A compound with molecular formula C6H9No that has an amide functional group and does not have an alkene group

Answers

Answer 1

Answer:

Following are the responses to the given question:

Explanation:

[tex]\to C_6H_9NO[/tex]

calculating the HOI:

[tex]= \frac{2C+2+N-H-X}{2} \\\\ =\frac{2\times 6+2+1-9-0}{2}\\\\ =\frac{12-6}{2}\\\\=\frac{6}{2}\\\\=3[/tex]

So, in the above compund there are three bounds or we can say that one is double and two bound is single.

Please find the attachment file of the Function group:

In the above given conditon compound doesn't include the alkene functional group that is absense of[tex]-C=C-[/tex] , and compound include [tex]-C\equiv C-[/tex]  So, please find the attached file of the structure of the compound:

A Compound With Molecular Formula C6H9No That Has An Amide Functional Group And Does Not Have An Alkene

Related Questions

How many moles of gas are in a 30 liter compressed air tank if the
temperature of the tank is 300K and the pressure is 200 atmospheres? *

Answers

Answer:

B

Explanation:

i think it’s is, B, not sure though

Calculate the mass of 5.22 mol of He.

Answers

Answer:

The mass is 20, 89 grams of He.

Explanation:

We calculate the weight of 1 mol of He, from the atomic weight of each element obtained from the periodic table: Weight 1 mol He= 4, 0020602 g. 1 mol He-----4, 0020602 g. 5,22 mol He---x= (5,22 mol He x4, 0020602 g)/ 1 mol He= 20, 89 g

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The mass of 5.22 mol of He will be 20.84 grams.

We have 5.22 mol of He.

We have to calculate its Mass.

Which element is represented by symbol He ?

Helium is a chemical element with the symbol He and atomic number 2. It is a gas which is colorless, odorless, tasteless, non-toxic, inert and monatomic.

According to the question -

Number of moles of Helium = 5.22 mol

Now, I mole of Helium will have its mass equal to its Atomic weight. Therefore -

Mass of 1 mole of He = 4.002602 g

So, the mass of 5.2 mol of He will be = 5.2 x 4.002602 = 20.84 grams

Hence, the mass of 5.22 mol of He will be 20.84 grams.

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