnetic fields. electric fields provide us with the pushing force we need to set off the contemporary float.

Learn more about electric fields here:-https://brainly.com/question/14372859

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Match the descriptions with the graphs !

Answers

Answer:

Graph 1 matches with B, 2 with A, and 3 with C.

Explanation:

Graph 2 shows a car whose distance part of the graph is not going up or down, while the time going up. That means that the car is stopped. Graph 1 shows a straight line, meaning that the car is traveling at a constant speed. Graph 3 is a curved line, meaning the speed of the car is changing somehow, and since the line is becoming more horizontal, the car is getting slower.

2. An object is dropped from rest. Calculate its velocity after 2.5s if it is dropped:
a.On Earth, where the acceleration due to gravity is 9.8m/s?
b. On Mars, where the acceleration due to gravity is 3.8m/s?

Answers

Answer:

a=24.5 b=9.5

Explanation:

True or false? A system must contain more than one object.

Answers

Answer:

true

Explanation:

normally -No system has ever performed well with one object.

A system must contain more than one object is a true statement.

What is system?

A system is a group of interacting or interrelated objects that act according to a set of rules to form a unified whole.

Normally, no system has ever performed well with one object.

To learn more about System here

https://brainly.com/question/24893867

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In 1994, Leroy Burrell of the United States set what was then a new world record for the men’s 100 m run. He ran the 1.00  102 m distance in 9.5 s. Assuming that he ran with a constant speed equal to his average speed, and his kinetic energy was 3.40  103 J, what was Burrell’s mass?

Answers

Answer:

61.33 Kg

Explanation:

From the question given above, the following data were obtained:

Distance = 1×10² m

Time = 9.5 s

Kinetic energy (KE) = 3.40×10³ J

Mass (m) =?

Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:

Distance = 1×10² m

Time = 9.5 s

Velocity =?

Velocity = Distance / time

Velocity = 1×10² / 9.5

Velocity = 10.53 m/s

Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:

Kinetic energy (KE) = 3.40×10³ J

Velocity (v) = 10.53 m/s

Mass (m) =?

KE = ½mv²

3.40×10³ = ½ × m × 10.53²

3.40×10³ = ½ × m × 110.8809

3.40×10³ = m × 55.44045

Divide both side by 55.44045

m = 3.40×10³ / 55.44045

m = 61.33 Kg

Thus, the mass of Leroy Burrell is 61.33 Kg


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Calculate the amount of torque of an object being pushed by 6 N force along a circular path of a radius of 1x10^-2 mat 30 degree angle

Answers

Answer:

[tex]\tau=0.03\ N-m[/tex]

Explanation:

Given that,

Force acting, F = 6N

The radius of the path, [tex]r=10^{-2}\ m[/tex]

Angle, [tex]\theta=30^{\circ}[/tex]

We need to find the amount of torque acting on the object. The formula for torque is given by :

[tex]\tau=Fr\sin\theta\\\\\tau=6\times 10^{-2}\times \sin(30)\\\\\tau=0.03\ N-m[/tex]

So, the required torque is equal to 0.03 N-m.

We observe that a moving charged particle experiences no magnetic force. From this we can definitely conclude that: (A) No magnetic field exists in that region of space. (B) The particle must be moving parallel to the magnetic field. (C) Either no magnetic field exists or the particle is moving parallel to B. (D) Either no magnetic field exists or the particle is moving vertical (perpendicular) to B.

Answers

Answer:

(C) Either no magnetic field exists or the particle is moving parallel to B.

Explanation:

The moving charged particle tends to show no magnetic forces. Due to its moving in the same direction and will be parallel to the field. As when the magnetic fed and charged particle velocity is parallel then there will be no force. As the magnetic field are made by the generation of the current with the field line concentric to the current-carrying wire.

The motor of a washing machine rotates with a period of 28 ms. What is the angular speed, in units of rad/s?

Answers

Answer:

2π/[28 x (10^-3)]

Explanation:

Angular speed : ω=2π/T

T = 28ms = 28 x (10^-3) s

Angular speed = 2π/[28 x (10^-3)]

A person drops a pebble of mass m1 from a height h, and it hits the floor with kinetic energy KE. The person drops another pebble of mass m2 from a height of 4h, and it hits the floor with the same kinetic energy KE. How do the masses of the pebbles compare

Answers

Answer:

Hello,

QUESTION)

✔ We have: KE = PE (potential energy)

PE = m x g x h

The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2  

PE1 = PE2 ⇔ PE1/PE2 = 1

[tex]\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\ \frac{m_1}{m_2\times 4} = 1 \\ \\ \frac{m_1}{m_2} = 4[/tex]

The mass m1 is therefore 4 times greater than that of the stone of mass m2.

 

If you wrap 150 coils of heavy wire around a big iron nail and attach the ends of the wire to a 6.0v battery, you have a A) radio B) electromagnet C) galvanometer D) ammeter​

Answers

Answer:

B

Explanation:

Because of the voltage attached to the iron nail

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