Bella earns 8% commission as a sales person. She sold a grandfather clock that cost $174. How much commission did Bella earn?

Step-by-step explanation:

For RIGHT triangles , you have to know  S-O-H-C-A-H-T-O-A

Use Pythagorean theorem to find Hypotenuse = 13 units

Then:

Sin Φ = Opposite leg / Hypotenuse  =  5/13

Cos Φ = Adjacent leg / Hypotenuse  = 12/13

Tan Φ = Opposite leg / Adjacent leg = 5/12  

D) 8.25

E) 12

F) 13.5

G) 26

H) 28

Answer:

the angles which are formed in matching corners or corresponding corners with the transversal when two parallel lines are intersected by any other line

Chad drinks  389.28  fluid ounces of water in 6 days.

A unit of weight equal to ¹/₁₂ troy pound see Weights and Measures Table. : a unit of weight equal to ¹/₁₆ avoirdupois pound. : a small amount. an ounce of sense.

An ounce (oz) is a unit of weight that is equal to one-sixteenth of a pound. Items that weigh approximately one ounce include a slice of bread and a pencil. A fluid ounce is a unit of liquid volume that is equal to one-eighth of a cup. A medicine cup has a volume of approximately one fluid ounce.

given that,

chad drinks 64.88 fluid ounces of water per day,

so in 6 days

he will drink = 6 x water drink per day

= 6 x 64.88

= 389.28

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The proportional relationship is y = 3x.

What is the proportional relationship?

If the corresponding elements of two sequences of numbers, frequently experimental data, have a constant ratio, known as the coefficient of proportionality or proportionality constant, then the two sequences of numbers are proportional or directly proportional.

Here, we have

Given:

x:  2, 6, 8, 10

y:  6, 18, 24, 30

We have to find the proportional relationship between x and y.

So, we can see from inspection and visual observation that there is a proportional relationship between x and y.

6 = 3  2,  18 = 3  6, 24 = 3  8, 30 = 3  10.

Hence, The proportional relationship is y = 3x.

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Answer:

x = 8, y = 3

Step-by-step explanation:

Assuming the figure is a parallelogram, opposite sides on a parallelogram are equal.

This means that 3x-2 = 2x+6 and 3y-5 = y+1.

To solve these equations:

3x-2 = 2x+6 (collect like terms)

3x-2x = 6+2

x = 8

3y-5 = y+1 (collect like terms)

3y-y = 1+5

2y = 6 (divide both sides by 2)

y = 3

∴ x = 8, y = 3

the area of the region is 13.01 ft².

Area is the region bounded by a plane shape.

To calculate the area of the of the shaded region, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the area is 13.01 ft².

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The best center is the mean because there are no outliers

To determine the best center, we need to examing the ages of the player withing the range of age.

The ages of the players are: 11, 10, 11, 11, 8, 11, 12, 11, 9, 10, 11, 12

In the above list of age, we can seee that there are no outliers are

When there are no outliers in a dataset, the best center to use is the mean

Hence, the best center is the mean

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The quotient function of f(x) and g(x) is given as follows:

(f/g)(x) = 3x^(3/4).

The functions in the context of this problem are defined as follows:

When we want to divide two functions, we just divide each other, hence:

(f/g)(x) = f(x)/g(x) = 3x/x^(1/4).

When we divide two terms with the same base and different exponents, we keep the base and subtract the exponents, hence:

x/x^(1/4) = x^(1 - 1/4) = x^(3/4).

Hence the function is:

(f/g)(x) = 3x^(3/4).

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We can use proportions to solve this problem. If 2 inches represent 75 miles, then we can set up a proportion:

2 inches / 75 miles = x inches / 11 miles

To solve for x, we can cross-multiply:

2 inches * 11 miles = 75 miles * x inches

22 inches = 75 miles * x inches

Divide both sides by 75 miles:

22 inches / 75 miles = x inches

Simplify:

0.2933 inches = x inches

Therefore, 11 miles on the map would be represented by approximately 0.2933 inches.

The absolute deviation for the observation of 16 in the data-set is given as follows:

5.

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations, which is also called the cardinality of the data-set.

Hence the mean of the data-set in this problem is given as follows:

(19 + 16 + 4 + 9 + 7)/5 = 11.

The absolute deviation of 16 is given by the difference between 16 and the mean of 11, hence:

16 - 11 = 5.

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Therefore , the solution of the given problem of unitary method comes out to be Aniya's final grade is 10%.

To complete the assignment, use the iii . -and-true core method, the real variables, and any pertinent information acquired through general and specific questions. In response, customers might be given another opportunity to sample expression the products. We will miss out on important developments in the comprehension of programmes if these changes don't take place.

Here,

Aniya obtained additional credit worth a total of 4 points because she received 44 out of a possible 40 (44 - 40 = 4). We can use the following equation to represent her grade as a percentage:

=> (Points Earned / Total Points) x 100 = percentage.

Inserting the values:

=> Percentage = (4/40) * 100.

=> Ratio = 0.1 x 100

=> percent = 10.

With the extra credit, Aniya's final grade is 10%.

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The smallest positive integer value of n for which 225n is a multiple of 540 is 8.

To determine the smallest positive integer value of n for which 225n is a multiple of 540, we need to find the least common multiple (LCM) of 225 and 540 and then divide it by 225.

To find the LCM of 225 and 540, we can factor both numbers into primes:

225 = 3^2 x 5^2

540 = 2^2 x 3^3 x 5

The LCM will be the product of the highest powers of each prime factor:

LCM = 2^2 x 3^3 x 5^2 = 1800

Now, we divide the LCM by 225:

1800 / 225 = 8

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The first step is to find the mean number of incorrect answers. Since there are 11 questions, and each question has a 50/50 chance of being answered incorrectly, we can expect the student to get 5.5 questions wrong on average.

Next, we need to calculate the variance. To do this, we can use the formula:

Variance = p(1-p)n

Where p is the probability of getting a question wrong (0.5), and n is the number of questions (11).

Variance = 0.5(1-0.5)11 = 1.375

Finally, we can find the standard deviation by taking the square root of the variance:

Standard deviation = sqrt(1.375) = 1.17 (rounded to two decimal places)

Therefore, the standard deviation of the number of incorrect answers on the exam is 1.17.

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The results are:

7a) Explicit = h(n) = [tex]0.87^{n-1}[/tex] * 200.

Recursive = h(0) = 200 and h(n) = 0.87 * h(n-1)

7b) Rebound height = 99.76 cm (rounded to the nearest hundredth).

8a) Explicit formula: A(n) = 575 + 47.50n

Recursive formula: A(0) = 575, A(n) = A(n-1) + 47.50

8b) 30 weeks to save $2000'

7a) Explicit: h(n) = [tex]0.87^{n-1}[/tex] * 200 (

where h(n) = height of the golf ball after n bounces,

0.87 is the rebound factor,

200 is the initial height)

h(n) = [tex]0.87^{n-1}[/tex] * 200

Recursive:  h(0) = 200

h(n) = 0.87 * h(n-1)

where h(n) = the height after n bounces,

h(n-1) = height after (n-1) bounces,

0.87 = rebound factor.

Apply given values:

h(0) = 200

h(n) = 0.87 * h(n-1)

7b) Rebound height, using recursive formula:

h(0) = 200

h(1) = 0.87 * 200 = 174

h(2) = 0.87 * 174 = 151.38

h(3) = 0.87 * 151.38 = 131.70

h(4) = 0.87 * 131.70 = 114.71

h(5) = 0.87 * 114.71 = 99.76 (rounded to the nearest hundredth)

8a)Explicit: A(n) = 575 + 47.50n,

where A(n) = amount of money Jessica has after n weeks,

575 = initial amount given by grandfather,

47.50 = amount Jessica adds each week.

Recursive: A(0) = 575, A(n) = A(n-1) + 47.50,

where A(n) = the amount of money Jessica has after n weeks,

A(n-1) = amount Jessica has after (n-1) weeks

47.50 = amount Jessica adds each week.

8b) Weeks to save $2000:

A(n) = 575 + 47.50n = 2000

Solving for n:

575 + 47.50n = 2000

47.50n = 2000 - 575

47.50n = 1425

n = 1425 / 47.50

= 30 weeks.

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The probability that the sample contains exactly two defective parts is 0.0058.

We may utilize the binomial probability formula to resolve this issue:

P(X = k) is equal to (n pick k) * p * k * (1-p) (n-k)

where n is the sample size, k denotes the number of successes, p denotes the likelihood that a success will occur, and (n pick k) denotes the binomial coefficient, which indicates the number of possible ways to select item k from n.

Here, n = 5, k = 2, and p = 0.025 (due to the fact that 2.5% of the pieces are flawed).

P(X = 2) therefore equals (5 pick 2)*0.025*2*(1 - 0.025)*3

We calculate P(X = 2) = 0.0058 using a calculator.

As a result, there is a 0.0058 percent chance that the sample has exactly two defective components.

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Answer:

B. 12x^2 + 31x + 20

Step-by-step explanation:

Use FOIL (First, Outer, Inner, Last)

(3x + 4)(4x + 5)

12x^2 + 15x +16x + 20

12x^2 + 31x + 20

Answer:

B

Step-by-step explanation:

You are going to want to use the FOIL method. First outer inner last. Multiply 3x*4x to get 12x^2 then multiply 3x*5 to get 15x then multiply 4*4x to get 16x and last multiply 4*5 to get 20. Since 15x and 16x are like terms we add them together to get 31x

In the event that a monopolistic firm takes over superbly competitive advertising, we would anticipate seeing the advertising cost of the great rise and the amount sold drop.

Be that as it may, when a monopolistic firm takes over the showcase, it picks up showcase control and the capacity to impact the cost. The monopolist can charge a better cost than the competitive advertising cost since there are no near substitutes for its item. As the monopolist raises the cost, the amount requested will drop, as customers switch to substitutes or decrease their utilization of the item.

we would anticipate seeing the advertising cost of the great rise and the amount sold fall as the monopolist tries to extend benefits by raising costs. This is often in differentiating from impeccably competitive advertising.

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The probability of reaching into the bucket and randomly drawing three balls numbered 4, 9, and 7 without replacement, in that order, is 1/990, which is a decimal rounded to the nearest millionth is 0.001.

The probability of drawing three balls numbered 4, 9, and 7 without replacement, in that order, can be found by multiplying the probabilities of drawing each ball in the correct order.

The probability of drawing the first ball, numbered 4, is 1/11, since there is only one ball numbered 4 out of 11 balls in the bucket.

After the first ball is drawn, there are 10 balls remaining in the bucket, and the probability of drawing the second ball, numbered 9, is 1/10, since there is only one ball numbered 9 remaining out of the 10 balls in the bucket.

After the first two balls are drawn, there are 9 balls remaining in the bucket, and the probability of drawing the third ball, numbered 7, is 1/9, since there is only one ball numbered 7 remaining out of the 9 balls in the bucket.

Therefore, the probability of drawing the balls numbered 4, 9, and 7 without replacement, in that order, is:

(1/11) * (1/10) * (1/9) = 1/990

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Joel cannot make a right triangle with the current lengths of fencing.

A right triangle is a triangle that has one angle that measures exactly 90 degrees (a right angle). This means that the other two angles of the triangle are acute (measuring less than 90 degrees). The side opposite the right angle is called the hypotenuse, and it is always the longest side of the triangle. The other two sides are called the legs of the triangle.

To check if Joel can make a right triangle with the current lengths of fencing, we can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the lengths of the two shorter sides (legs) is equal to the square of the length of the longest side (hypotenuse).

So, let's check if the measurements satisfy the Pythagorean theorem:

8²  + 15² = 64 + 225 = 289

20²  = 400

According to the Pythagorean theorem, a triangle with sides of length 8 ft, 15 ft, and 20 ft would be a right triangle if it satisfies the equation a²  + b²  = c² , where a and b are the shorter sides (legs) and c is the longest side (hypotenuse). However, in this case, we can see that the sum of the squares of the shorter sides (8²  + 15² ) is not equal to the square of the longest side (20² ), so the measurements cannot form a right triangle.

Therefore, Joel cannot make a right triangle with the current lengths of fencing.

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The opportunity of drawing a chocolate from the bag is 0.4, therefore, the answer is A. 0.4.

Steven has a bag of 20 pieces of candy, out of which 8 are chocolates. If he draws one piece of sweet at random, the opportunity of it being a chocolate may be calculated through dividing the wide variety of chocolates in the bag with the aid of the full quantity of chocolates inside the bag. In this situation, there are 8 chocolates out of 20 total candies.

The formulation to calculate the opportunity is:

P(chocolate) = number of candies / total range of candies

Substituting the given values, we get:

P(chocolate) = 8 / 20

Simplifying this fraction, we get:

P(chocolate) = 0.4

Consequently, the opportunity of drawing a chocolate from the bag is 0.4  

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Identifying  the first term and common difference and writing a recursive rule:

a. an = an-1 - 5, n > 1

b.  an = an-1 + 12, n > 1

a) The first term is 1 and the common difference is -5. To write a recursive rule for this sequence, we can use the formula:

an = an-1 + d

where an is the nth term of the sequence, an-1 is the (n-1)th term, and d is the common difference.

Using this formula, we get the recursive rule:

a1 = 1

an = an-1 - 5, n > 1

b) The first term is 11 and the common difference is 12. To write a recursive rule for this sequence, we can use the same formula as above:

an = an-1 + d

Using this formula, we get the recursive rule:

a1 = 11

an = an-1 + 12, n > 1

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As per the unitary method, the list shows the number of each type of animal on this farm is

Number of pigs = x

Number of horses = 2x

Number of cows = 8x

Let us start by assigning variables to each type of animal on the farm. Let's say the number of pigs is "x".

From the problem statement, we know that there are twice as many horses as pigs. Therefore, the number of horses would be 2x.

Further, we know that there are four times as many cows as horses. So, the number of cows would be 4 times the number of horses. Mathematically, we can represent it as:

Number of cows = 4 * Number of horses

Or, Number of cows = 4 * (2x) = 8x

Therefore, we have the number of each type of animal on the farm as follows:

Number of pigs = x

Number of horses = 2x

Number of cows = 8x

This is the same ratio as we found using the unitary method.

Therefore, our solution is correct.

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Answer:

3.14×10.1×10.1

3.14×102.01

320.311

=320.300

The equation √( x - 1 ) - 5 = x - 8 has 2 valid and no extraneous solution , a valid solution is x = 2 or 5.

Equation is equal to,

√( x - 1 ) - 5 = x - 8

Add 5 on both the side of the equation we get,

⇒ √( x - 1 ) - 5 + 5 = x - 8 + 5

⇒ √( x - 1 ) = x - 3

Squaring both the sides of the equation we get,

⇒ ( √x - 1 )² = ( x - 3 )²

⇒ x - 1 = x² - 6x + 9

⇒ x² - 6x - x +  9 + 1 = 0

⇒ x² -7x + 10 =0

Factorize it using splitting method to get the solution,

⇒ x² - 2x - 5x + 10 =0

⇒ x( x -2 ) - 5 ( x - 2 ) =0

⇒ ( x - 2 ) ( x - 5 ) = 0

⇒  x = 2 or x = 5

Therefore, equation has 2 valid solution and no extraneous solution.

valid solution for x = 2 or 5.

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The above question is incomplete, the complete question is :

Consider this equation.

√( x - 1 ) - 5 = x - 8

The equation has blank and blank. A valid solution for x is blank.

a. The ranges of g(x) and h(x) differ by a constant value of 1, since h(x) is simply g(x) shifted upward by 1 unit. Therefore, the range unit.

b.

Graph of g(x) = 2x + 1 and h(x) = 2x + 2 over the interval 0 < x < 5:

![Graph of g(x) over the interval 0 < x < 5 is (1, 11), while the range of h(x) is (2, 12). This confirms that the range of h(x) is equal to the range of g(x) shifted upward by 1 unit.

g(x) = 2x+1 h(x) = 2x + 2

for the domain 0 < x < 5.

These are two parallel lines where h(x) is 1 unit above g(x) Then, the range of h(x) over the given domain will have endpoints 1 unit greater.

g(0) = 2(0) + 1 g(0) = 0 + 1 g(0) = 1

Evaluating g(x) when x = 5 :

g(5) = 2(5) + 1

g(5) = 10 + 1

g(5) = 11

Then, we can graph g(x) by connecting the points (0, 1) and (5, 11).

Evaluating h(x) when x = 0 :

h(0) = 2(0) + 2 h(0) = 0 + 2 h(0) = 2

Evaluating h(x) when x = 5 :

h(5) = 2(5) + 2

h(5) = 10 + 2

h(5) = 12

Then, we can graph h(x) by connecting the points (0, 2) and (5, 12).

From the graph, the range of g(x) over the given domain is (1, 11) and of h(x) is (2,12)