HELP ME PLEASE


The half-life of Palladium-100 is 4 days. After 12 days a sample of Palladium-100 has been reduced to a mass of 2 mg.


What was the initial mass (in mg) of the sample?


What is the mass 5 weeks after the start?

Answers

Answer 1

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

[tex]P(t)=A(r)^t[/tex]

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

[tex]\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}[/tex]

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

[tex]\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}[/tex]

Solve for A. Simplify:

[tex]\displaystyle 2=A\Big(\frac{1}{2}\Big)^3[/tex]

Simplify:

[tex]\displaystyle 2=A\Big(\frac{1}{8}\Big)[/tex]

Thus, the initial mass of the sample was:

[tex]A=16\text{ mg}[/tex]

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

[tex]\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}[/tex]

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.


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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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