Answer:
81
Step-by-step explanation:
25 and 27 are not perfect squares so they can not be the answer.
36 and 81 are both multiples of 3, but only 81 is not even, so the answer is 81
3(2x - 1) + 7 = -44 solve for x
Answer:
I love algebra anyways
The ans is in the picture with the steps how i got it
(hope this helps can i plz have brainlist :D hehe)
Step-by-step explanation:
answer is x =-8
hope that helps^^
Fill in the table using this function rule.
y=-2x +4
Answer
i think this is what you mean
Step-by-step explanation:
x y
2 0
1 2
0 4
-1 6
-2 8
Suppose X has an exponential distribution with mean equal to 11. Determine the following: (a) (Round your answer to 3 decimal places.) (b) (Round your answer to 3 decimal places.) (c) (Round your answer to 3 decimal places.) (d) Find the value of x such that . (Round your answer to 2 decimal places.)
Answer:
[tex]P(X > 11) = 0.368[/tex]
[tex]P(X > 22) = 0.135[/tex]
[tex]P(X > 33) = 0.050[/tex]
[tex]x = 33[/tex]
Step-by-step explanation:
Given
[tex]E(x) = 11[/tex] --- Mean
Required (Missing from the question)
[tex](a)\ P(X>11)[/tex]
[tex](b)\ P(X>22)[/tex]
[tex](c)\ P(X>33)[/tex]
(d) x such that [tex]P(X <x)=0.95[/tex]
In an exponential distribution:
[tex]f(x) = \lambda e^{-\lambda x}, x \ge 0[/tex] --- the pdf
[tex]F(x) = 1 - e^{-\lambda x}, x \ge 0[/tex] --- the cdf
[tex]P(X > x) = 1 - F(x)[/tex]
In the above equations:
[tex]\lambda = \frac{1}{E(x)}[/tex]
Substitute 11 for E(x)
[tex]\lambda = \frac{1}{11}[/tex]
Now, we solve (a) to (d) as follows:
Solving (a): P(X>11)
[tex]P(X > 11) = 1 - F(11)[/tex]
Substitute 11 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]
[tex]P(X > 11) = 1 - (1 - e^{-\frac{1}{11}* 11})[/tex]
[tex]P(X > 11) = 1 - (1 - e^{-\frac{11}{11}})[/tex]
[tex]P(X > 11) = 1 - (1 - e^{-1})[/tex]
Remove bracket
[tex]P(X > 11) = 1 - 1 + e^{-1}[/tex]
[tex]P(X > 11) = e^{-1}[/tex]
[tex]P(X > 11) = 0.368[/tex]
Solving (b): P(X>22)
[tex]P(X > 22) = 1 - F(22)[/tex]
Substitute 22 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]
[tex]P(X > 22) = 1 - (1 - e^{-\frac{1}{11}* 22})[/tex]
[tex]P(X > 22) = 1 - (1 - e^{-\frac{22}{11}})[/tex]
[tex]P(X > 22) = 1 - (1 - e^{-2})[/tex]
Remove bracket
[tex]P(X > 22) = 1 - 1 + e^{-2}[/tex]
[tex]P(X > 22) = e^{-2}[/tex]
[tex]P(X > 22) = 0.135[/tex]
Solving (c): P(X>33)
[tex]P(X > 33) = 1 - F(33)[/tex]
Substitute 33 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]
[tex]P(X > 33) = 1 - (1 - e^{-\frac{1}{11}* 33})[/tex]
[tex]P(X > 33) = 1 - (1 - e^{-\frac{33}{11}})[/tex]
[tex]P(X > 33) = 1 - (1 - e^{-3})[/tex]
Remove bracket
[tex]P(X > 33) = 1 - 1 + e^{-3}[/tex]
[tex]P(X > 33) = e^{-3}[/tex]
[tex]P(X > 33) = 0.050[/tex]
Solving (d): x when [tex]P(X <x)=0.95[/tex]
Here, we make use of:
[tex]P(X<x) = F(x)[/tex]
Substitute [tex]F(x) = 1 - e^{-\lambda x}[/tex]
[tex]P(X<x) = 1 - e^{-\lambda x}[/tex]
So, we have:
[tex]0.95 = 1 - e^{-\lambda x}[/tex]
Subtract 1 from both sides
[tex]0.95 -1= 1-1 - e^{-\lambda x}[/tex]
[tex]-0.05=- e^{-\lambda x}[/tex]
Reorder the equation
[tex]e^{-\lambda x} = 0.05[/tex]
Substitute 1/11 for [tex]\lambda[/tex]
[tex]e^{-\frac{1}{11} x} = 0.05[/tex]
Solve for x:
[tex]x = -\frac{1}{1/11}\ ln(0.05)[/tex]
[tex]x = -11\ ln(0.05)[/tex]
[tex]x = 32.9530550091[/tex]
[tex]x = 33[/tex] --- approximated
Someone please help me I’ll give out brainliest please dont answer if you don’t know
Answer:
$56.10
Step-by-step explanation:
Answer:
$8.50
Step-by-step explanation:
solve and recieve brain list I took a better picture
I'm so confused what is the answer plz?
Answer:
option b .
yes, by SAS.
.............
ILL GIVE BRAINLEST !!!!
Enter an equation for the function that includes the points. Give your answer in the form a(b*). In the
event that a = 1, give your answer in the form b*.
(1, 12) and (2, 144)
The equation is f(x)=
What is the factors for x squared plus 5x - 6
Answer:
=[tex](x-1)(x+6)[/tex]
Step-by-step explanation:
Answer:
[tex]x^{2} +5x-6=(x-1)(x+6)[/tex]
Step-by-step explanation:
Please help me!!!!!!!!!!
Identify all sets to which the number -7 belongs.
Answer:
Step-by-step explanation:
-7 which set of number belongs, betwen
Natural
Whole
Intergers
Rational
Irrational
Real
a classroom is 30 feet wide the ceiling is 10 feet above the floor what is the volume
Answer:
300 sqft
Step-by-step explanation:
30 times ten is 300 and the measure is feet squared
Answer:
9000 ft 3
Step-by-step explanation:
Let f(x) = 4x - 1, h(x) = - X-3.
Find (f o h)(-5).
Answer:
(f o h)(-5)=-33
Step-by-step explanation:
Let f(x) = 4x - 1, h(x) = - X-3.
(f o h)=4(-x-3)-1
(f o h)=-4x-12-1
(f o h)=-4x-13
(f o h)(-5)=-4(-(-5))-13
(f o h)(-5)=-20-13
(f o h)(-5)=-33
Answer for 5 stars answer and a heart with a comment. Please hurry!
Here is a diagram of a person standing next to a lorry.
The diagram shows two centimetre rulers.
The person and the lorry are drawn to the same scale.
The lorry is approximately 9.5 m in length.
Using the scale diagram, estimate the height of the person in metres.
Answer:
Length of the person = 1.9 m
Step-by-step explanation:
Actual length of the lorry = 9.5 m
Length of the lorry as per scale = 10 cm
Scale factor used to get the actual length of the lorry = [tex]\frac{\text{Actual length}}{\text{Length on scale}}[/tex]
= [tex]\frac{9.5}{10}[/tex]
= 0.95 : 1
Let the actual length of the person = x meters
Length of the person as per scale = 2 cm
Scale factor used to get the length of person is same.
Therefore, relation between the actual length of the person and scale length will be,
[tex]\frac{x}{2}= \frac{0.95}{1}[/tex]
x = 2 × 0.95
x = 1.9 meters
A zoo worker works 189.25 hours in 23 days. If she works the exact same number of hours per day, how many hours does she work each day?
Graphing linear equation using a table [ x = - 1 ]
• • • • • • • • • • • • • • • • • • • • • • • • • • • •
(I only need help in filling the table, aswell as the slope and y-intercept, thanks! ^u^)
0
1
2
3
4
5
take x 1 so 1-1
2-1..........
Last year, Tim rode his bike a total of 50 3/8 miles. This year, he rode his bike a total of 258 3/4 miles. Which of the following explains about how much farther Tim rode his bike this year than last year? A. About 200 times farther; Subtract last year's distance from this year's distance to get 208 3/8.
Then round to the nearest hundred to get 200.
B. About 50 times farther; Round each distance to the nearest whole number.
Then multiply last year's distance by 50 to see that 259 is close to 50 × 5.
C. About 10 times farther; 258 is about 5 times 50, and 34 is 2 times 38, so multiply 5 × 2 to get 10.
D. About 5 times farther; Round each distance to the nearest whole number.
Then multiply last year's distance by 5 to see that 259 is close to 50 × 5.
Answer:
D
Step-by-step explanation:
The lifetimes of a certain brand of light bulbs are known to be normally dsitributed with a mean of 1700 hours and standard deviation of 400 hours. A random sample of 64 of these light bulbs is taken. The probability is 0.20 that the sample mean lifetime is more than how many hours?
A. 1652.
B. 1725.
C. 1752.
D. 1670.
Answer:
1742 hours
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Single light:
Mean of 1700 hours and standard deviation of 400 hours, which means that [tex]\mu = 1700, \sigma = 400[/tex]
Sample of 64:
This means that [tex]n = 64, s = \frac{400}{\sqrt{64}} = 50[/tex]
The probability is 0.20 that the sample mean lifetime is more than how many hours?
This is the 100 - 20 = 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.84
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]0.84 = \frac{X - 1700}{50}[/tex]
[tex]X - 1700 = 50*0.84[/tex]
[tex]X = 1700 + 50*0.84[/tex]
[tex]X = 1742[/tex]
What is the fraction shown above?
Find the difference.
4-(-8)=
Answer:
4
Step-by-step explanation:
subtract negative 4 by negative 8
Please help with my question
if you have 60 G of fluorescent powder and 124 cups of medium base paint, and the ratio is one part powder to five parts paint how many cups of paint can I make with fluorescent powder
Answer:
1.268 cups
Step-by-step explanation:
60 G=0.2536 cups (I found a G to cup converter on the internet)
0.2536x5=1.268 cups of paint it would mix with at a 1 to 5 ratio
Which value for p makes the expressions 9p - 5 and (3 + p) 5 equivalent?
7
6
4
5
1
10
Answer:
numbers dont do into math please move this to englash
Step-by-step explanation:
it posted Wong
4/5 ÷ 1/5 = ?????????
Answer:
4
Step-by-step explanation:keep change flip 4/5 x 5/1 = 20/5= 4
12+22+32+...+102 =?
Answer:
750 is the answer. Hope it helps!
Find c. Round to the nearest tenth.
Answer:
Here,
150+10=180
162-180=18
Answer is 18°
Step-by-step explanation:
So the round of nearest tenth is 18°
Hope it will help have a great day at school. ^_^
Which graph represents the parametric equations x = 1 – t2 and y = 2t, where 0 ≤ t ≤ 5?
ANSWER: A
After plotting the above equation on the coordinate plane, we can see the graph of the function.
What are parametric equations?A parametric equation in mathematics specifies a set of numbers as functions of one or more independent variables known as parameters.
We have two parametric equations:
x = 1 – t² and
y = 2t
t = y/2 and
0 ≤ t² ≤ 5
1 ≤ 1 - t²≤ 4
1 ≤ x≤ 4
Plug the above value in x = 1 – t²
x = 1- (y/2)²
x = 1 - y²/4
4x = 4 - y²
y² = 4(1 - x)
Thus, after plotting the above equation on the coordinate plane, we can see the graph of the function.
Learn more about the parametric function here:
brainly.com/question/10271163
#SPJ2
Ron sells bananas for $0.60 each. How many bananas did Ron sell if he made $150.00, after taking off $39.00 for his banana stand rental?
The number of bananas that Ron sold is 315.
What is Division?Division is one of the operation in mathematics where number is divided into equal parts as that of a definite number.
Given that,
Cost for a banana = $0.60
Also given, he made $150.00, after taking off $39.00 for his banana stand rental.
Total amount of money that Ron made by selling the bananas = $150 + $39 = $189
Number of bananas sold = 189 / 0.6
= 315
Hence Ron sold 315 bananas.
Learn more about Division here :
https://brainly.com/question/28598725
#SPJ2
The medical practice you are working at has seen an average of 22.4 patients a day for the past 3 months. 3/4ths of those patients have insurance in one form or another.
What is the discriminate of y=x^2-8x+2
Answer:
56
Step-by-step explanation: Use the values of a, b, and c to find the discriminant.
Answer:
[tex]\Delta =56[/tex]
Step-by-step explanation:
We are given:
[tex]y = x^2 - 8x + 2[/tex][tex]y=x^2-8x+2[/tex]
So, a = 1, b = -8, and c = 2.
The discriminant (symbolized by Δ) is given by:
[tex]\Delta =b^2-4ac[/tex]
So, our discriminant in this case will be:
[tex]\Delta=(-8)^2-4(1)(2)=64-8=56[/tex]
Since our discriminant is a positive value, our equation has two real roots.
which table shows a proportional relationship between x and y ?
Answer:
Table C
Step-by-step explanation:
Given
Table A to D
Required
Which shows a proportional relationship
To do this, we make use of:
[tex]k = \frac{y}{x}[/tex]
Where k is the constant of proportionality.
In table (A)
x = 2, y = 4
[tex]k = \frac{y}{x}[/tex]
[tex]k = \frac{4}{2}[/tex]
[tex]k = 2[/tex]
x = 4, y = 9
[tex]k = \frac{y}{x}[/tex]
[tex]k = \frac{9}{4}[/tex]
[tex]k = 2.25[/tex]
Both values of k are different. Hence, no proportional relationship
In table (B)
x = 3, y = 4
[tex]k = \frac{y}{x}[/tex]
[tex]k = \frac{4}{3}[/tex]
[tex]k = 1.33[/tex]
x = 9, y = 16
[tex]k = \frac{y}{x}[/tex]
[tex]k = \frac{16}{9}[/tex]
[tex]k = 1.78[/tex]
Both values of k are different. Hence, no proportional relationship
In table (C):
x = 4, y = 12
[tex]k = \frac{y}{x}[/tex]
[tex]k = \frac{12}{4}[/tex]
[tex]k = 3[/tex]
x = 5, y = 15
[tex]k = \frac{y}{x}[/tex]
[tex]k = \frac{15}{5}[/tex]
[tex]k = 3[/tex]
x = 6, y = 18
[tex]k = \frac{y}{x}[/tex]
[tex]k = \frac{18}{6}[/tex]
[tex]k = 3[/tex]
This shows a proportional relationship because all values of k are the same for this table