Acceleration is the time rate of change in velocity.
Acceleration = Rate of change of velocity
NEED ASAP
WILL GIVE YOU 100 BRAINLY
The far point of a nearsighted person is 100 cm. What power glasses must they use to correct this problem and be able to see signs while driving?
Answer:
I need help with this
Explanation:
Expand(Find the cube of):(x+y)³
( x + y )³
x³ + y³ + 3x²y + 3xy²
(or)
x³ + y³ + 3xy (x+y)
7.
The speed of an electromagnetic wave is a constant, 3.0 x 108 m/s. The wavelength of a wave is 0.6 meters.
What is the frequency?
1.8 Hz
5.0 Hz
5.0 x 108 Hz
O 1.8 x 108 Hz
how do you hook an ammeter and a voltmeter in a circuit?
Answer:
ammeter goes in series and a voltmeter goes in parallel
Explanation:
The Hubble Space Telescope (HST) orbits 569 km above Earth's surface. If HST has a tangential speed of 7,750
m/s, how long is HST's orbital period? The radius of Earth is 6.38 x 106m. Make sure to use correct significant
figures.
Answer:
Mean radius of earth = 6.37E6 meters
Orbital radius = .569E6 meters
Total radius = (6.37 + .57) * 10^6 m = 6.94E6 m
P = S / t = 2 * pi * 6.94E6 / 7.75E3 sec = 5630 sec = 93.8 min
what is the length of the X component of the vector plotted below
Answer:
5
Explanation:
If you straighten out the line, it touches the 5, which makes the length 5
The image shown is an illustration of Kepler’s second law. An illustration with a circle representing the sun and a smaller circle representing a planet. The sun is at a focus of a draw ellipse that the planet is on. There are lines drawn radially out from the Sun to the elliptical path of the planet. The planet is at the part of the ellipse that is closest to the sun. The position of the planet is labeled W and the position opposite the planet is labeled Z. The line closest to W is labeled X and the line closest to Z is labeld Y. Which conclusion is best supported by the image? The gravitational force at W is less than the gravitational force at Y. The time needed to travel from W to X is the same as the time needed to travel from Y to Z. The gravitational force at W is the same as the gravitational force at Y. The time needed to travel from W to X is greater than the time needed to travel from Y to Z.
Answer:
B; the time needed to travel from W to X is the same as the time needed to travel from Y to Z.
Explanation:
According to Kepler's Second Law, the time it takes to travel each sweep of area is equal, the same way the area of each section is also equal. Also, this answer is correct on Edge.
Answer:
The answer is B !
Explanation:
I took the test and got it correct
Please help I’ll give brainliest
Answer:
Magnetic Field
Explanation:
4. A current of 3.00 A flows through a resistor when it is connected to a
12.0 - V battery. What is the resistance of the resistor?*
2.4 ohms
36 ohms
4 ohms
0.3 ohms
Answer:
V=IR
12 = 3 ×RESISTANCE
RESISTANCE=12/3
=4 Ohms
answer is the third option
HURRY IM TIMED ON THIS!!
What would make oppositely charged objects attract each other more?
A. increasing the positive charge of the positively charged object and increasing the negative charge of the
negatively charged object
B. decreasing the positive charge of the positively charged object and decreasing the negative charge of the
negatively charged object
C. increasing the distance between the positively charged object and the negatively charged object
D. maintaining the distance between the positively charged object and the negatively charged object
Answer:
The correct answer is A. increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object
A ticker timer 50dots per second. When a body is pulled by a tap through the timer, the distance between the third and fourth dot is 3cm and the distance between fourth and fifth dot is 4cm.What is the acceleration of the body?
Answer:
Explanation:
Time for one dot = 1 /50 = .02 s
Distance between 3 rd and fourth dot is 3 cm and time taken to travel this distance is .02 s
velocity = 3 cm / .02 = 150 cm /s
Distance between 4 th and 5 th dot is 4 cm and time taken to travel this distance is .02 s
velocity = 4 cm / .02 = 200 cm /s
change in velocity = 200 cm/s - 150cm/s = 50 cm /s
Time taken = .02 s
Acceleration = 50 / .02 cm/s²
= 2500 cm/s²
Assuming constant volume, the pressure of a sealed system is 25.0 kPa at 25.0°C. If the temperature of the system increases by 15.0 °C, what is the new pressure of the sealed system?
Answer:
use the gas law equations
Electromagnetic waves travel at a speed of 3.0 x 108 m/s. A radio station transmits waves
with a wavelength of 2.5 x 102 m.
Calculate the frequency of the radio waves.
Answer:
1.2×10⁶ Hz
Explanation:
Applying,
v = λf............. Equation 1
Where v = speed of wave, λ = wavelength, f = frequency.
make f the subject of the equation
f = v/λ............... Equation 2
From the question,
Given: v = 3.0×10⁸ m/s, λ = 2.5×10² m
Substitute these values into equation 2
f = 3.0×10⁸/2.5×10²
f = 1.2×10⁶ Hz
S_I_L_
_O_T_A_L
P_W_R
J_M_
S_E_D_
_A_S_N_
K_C_
Answer:
Football
Power
Jamm
Steady
Kick
An astronaut is said to be weightless when he/she travels in a satellite. Does it mean that the earth does not attract him/her
First of all, what a weight is? weight is m × g.. and when a person is in space then the force of gravity isn't acting on him or her, so yeah it will not have weight, but remember gravity is a very very low, now if a body has more mass, more gravity will act on it right? just imagine the mass of a person and that of earth.. now yes, earth will do exert a force on the astronaut but is negiligable.
. It requires 250 N to lift up a bag full of hockey equipment. How much work is done while carrying it 12 m down the stairs into the basement?
( only need answer no work is needed )
Answer:
Explanation:
Work = force times displacement, therefore,
W = 250(12) so
W = 3.0 × 10³ N*m
What is the momentum of an object with a mass of 50 kg travelling at 8 m/s?
Please answer ASAP
We know that,
p = mv
Where p is momentum,m is mass & v is velocity.From ques. we have;
mass = 50 kgVelocity = 8 m/sSo,
p = 50 × 8
p = 400 kg m/s
p = mv
Clearly, now just put the values
p = 50 × 8
p = 400 kg m/s
What is the constraint forces
Answer:
(1) Support
(2) Tension
(3) Reaction
The constraint forces are forces that occur in pairs such that the net force (effect) is zero
The details of the constraint forces are;
(1) The support force at the top of the swing acting upwards
(2) The tension in the swing rope acting upwards
(3) The (normal) reaction between the legs of the swing frame and the ground
Explanation:
The normal reaction is the force equal in magnitude and opposite in direction to the total weight force the swing and the person on the swing posses due to gravitational attraction which prevents the downward or sideways motion of the entire swing
how much time does a stone take to reach on the surface of the earth drop from the height 20m and what will be it's acceleration due to gravity after 3 seconds
Anwser this Question , i will Brainelist .
Answer:
D option
Explanation:
describe what happens in terms of energy when you blow up a ballon and release it without trying its neck
Answer:
The answer is below
Explanation:
When a gallon is blown the air energy is saved as potential energy which is compressed inside the balloon. However, when the balloon is released without trying its neck, the air energy quickly turned to kinetic energy, in which the air energy keeps moving as the balloon float around the space.
Hence, in short, what happens in terms of energy when you blow up a balloon and release it without trying its neck is that the air energy moves from potential energy to kinetic energy.
Cho q1= 8.10 mũ -8C ; q2 = -8.10 mũ -8C . Đặt tại 2 điểm A và B cách nhau 6cm trong không khí . Xác định lực điện dung dịch lên qo = 8.10 mũ -8C đặt tại : a. CA= 4cm , CB= 10cm b. CA=CB= 5cm c. CA= 6cm , CB= 6cm
Answer:
♂️
Explanation:
♂️♂️♂️
Along a horizontal snow-covered track, a sled, of mass m = 105 kg, slides by the action of a horizontal force of 230 N. The coefficient of friction between the sled and the snow is µ = 0.025.
Answer:
Explanation:
The only thing I can figure you need here is the accleration of the sled. The equation we need to find this is Newton's Second Law that says that sum of the forces acting on an object is equal to the object's mass times its acceleration. For us, that looks like this because of the friction working against the sled:
F - f = ma but of course it's much more involved than that simple equation! We have the F value as 230 N, and we have the mass as 105, but we do not have the frictional force, f, and we need it to solve for a in the above equation. We know that
f = μ[tex]F_n[/tex] where μ is the coefficient of friction, and [tex]F_n[/tex] is the normal force, aka weight of the object. We will use the coefficient of friction and find the weight in order to fill in for f:
[tex]F_n=mg[/tex] so
[tex]F_n=(105)(9.8)[/tex] so the weight of the sled is
[tex]F_n=[/tex] 1.0 × 10³ with the correct number of sig dig there. Now to find f:
f = (.025)(1.0 × 10³) so
f = 25 to the correct number of sig fig. Now on to our "real" equation:
F - f = ma and
230 - 25 = 105a. We have to do the subtraction first, round, and then divide since the rules for addition and subtraction are different from the rules for dividing and multiplying.
230 - 25 will round to the tens place giving us 210. Then
210 = 105a. 210 has 2 sig figs in it while 105 has 3, so we will divide and round to 2 sig fig:
a = 2.0 m/sec²
A foot is 1/3 of a yard. What part of a meter is a millimeter?
1/2
1/5
1/100
1/1000
Answer:
Explanation:
1/1000
If a foot is 1/3 of a yard the 1/1000 part of a meter is a millimeter, therefore the correct answer is option D.
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.
Any additional quantity of that type can be stated as a multiple of the measurement unit.
As given in the problem a foot is 1/3 of a yard then we have to find out what part of a meter is a millimeter,
1 meter = 100 centimeters
1 centimeters = 10 millimeters
1 meter = 100×10 millimeters
1 meter = 1000 millimeters
1 millimeters = 1/1000 meter
Thus, the 1/1000 part of a meter is a millimeter, therefore the correct answer is option D.
Learn more about the unit of measurement from here;
brainly.com/question/12629581
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A student does 686 J of work on an object in 3.1 seconds. What is the power output of the student?
Answer:
221.29 Watts
Explanation:
P=W/t
P=686/3.1
P=221.29 Watts
If you were part of a track and field team, what event would you like to participate in? And why? Please provide at least 3 complete sentences with your explanation.
I wouldn't participate in any event, I'd leave the track and field team.
What will be the ME of a machine that produces a 240 N work with a 300
N work input?
Given:
Solution:
Answer:
Answer:
Efficiency = 80%
Explanation:
Given the following data;
Work output = 240 N
Work Input = 300 N
To find the mechanical efficiency of a machine;
[tex] Efficiency = \frac {Out-put \; work}{In-put \; work} * 100 [/tex]
Substituting into the equation, we have;
[tex] Efficiency = \frac {240}{300} * 100 [/tex]
[tex] Efficiency = 0.8 * 100 [/tex]
Efficiency = 80%
Therefore, the mechanical efficiency of the machine is 80 percent.
What is capacitive reactance and how to find it??
Answer:
Capacitivie reactance is the angular frequency
Explanation:
hope this helps
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Processing Questions:
Directions: Answer the questions below on a clean sheet of paper.
1. How was the result of your physical fitness test in Flexibility and muscular
strength compared to your previous assessments?
2. Did you notice some improvements? If no, what do you need to do to improve
it?
Answer:
How was the result of your physical fitness test in Flexibility and muscular
strength compared to your previous assessments?
Explanation:
Please help ASAP -multiple choice- will give brainliest
Answer:
C. An article written by a scientist
Explanation:
Research-based original articles written by a scientist can act as a primary source of information. Textbooks, dictionaries and encyclopedias are generally classified as secondary sources and are rarely primary sources.