C3H5N3O9(s) --> N2(g) + CO2(g) + H2O(g) + O2(g) Solid nitroglycerine explodes when heated, producing several different gases (according to the reaction above). If a government scientist explodes 777 g of nitroglycerine, How many grams of each gas should be produced? How many molecules of each gas will be produced?

Answers

Answer 1

Answer:

- 143.6 g of N₂ ; 3.08×10²⁴ molecules of N₂

- 451.4 g of CO₂ ; 6.17×10²⁴ molecules of CO₂

- 153.9 g of H₂O ; 5.14×10²⁴ molecules of H₂O

- 27.3 g of O₂ ; 5.14×10²³ molecules of O₂

Explanation:

This is a reaction of decomposition:

4C₃H₅N₃O₉(s)  →  6N₂(g)  +  12CO₂(g)  +  10H₂O(g)  +  O₂(g)

4 moles of solid nitroglycerine decompose to 6 moles of nitrogen, 12 moles of carbon dioxide, 10 moles of water vapor and 1 mol of oxygen

We convert mass to moles → 777 g. 1mol/ 227g = 3.42 moles

4 moles of C₃H₅N₃O₉ can decompose to:

6 moles of N₂ ____  12 moles of CO₂ ___ 10 moles of H₂O ___ 1 mol of O₂

Then, 3.42 moles of C₃H₅N₃O₉ may decompose to:

(3.42 . 6) / 4  =  5.13 moles of N₂

(3.42 . 12) / 4 = 10.26 moles of CO₂

(3.42 . 10) / 4 = 8.55 moles of water vapor

(3.42 . 1) / 4 = 0.855 moles of oxygen

We convert the moles to mass:

5.13 mol . 28 g/mol = 143.6 g of N₂

10.26 mol . 44 g/mol = 451.4 g of CO₂

8.55 mol . 18 g/mol = 153.9 g of H₂O

0.855 mol . 28 g/mol = 27.3 g of O₂

We count the atoms:

5.13 mol . 6.02×10²³ molecules /mol = 3.08×10²⁴ molecules of N₂

10.26 mol . 6.02×10²³ molecules /mol = 6.17×10²⁴ molecules of CO₂

8.55 mol . 6.02×10²³ molecules /mol = 5.14×10²⁴ molecules of H₂O

0.855 mol . 6.02×10²³ molecules /mol = 5.14×10²³ molecules of O₂


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i took the test

A reaction which is exothermic and results in an increase in the entropy of the system is said to be always spontaneous. A spontaneous reaction is one that produces heat. The correct option is D.

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A process which has an urge or a natural tendency to occur under a given set of conditions is defined as the spontaneous process. Some of the spontaneous process need no initiation, they take by themselves. Dissolution of common salt in water, evaporation, etc. are examples.

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Balance your chemical reaction first. Start by balancing carbon so you have 2 carbons on both sides.

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However, you can’t have a decimal in a coefficient. So, multiply everything by two.

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Explanation:

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Answer:

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Answer:

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Please help!
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Answers

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please if you know help
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Answers

Answer: a. 249.5 g/mol

b. 1.996 g

c. Measure 1.996 g of [tex]CuSO_4.5H_2O[/tex] and dissolve in water until the volume is 400 ml

Explanation:

Molar mass is the sum of atomic masses of all the elements present.

Thus molar mass of [tex]CuSO_4.5H_2O[/tex] = 1(63.5)+1(32)+4(16)+5(18) = 249.5 g/mol

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To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{given mass of solute}\times 1000}{\text {Molar mass of solute}}\times \text{Volume of solution in ml}}[/tex]

[tex]0.02mol/L=\frac{x\times 1000}{249.5g/mol\times 400}[/tex]

[tex]x=1.996 g[/tex]

c. We need to measure 1.996 g of [tex]CuSO_4.5H_2O[/tex] and dissolve it in water to make the volume 400 ml.

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The balanced chemical equation is:

[tex]C_{25}H_{52}+38O_2\rightarrow 25CO_2+26H_2O[/tex]

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