2
CuCl2 +4KI -> 2 Cul + 4 KCI + 12

2CuCl2 +4KI -> 2 Cul + 4 KCI + 12

Answers

Answer 1

Answer:

Explanation:

This is an example of a limiting reactant question, and is very common as a general chemistry problem.

We first see the balanced equation, that is:

2CuCl2+4KI→2CuI+4KCl+I2

We first need to find the limiting reactant

We see that 0.56 g of copper(II) chloride (CuCl2) reacts with 0.64 g of potassium iodide (KI) . So, let's convert those amounts into moles.

Copper(II) chloride has a molar mass of

134.45 g/mol . So in 0.56 g of copper(II) chloride, then there exist

0.56g134.45g/mol≈4.17⋅10−3 mol

Potassium iodide has a molar mass of

166 g/mol . So, in 0.64 g of potassium iodide, there exist

if it wrong i am sorry


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Question 1 options:

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Without producers, consumers would starve

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Answers

Answer:

All of these answers are correct.

Explanation:

They are all correct because producers make their food(energy) through photosynthesis, they provide food to herbivores and therefore the rest of the food chain, and without them, the food chain would collapse and all the consumers would starve.

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Gucci ghhvhjhsgjjn hvh

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How many moles are in 25.0 grams of KMnO4?

0.124 mol KMnO4
0.158 mol KMnO4
0.199 mol KMnO4
0.316 mol KMnO4

Answers

The answer is: 0.158 mol
You find this by doing:
number of moles (n) = mass (m) / molar mass (M)
n=158.034/25.0

Answer:

158 mol :)

Explanation:

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