I need help plsss help

Answer:[tex]h=\sqrt{96}in.[/tex]

Step-by-step explanation:

.

Answer:

2.

3p+15−8+11p

=3p+15+−8+11p

Combine Like Terms:

=3p+15+−8+11p

=(3p+11p)+(15+−8)

=14p+7

Answer:

=14p+7

3.

Let's simplify step-by-step.

14p+15−8

=14p+15+−8

Combine Like Terms:

=14p+15+−8

=(14p)+(15+−8)

=14p+7

Answer:

=14p+7

4. Factor 14p+7

14p+7

=7(2p+1)

Answer:

7(2p+1)

Answer:

A. x= -5

B. x= 8

Step-by-step explanation:

A. 25 - 3x = 40

-3x = 40 - 25

-3x = 15

x= 15/-3

x= -5

B. 2 (x-10) =  -4

x-10 = -4/2

x-10 = -2

x = 8

A. 25 - 3x = 40

         -3x = 40 - 25

               = 15

            -x = 15/3

             x = -5

   Checking

    25 - 3*-5 = 40

    25 + 15 = 40

            40 = 40

       LHS = RHS

B. 2(x-10) = -4

    2x - 20 = -4

            2x = -4 +20

             x = 16/2 = 8

Hope u understand

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Thank You

Answer:

18

Step-by-step explanation:

mark me as

brainliest

18

Answer:

144 ounces

Step-by-step explanation:

Answer:

48 1/4 packages

Step-by-step explanation:

Answer:

Step-by-step explanation:

Was the latter half of this function, -64 / 2x + 14, meant to be:

-64 / 2x              +              14, or

-64 / (2x + 14)?

In the first case the vertical asymptote is x = 0.

In the second, the vertical asymptote is the root of 2x + 14, or x = -7

Use parentheses in problems such as this one, to eliminate ambiguity.

Answer:

(20, -2)

Step-by-step explanation:

Given the coordinate vectors p=(4,3) and q=(-2,7),

4p - 2q  = 4(4, 3)- 2(-2, 7)

4p - 2q  = (16, 12) - (-4, 14)

4p - 2q  = (16+4, 12-14)

4p - 2q  =(20, -2)

hence the required vector is (20, -2)

Answer:

When the dimensions of the shape, such as radius, height, or length change, both surface area and volume also change. However, the volume of the object always changes more than the surface area for the same change in dimensions.

Step-by-step explanation:

Consider LHS

[tex] \cos(x) + \sin(x) \tan(x) = \sec(x) [/tex]

Apply quotient identies

[tex] \cos(x) + \sin(x) \times \frac{ \sin(x) }{ \cos(x) } = \sec(x) [/tex]

Multiply the fraction and sine.

[tex] \cos(x) + \frac{ \sin {}^{2} (x) }{ \cos(x) } = \sec(x) [/tex]

Make cos x a fraction with cos x as it denominator.

[tex] \cos(x) \times \cos(x) = \cos {}^{2} (x) [/tex]

so

[tex] \frac{ \cos {}^{2} (x) }{ \cos(x) } + \frac{ \sin {}^{2} (x) }{ \cos(x) } = \sec(x) [/tex]

Pythagorean Identity tells us sin squared and cos squared equals 1 so

[tex] \frac{1}{ \cos(x) } = \sec(x) [/tex]

Apply reciprocal identity.

[tex] \sec(x) = \sec(x) [/tex]

Answer:

B,E

Step-by-step explanation:

(5,0) (5=x, 0=y)

A is false because y = 0

B is true because x=5

c is false because y = 0

D is false because again y = 0

E is true because 5,0 is on the x axis

- Gage Millar, Algebra 2 tutor

Answer:

92.5

Step-by-step explanation:

you would add 90+95 which is 185 then divide that by 2 to get ur answer

Answer:

See the three attached images.

Step-by-step explanation:

image1 shows the intersection of b and c:  [tex]b \cap c[/tex]. (green "football")

image2 shows the complement of a (outside a):  [tex]a'[/tex]  (yellow)

image3 shows the intersection of those sets:  [tex]a'\cap (b\cap c)[/tex] (green "football with a bite out of it")   :-)

Answer:

1.6$

Step-by-step explanation:

6.4/4=1.6

Answer:

plz mark brainliest

Answer:12345678910

Step-by-step explanation:

Answer:

ans = <ebc= 115°

hope this will help

.

.

Answer:

x=0

y= x + 8

Step-by-step explanation:

find the oblique asymptotes using long polynomial divison

Answer:

The answer is: u-3>-6

This is because 10-3=7 and 7>-6

Answer:

1/2

Step-by-step explanation:

total marbles 6

white marbles 3

white marbles/ total = 3/6

simply 1/2

Step-by-step explanation:

total marbles 6

white marbles 3

white marbles/total =3/6

simply 1/2

Answer:

16.28 squared inches

Step-by-step explanation:

Use the formula A = bh.

b = base

h = height

A = (4.4) (3.7)

A = 16.28

Answer:

 ^^

Step-by-step explanation:

Answer:

You didn't add the range. I'll use (0<x<2π)

cosx = -1/2

x=-cos-¹(1/2)

x= -60°

Cosine is negative in the second and 3rd quadrants

180-x ---- Second quadrant

x+180 ----- 3rd quadrant

So

Our answer

180-(-60)=240° or 4π/3 second quad

180+(-60) = 120° or 2π/3---- 3rd quad

Answer:

Area of a circle = πr^2 if pi here = 3

then (3 × 81) in^2 = 243 in^2

Hope it helps

Answer:

The area of circle is 254.34 in².

Step-by-step explanation:

Given :

To Find :

Using Formulas :

[tex]\star{\small{\underline{\boxed{\sf{\pink{R = \dfrac{D}{2}}}}}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\pink{Area_{(Circle)} = \pi{r}^{2} }}}}}}[/tex]

Solution :

Here we have given that diameter of circle is 18 in. So, finding the radius of circle :

[tex]\implies{\sf{Radius = \dfrac{D}{2}}}[/tex]

[tex]\implies{\sf{Radius = \dfrac{18}{2}}}[/tex]

[tex]\implies{\sf{Radius = \cancel{\dfrac{18}{2}}}}[/tex]

[tex]\implies{\sf{Radius = 9 \: in}}[/tex]

[tex]\star{\underline{\boxed{\sf{\red{Radius = 9 \: in}}}}}[/tex]

Hence, the radius of circle is 9 in.

[tex]\rule{200}2[/tex]

Now, we know the radius of circle is 9 in. So, finding the area of circle by substituting the values in the formula :

[tex]\implies{\sf{Area_{(Circle)} = \pi{r}^{2}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = 3.14\times {(9)}^{2}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = 3.14\times {(9 \times 9)}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = 3.14\times (81)}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = \dfrac{314}{100} \times 81}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = \dfrac{314 \times 81}{100}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = \dfrac{25434}{100}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = 254.34 \: {in}^{2} }}[/tex]

[tex]{\star{\underline{\boxed{\sf{\red{Area_{(Circle)} = 254.34 \: {in}^{2}}}}}}}[/tex]

Hence, the area of circle is 254.34 in².

[tex]\rule{300}{1.5}[/tex]

Answer:

163/500

Step-by-step explanation:

we will not only clearly explain how to get the answer to 0.326 as a fraction, but also prove to you that our answer is correct.

First, note that 1000 multiplied by .326 will get rid of the decimal point. Therefore, make a fraction where the numerator is .326 times 1000 and denominator is 1000 like this:

.326 x 1000

1000

Next, multiply the numbers in the numerator together and keep the denominator as is. Now our fraction looks like this:

326

1000

The greatest common factor of 326 and 1000 is 2, which means you can divide the numerator and denominator by 2 and keep the same value:

326 ÷ 2

1000 ÷ 2

And when calculating the numerator and denominator in our fraction above, we get .326 as a fraction in the simplest form possible:

.326 =

163

500

Answer:

It would be the fourth one

Step-by-step explanation:

Answer:

Las ganancias totales de la empresa B en dicho año fueron de $51.532,90.

Step-by-step explanation:

Dado que una empresa A gana $42.758,35 en un año, y si la empresa B gastara $8.774,55 tendría tantas ganancias como la primera empresa, para determinar cuál es la ganancia total de la empresa B se debe realizar el siguiente calculo:

Ganancias B - 8.774,55 = 42.758,35

Ganancias B = 42.758,35 + 8.774,55

Ganancias B = 51.532,90

Por lo tanto, las ganancias totales de la empresa B en dicho año fueron de $51.532,90.

Step-by-step explanation:

-2(x + 3) = 2x - (5 – x)

-2x+6= 2x-5+x

-2x+6=3x-5

-2x-3x=-5-6

-5x=-11

x= 11/5

( 1 solution)

Answer:

Solution given:

-2(x + 3) = 2x - (5 – x)

-2x-6=2x-5+x

-6+5=2x+2x+x

5x=-1

x=[tex] \frac{-1}{5} [/tex]

It has one Solution.

Answer:

x = 11

Step-by-step explanation:

Since we are given triangle PQR is similar to triangle PTU, we can write a proportion to connect the side lengths:

PQ / PT = QR / TU = PR / PU

We don't really care about QR and TU because the are irrelevant to the problem, so we can remove them:

PQ / PT = PR / PU

Now, we can substitute the values given by the diagram:

70 / 30 = 49 / (x + 10)

We can cross multiply,

70(x + 10) = 30 * 49

And divide by 70 on both sides(too lazy to multiply :P)

x + 10 = 3 * 7

x + 10 = 21

x = 11