Breinor needed some school supplies to finish out the year. His mom bought him a 3-pack of pens for $3.59, a pack of highlighters for $5.15, and two notebooks for a $1.99 each. The sales tax is 8%. What was the total price she paid including tax? $12.72
$12.72

$13.74
$13.74

$10.73
$10.73

$11.59

Step-by-step explanation:

With the quadratic equation in this form: [tex]ax^2+bx+c=0[/tex]

Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.

Example: 2x^2 + 7x + 3

ac is 2×3 = 6 and b is 7

So we want two numbers that multiply together to make 6, and add up to 7

In fact 6 and 1 do that (6×1=6, and 6+1=7)

How do we find 6 and 1?

It helps to list the factors of ac=6, and then try adding some to get b=7.

Factors of 6 include 1, 2, 3 and 6.

1 and 6 add to 7, and 6×1=6.

Step 2: Rewrite the middle with those numbers:

Rewrite 7x with 6x and 1x:

2x^2 + 6x + x + 3

Step 3: Factor the first two and last two terms separately:

The first two terms 2x^2 + 6x factor into 2x(x+3)

The last two terms x+3 don't actually change in this case

So we get:

2x(x+3) + (x+3)

Step 4: If we've done this correctly, our two new terms should have a clearly visible common factor.

In this case we can see that (x+3) is common to both terms, so we can go:

Start with: 2x(x+3) + (x+3)

Which is: 2x(x+3) + 1(x+3)

And so: (2x+1)(x+3)

Done!

Check: (2x+1)(x+3) = 2x2 + 6x + x + 3 = 2x2 + 7x + 3 (Yes)

Please Mark As Brainliest

Answer:

x int. (-1,0) and (-2,0).   y-int,(0,10)

Step-by-step explanation:

y-int. it's 10 because the y-int is always the c value.

x-int.

x=-b±√b²-4ac/2a

x=-15±√15²-4(5)(10)/2(5)

x=-15±√225-200/10

x=-15±√25/10

x= -15+5/10.      x=-15-5/10

x=-10/10.           x=-20/10

x=-1.                  x=-2

Answer:

The first 3 installments of Mr. X were $ 180.

Step-by-step explanation:

Since Mr X arranges to pay off a Debt of $ 9600 in 48 annual installments which form an AP, and when 40 of these installments are paid, Mr X become insolvent, and he still owe his creditor $ 2400, to find the value of each of the first three installments of Mr X the following calculation must be performed:

((9,600 - 2,400) / 40) = X

7,200 / 40 = X

180 = X

Therefore, the first 3 installments of Mr. X were $ 180.

Answer:

false is the correct answer right

Answer:

4600 grams of peanuts

Step-by-step explanation:

For 2 kg of peanuts the customer will get 300 g free.

So if 4 kg of peanuts the customer will get 600 g free.

1kg = 1000g

If 4kg, thus it is 4000g

All mass of peanut the customer gets is 4000g + 600g = 4600g of peanuts.

Answer:

0.5 cm

Step-by-step explanation:

Answer:

71

Step-by-step explanation:

if you add 15+15+11+11+19 you will be getting 71

Answer:

80

Step-by-step explanation:

20+80+x=180

100+x=180

x=180-100

x=80

plz mark as brainliest

Answer:

The solution of given expression = 5 , -3

Step-by-step explanation:

Given expression;

15 - 4x = x² - 6x

Find:

The solution of given expression

Computation:

15 - 4x = x² - 6x

x² - 6x + 4x - 15 = 0

x² - 2x - 15 = 0

x² - (5 - 3)x - 15 = 0

x² - 5x + 3x - 15 = 0

x(x - 5) + 3(x - 5) = 0

(x - 5)(x + 3) = 0

So,

x - 5 = 0 and x + 3 = 0

x = 5 and x = -3

The solution of given expression = 5 , -3

the is going to be x=3 43- 35 =18

may be that the way it should be

Answer:

29 IS THE ANSWER PLEASE MARK AS BRAIN IST

Step-by-step explanation:

Answer:

[tex]r=3\\h=5\\\\8r+h\\= 8(3) + (5)\\= 24 + 5\\= 29[/tex]

Answer:

x= -7

Step-by-step explanation:

Answer:

-7

Step-by-step explanation:

-19x+32=-24x-3

-19x+24x=-3-32

5x=-35

X=-35/5= -7

Answer: A, C, D

Step-by-step explanation:

A is correct because Audrey reads 40 pages a day, and David reads 20. When you divide 40 by 20, you get 2. This means that 2 times 20 would be 40, and anything multiplied by 2 is "twice".

40 ÷ 20 = 2

2 × 20 = 40

B is not correct because after 6 days, Audrey reads 240 pages, and David reads only 120. We can figure this out by multiplying the pages read by 6.

Audrey: 40 × 6 = 240

David: 20 × 6 = 120

C is correct because when you subtract 20 from 40, you get 20. Since Audrey reads 40 pages a day and David reads 20, you can use this equation: 40-20 to figure the answer out. Audrey reads 20 more pages every day.

[tex]40-20=20[/tex]

D is correct because after 2 days, Audrey will have read 80 pages, and David will have read 40 pages. When you subtract 40 from 80, you get 40 pages.

40 × 2 = 80

20 × 2 = 40

80 - 40 = 40

E is not correct because, after 3 days, Audrey will have read 120 pages, and David will have read 60 pages. One-third of 120 is 40, not 60. Three times 60 would be 180, not 120. So, This answer is incorrect.

Answer:

(x-8)² or (x-8)(x-8)

Step-by-step explanation:

x^2-16x+64

x^2 -8x -8x +64

x (x-8) - 8(x-8)

(x-8) (x-8)

(x-8)^2

Answer:

the slope is 1.75

Step-by-step explanation:

Interpretation: The weight of newborn is 6 lb at birth, and every month baby gained 1.75 lb. You replace x with month you want to know the weight.  For example you can calculate the weight after 4 month : w= 1.75(4)+6= 13 lb

Answer:

Step-by-step explanation:

to find the answer you will want to gather the indenpent varible and dependent varrible. SO when you look at the problem you see 25%. You have to find the amount of money on each thing they bought. The budget and how much  they have to spend.

Answer:

The  sequence  is:

10, 30, 50, 70, 90.....................

Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

Sum of first 5 terms ([tex]S_{5}[/tex]) = 250

or, [tex]\frac{n}{2} [{2a+(n-1)d}] = 250[/tex]

or, [tex]\frac{5}{2} [2*10 + 4d]=250[/tex]

or, [tex]\frac{5}{2} * 4[5+d]=250[/tex]

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

Answer:

(a) Name: Multinomial distribution

Parameters: [tex]p_1 = 5\%[/tex]   [tex]p_2 = 85\%[/tex]   [tex]p_3 = 10\%[/tex]  [tex]n = 20[/tex]

(b) Range: [tex]\{(x,y,z)| x + y + z=20\}[/tex]

(c) Name: Binomial distribution

Parameters: [tex]p_1 = 5\%[/tex]      [tex]n = 20[/tex]

[tex](d)\ E(x) = 1[/tex]   [tex]Var(x) = 0.95[/tex]

[tex](e)\ P(X = 1, Y = 17, Z = 3) = 0[/tex]

[tex](f)\ P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]

[tex](g)\ P(X \le 1) = 0.7359[/tex]

[tex](h)\ E(Y) = 17[/tex]

Step-by-step explanation:

Given

[tex]p_1 = 5\%[/tex]

[tex]p_2 = 85\%[/tex]

[tex]p_3 = 10\%[/tex]

[tex]n = 20[/tex]

[tex]X \to[/tex] High Slabs

[tex]Y \to[/tex] Medium Slabs

[tex]Z \to[/tex] Low Slabs

Solving (a): Names and values of joint pdf of X, Y and Z

Given that:

[tex]X \to[/tex] Number of voids considered as high slabs

[tex]Y \to[/tex] Number of voids considered as medium slabs

[tex]Z \to[/tex] Number of voids considered as low slabs

Since the variables are more than 2 (2 means binomial), then the name is multinomial distribution

The parameters are:

[tex]p_1 = 5\%[/tex]   [tex]p_2 = 85\%[/tex]   [tex]p_3 = 10\%[/tex]  [tex]n = 20[/tex]

And the mass function is:

[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]

Solving (b): The range of the joint pdf of X, Y and Z

Given that:

[tex]n = 20[/tex]

The number of voids (x, y and z) cannot be negative and they must be integers; So:

[tex]x + y + z = n[/tex]

[tex]x + y + z = 20[/tex]

Hence, the range is:

[tex]\{(x,y,z)| x + y + z=20\}[/tex]

Solving (c): Names and values of marginal pdf of X

We have the following parameters attributed to X:

[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]

Hence, the name is: Binomial distribution

Solving (d): E(x) and Var(x)

In (c), we have:

[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]

[tex]E(x) = p_1* n[/tex]

[tex]E(x) = 5\% * 20[/tex]

[tex]E(x) = 1[/tex]

[tex]Var(x) = E(x) * (1 - p_1)[/tex]

[tex]Var(x) = 1 * (1 - 5\%)[/tex]

[tex]Var(x) = 1 * 0.95[/tex]

[tex]Var(x) = 0.95[/tex]

[tex](e)\ P(X = 1, Y = 17, Z = 3)[/tex]

In (b), we have: [tex]x + y + z = 20[/tex]

However, the given values of x in this question implies that:

[tex]x + y + z = 1 + 17 + 3[/tex]

[tex]x + y + z = 21[/tex]

Hence:

[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]

[tex](f)\ P{X \le 1, Y = 17, Z = 3)[/tex]

This question implies that:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) + P(X = 1, Y = 17, Z = 3)[/tex]

Because

[tex]0, 1 \le 1[/tex] --- for x

In (e), we have:

[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]

So:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) +0[/tex]

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]

In (a), we have:

[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]

So:

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{0! * 17! * 3!} * (5\%)^0 * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{1 * 17! * 3!} * 1 * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{17! * 3!} * (85\%)^{17} * (10\%)^{3}[/tex]

Expand

[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18*17!}{17! * 3*2*1} * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18}{6} * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = 20*19*3 * (85\%)^{17} * (10\%)^{3}[/tex]

Using a calculator, we have:

[tex]P(X=0; Y=17; Z = 3) = 0.07195[/tex]

So:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]

[tex]P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]

[tex](g)\ P(X \le 1)[/tex]

This implies that:

[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]

In (c), we established that X is a binomial distribution with the following parameters:

[tex]p_1 = 5\%[/tex]      [tex]n = 20[/tex]

Such that:

[tex]P(X=x) = ^nC_x * p_1^x * (1 - p_1)^{n - x}[/tex]

So:

[tex]P(X=0) = ^{20}C_0 * (5\%)^0 * (1 - 5\%)^{20 - 0}[/tex]

[tex]P(X=0) = ^{20}C_0 * 1 * (1 - 5\%)^{20}[/tex]

[tex]P(X=0) = 1 * 1 * (95\%)^{20}[/tex]

[tex]P(X=0) = 0.3585[/tex]

[tex]P(X=1) = ^{20}C_1 * (5\%)^1 * (1 - 5\%)^{20 - 1}[/tex]

[tex]P(X=1) = 20 * (5\%)* (1 - 5\%)^{19}[/tex]

[tex]P(X=1) = 0.3774[/tex]

So:

[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]

[tex]P(X \le 1) = 0.3585 + 0.3774[/tex]

[tex]P(X \le 1) = 0.7359[/tex]

[tex](h)\ E(Y)[/tex]

Y has the following parameters

[tex]p_2 = 85\%[/tex]  and    [tex]n = 20[/tex]

[tex]E(Y) = p_2 * n[/tex]

[tex]E(Y) = 85\% * 20[/tex]

[tex]E(Y) = 17[/tex]

Answer:

600 or 16

Step-by-step explanation:

Answer:

A high school drama club is selling tickets for a fundraiser event. Based on data from past events, the number of tickets sold can be modeled by a linear function Q(x)=-40x+640, where x is the price, in dollars, of each ticket.

Answer:

H0: μ ≤ 1.30

H1: μ > 1.30

|Test statistic | > 1.833 ; Reject H0

Test statistic = 3.11

Yes

Pvalue = 0.006

Step-by-step explanation:

H0: μ ≤ 1.30

H1: μ > 1.30

Samples, X ; 1.36,1.35,1.33, 1.66, 1.58, 1.32, 1.38, 1.42, 1.90, 1.54

Xbar = 14.84 / 10 = 1.484

Standard deviation, s = 0.187 (calculator)

Decison rule :

|Test statistic | > TCritical ; reject H0

df = n - 1 = 10 - 1 = 9

Tcritical(0.05; 9) = 1.833

|Test statistic | > 1.833 ; Reject H0

Test statistic :

(xbar - μ) ÷ (s/√(n))

(1.484 - 1.30) ÷ (0.187/√(10))

0.184 / 0.0591345

Test statistic = 3.11

Since ;

|Test statistic | > TCritical ; We reject H0 and conclude that water consumption has increased

Pvalue estimate using the Pvalue calculator :

Pvalue = 0.006

Answer:

55 in²

Step-by-step explanation:

Base x Height

Answer:

[tex]x_2 - x_1 = 1[/tex] gives [tex]y_2 - y_1 = 4[/tex]

Step-by-step explanation:

Given

[tex]y = 4x[/tex]

[tex](x_1,x_2) = (x,x+1)[/tex]

Required

Show that the y values increases by 4 for [tex]x_2 - x_1 = 1[/tex]

We have:

[tex]y = 4x[/tex]

For [tex]x_1 = x[/tex]

[tex]y_1 = 4x_1[/tex]

Substitute [tex]x_1 = x[/tex]

[tex]y_1 = 4x[/tex]

For [tex]x_2 = x + 1[/tex]

[tex]y_2 = 4x_2[/tex]

Substitute [tex]x_2 = x + 1[/tex]

[tex]y_2 = 4(x+1)[/tex]

[tex]y_2 = 4x+4[/tex]

So, we have:

[tex]y_2 = 4x+4[/tex]

[tex]y_1 = 4x[/tex]

Subtract [tex]y_1[/tex] from [tex]y_2[/tex]

[tex]y_2 - y_1 = 4x + 4 - 4x[/tex]

Collect like terms

[tex]y_2 - y_1 = 4x - 4x+ 4[/tex]

[tex]y_2 - y_1 = 4[/tex]

Hence:

[tex]x_2 - x_1 = 1[/tex] gives [tex]y_2 - y_1 = 4[/tex]

i.e. an increment of 4

Answer:

e. a and b only

Step-by-step explanation:

Question - A lambda expression is typically used ?

Solution -

The correct option is - e. a and b only

Reason -

As we know that, lambda expression is used to define anonymous function object.

So,

It is used when the function is short or the function is simple.

And it is used for the functions that are only used once.

So,

a. for functions that are only used once

b. for simple functions

a and b both parts are correct.

So,

The correct option is - e. a and b only

Answer:

qwetyuookvxscv

fdfhputetu you ggvkpr

fhhjkkpopuu

Answer:

parallelogram

Step-by-step explanation:

opposite sides are parallel and equal

Answer:

B. 2

Step-by-step explanation:

The precision of a scientific measuring tool can be defined as how close the values between multiple measurements are to each other, when repeated under the same conditions.

This ultimately implies that, the precision of a scientific measuring tool reflects the reproducibility and repeatability of its measurements, irrespective of how accurate the measurements are.

In science, one of the most effective ways to determine the precision of a scientific measuring tool is to find the difference between the highest and lowest measurements (measured values).

Given the following number; 16.82

The last digit "2" in 16.82 represents the hundredth value and should be used to determine the level of precision of the number.