Calculate all four second-order partial derivatives and check that . Assume the variables are restricted to a domain on which the function is defined.

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Answer 1

The function is defined on the given domain, we need to make sure that all the partial derivatives are defined and continuous within the domain.

To calculate the four second-order partial derivatives, we need to differentiate the function twice with respect to each variable. Let's denote the function as f(x, y, z).

The four second-order partial derivatives are:
1. ∂²f/∂x²: Differentiate f with respect to x twice, while keeping y and z constant.
2. ∂²f/∂y²: Differentiate f with respect to y twice, while keeping x and z constant.
3. ∂²f/∂z²: Differentiate f with respect to z twice, while keeping x and y constant.
4. ∂²f/∂x∂y: Differentiate f with respect to x first, then differentiate the result with respect to y, while keeping z constant.

To check that the function is defined on the given domain, we need to make sure that all the partial derivatives are defined and continuous within the domain.

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Related Questions

Angie is working on solving the exponential equation 23^x =6; however, she is not quite sure where to start

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To solve the exponential equation 23ˣ = 6, Angie can use the equation x = ln(6) / ln(23) to find an approximate value for x.

To solve the exponential equation 23ˣ = 6, you can follow these steps:

Step 1: Take the logarithm of both sides of the equation. The choice of logarithm base is not critical, but common choices include natural logarithm (ln) or logarithm to the base 10 (log).

Using the natural logarithm (ln) in this case, the equation becomes:

ln(23ˣ) = ln(6)

Step 2: Apply the logarithmic property of exponents, which states that the logarithm of a number raised to an exponent is equal to the exponent multiplied by the logarithm of the number.

In this case, we can rewrite the left side of the equation as:

x * ln(23) = ln(6)

Step 3: Solve for x by dividing both sides of the equation by ln(23):

x = ln(6) / ln(23)

Using a calculator, you can compute the approximate value of x by evaluating the right side of the equation. Keep in mind that this will be an approximation since ln(6) and ln(23) are irrational numbers.

Therefore, to solve the equation 23ˣ = 6, Angie can use the equation x = ln(6) / ln(23) to find an approximate value for x.

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13. Find the sum of the arithmetic

sequence 4, 1, -2, -5,. , -56.

-777-3,3-3,

A

B

-546

C -542

D -490

Answers

The sum of the arithmetic sequence is -468 (option D).

To find the sum of an arithmetic sequence, we can use the formula:

Sum = (n/2) * (first term + last term)

In this case, the first term of the sequence is 4, and the common difference between consecutive terms is -3. We need to find the last term of the sequence.

To find the last term, we can use the formula for the nth term of an arithmetic sequence:

last term = first term + (n - 1) * common difference

In this case, the last term is -56. We can use this information to find the number of terms (n) in the sequence:

-56 = 4 + (n - 1) * (-3)

-56 = 4 - 3n + 3

-56 - 4 + 3 = -3n

-53 = -3n

n = -53 / -3 = 17.67

Since the number of terms should be a whole number, we round up to the nearest whole number and get n = 18.

Now, we can find the sum of the arithmetic sequence:

Sum = (18/2) * (4 + (-56))

Sum = 9 * (-52)

Sum = -468

Therefore, the sum of the arithmetic sequence is -468 (option D).

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Suppose that in a particular sample, the mean is 50 and the standard deviation is 10. What is the z score associated with a raw score of 68?

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The z-score associated with a raw score of 68 is 1.8.

Given mean = 50 and standard deviation = 10.

Z-score is also known as standard score gives us an idea of how far a data point is from the mean. It indicates how many standard deviations an element is from the mean. Hence, Z-Score is measured in terms of standard deviation from the mean.

The formula for calculating the z-score is given as

z = (X - μ) / σ

where X is the raw score, μ is the mean and σ is the standard deviation.

In this case, the raw score is X = 68.

Substituting the given values in the formula, we get

z = (68 - 50) / 10

z = 18 / 10

z = 1.8

Therefore, the z-score associated with a raw score of 68 is 1.8.

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