1)Pulmonary artery

2)Pulmonary vein

3)Aorta

4)Inferior vena cava



Answer and I will give you brainiliest
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spray him in the eyes and you have until he washes it put

Answer:

The frequency of a sound wave is what your ear understands as pitch. A higher frequency sound has a higher pitch and the lower the period

Answer:

High-frequency sound waves produce high-pitched sounds, and low-frequency sound waves produce low-pitched sounds.

Answer:

a. 104.5 C b. 7.94 × 10⁶ A/m² c. 5.83 × 10⁻⁴ m/s

Explanation:

a. How much electric charge passes through the starter motor?

Using Q = It where Q = electric charge passing through the starter motor, I = current = 110 A and t = time = 0.95 s

So, Q = It = 110 A × 0.95 s = 104.5 C

b. What is the current density in the wire?

The current density, J = I/A where I = current = 110 A and A = cross-sectional area = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m

So, J = I/A

= I/πd²/4

= 4I/πd²

= 4 × 110 A/π(4.20 × 10⁻³ m)²

= 440 A/55.42 × 10⁻⁶ m²

= 7.94 × 10⁶ A/m²

c. How far does an electron travel along the wire while the starter motor is on? (The density of conduction electrons in copper is n = 8.50×1028 1/m3.)

To find how far the electron travels, we need to find the electron drift velocity from

J = nev where J = current density = 7.94 × 10⁶ A/m², n = electron density = 8.50 × 10²⁸ m⁻³, e = electron charge = 1.602 × 10⁻¹⁹ C, v = drift velocity of electrons and A = cross-sectional area of wire = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m

So, v = J/ne

Substituting the values of the variables into the equation, we have

v = 7.94 × 10⁶ A/m² ÷ (8.50 × 10²⁸ m⁻³ × 1.602 × 10⁻¹⁹ C)

v = 7.94 × 10⁶ A/m² ÷ (13.617 × 10⁹ Cm⁻³)

v = 0.583 × 10⁻³ m/s

v = 5.83 × 10⁻⁴ m/s

Answer:

The time it takes the ball to rise equals the time it takes to fall.

Explanation:

because what goes up at some point must come down

Answer:

Explanation:

A compound machine is a combination of two or more simple machines.

BRAINLIEST? plz

Answer:

The following seems to be the summary including its given phrase.

Explanation:

1 Newton force is equal to the 10⁻⁵ dynes. The unit of force will be dyne and the value of force will be 0.1 dynes.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration.

Its SI unit is Newton, MKS unit is kgm/s² and CGS unit is dyne.

The given formulae are;

F = k I l

k is a constant with unit=  N A-1 m-1

I is currently measured in mA = 10⁻³A

l is the length measured in mm= 10⁻³ m

F = k I l

F= N A-1 m-1× 10⁻³A×10⁻³ m

F= 10⁻⁶ N                 ( 1N = 10⁻⁵ dyne)

F= 0.1 dyne

Hence the unit of force will be dyne and the value of force will be 0.1 dynes.

To learn more about the force refer to the link;

https://brainly.com/question/26115859

Answer:

No kinetic energy-because there is no movement

Explanation:

It states that the monk is at complete rest so there is no movement.

Answer:

Is fire matter? Matter is anything that has mass and occupies space. The flame itself is a mixture of gases (vaporized fuel, oxygen, carbon dioxide, carbon monoxide, water vapor, and many other things) and so is matter. The light produced by the flame is energy, not matter.

Answer:

I don't understand the question

Explanation:

sorry I cant help because I am just a first former

Answer: Yes the answer is C

Explanation: Look a pictures of field vectors, they are represented with the arrows.

Complete question:

Consider the hypothetical reaction 4A + 2B → C + 3D

Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 1.600 M?

Answer:

the final concentration of A is 0.992 M.

Explanation:

Given;

time of reaction, t = 4.0 s

rate of change of the concentration of B =  -0.0760 M/s

initial concentration of A = 1.600 M

⇒Determine the rate of change of the concentration of A.

From the given reaction: 4A + 2B → C + 3D

2 moles of B ---------------> 4 moles of A

-0.0760 M/s of B -----------> x

[tex]x = \frac{4(-0.076)}{2} \\\\x = -0.152 \ M/s[/tex]

⇒Determine the change in concentration of A after 4s;

ΔA = -0.152 M/s  x 4s

ΔA = -0.608 M

⇒ Determine the final concentration of A  after 4s

A = A₀ + ΔA

A = 1.6 M + (-0.608 M)

A = 1.6 M - 0.608 M

A = 0.992 M

Therefore, the final concentration of A is 0.992 M.

All four choices are correct responses. (A), (B), (C), (D)

Answer:

θ = 63.5º

Explanation:

       [tex]sin \theta_{i}* n_{i} = sin \theta_{r}* n_{r} (1)[/tex]

       where θi = angle of incidence  (with the normal to the surface)

                  θr = angle of refraction (with the normal to the surface)

                  ni = index of refraction of denser medium = 1.520

                  nr = index of refraction of less dense medium = 1.361

       [tex]sin \theta_{i} = \frac{1.361}{1.520} = 0.895 (3)[/tex]

       ⇒   θi = sin⁻¹ (0.895) = 63.5º

Answer:

Yes.

Explanation:

Answer:

I do believe it is. (more characters for character limit)

Answer:

Eliza’s suggestion is the most promising

Explanation:

Newton’s law of universal gravitation is [tex]F = G\frac{m_1m_2}{r^2}[/tex] where G is a constant and both masses are constant in this experiment as well. So it only depends on r, the distance between the center of mass of both objects.

Bringing it high in the sky, as Flo suggests, is definitely not a good idea because it only increases the distance from the center of the Earth mass.

A mountain contains significant mass, so the center of the Earth mass is somewhat shifted to regions with the largest mountains. However, standing on top of a mountain, as Lorenzo suggests, doesn’t help since the shift of the center of mass, if any, is far smaller than the height of the mountain.

Standing near sea level, as Eliza suggests, is a good way to minimize the distance to the center of the Earth mass.

Answer:

Explanation:

An N-type semiconductor is a type of material used in electronics. It is made by adding an impurity to a pure semiconductor such as silicon or germanium. The impurities used may be phosphorus, arsenic, antimony, bismuth or some other chemical element. They are called donor impurities