What is the smallest sample size required to provide a 95% confidence interval for a
mean, if it important that the interval be no longer than 1cm? You may assume that the
population is normal with variance 9cm2.

Answer:

99% chance tommy has it

Step-by-step explanation:

cuz do da math

Answer:

She is saving 10 cents per pound

Step-by-step explanation:

First, we need to find how much she would pay without the sale:

12.5(1.8) = 22.5

Now, we can calculate how much she saved:

22.5 - 21.25 = 1.25

To find how much she's saving per pound, we divide the difference by the number of pounds:

1.25/12.5 = 0.1

She is saving 10 cents per pound

Answer:

A

Step-by-step explanation:

I took the test and got it right

Answer:

$200

I hope this helps!

Answer:

200rupees

Step-by-step explanation:

according to the question ,kajol has 75 rupees

amount earned=3/8* amount earned

                        =75/3*8

                         =200 rupees

Answer:

Step-by-step explanation:

a) You're trying to justify that two sums equal to 180° are equal to each other. The Transitive Property of Equality is that justification.

__

b) You're trying to justify that angles 3 and 6 are congruent. These are between the parallel lines, so are "interior" angles. They are on opposite sides of the transversal, so are "alternate" angles. They do not share a vertex, so cannot be vertical angles. The applicable theorem is the Alternate Interior Angles Theorem.

Answer:

Step-by-step explanation:

Answer:

25%

Step-by-step explanation:

The probability of having a boy is 50%

To calculate the probability of him having 2 boys, multiply the probabilities together

0.5(0.5) = 0.25

Answer:

D. Quadratic parent function.

Step-by-step explanation:

Answer:

53/28

Step-by-step explanation:

100 g jam

Blackberry / sugar= 53/28

Answer:

Solution,

Amount of sugar=100-(19+53)

=100-72

=28 gram

Ratio of blackberries to sugar=53/28

=53:28

Hope this helps..

Good luck on your assignment..

Answer:

True

Step-by-step explanation:

3y=5x

Put x as 3 and y as 5.

3(5) = 5(3)

15 = 15

Hence, true.

Answer:

X=3

y=15

[tex]3y = 5x \\ 3 \times 5 = 5 \times 3 \\ 15 = 15[/tex]

Proved.

Hope it helps..

Answer:

352 cm/s

Step-by-step explanation:

circ = 44pi

speed = distance * time

distance = circ * 4 = 176pi

speed = 176pi/0.5

Answer:

≈ 1106 cm/s

Step-by-step explanation:

linear speed = angular speed x radius of the rotation

v = ωr

v = linear speed (m/s)

ω = angular speed (radians/s)

r = radius of the rotation (m)

------------

Given:

Linear speed is:

Answer:

Given:

A right triangle in which an altitude is drawn from the right angle vertex

To find: value of X

We have leg rule in similarity in right triangle as:

[tex] \frac{leg}{part} = \frac{hypotenuse}{leg} \\ [/tex]

Plugging the given values,

[tex] \frac{z}{3} = \frac{3 + 27}{z} \\ z \times z = 3(3 + 27) \: \: (cross \: multiplication) \\ {z}^{2} = 9 + 81 \\ {z}^{2} = 90 \\ z = \sqrt{90} \\ z = 3 \sqrt{10} [/tex]

Hope this helps...

Good luck on your assignment..

Answer:

56 cats

88 dogs

Step-by-step explanation:

x=cats

x+32=dogs

x+x+32=144

2x=144-32

2x=112

x=112/2

x=56 (56 cats)

x+32=88 (88 dogs)

Answer:

56

Step-by-step explanation:

In order to solve this question you need to subtract 32 by 144 then divide that answer by 2.

So we know that they're 32 more dogs then cats and there is 144 dogs and cats all together.

[tex]144 - 32 = 112[/tex]

Divide it in half

[tex]112 \div2=56[/tex]

[tex]56+32 = 88[/tex]

[tex]= 56[/tex]

Therefore they're 56 cats in the pet store.

Hope this helps.

Answer: a. 1320

b.495

Step-by-step explanation:

Complete question is provided in the attachment.

Total members on the board = 12

a. Persons to chose : chairperson, first vice​ chairperson, second vice​ chairperson, and​ secretary

i.e. Total 3 posts in an order.

Number of ways to choose 3 persons from 12 in an order = [tex]^{12}P_3[/tex]  [By permutation]

[tex]=\dfrac{12!}{(12-3)!}\\\\=\dfrac{12!}{7!}\\\\=12\times11\times10\\\\=1320[/tex]

hence, 1320 different slates of candidates are​ possible .

b. number of ways to choose 4 members out of 12 ( order not matters)=[tex]^{12}C_{4}[/tex] [By combinations]

[tex]=\dfrac{12!}{4!8!}\\\\=\dfrac{12\times11\times10\times9}{24}\\\\=495[/tex]

Hence, the number of different subcommittees are​ possible =495

Answer:

Option C is the correct option

Step-by-step explanation:

g = 8 ( given )

Now,

[tex] \frac{g}{2} + 3[/tex]

Plugging the value of g

[tex] \frac{8}{2} + 3[/tex]

[tex] \frac{8 + 3 \times 2}{2} [/tex]

[tex] \frac{8 + 6}{2} [/tex]

[tex] \frac{14}{2} [/tex]

[tex]7[/tex]

Hope this helps...

Good luck on your assignment...

Answer:

Answer is Y

Step-by-step explanation:

Answer:

[tex]P(a=31,b=39,c=7,d=23) = 0.000668[/tex]

Step-by-step explanation:

Sample space, n = 100

Let the number of students signed up for CSE 311 = a

Let the number of students signed up for CSE 312 = b

Let the number of students signed up for CSE 331 = c

Let the number of students signed up for CSE 332 = d

Probability of taking CSE 311, [tex]P_a[/tex] = 0.3

Probability of taking CSE 312, [tex]P_b[/tex] = 0.4

Probability of taking CSE 331, [tex]P_c[/tex] = 0.1

Probability of taking CSE 332, [tex]P_d[/tex] = 0.2

[tex]P(a,b,c,d) = \frac{n!}{a! b! c! d!} p_a^{a} p_b^{b} p_c^{c} p_d^{d} \\P(a=31,b=39,c=7,d=23) = \frac{100!}{31! 39! 7! 23!} * 0.3^{31} * 0.4^{39} * 0.1^{7} 0.2^{23}\\P(a=31,b=39,c=7,d=23) = \frac{4.58*10^{111}}{2.13*10^{56}* 5040 }* (1.57*10^{-55})\\P(a=31,b=39,c=7,d=23) = 0.000668[/tex]

Answer:

Step-by-step explanation:

Let's organise our information :

we want to khow the value of x that gives us : (1/2)x²+2x+3=x+7

Now the trick is to write this expression as a quadratic equation with zero at one side :

Now let's solve this equation :

Δ=1²-4*(1/2)*(-4)

 = 9

So we have two solutions :

So the solutions are -4 and 2

Answer:

Step-by-step explanation:

Let the five courses with their corresponding credit hours be represented as shown;

FST 201 = 4

FST 203 = 5

FST 112 = 1

FST 219 = 5

FST 223 = 4

If a student earned grades of​ B, B,​ A, C, and D respectively in those courses with the following grading system  A =​4, B =​3, C =​2, D =​1, and F =0, before we can get the student GPA, we need to know the total credit point for the five courses.

Credit point for each course = Number of credit hour * point for each grade

FST 201 = 4 * 4 = 16points (A)

FST 203 = 5 * 4 = 20points (A)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 4 = 20points (A)

FST 223 = 4 * 4 = 16points (A)

Total credit point = 16+20+4+20+16 = 76points

Total credit point gotten by the student is calculated as thus;

FST 201 = 4 * 3 = 12points (B)

FST 203 = 5 * 3 = 15points (B)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 2 = 10points (C)

FST 223 = 4 * 1 = 4points (D)

Total credit point gotten by the student = 45points.

student's Grade Point Average​ (GPA) = Total credit point/Total credit point gotten by the student = 76/45 = 1.69 (to 2dp)

Answer:  c) rotation of 180° & shift right 1 unit and down 2 units

Step-by-step explanation:

Rotation of 180° changes the signs of x and y

(x, y)   →   (-x, -y)

Shift right one unit adds 1 to x, Shift two down subtracts 2 from y

(-x, -y)   →   (-x + 1, -y - 2)

  (x, y)          (-x + 1, -y - 2)  

(-1, -2)    →       (2, 0)

(-4, -1)    →       (5, -1)

(-4, -3)   →       (5, 1)

Answer:

75435912

Step-by-step explanation:

1495486+73940426

= 75435912

Answer:

75,435,912

Step-by-step explanation:

=> 1495486 + 73940426

Using Calculator

=> 75,435,912

Answer:

a. 10295472 ways

b. 4272048 ways

c. 6023424 ways

Step-by-step explanation:

Given that:

Camera shop stocks ----- 8 different types of batteries

one of which is ---- A76

Assume that there are ------ at least 30 batteries of each type.

a.

How many ways can a total inventory of 30 batteries be distributed among the eight different types.

The number of ways a total inventory of 30 batteries be distributed is :

[tex]= \left \{ {{30+8-1} \atop {30}} \right. \}[/tex]

[tex]= \left \{ {{37} \atop {30}} \right. \}[/tex]

[tex]=\dfrac{37!}{30! *7!}[/tex]

[tex]= \dfrac{37*36*35*34*33*32*31*30!}{30!*7*6*5*4*3*2*1}[/tex]

[tex]= \dfrac{37*36*35*34*33*32*31}{7*6*5*4*3*2*1}[/tex]

= 10295472 ways

b.

How many ways can a total inventory of 30 batteries be distributed among the eight different types if the inventory must include at least four A76 batteries?

If we must include 4  A76 batteries; then the number of ways a total inventory of 30 batteries can be distributed among eight different types of batteries will be:

30 - 4 = 26 batteries

Now;

[tex]= \left \{ {{26+8-1} \atop {26}} \right. \}[/tex]

[tex]= \left \{ {{33} \atop {26}} \right. \}[/tex]

[tex]=\dfrac{33!}{26! \ \ 7!}[/tex]

[tex]=\dfrac{33*32*31*30*29*28*27*26!}{26! \ * \ 7*6*5*4*3*2*1}[/tex]

[tex]=\dfrac{33*32*31*30*29*28*27}{ \ 7*6*5*4*3*2*1}[/tex]

= 4272048 ways

c. If we must include at most three A7b batteries. the number of ways that a total inventory of 30 batteries can be distributed among eight different types of inventory is:

[tex]= \sum \limits ^3 _{x=0} \left \{ {{(30-x)+7-1} \atop {30-x}} \right. \} \\ \\ \\ = \sum \limits ^3 _{x=0} \left \{ {{(30-0)+7-1} \atop {30-0}} \right. \} = (^{36}_{30})+(^{35}_{29})+ (^{34}_{28})+ (^{33}_{27})[/tex]

[tex]= \dfrac{36!}{30! * 6!} + \dfrac{35!}{29! * 6!} + \dfrac{34!}{28! * 6!} + \dfrac{33!}{27! * 6!}[/tex]

= 1947792 + 1623160 + 1344904 + 1107568

= 6023424 ways

Answer:

Hope it helps you :)

And i hope you understand  

For store 1, it can be placed on 16 sites. Store 2 can be placed on 15 sites( since store 1 is already on site 1). Store 3 can be placed on 14 sites and so on until store 5 which has 12 sites.

Therefore the number of way is

C= 16*15*14*13*12

c=524,160 possibilities

Answer:

8

Step-by-step explanation:

the value of x is 8 because the sides are the same

Answer:

-12+28i+3i-7i-65i+28

14 -41i

Answer:

No solutions.

Step-by-step explanation:

5x = 8x^-1/3

Divide 8 into both sides.

5/8x = x^-1/3

Divide both sides by x.

5/8 = x^-4/3

Multiply both sides by the exponent -3/4.

5/8^-3/4 = x

1.422624 = x

Plug in 1.422624 for x to check.

It does not work. There are no real solutions.

Answer:

ABC = 88

Step-by-step explanation:

Angle Formed by Two Chords  = 1/2( sum of Intercepted Arcs)

ABD = 1/2 ( 131+ 53)

ABD = 1/2 (184)

       =92

ABC = 180 -ABD

ABC = 88

Answer:

140

Step-by-step explanation:

The maximum is the furthest the line that goes out the furthest, the minimum would be about 83-84

Answer:

the other person is correct!

Step-by-step explanation:

Answer:

solution,

Highest score=9

lowest score=1

now,

range= highest score-lowest score

=9-1

=8

Hope this helps...

Answer:

8

Step-by-step explanation:

The range of the sequence is the largest number - the smallest number.

The largest number is 9.

The smallest number is 1.

9 - 1

= 8

The range of the sequence is 8.

Answer:

x = 270 gallons

270 gallons of a 50% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 40% antifreeze

Step-by-step explanation:

Let x represent the number of gallons of the 50% antifreeze solution.

The volume of the 10% antifreeze is = 90 gallons

The volume of the mixture that is 40% antifreeze = 90+x

The amount of antifreeze in the two solutions must be equal to the amount of anti freeze in the mixture;

50% of x + 10% of 90 = 40% of (90+x)

0.50(x) + 0.10(90) = 0.40(90+x)

0.50x + 9 = 36 + 0.40x

Collecting the like terms;

0.50x - 0.40x = 36-9

0.10x = 27

x = 27/0.10

x = 270 gallons

270 gallons of a 50% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 40% antifreeze

Answer:

The answer is option B.

Step-by-step explanation:

Using the expression

[tex] {e}^{ ln(x) } = x[/tex]

[tex] {e}^{ ln(4) } = 4[/tex]

Hope this helps you