Answer:
The ratio of the new internal energy to the old is 4
Explanation:
let the old pressure of the gas = P₁
let the old volume of the gas = V₁
then, the new pressure of the gas = 2P₁
the new volume of the gas = 2V₁
The internal energy of the gas is given as;
PV = nRT
PV = k
P₁V₁ = P₂V₂
[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]
The ratio of the new internal energy to the old is 4
A large bagel spins with angular speed w about its center. A smaller bagel spins with triple the angular speed.
How does the period Tlarge of the large bagel compare with the period Tsmall of the small bagel?
Answer:
T large = 3T small
Explanation:
It's just 3 times larger
the question is in a picture
Answer:
same for all objects
Explanation:
earth pulls every object by same force of gravity
a car is initially at rest. ten seconds later it is moving 30 m/s. what is the car's acceleration
Answer:
The car's acceleration is [tex]3\ m/s^2[/tex]
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes uniformly over time.
The final speed is given by:
[tex]v_f=v_o+at[/tex]
Where a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
Using the equation above we can solve for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
The car is initially at rest (vo=0) and t=10 seconds later it's moving at vf=30 m/s, thus its acceleration is:
[tex]\displaystyle a=\frac{30-0}{10}[/tex]
[tex]\displaystyle a=\frac{30}{10}=3[/tex]
[tex]a = 3\ m/s^2[/tex]
The car's acceleration is [tex]3\ m/s^2[/tex]
calculate the load placed 10m from the fulcrum that can be balanced by an effort of 5 N applied at a distance of 4 m from the fulcrum in a lever
Answer:
A = 2 m from fulcrum
Explanation:
Product of anti clockwise = Product of clockwise moment
5 × 4 = 10 × A
20 = 10 x A
A = 20 / 10
A = 2 m from fulcrum
A water-skier of mass 75.0 kg initially at rest is being pulled due east by a horizontal towrope. The rope exerts a force of 365 N (east). The water (and air) exerts a combined average frictional force of 190 N (in the opposite direction). How fast will the skier be moving after a distance of 38.0 m?
Answer:
The skier will be moving at 13.31 m/s.
Explanation:
To calculate the velocity of the skier we need to find the acceleration, as follows:
[tex] \Sigma F = ma [/tex]
[tex] F_{r} - F_{f} = ma [/tex]
Where:
[tex] F_{r}[/tex]: is the force due to the rope = 365 N
[tex] F_{f}[/tex]: is the combined average frictional force = 190 N
m: is the mass = 75.0 kg
[tex] a = \frac{365 N - 190 N}{75.0 kg} = 2.33 m/s^{2} [/tex]
Now, we can calculate the velocity of the skier by using the following kinematic equation:
[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]
Where:
[tex] v_{f}[/tex]: is the final velocity =?
[tex] v_{0}[/tex]: is the initial velocity = 0 (the skier is initially at rest)
d: is the distance = 38.0 m
[tex] v_{f} = \sqrt{2*2.33 m/s^{2}*38.0 m} = 13.31 m/s [/tex]
Therefore, the skier will be moving at 13.31 m/s.
I hope it helps you!
A stretched string is 1.95 m long and has a mass of 19.1 g. When the string oscillates at 440 Hz, which is the frequency of the standard A pitch, transverse waves with a wavelength of 16.7 cm travel along the string. Calculate the tension T in the string.
T= ________ N
Answer:
The tension in the string is 52.89 N.
Explanation:
Given;
mass of the string, m = 19.1 g = 0.0191 kg
length of the string, L = 1.95 m
⇒mass per unit length, μ = 0.0191 / 1.95 = 0.009795 kg/m
Also Given;
frequency of the string, F = 440 Hz
wavelength of the sound wave, λ = 16.7 cm = 0.167 m
⇒the speed of the wave, v = Fλ = 440 x 0.167 = 73.48 m/s
The tension T in the string is calculated as;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu}\\\\T = v^2 \mu\\\\T = (73.48)^2 (0.009795)\\\\T = 52.89 \ N[/tex]
Therefore, the tension in the string is 52.89 N.
Choose the correct answer
Answer:
1.(c) 7
2.(d) 900
3.(b) two
4.(c) 0.0007
5.(d)0.0004
Explanation:
(1) White light after reflection through prism splits into 7 colors.
(2) Arabs and Chinese knew about lenses in about 900 AD
(3) There are Two more colors in the spectrum which cannot be seen with naked eye.
(4) Wavelength of red light is 0.0007mm
(5) Wavelength of violet light is 0.0004mm
PLZZZ I will give brainliest. A ball that contains mechanical energy is rolled across the floor. You notice the ball is slowing down. If the ball started with 20 units of energy, explain how much energy would there be when the ball comes to a complete stop? How can you tell?
Answer: because of friction it will stop rolling completly
Explanation:
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level (b) is 60.0 dB.
How many meters from the source would the sound level be one-fourth the sound level at 3.00 m?
Given that,
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.
To find,
The distance from the source would the sound level be one-fourth the sound level at 3.00 m.
Solution,
The intensity from a source is inversely proportional to the distance.
Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?
Using relation :
[tex]\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\\r_2^2=\dfrac{I_1r_1^2}{I_2}\\\\r_2^2=\dfrac{60\times (3)^2}{15}\\\\r_2=6\ m[/tex]
So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.
A rock is at the top og a 20 meter tall hill. The rock has a mass of 10 kg. How much potential energy does it have
Answer:
1962 joules
Explanation:
m = 10 kg
h = 20 m
g = 9.81 ms^-2
PE = ?
PE = MGH
PE = 10 x 9.81 x 20
PE = 1962 joules
Alex kicks a soccer ball with a force of 250 N. The force is applied to the soccer ball for 0.05 seconds. What is the impulse applied to the ball?
Answer:
12.5 Ns.
Explanation:
From the question given above, the following data were obtained:
Force (F) = 250 N.
Time (t) = 0.05 s
Impulse =?
Impulse can be obtained by using the following formula:
Impulse = force × time
Impulse = 250 × 0.05
Impulse = 12.5 Ns
Thus, the Impulse applied to the ball is 12.5 Ns.
An image is a copy of an objecí formed by what light
Answer:
Plane mirror
Explanation:
A virtual image is a copy of an object formed at the location from which the light rays appear to come.
As the mass of a body increases, its gravitational force of attraction to the Earth...
Answer:
the answer may be mass and distance
What is the power output in watts and horsepower of a 70.0-kg sprinter who accelerates from rest to 10.0 m/s in 3.00 s
Given that,
Mass of a sprinter = 70 kg
Initial velocity, u = 0
Final velocity, v = 10 m/s
Time, t = 3 s
To find,
Power output.
Solution,
The work done by the sprinter is equal to its kinetic energy.
[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\\=\dfrac{1}{2}\times 70\times 10^2\\\\=3500\ J[/tex]
Let P is power output. Power is equal to work done per unit time. So,
[tex]P=\dfrac{3500\ J}{3\ s}\\\\=1166.67\ W[/tex]
So, the power output is 1166.66 W.
help asap
what is the force responsible for seafloor spreading and the formation of new ocean floor at mid ocean ridges
Answer:
magma
Explanation:
I wanna think that that's right if it's not in so sorry but I'm pretty sure it's magma
Intrusive magma forced up towards the ocean ridge is the force responsible for seafloor spread. The correct option is B.
What is seafloor spreading?Seafloor spreading is a process that occurs at mid-ocean ridges where the oceanic crust is produced by volcanic activity and then moves away from the ridge.
Plate tectonics' continental drift is explained by seafloor spreading. When oceanic plates diverge, tensile stress causes fractures in the lithosphere.
Ridge push occurs when plates are not subducting and are driven by gravity as they slide off the elevated mid-ocean ridges.
Magma rises from the fractures at a spreading center and cools on the ocean floor to form a new seabed.
The spreading rate is the rate at which an ocean basin widens due to seafloor spreading and determines whether the ridge is fast, intermediate, or slow.
Thus, the correct option is B.
For more details regarding seafloor spreading, visit:
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A box takes 450 N to start moving when the coefficient of static friction is 0.25. What is
the box's weight?
Alex, parked by the side of an east-west road, is watching car P, which is moving in a westerly direction. Barbara, driving east at a speed 52 km/h, watches the same car. Take the easterly direction as positive. If Alex measures a speed of 78 km/h for car P, what velocity will Barbara measure?
Answer:
[tex]v_{PB} = 130\ km/h[/tex]
Explanation:
Since, Alex is at rest. Therefore, the speed measured by him will be the absolute speed of car P. Therefore, taking easterly direction as positive:
[tex]Absolute\ Velocity\ of\ Car\ P = v_{P} = -78\ km/h[/tex]
And the absolute velocity of Barbara's Car is given as:[tex]Absolute\ Velocity\ of\ Barbara's\ Car = v_{B} = 52\ km/h[/tex]
Now, for the velocity of Car p with respect to the velocity of Barbara's Car can be given s follows:
[tex]Velocity\ of\ Car\ P\ measured\ by\ Barbara = v_{PB} = v_{B}-v_{P}\\\\v_{PB} = 52\ km/h-(-78\ km/h)[/tex]
[tex]v_{PB} = 130\ km/h[/tex]
A ball is tied to the end of a cable of negligible mass. The ball is spun in a circle with a radius 7.1 m making 3.9 revolutions every 9.4 second. What is the centripetal acceleration of the ball?
Answer:
48,2 m/s²
Explanation:
We're gonna use the Centripetal Acceleration formula: v² / r but before that, we got to know the velocity, that is not shown clearly to us, so....
To know the velocity let's calculate the distance that the ball traveled
The circumference of a circle formula is:
2piR
2 . 3,14 . 7,1 | That is equal to 44,588 m
We know that the ball traveled this distance 3,9 times, so...
44,588 . 3,9 = 173,8932 m
Ok, now we have the distance, just need to know the time, that is 9.4 seconds.
Velocity = Distance / Time
V = 173,8932 / 9,4
V = 18,5 (approximate)
So...
We are back to the first formula:
Ca = v² / r
Ca = 18,5² / 7.1
Ca = 48,2 m/s² (approximate)
I hope it is correct, hahaha.
Elizabeth was a brilliant lawyer until she began hearing voices and seeing things that are not there. She also has trouble with her thought processes and making sense in her speech. She is suffering from:
A. fugue
B. schizophrenia
C. anxiety
D. dissociation
Answer:
B) Schizophrenia
Explanation:
Hope this helps!
A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical oscillations having a period of 3.50 s. Find the force constant of the spring.
Answer:
17.71N/m
Explanation:
The period of the spring is expressed according to the expression;
[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\[/tex]
m is the mass of the object
k is the force constant
Given
m = 5.50kg
T = 3.50s
Substitute into the formula;
[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} = \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k = 17.71N/m[/tex]
Hence the force constant of the spring is 17.71N/m
HELP PLEASE
When a magnet spins in a oil of wire it generates
A. Magnetism
B.convection
C. Radiation
D.electricity
Answer:
A, Magnetism
Explanation:
An ordinary electric generator produces electric power by spinning a strong magnet inside a set of wire coils. As the magnet spins, its magnetic field sweeps across the coils and gives rise to electric fields in those coils.
Hope this helps!!
The physical quantity which have both magnitude and direction is a vector?why?
Answer:
hiiiiiiiiiiiii baby.........
A monatomic ideal gas with volume 0.230 L is rapidly compressed, so the process can be considered adiabatic. If the gas is initially at 1.01 105 Pa and 3.00 102 K and the final temperature is 489 K, find the work done by the gas on the environment, Wenv.
Answer:
The value is [tex]W = - 17.53 \ J[/tex]
Explanation:
From the question we are told that
The volume is [tex]V = 0.230 \ L = 0.230 *10^{-3} \ m^{-3}[/tex]
The initial pressure is [tex]P_1 = 1.01105 \ Pa[/tex]
The initial temperature is [tex]T_1 = 3.00*10^2 \ K[/tex]
The final temperature is [tex]T_2 = 489 \ K[/tex]
Generally for an adiabatic process the workdone is mathematically represented as
[tex]W = - \Delta U[/tex]
Here [tex]\Delta U[/tex] is the internal energy of the system which is mathematically represented as
[tex]\Delta U = \frac{3}{2} * nR \Delta T[/tex]
So
[tex]W = - \frac{3}{2} * nR \Delta T[/tex]
Generally from ideal gas equation we have that
[tex]n = \frac{P_1V }{ RT_1 }[/tex]
Here R is the gas constant with value [tex]R = 8.314 J/mol\cdot K[/tex]
So
[tex]n = \frac{1.01 *0^{5} * 0.230 *10^{-3}}{ 8.314 * 3.0*10^2 }[/tex]
=> [tex]n = 0.009313 \ mol[/tex]
So
[tex]W = - \frac{3}{2} * 0.009313 * 8.314 * (451 - 3.00*10^2)[/tex]
=> [tex]W = - 17.53 \ J[/tex]
The activity of mining has direct negative effects on
a. atmosphere
b.hydrosphere
c.biosphere
d.geosphere
Answer:
A
Explanation:
When coal is burned it releases many harmful chemicals into the air, such as methane (greenhouse gas) and contributes to global warming
A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer
Answer:
After 3secondsExplanation:
A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer
Using the formula for calculating speed expressed as;
Speed = Distance/Time
Given;
Distance = 3km = 3000m
Speed = 1000m/s
Required
How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer (Time)
From the formula;
Time = Distance/speed
Time = 3000/1000
Time = 3seconds
Hence the sound of the aircraft is heard after 3 seconds
Which is the luminous object?
An astronaut on the Moon releases a rock from rest and allows it to drop straight downward. If the acceleration due to gravity on the Moon is 1.62m/s2 and the rock falls for 2.4s before hitting the ground, what is its speed just before it lands?
Answer:
speed before landing = 3.9 m/s (3 s.f.)
Explanation:
As rock is released from rest, u = 0 m/s a = 1.62 m/s² t = 2.4 s v = ?
v = u + at
v = 0 + (1.62 x 2.4)
v = 3.888 = 3.9 s (3 s.f.)
Hope this helps!
The speed of the rock before hitting the ground is 3.89 m/s
The given parameters;
acceleration due to gravity on moon, g = 1.62 m/s²
time taken for the object to fall, t = 2.4 s
To find:
the speed of the object before hitting the ground;The maximum height of fall of the rock is calculated as;
[tex]h = v_0t + \frac{1}{2} gt^2\\\\v_0 = 0\\\\h = \frac{1}{2} gt^2\\\\h = 0.5 \times 1.62 \times 2.4^2 \\\\h = 4.67 \ m[/tex]
The speed of the rock before hitting the ground is calculated as;
[tex]v_f^2 = v_0 ^2 + 2gh\\\\v_f^2 = 0 + 2\times 1.62 \times 4.67\\\\v_f^2 = 15.13\\\\v_f = \sqrt{15.13} \\\\v_f = 3.89 \ m/s[/tex]
Thus, the speed of the rock before hitting the ground is 3.89 m/s
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Starting with the definitions of momentum and kinetic energy, derive an equation for the kinetic energy of a particle expressed as a function of its momentum.
Answer:
[tex]K.E = (\frac{1}{2})Pv[/tex]
Explanation:
The momentum of a particle is defined as the product of its mass and velocity:
[tex]P = mv[/tex] -------------------- equation (1)
where,
P = momentum of the particle
m = mass of the particle
v = velocity of the particle
The kinetic energy of the particle is given as follows:
[tex]K.E = (\frac{1}{2})mv^2\\\\K.E = (\frac{1}{2})v(mv)[/tex]
using equation (1), we get:
[tex]K.E = (\frac{1}{2})Pv[/tex]
A 0.50 mº gas tank holds 3.0 moles of ideal monatomic Helium gas at a temperature of 250 K. What is the mms speed of the molecules? (The Boltzmann constant is 1.38 x 10-23 J/K, NA = 6.022 x 1023 molecules/mol.)
Answer:
v = 1247.92 m/s
Explanation:
The formula for kinetic energy is given as follows:
[tex]K.E = \frac{1}{2}mv^2[/tex]
Another formula that is used for Kinetic Energy is given as:
[tex]K.E = \frac{3}{2}KT[/tex]
Comparing both formulae for K.E:
[tex]\frac{1}{2}mv^2 = \frac{3}{2}KT\\\\mv^2 = 3KT\\v = \sqrt{ \frac{3KT}{m}}[/tex]
where,
v = rms speed of helium molecule = ?
K = Boltzmann Constant = 1.38 x 10⁻²³ J/k
T = Absolute Temperature = 250 K
m = mass of helium molecule = 6.646 x 10⁻²⁷ kg
Therefore,
[tex]v = \sqrt{\frac{(3)(1.38\ x\ 10^{-23}\ J/k)(250\ k)}{6.646\ x\ 10^{-27}\ kg}} \\\\[/tex]
v = 1247.92 m/s
Newton's 2nd Law describes the relationship between force, mass, and acceleration of an object with the formula F=ma. Which scenario below will result in the greatest accleration? (AKS 8b / DOK 1)
A. A 20 kg rock thrown with a 100 N force.
B. A 10,000 kg rocket launched with 100,000 N of force.
C. A 2,000 kg car accelerated with a 1000 N force from the engine.
D. A 50 kg student pushed in a chair with a force of 1000 N.
Answer:D
Explanation:If you want to find the acceleration do Force/mass.
The greatest magnitude of acceleration is of 20 m/s², by the student of 50 kg pushing the chair with 1000 N of force. Hence, option (D) is correct.
As per the Newton's second law, " The applied force on an object is equal to the product of mass of object and acceleration cause by the applied force. Then, the mathematical expression is,
F = ma
Here, F is the applied force, m is the mass and a is acceleration.
(A)
For 20 kg mass and 100 N force, the acceleration is,
F = ma
100 = (20)a
a = 5 m/s²
(B)
For 10,000 kg mass of rocket and 100,000 N force, the acceleration is,
F = ma
100 ,000= (10,000)a
a = 10 m/s²
(C) For a 2,000 kg mass of car and force of 1000 N, the acceleration is,
F = ma
1000 = (2000)a
a = 0.5 m/s²
(D) For a mass of 50 kg student and applied force of 1000 N, the acceleration is,
F = ma
1000 = (50)a
a =20 m/s².
Thus, we can conclude that the greatest magnitude of acceleration is of 20 m/s², by the student of 50 kg pushing the chair with 1000 N of force. Hence, option (D) is correct.
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