The sixth-grade class is raising money to have a
class trip at the end of the year. They began the year
with $1,500. Now they have $1,650 in the account.
What is the percent increase for the money the class
has raised?

Answer:

[tex]Fraction = \frac{31}{38}[/tex]

[tex]\theta = 296.18^\circ[/tex]

[tex]Area = 29.62 \pi[/tex]

Step-by-step explanation:

Given

[tex]r = 6[/tex]--- radius

[tex]L = 31[/tex] --- arc length

Solving (a): Fraction represented by the arc

First, calculate the circumference (C)

[tex]C = 2\pi r[/tex]

So, we have:

[tex]C = 2 * 3.14 * 6[/tex]

[tex]C = 38[/tex] --- approximated

So, the fraction represented by the arc is:

[tex]Fraction = \frac{L}{C}[/tex]

[tex]Fraction = \frac{31}{38}[/tex]

Solving (b): Measure of the center angle

Using arc length formula, we have:

[tex]L = \frac{\theta}{360} * 2\pi r[/tex]

This gives

[tex]31 = \frac{\theta}{360} * 2 * 3.14 * 6[/tex]

[tex]31 = \frac{\theta}{360} * 37.68[/tex]

Make [tex]\theta[/tex] the subject

[tex]\theta = \frac{360 * 31}{37.68}[/tex]

[tex]\theta = 296.18^\circ[/tex]

Solving (c): The area of the sector

This is calculated as:

[tex]Area = \frac{\theta}{360} * \pi r^2[/tex]

So, we have:

[tex]Area = \frac{296.18}{360} * \pi * 6^2[/tex]

[tex]Area = \frac{296.18}{360} * \pi * 36[/tex]

Divide 360 and 36

[tex]Area = \frac{296.18}{10} * \pi[/tex]

[tex]Area = 29.618 * \pi\\[/tex]

[tex]Area = 29.62 \pi[/tex] --- approximated

Answer:

You have to simplify the fraction and turn it into a decimal.

Step-by-step explanation:

Meaning: Make the fraction smaller and turn it into the correct decimal.

EXAMPLE:

2/4 simplified is 1/2

1/2 is equal to 0.50

Answer:

76 books

Step-by-step explanation:

2/3 × 114 = 76

__________

Answer:

True

Step-by-step explanation:

Equivalent fractions are fractions with different numbers representing the same part of a whole.

Answer:

Part a:  Since the calculated value of t = 2.412 does not fall in the critical region t > ± 2.539 we conclude that population mean expense ratio does not exceed 1% at 0.01 significance level.

Part b:  Yes we accepted the null hypothesis when it is false so we made a type II error.

Part c: Power = 0.6591=0.66

Step-by-step explanation:

Part a:

Let the null and alternate hypotheses be

H0: u ≤ 1 against the claim Ha: u > 1

The significance level is ∝=0.01

As the standard deviation of the population is not given we use t- test which has n-1= 20-1= 19 degrees of freedom

This is one tailed test the critical region is t > ± 2.539

The mean is calculated to be 1.24 and standard deviation of the sample = s= 0.4486

We take population mean = u= 1

The test statistic is

t = x`-u/ s/ √n

t= 1.24-1 / 0.445/√20

t= 0.24/0.0995

t= 2.412

Since the calculated value of t = 2.412 does not fall in the critical region t > ± 2.539 we conclude that population mean expense ratio does not exceed 1% at 0.01 significance level.

Part b:

Type I errors are those errors when the null hypothesis is true and is rejected.

Type II errors are those in which the null hypothesis is false and is accepted.

If we had rejected the null hypothesis as it was true then we would have made a type I error.

Population mean = u = 1.33

And our null hypothesis is u= 1

Yes we accepted the null hypothesis when it is false so we made a type II error.

Part c:

When σ= 0.5

For Part a: μ= 1.33

Power = P (reject H0/ H0 is false)

= 1-β

P (reject H0/ H0 is false) = P (z > 2.539+ (u`-u0) / σ*√n)

= P (z > 2.539+ (1-1.33) /0.5 *√20)

=P (z > 2.539-2.9516)

= P (z > 0.4126)

= 0.5 - P (z= 0.2938)                                         from the area of table.

= 0.5- 0.1591

=0.3409

Power = 1-β = 1- 0.3409= 0.6591=0.66

Answer:

(1/2,1/4) because m= 1/5 and m= 1/2 and te equation is y=1/4x - 5/2 and y= 1/2x - 1

Substracting both

[tex]\\ \sf\Rrightarrow x=4-10=-6[/tex]

Putting in eq(2)

[tex]\\ \sf\Rrightarrow -6-4y=10[/tex]

[tex]\\ \sf\Rrightarrow -4y=16[/tex]

[tex]\\ \sf\Rrightarrow y=-4[/tex]

Hence our solution is

Answer:

2x= 38.5

Step-by-step explanation:

I'm not sure where u got 12x but 2 x = 38.5:

2x + 5 =82

subtract 5 for 82

2x = 77

77 divided by 2 is 38.5

x = 38.5

hope this helps :)

[tex]{\boxed{\mathcal{\red{h\:=\:9.5}}}}[/tex] ✅

[tex]h + \frac{1}{2} = 10 \\ ⇢ h + 0.5 = 10 \\ ⇢ h \: = 10 - 0.5 \\ ⇢ h = 9.5[/tex]

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Answer:

3000 in3 ? I haven't actually done this i-ready before- but I believe it's

Width x Length x Height = Final result?

Step-by-step explanation:

Step-by-step explanation:

you can get simply V= ABh πr^2 h π3.14^2 x 17.9 then you get the answer Ihope I can help you

Answer:

C. [tex]D_\frac{1}{7} (P)=P'(\frac{1}{4},-\frac{5}{14} )[/tex]

Step-by-step explanation:

[tex]\frac{7}{4}*\frac{1}{7}=\frac{7}{28} =\frac{1}{4}[/tex]

[tex]-\frac{5}{2} *\frac{1}{7} =-\frac{5}{14}[/tex]

Answer:

He was an Anti-federalist

Step-by-step explanation:

Answer:

Anti-federalist

Step-by-step explanation:

The Federalists, led by Secretary of Treasury Alexander Hamilton, wanted a strong central government, while the Anti-Federalists, led by Secretary of State Thomas Jefferson, advocated states' rights instead of centralized power.

Answer:

That would be (8,0) my good sir ( ma'am )

Step-by-step explanation:

Have a nice day

Answer:

[tex]40[/tex]

hope this helps you.

Can I have the brainliest please?

Answer:

0.8k +14

Step-by-step explanation:

See the steps below:)

Answer:

15 plates

Step-by-step explanation:

450 divided by 30 = 15, meaning 30 x 15 would be 450 mg. This also means that if the weight of some plates was 450 mg, there would be 15 plates.

Answer:

15

Step-by-step explanation:

Your units are a little confused.

The mass (total ) is 450 mg

1 plate weighs 30 mg

1 plate / 30 mg  =  x plates / 450 mg             Cross multiply

1 * 450 = 30x                                                   Divide by 30

450 / 30 = x

x = 15

There are 15 gold plates.

Answer: [tex]3x^{-2.5}[/tex]

Step-by-step explanation:

Given

Expression is

[tex]\dfrac{12\sqrt{x}}{4x^3}[/tex]

Using exponent property [tex]x^a\cdot x^b=x^{a+b}[/tex]

Writing expression in the form of [tex]k\cdot x^n[/tex]

[tex]\Rightarrow \dfrac{12\sqrt{x}}{4x^3}=\dfrac{3\times 4}{4}\times \dfrac{x^{0.5}}{x^3}\\\\\Rightarrow \dfrac{3\times 4}{4}\times x^{0.5-3}\\\\\Rightarrow 3x^{-2.5}[/tex]

Answer:

-9 + 4i

Step-by-step explanation:

The additive inverse ("opposite") of a complex number a + bi  is  -a - bi.

Just use the opposites of  a  and  b.

Answer:

∠A and ∠G is the pair of vertical angles.

Step-by-step explanation:

From the figure attached,

Two lines 'm' and 'n' are two parallel lines. These lines intersect a horizontal line 'l'.

Since, "Pair of opposite angles formed at the point of intersection are the vertical angles and equal in measure."

Therefore, Opposite angles ∠A ≅ ∠G, ∠B ≅ ∠H, ∠C ≅ ∠E and ∠D ∠F are the vertical angles.

From the given options,

∠A and ∠G is the pair representing the pair of vertical angles and thus congruent.

Answer:

∠A and ∠G

Step-by-Step Explaination:

I did it on

E

D

G

E

N

U

I

T

Y

9514 1404 393

Answer:

  900

Step-by-step explanation:

Let x represent the number. The given relationship is ...

  (3/5)x = 2 +(2/3)x

  -2 = 1/15x . . . . . . . . subtract 2+3/5x from both sides

  -30 = x . . . . . . . . . . multiply by 15

Then the square of the number is ...

  x² = (-30)² = 900

Answer:

See image

Step-by-step explanation:

I clicked submit and it was right

Also dude I remember doing this and struggling before

First find the area of one side.

The area of the side of a cube is s^2 where s is the length if one edge.

The edge length is given as 2/3, so the area of a side is 2/3^2 which is equal to 2/3 x 2/3 = 4/9 square units.

A cube has 6 sides so now to find the surface area of the cube multiply the area of one side by 6 sides:

4/9 square units x 6 = (4 x6)/9 = 24/9 which can be rewritten as 2 2/3 square units

The answer is 2 2/3 units^2

Answer:

49

Step-by-step explanation:

the number would simply be

14÷2=7

7²=49

GE = 26

Step-by-step explanation:

OP = 16 + 9 = 25

PE - OG = 7

Using Pythagorean theorem,

(GE)^2 = (OP)^2 + (PE - OG)^2

=(25)^2 + (7)^2

= 625 + 49

= 674

or

GE = √674 = 25.96 or 26

Answer:

.01 + .3 = 0.31

Step-by-step explanation:

Answer:

The average rate of change of the function over the interval is of 6.

Step-by-step explanation:

Average rate of change:

The average rate of change of a function h(x) over an interval [a,b] is given by:

[tex]A = \frac{h(b)-h(a)}{b-a}[/tex]

In this question:

Over the interval [-9,-2], so [tex]a = -9, b = -2, b - a = -2 -(-9) = 7[/tex]

The function is:

[tex]h(x) = -x^2 - 5x + 14[/tex]

[tex]h(-9) = -9^2 -5(-9) + 14 = -81 + 45 + 14 = -22[/tex]

[tex]h(-2) = -2^2 -5(-2) + 14 = -4 + 10 + 14 = 20[/tex]

Then

[tex]A = \frac{h(-2)-h(-9)}{7} = \frac{20-(-22)}{7} = \frac{42}{7} = 6[/tex]

The average rate of change of the function over the interval is of 6.

Answer:

700

Hope this helps!!

Answer:

700

Step-by-step explanation:

Answer:

The rate at which the tip of his shadow is moving down is [tex]\frac{24}{15} ft/sec[/tex]

Step-by-step explanation:

Given - A flood lamp is installed on the ground 200 feet from a vertical wall. A six-foot-tall man is walking towards the wall at the rate of 30 feet per second.

To find - How fast is the tip of his shadow moving down the wall when he is 50 feet from the wall ?

Proof -

From the given information, the figure becomes

Triangle ABC and Triangle DBE are similar triangle

AC/DE = BC/BE

⇒h/6 = 200/(200-x)

⇒h = 1200/(200 -x)

Now,

Differentiate h with respect to t, we get

[tex]\frac{dh}{dt} = 1200(-\frac{1}{(200-x)^{2} } )(-1)\frac{dx}{dt}[/tex]

⇒[tex]\frac{dh}{dt} = (\frac{1200}{(200-x)^{2} } )\frac{dx}{dt}[/tex]

Now,

If the rate of the tip is moving down the wall

At x = 50 feet, dx/dt = 30 feet per second

So,

⇒[tex]\frac{dh}{dt} = (\frac{1200}{(200-50)^{2} } )(30)[/tex]

⇒[tex]\frac{dh}{dt} = \frac{1200}{(150)^{2} } (30)[/tex]

⇒[tex]\frac{dh}{dt} = \frac{1200}{(150)(150) } (30)[/tex]

⇒[tex]\frac{dh}{dt} = \frac{24}{15 }[/tex]

So, we get

The rate at which the tip of his shadow is moving down is [tex]\frac{24}{15} ft/sec[/tex]