Answer: A School (I made this 2 years ago for a project, I didn't feel like making a new analogy)
1. Nucleus: Principle because they control the school.
2. Cytoplasm: Water pipes because they constantly move and have water in it.
3. Cell Membrane: The doors to the school because they let things in and out.
4. Lysosome: The trash and the janitors because they dispose of everything.
5. Mitocondria: The power lines because they provide/create the energy.
6. Ribosome: The teachers because they are assembled by the “principle” and give the proteins which is the knowledge.
7. Vacuoles: The closets because they store the materials.
8. Endoplasmic Reticulum: The hallways because it allows to move from one place to another.
9. Golgi Bodies: The conference room because they make the AKS perfect and send it to the teachers.
determine the number of moles of sulfur are present in 34.68 of disulfur pentoxide
plz show how you got your answer
Answer:
0.4816 mol S
Explanation:
I'm going to answer this question under the assumption that the question is how many moles of sulfur are present in 34.68 grams of disulfur pentoxide.
The molecular formula of disulfur pentoxide is S₂O₅ (di means two and penta means five).
Now we convert 34.68 g of S₂O₅ into moles, using its molar mass:
34.68 g ÷ 144 g/mol = 0.2408 moles S₂O₅Then we convert moles of S₂O₅ into moles of S, given that there are two moles of S per S₂O₅ mol:
0.2408 moles S₂O₅ * [tex]\frac{2molS}{1molS_2O_5}[/tex] = 0.4816 mol SWhich one is not an ore of copper
1 Azurite
2 Malachite
3 Haematite
4 Chalcopyrite
in chemistry what is nickle (II) nitrate solution mixed with a sodium hydroxide solution
Answer:
I hope this will help you and Please mark me as Brilliant
Explanation:
Approximately 2 mL of Solution A (on the left) is added to a sample of Solution B (on the right) with a dropping pipet. If a precipitate forms, the resulting precipitate is suspended in the mixture. The mixture is then stirred with a glass stirring rod and the precipitate is allowed to settle for about a minute.
Solution A: 0.5 M sodium hydroxide, colorless
Solution B: 0.2 M nickel(II) nitrate, green
Precipitate: light green
Ni(NO3)2(aq) + 2 NaOH(aq) —> Ni(OH)2(s) + 2 NaNO3(aq)
Credits:
Design
Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859
John W. Moore University of Wisconsin - Madison, Madison, WI 53706
Video
Jerrold J. Jacobsen University of Wisconsin - Madison, Madison, WI 53706
Text
Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859
QUESTIONS
1. Vinegar contains acetic Acid, CH3COOH. Titration of 5.00g of vinegar with 0.100 M
NaOH requires 33.0cmº to reach the equivalence point.
(a) What is the weight percentage of CH3COOH in vinegar?
(b) If the vinegar has a density of 1.005gcm", what is the molarity of CH3COOH in
vinegar?
Answer:
389929.827
Explanation:
33806.78° C
Answer:
(a) 3.96 (w/w) %
(b) 0.663M
Explanation:
The acetic acid, CH₃COOH, reacts with NaOH as follows:
CH₃COOH + NaOH → CH₃COONa + H₂O
Where 1 mole of acetic acid reacts with 1 mole of NaOH
In the equivalence point of the titration, the moles of acetic acid are equal to moles of NaOH added. To solve this question we need to find the moles of NaOH and thus, the mass of acetic acid
Moles NaOH = Moles acetic acid:
33.0cm³ = 0.033L * (0.100moles / L) = 0.0033 moles
Mass acetic acid -Molar mass: 60g/mol-:
0.0033 moles * (60g / mol) = 0.198g
a) Weight percent is 100 times the ratio of the mass of acetic acid (0.198g) in the mass of vinegar (5.00g):
0.198g / 5.00g * 100 = 3.96 (w/w) %
(b) The volume of the vinegar in the 5.00g is:
5.00g * (1mL / 1.005g) * (1L / 1000mL) = 0.00498L
And the molarity is:
0.0033moles / 0.00498L = 0.663M
Concluding Remarks. Reflect on the experimental procedures you have undertaken and the possible sources of error. Then write a summary paragraph comparing your results, commenting upon the common ion effect and its influence on solubility, and commenting upon activity effects and their influence on the Ksp value.
Explanation:
Whenever an ion in a solution is common for any two different salts, a common ion effect is formed that serves as the sources. Further addition of the common ion that is the product of a dissolution of the first. Adding the product ion decreases the solubility for the 1st salt.
Equilibrium made between the reactants as well as the products are described by the equilibrium constant. This expression for the insoluble salt is written using the rules that were used for other equilibriums. Equilibrium constant is known as the solubility product, Ksp.
The interactions between the ions are the results of the activity effects. The ion's activity is influenced by the surrounding. In case of water molecule, the activity of the ion has different values from the one in the middle of the counterion cloud. The Ksp values are used to decide for the order of the precipitation of any two or more of insoluble salts.
What is the momentum of a 1,700 kg car travelling in a straight line at 13 m/s?
Answer:
Explanation:
We know that momentum is the product of mass and velocity so here
mass (m) = 1700 kg
velocity (v) = 13 m/s
So now
momentum = m * v
= 1700 * 13
= 22100 kg m/s
hope it helps :)
what action form a diffrent chemical substance
Answer:
Chemical reactions leads to formation of a new chemical subtance.
How many atoms of K are present in 195.49 grams of K? (5 points)
a
3.0110 x 1024
b
6.0220 x 1024
c
1.1772 x 1026
d
4.5797 x 1027
Answer:
A
Explanation:
195.49 g K x 1 mole / 39.01 g x 6.022 x 10^23 atoms/mole = 30.11 x 10^23 = 3.011 x 10^24
The number of K atoms present in 195.49 grams of K is 3.0110 × 10²⁴ atoms. The correct option is a 3.0110 x 10²⁴.
StoichiometryFrom the question,
We are to determine the number of K atoms present in 195.49 grams of K.
First, we will determine the number of moles K present
Using the formula,
[tex]Number\ of\ moles = \frac{Mass}{Atomic\ mass}[/tex]
Atomic mass of K = 39.0983 g/mol
Number of moles of K present = [tex]\frac{195.49}{39.0983}[/tex]
Number of moles of K present = 4.99996 moles
Number of moles of K present ≅ 5 moles
Now, for the number of atoms present
From the formula
Number of atoms = Number of atoms × Avogadro's constant
Number of K atoms present = 5 × 6.022 × 10²³
Number of K atoms present = 5 × 6.022 × 10²³
Number of K atoms present = 30.11 × 10²³
Number of K atoms present = 3.0110 × 10²⁴ atoms
Hence, the number of K atoms present in 195.49 grams of K is 3.0110 × 10²⁴ atoms. The correct option is a 3.0110 x 10²⁴.
Learn more on Stoichiometry here: https://brainly.com/question/16505596
Stirring increases the rate of dissolution because it?
a. raises the temperature.
b. brings fresh solvent into contact with the solute.
c. decreases the surface area of the solute.
d.lowers the temperature.
PLS HELP, NEED HELLLLLPPPPP!!
How are air temperature and humidity related?
Colder air can hold more water vapor than warmer air.
Warmer air and colder air can hold the same amount of water vapor.
Warmer air can move faster than colder air.
Warmer air can hold more water vapor than colder air.
Answer:
I got you! I think the answer is D. Warmer air can hold more water vapor than colder air.
Explanation:
Although this statement is true, I could be incorrect, but it is unlikely. When warm air recieves more water vapor it expands while cold air becomes packed and unstable.
Hope this helps out, good luck! (¤﹏¤)
~ #LearnWithBrainly ~
Answer:
B!Explanation:
Write the balanced NET IONIC equation for the reaction that occurs when perchloric acid and calcium hypochlorite are combined. It is not necessary to include states such as (aq) or (s).
Answer:
[tex]H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}[/tex]
Explanation:
Hello there!
In this case, since perchloric acid is HClO4 and is a strong acid and calcium hypochlorite is Ca(ClO)2, the undergoing molecular chemical reaction turns out:
[tex]2HClO_4{(aq)}+Ca(ClO)_2{(aq)}\rightarrow 2HClO{(aq)}+Ca(ClO_4)_2{(aq)}[/tex]
Thus, since the resulting hypochlorous acid is weak, it does not fully ionize, so it remains unionized, however, we can write the ions for the other species:
[tex]2H^++2(ClO_4)^-+Ca^{2+}+2(ClO)^-\rightarrow 2HClO{(aq)}+Ca^{2+}+2(ClO_4)^-[/tex]
Now, we can cancel out the spectator ions, calcium and perchlorate, to obtain:
[tex]2H^+(aq)+2(ClO)^-(aq)\rightarrow 2HClO{(aq)}\\\\H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}[/tex]
Best regards!
If 9.00 g helium gas is added to a 1.00 L ballon containing 1.00 g of helium gas, what is the new volume of the ballon? Assume no change in temperature or pressure.
Answer:
10 L
Explanation:
We'll begin by calculating the number of mole in 9 g and 1 g of He. This can be obtained as follow:
Mass of He = 9 g
Molar mass of he= 4 g/mol
Mole of He =?
Mole = mass /Molar mass
Mole of He = 9/4
Mole of He = 2.25 moles
Mass of He = 1 g
Molar mass of he= 4 g/mol
Mole of He =?
Mole = mass /Molar mass
Mole of He = 1/4
Mole of He = 0.25 moles
Finally, we shall determine the new volume of the balloon as follow:
Initial mole (n₁) = 0.25 mole
Initial volume (V₁) = 1 L
Final mole (n₂) = 0.25 + 2.25 = 2.5 moles
Final volume (V₂) =?
V₁/n₁ = V₂/n₂
1 / 0.25 = V₂ / 2.5
4 = V₂ / 2.5
Cross multiply
V₂ = 4 × 2.5
V₂ = 10 L
Therefore, the new volume of the balloon is 10 L
what can be concluded about heat of neutralization
Answer:
its exothermic oooooooooooooooooooooo
Baking soda (NaHCO3) and vinegar (HC2H3O2) react to form sodium acetate, water, and carbon dioxide. If 42.00 g of baking soda react, how many moles of carbon dioxide will form? Show your work. (3 points)
NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO
Answer:
0.5 mole of CO₂.
Explanation:
We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:
Mass of NaHCO₃ = 42 g
Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)
= 23 + 1 + 12 + 48
= 84 g/mol
Mole of NaHCO₃ =?
Mole = mass / molar mass
Mole of NaHCO₃ = 42/84
Mole of NaHCO₃ = 0.5 mole
Next, balanced equation for the reaction. This is given below:
NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂
Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.
Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.
Thus, 0.5 mole of CO₂ was obtained from the reaction.
Using the graph below, at what depth does the thermocline begin?
0 meters
100 meters
200 meters
300 meters
Answer:
200 meters
Explanation:
which solution would help local farms if the water level in a reservoir used for irrigation became low?
Answer:
Build wind-powered pumps to use groundwater
Explanation:
Answer:
Its B!
Explanation:
Did it on the test!
A solution contains 6 mg isopropanol dissolved in 2 kg H2O. The isopropanol concentration is?
a. 3% isopropanol.
b.3 M isopropanol.
c.3 m isopropanol.
d. 3 ppm isopropanol.
Answer:
Option D. 3 ppm isopropanol.
Explanation:
From the question given above, the following data were obtained:
Mass of isopropanol = 6 mg
Mass of water = 2 Kg
Isopropanol concentration =?
Concentration = mass isopropanol / mass of water
Isopropanol concentration = 6 mg / 2 kg
Isopropanol concentration = 3 mg/Kg
Next, we shall convert 3 mg/Kg to ppm. This can be obtained as follow:
Recall:
1 mg/Kg = 1 ppm
Therefore,
3 mg/Kg = 3 ppm
Thus, the isopropanol concentration is 3 ppm.
Please help due in 5 min.
Answer:
B) Hope this helps! :)
Explanation:
Hydrogen peroxide with a concentration of 3.0 percent (3.0 g of H2O2 in 100 mL of solution) is sold in drugstores for use as an antiseptic. For a 10.0-mL 3.0 percent H2O2 solution, calculate (a) the oxygen gas produced (in liters) at STP when the compound undergoes complete decomposition and (b) the ratio of the volume of O2 collected to the initial volume of the H2O2 solution.
Answer:
a) 0.099 L
b) 9.9
Explanation:
Now, given the equation for the decomposition of H2O2;
2H2O2(l) ------> 2H2O(l) + O2(g)
Mass of H2O2;
percent w/v concentration = mass/volume * 100
volume = 10.0-mL
percent w/v concentration = 3.0 percent
mass of H2O2 = x
3 = x/ 10 * 100
30 = 100x
x = 30/100
x = 0.3 g of H2O2
Number of moles in 0.3 g of H2O2 = mass/ molar mass
Molar mass of H2O2 = 34.0147 g/mol
Number of moles in 0.3 g of H2O2 = 0.3g/34.0147 g/mol
= 0.0088 moles
From the reaction equation;
2 moles of H2O2 yields 1 mole of oxygen
0.0088 moles of H2O2 = 0.0088 * 1/2 = 0.0044 moles of oxygen
If 1 mole of oxygen occupies 22.4 L
0.0044 moles of oxygen occupies 0.0044 * 22.4/1
= 0.099 L
b) initial volume of the H2O2 solution = 10 * 10-3 L
Hence, ratio of the volume of O2 collected to the initial volume of the H2O2 solution = 0.099 L/10 * 10-3 L = 9.9
A solid powder is composed of molecules containing silver (Ag), nitrogen (N), and oxygen (O) atoms. All of the molecules are identical. How is this substance classified? (A) as a heterogeneous mixture (B) as a homogeneous mixture (C) as a compound (D)as an element
Can the crabs see the plankton they eat near the ocean floor?
Answer:
Explanation:
The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.
Crabs cannot see the plankton they eat near the ocean floor.
What are Plankton ?Plankton are a collection of tiny organisms that live at and beneath the surface of lakes, rivers, ponds, and oceans across the planet.
Some crabs have colour coding capabilities , but the crabs to see the Planktons the light must reach the plankton , reflect and reach to the eyes of crabs , but the light does not reach inside the ocean and so crabs see the plankton they eat near the ocean floor.
Hence crabs cannot see the plankton they eat near the ocean floor.
To know more about Plankton
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In any food web, the organisms that are responsible for converting raw energy into usable chemical energy are collectively called ________, while organisms
that recycle the nutrients trapped in dead organisms are collectively called ________.
A) producers; consumers.
B) producers; decomposers.
C) heterotrophs; consumers.
D) heterotrophs; autotrophs.
Answer:
B. Producers and decomposers
Explanation:
Producers aka plants convert raw energy into chemical energy.
Decomposers are responsible for decomposing dead organisms.
Answer:
the answer is b
Explanation:
Because it provides for the restoration of the life cycle
What is the sign of a chemical reaction
Polar bears are well adapted to the Arctic environment due to their white
fur coats. Which statement BEST explains why white coat color was
possibly favored by natural selection over other coat colors?
answer: white fur works as a camouflage against the white snow, allowing polar bears an advantage when hunting for food and hiding from predators
The decomposition of ethylene oxide (CH₂)₂O(g) → CH₄(g) + CO(g) is a first order reaction with a half-life of 58.0 min at 652 K. The activation energy of the reaction is 218 kJ/mol. Calculate the half-life at 623 K.
Answer:
[tex]t_{1/2}=375.5min[/tex]
Explanation:
Hello!
In this case, since this problem refers to two different temperatures, it is possible to compute the rate constant at 652 K given the half-life at such temperature:
[tex]k=\frac{ln(2)}{58.0 min}=0.0120min^{-1}[/tex]
Next, by using the T-variable version of the Arrhenius equation, we can compute the rate constant at 623 K:
[tex]ln(\frac{k_2}{k_1} )=-\frac{Ea}{R}(\frac{1}{T_2}-\frac{1}{T_1} ) \\\\ln(\frac{k_2}{k_1} )=-\frac{218000J/mol}{8.3145\frac{J}{mol*K}}(\frac{1}{623K}-\frac{1}{652K})\\\\ln(\frac{k_2}{k_1} )=-1.872\\\\k_2=0.0120min^{-1}exp(-1.872)\\\\k_2=0.00185min^{-1}[/tex]
Finally, the half-life at 623 K turns out to be:
[tex]t_{1/2}=\frac{ln(2)}{0.00185min^{-1}} \\\\t_{1/2}=375.5min[/tex]
Best regards!
R.I.P too my brainly account lol..
Answer:
i don't know what happened but r.i.p account
Answer:
Rest in peace.
Explanation: I need these 50 points tho.
Which answer would represent 0.001 moles?
Answer:
Which answer would represent 0.001 moles?
Revise and repeat: Is more water always better? Create your own experiments to find the ideal amount of water for each kind of plant. Explain your findings below. PLSSSSSSSSSSSSSSSSSSSS HELPPPPPPPPPPPPPPP!
More water is better but not always because access to water or sunlight is harmful to plants.
What is the importance of water?Water is an important part not only for plants to run the ecosystem it is always important but in a fixed amount not in a large quantity as access to anything is harmful t the environment as access to water can also damage the ecosystem.
Water is said to be life for plants but more water leads them not to grow in a manageable way like access to water in the soil will not allow the soil to hold the plant for growing plants will float on sol and the root will not be able to grow.
Therefore, water is essential always but in fixed quantity not in the large amount in access.
Learn more about the importance of water, here;
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PLEASE HELP
For the following chemical reaction, what mass of silver iodide, Agl, (in grams) will be produced from 3.11 mol of calcium
iodide, Calz?
Cal, + 2 AgNO, — 2 AgI + Ca(NO3)2
Answer:
1461.7 g of AgI
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI
Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:
Mole of AgI = 6.22 moles
Molar mass of AgI = 108 + 127
= 235 g/mol
Mass of AgI =?
Mass = mole × molar mass
Mass of AgI = 6.22 × 235
Mass of AgI = 1461.7 g
Therefore, 1461.7 g of AgI were obtained from the reaction.
Which tile should be used to solve the following problem?
I will give brainliest PLEASE HELP
Answer: B. [tex]\frac{\text {2 mol} H_2O}{\text {2 mol HCl}}[/tex]
Explanation:
The balanced chemical equation is:
[tex]Ca(OH)_2(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)[/tex]
is the limiting reagent as it limits the formation of product and is the excess reagent.
According to stoichiometry :
2 moles of produce = 2 moles of
Thus 3.25 moles of [tex]HCl[/tex] will produce=[tex]\frac{2}{2}\times 3.25=3.25moles[/tex] of [tex]H_2O[/tex]
Thus the tile used is [tex]\frac{\text {2 mol } H_2O}{\text {2 mol HCl}}[/tex]
Answer:Below is the answer to all 5 of stoichiometry question
Explanation:
1. B. The student chose the correct tile, but needs to flip the tile to make the units cancel.
2.C. 2.3 moles of oxygen (O2)
3. B. Tile B
4. A. 2.9 moles of aluminum sulfate
5. B. 42.0 grams