A 1.3-kg book rests on a table. A downward force of 15 N is exerted on the top of the book by a hand pushing down on the
book
What is the net force on the book?

Answer:

B. The thrown ball

Explanation:

because you are giving the ball a higher force causing the acceleration to be higher

Answer:

*Doppler effect by the displacement or towards the red

*The microwave temperature of the universe

Explanation:

The expansion of the universe can be visualized in various facts

* the stars and galaxies are moving away from us, this is observed in the Doppler effect by the displacement or towards the red of the hydrogen lines.

* The microwave temperature of the universe that comes from everywhere, this temperature is the rest of the temperature of an initial great explosion (big ban), for which the expanding universe must cool down.

Answer:

0.54

Explanation:

2.7÷5 = 0.54

Hope this helps!

Answer:

b down

Explanation:

because as she is jumping she is bending her nees so the acceleration is down words

Answer:

b down

Explanation:

Answer:

the force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface

Explanation:

Answer:

Gravitational force is the force of attraction in which body having certain mass in the universe attracts every other body which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

c.  6.6

The x-component of a vector can be either sinθ or cosθ, depending on which angle you are given.

Cosθ always goes with the side of a right triangle that is adjacent to (touches) the given angle.

The projection of a vector quantity on the x axis of a coordinate system.

If you shine a light straight down onto that vector, then the length of its shadow on the x-axis is

x-component = 8· cosine(34°)

x-component = 8 · (0.829)

x-component = 6.6

Therefore,

6.6  is the length of the x-component of the vector.

Learn more about x- component here:

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Answer:

Explanation:

Time of flight = 2 x u sinα / g where u sinα is vertical component of projectile's velocity u .

So Time of flight = 2 x vertical component / g

vertical component = constant

g is also constant so

Time of flight will also be constant .

It will remain unchanged .

Answer:

The more velocity an object has the harder it is to slow it down

Explanation:

slow it down

Answer:

momentum=31.5

Explanation:

given,

mass(m)=2.1kg

velocity(v)=15m/s

momentum(p)=?

now,

p=mv

p=15×2.1

p=31.5 kgm/s

1 Newton force is equal to the 10⁻⁵ dynes. The unit of force will be dyne and the value of force will be 0.1 dynes.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration.

Its SI unit is Newton, MKS unit is kgm/s² and CGS unit is dyne.

The given formulae are;

F = k I l

k is a constant with unit=  N A-1 m-1

I is currently measured in mA = 10⁻³A

l is the length measured in mm= 10⁻³ m

F = k I l

F= N A-1 m-1× 10⁻³A×10⁻³ m

F= 10⁻⁶ N                 ( 1N = 10⁻⁵ dyne)

F= 0.1 dyne

Hence the unit of force will be dyne and the value of force will be 0.1 dynes.

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Answer:

B. It increases

Explanation:

Im sure

Answer:

I don't know this for sure, but I think its because they need to be able to sit in their seats without flying in the air.

Explanation:

Because of the centrifugal force he ship must rotate so that passengers feel effects similar to gravity.

''Centrifugal force is force acting on a body performing circular motion, which is along radius of the circle and directed outwards from the center of circle".  Since Centrifugal force acts at right angle to the tangential velocity of the body, there is no displacement in the direction of the force, hence no work done. It has newton(N) as Si unit.

centripetal force is given by,

F= mv²÷r

Where m is mass of the body v is velocity of the body r is radius of circle at which body is moving.

When space ship rotate to the certain angular velocity, centrifugal force will act on each object in the space ship. that force will force the object radially outwards as result all will stuck on the floor and all will experience the feel of gravity.

To know more about gravity :

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Answer:

The answer is "[tex]12682.267\ \ \frac{W}{m^2}[/tex]"

Explanation:

Calculating the mass flow rate of fluid:

[tex]m= \rho AV[/tex]

   [tex]= \rho \frac{\pi}{4} D^2\ V\\\\= 100 \times \frac{\pi}{4} \times (0.0127)^2\times 0.2\\\\=0.0253 \ \frac{kg}{s}\\\\[/tex]

Calculating the amount of heat transfer.

[tex]q =m\timesC_p(T_{m,0}-T_{m,i})[/tex]

  [tex]=0.0253 \times 4000 (75-25)\\\\=0.0253 \times 4000(50)\\\\=0.0253 \times 200,000 \\\\= 5060 \ W[/tex]

Calculating the required value for heat flux:

[tex]q"=\frac{q}{A_s}[/tex]

   [tex]=\frac{q}{\pi DL}\\\\= \frac{5060}{\pi \times 0.0127 \times 10}\\\\= 12682.267 \frac{W}{m^2}\\[/tex]

Answer:

[tex]a=5.51\ m/s^2[/tex]

Explanation:

Given that,

The mass of a bag of acorns, m = 8.5 kg

The force acting on the bag = 80 N

The force of friction = 32 N

We need to find the acceleration of the bag of acorns.

Net force acting on it is = 80 N - 32 N

= 48 N

Let a be the acceleration of the bag of acorns. So,

F = ma

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{48}{8.7}\\\\a=5.51\ m/s^2[/tex]

So, the acceleration of the bag of acorns is [tex]5.51\ m/s^2[/tex].

Answer: Yes the answer is C

Explanation: Look a pictures of field vectors, they are represented with the arrows.

Answer:

This may help

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

Answer:

a. 1.642 Ns/m b. 0.0294 N c. 5 × 10⁵ ms

Explanation:

a. Presuming the resistive force R = −bv, what is the value of b (N s/m)?

Using the equation of motion on the object,

W + R = ma where W = weight of the mass = mg where m =mass of marble = 3.00 g = 0.003 kg and g = acceleration due to gravity = 9.8 m/s² , R = resistive force = -bv where v = velocity and a = acceleration of marble.

So,

mg - bv = ma

At terminal speed, a = 0,

So, mg - bvt =m(0)

mg - bvt = 0

mg = bvt

b = mg/vt since terminal speed vt = 1.79 cm/s = 0.0179 m/s

So, b = 0.003 kg × 9.8 m/s²/0.0179 m/s

b = 0.0294 kgm/s² ÷ 0.0179 m/s

b = 1.642 Ns/m

b. What is the strength of the resistive force (N) when the marble reaches terminal speed?

Since the resistive force R = -bv, at terminal speed, vt

R = -bvt

R = -1.642 Ns/m × 0.0179 m/s

R = -0.0294 N

So, its strength is 0.0294 N

(c) How long in milliseconds does it take for it to reach a speed of 0.600vt?

Using mg - bv = ma where a = dv/dt,

mg - bv = mdv/dt

g - bv/m = dv/dt

separating the variables, we have

dv/(g - bv/m) = dt

Integrating, we have

∫dv/(g - bv/m) = ∫dt

(-b/m)/(-b/m) × ∫dv/ (g - bv/m) = ∫dt

1/(-b/m) ∫(-b/m)dv/(g - bv/m) = ∫dt

1/(-b/m) ㏑(g - bv/m) = t + C

㏑(g - bv/m) = -m/bt - mC/b

㏑(g - bv/m) = -m/bt + C'  (C' = -mC/b)

taking antilogarithm of both sides, we have

g - bv/m = exp(-m/bt + C')

g - bv/m = exp(-m/bt)expC'

g - bv/m = Aexp(-m/bt) (A = expC')

bv/m = g - Aexp(-m/bt)

v = mg/b - (Am/b)exp(-m/bt)

when t = 0, v = 0 (since the marble starts from rest)

0 = mg/b - (Am/b)exp(-m/b(0))

0 = mg/b - (Am/b)exp(0))

-mgb = -Am/b

A = g

v = mg/b - (mg/b)exp(-m/bt)

when v = 0.600vt = 0.600 × 0.0179 m/s = 0.01074 m/s

mg/b = 0.003 kg × 9.8 m/s²/1.642 Ns/m = 0.0179 m/s and m/b = 0.003 kg/1.642 Ns/m = 0.00183/s

So,v = mg/b - (mg/b)exp(-m/bt)

0.01074 m/s = 0.0179 m/s - (0.0179 m/s)exp[(-0.00183/s)t]

0.01074 m/s - 0.0179 m/s = - (0.0179 m/s)exp[(-0.00183/s)t]

-0.00716 m/s = - (0.0179 m/s)exp[(-0.00183/s)t]

exp[(-0.00183/s)t] = -0.00716 m/s/-0.0179 m/s

exp[(-0.00183/s)t] = 0.4

taking natural logarithm of both sides, we have

(-0.00183/s)t = ㏑(0.4)

(-0.00183/s)t = -0.9163

t = -0.9163/-0.00183

t = 500 s

t = 500 × 1000 ms

t = 5 × 100000

t = 5 × 10⁵ ms

Answer:

a)[tex]|N|=9.83\: N[/tex]  at the top

[tex]|N|=33.37\: N[/tex] at the botton

b) The minimum velocity will be [tex]v=4.43\: m/s[/tex].

Step-by-step explanation:

a) Using the second Newton's law, at the top of the circle we have.

[tex]\Sigma F=ma_{c}[/tex]

The forces at the top are the weight and the normal force.

[tex]W-N=m\frac{v^{2}}{R}[/tex]

[tex]mg-N=m\frac{v^{2}}{R}[/tex]

[tex]N=mg-(m\frac{v^{2}}{R})[/tex]

[tex]N=1.2*9.81-(1.2\frac{6^{2}}{2})[/tex]        

[tex]N=-9.83\: N[/tex]  

[tex]|N|=9.83\: N[/tex]      

At the botton of the circle we have:

[tex]N-W=m\frac{v^{2}}{R}[/tex]

[tex]N-mg=m\frac{v^{2}}{R}[/tex]

[tex]N=1.2*9.81+(1.2\frac{6^{2}}{2})[/tex]  

[tex]|N|=33.37\: N[/tex]

b) If we do the normal force equal to zero we can find the minimum velocity, which means:

[tex]W-0=m\frac{v^{2}}{R}[/tex]

[tex]mg=m\frac{v^{2}}{R}[/tex]

[tex]v=\sqrt{Rg}[/tex]

[tex]v=\sqrt{2*9.81}[/tex]

Therefore, the minimum velocity will be [tex]v=4.43\: m/s[/tex].

I hope it helps you!

Answer:

A. 14.14 m/s²

B. 127.26 m/s

C. 572.67 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) of jet = 4250 kg

Force (F) = 60100 N

A. Determination of the acceleration of the jet.

Mass (m) of jet = 4250 kg

Force (F) = 60100 N

Acceleration (a) =?

F = ma

60100 = 4250 × a

Divide both side by 4250

a = 60100 / 4250

a = 14.14 m/s²

B. Determination of the speed of the jet after 9 s.

Initial velocity (u) = 0 m/s

Acceleration (a) = 14.14 m/s²

Time (t) = 9 s

Final velocity (v) =?

v = u + at

v = 0 + (14.14 × 9)

v = 0 + 127.26

v = 127.26 m/s

C. Determination of the distance travelled during the time.

Initial velocity (u) = 0 m/s

Acceleration (a) = 14.14 m/s²

Time (t) = 9 s

Distance travelled (s) =?

s = ut + ½at²

s = (0 × 9) + (½ × 14.14 × 9²)

s = 0 + (7.07 × 81)

s = 0 + 572.67

s = 572.67 m.

Answer:

1.241/s

Explanation:

From this question, we have the following information:

Mass of oscillator = 310

The time Period, t = 0.180

Decrease = 20 %

Amplitude of oscillation has the formula

A = Aoe^yt

1-20% = 80%

= 0.80

Y x 0.18 = -ln(0.8)

= 0.18Y = 0.2234

Y = 0.2233/0.18

Y = 1.241/s

The damping constant y is Therefore equal to 1.241s

Answer:

48

Explanation:

The formula is d, time t, and speed or rate of travel r is:

d = rt.

We know that d = 120 km and t = 2 hours and 30 minutes = 2.5 hrs.

So you now plug in for d and t to find r, we get:

120 km = r(2.5 hrs)

divide both sides by 2.5 and we get

120 km/2.5 hrs = [r(2.5 hrs)]/2.5 hrs

120 km/2.5 hrs = r(2.5 hrs/2.5 hrs)

48 km/hr = r(1)

r = 48 km/hr

Speed = (distance covered) / (time to cover the distance)

Speed = (120 km) / (2.5 hr)

Speed = (120/2.5) (km/hr)

Speed = 48 km/hr (B)

so 30.8/13= is 2.369

so round your ans to I dp which is

2.4d/kg

All four choices are correct responses. (A), (B), (C), (D)

Answer:

|---20----|

|            |

| 50       |50

|---D--->|

Start      End

Total displacement(D)  20 yards (East).

Explanation:

Answer:

The answer is 6.

90 - (3+9) • 7

90 - (12) • 7

90 - 12 • 7

90 - 84

6

Answer:

B. 4700 J

Explanation:

Given the following data;

Mechanical energy = 4900J

Mass = 100kg

Velocity = 2m/s

To find the potential energy;

Mechanical energy = kinetic energy + potential energy

First of all, we would determine the kinetic energy of the object;

K.E = ½mv²

K.E = ½*100*2²

K.E = 50*4

K.E = 200 J

Substituting into the equation, we have;

4900 = 200 + P.E

P.E = 4900 - 200

P.E = 4700 Joules

Answer:

hardness, luster, color, streak, specific gravity, cleavage, fracture, and tenacity.

Explanation:

doesn't really need one.

Answer:

a

Explanation: