at the beginning of grade 6 the number of advanced math to the number of regluar math students was 3:8 however after taking placement tests students were moved around chaning the ratio of the number of advanced math students to the number of regluar math students was 4:7 how many student students started in reglaur math and advanced math if there were 92 students in advanced math after the placement test. Please tell me how to do this on a tape diagram

Answer:

Jared transfers $55 to his checking account from his savings account.

Jared spends $55 from his checking account to purchase a college Algebra textbook

Jared withdraws $55 from his checking account

Hope this helps!

Answer:

4abc..............................

Answer:

The answer I got was 266

Step-by-step explanation:

700 - 62% = 266

62% = 434

700 - 434 (62%) = 266

Answer:

the missing angle is 73

Answer:

Z^10

Step-by-step explanation:

Answer:

multiply 5*2=10

your answer will be =z^10

Step-by-step explanation:

Answer:

it would take him 19 track practices

Step-by-step explanation:

26miles - 7miles= 19miles

96.666..., or about 97 minutes/every mile.

Answer:

Step-by-step explanation:

We need to set the equation equal to 0

-4 - x > 0

+ -4   +   -4

Answer:

13x + x^2 - 9

Step-by-step explanation:

You have to distribute then eliminate redundant parentheses then subtract the numbers then combine like terms then multiply by one then combine like terms and then the answer is 1  13x + x^2 - 9.

Answer:

A(-8,5)

Step-by-step explanation:

Given two points (-6, 3), and (-10, 7). The midpoint is calculated by averaging the x, and y values of two coordinates. As (-10, 7) is the the first point (x1, y1), and (-6, 3) is the second point (x2, y2).

[tex]midpoint \: of \: (x_{1},y_{1}), \: and \: (x_{2},y_{2}) \\ = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})[/tex]

[tex] midpoint \: of \: (-6,3), \: and \: (-10,7) = (\frac{-10 + -6}{2}, \frac{7 + 3}{2}) \: = (\frac{-16}{2}, \frac{10}{2}) \: = (-8,5)[/tex]

Answer:

22

Step-by-step explanation:

Let us interpret this problem;

        ---------------34-------------------

       P         Q       S      R            T

                    ----- 8 --------

        --------  --------- --------

             x        x         x

Let PQ = SQ = SR

Find RT;

    QS + SR = 8

    Also;

          x + x = 8

            2x = 8

              x = 4

To find RT;

    RT = PT - (PQ + QR)

   RT = 34 - (4 + 8) = 34 - 12 = 22

Answer:

22

Step-by-step explanation:

Answer:

x = -15/2 or -7.5

Step-by-step explanation:

6x - 4(x - 9) = 2(3 - x)

6x - 4x + 36 = 6 - 2x

2x + 36 = 6 - 2x

4x + 36 = 6

4x = -30

x = -30/4

x = -15/2

Check:

6(-7.5) + -4(-7.5 - 9) = 2(3 + 7.5)

-45 + 66 = 2(10.5)

21 = 21

Answer:

[tex]-\frac{15}{2}[/tex]

Step-by-step explanation:

6x-4(x-9)=2(3-x)

6x-4x+36=6-2x (expansion)

2x+36=6-2x (collecting like terms)

2x+2x=6-36

4x=-30 (-30/4)

x=-[tex]-\frac{15}{2}[/tex]    

Answer:

that all depends on the car mileage, say she gets 20 mpg itd be 20x22

Answer:

 y  = 72x

324miles

Step-by-step explanation:

Given parameters:

      Speed of the car = 72miles/hr

       distance  = y

        time  = xhrs

Unknown:

Write a direct variation equation for the distance=  ?

Distance covered in 4.5hrs =?

Solution:

A. Write a direct variation equation for the distance;

    A direct variation is a linear equation.

   It often takes the form y = kx

For this problem;

      Distance  = speed x time

input the parameters;

      y  = 72x

The direct variation equation is  y  = 72x

B. Distance traveled in 4.5hrs

   y  = 72x

  x is the time taken;

  So;

        y  = 72 x 4.5  = 324miles

4

rtbnjtfbu7yhjujkuf. ,i

Answer:3x41 squared

Step-by-step explanation:

Answer:

the answer should be 7a^3-4a^2-2a-87

Answer:

(7w + 9x)(7w - 9x)

Step-by-step explanation:

 Given expression;

        49w²  - 81x²

Now to solve the problem;

         49w² - 81x² = 7²w² - 9²x²

Using differences of two squares;

        x²  - y²   = (x + y)(x - y)

So;

7²w² - 9²x²  = (7w + 9x)(7w - 9x)

Answer:

[tex]Orchestral\ Time = \frac{3}{10}\ hour[/tex]

Step-by-step explanation:

Given

[tex]Time = 1\ hour[/tex]

[tex]Musical\ Pieces = \frac{3}{4}\ hour[/tex]

[tex]Practicing\ Sales = \frac{1}{4}\ hour[/tex]

Orchestral = [tex]\frac{2}{5}[/tex] of music practice time

Required

Determine time spent on orchestral pieces

From the given parameters, we have:

Orchestral = [tex]\frac{2}{5}[/tex] of music practice time

Substitute [tex]\frac{3}{4}\ hour[/tex] for music practice time.

So, we have:

[tex]Orchestral\ Time = \frac{2}{5} * \frac{3}{4}\ hour[/tex]

[tex]Orchestral\ Time = \frac{1}{5} * \frac{3}{2}\ hour[/tex]

[tex]Orchestral\ Time = \frac{3}{10}\ hour[/tex]

Answer:

8962

Step-by-step explanation:

8×1+9...etc..etc

= 8962

Answer:

8.962

Step-by-step explanation:

Answer:

J

Step-by-step explanation:

dude trust me

Step-by-step explanation:

Hey there!

The given points are; (4,4) and (1,2) as (x1,y1) and (x2,y2).

Note: Use double point formula for the equation.

Now;

[tex](y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)[/tex]

Put all values.

[tex](y - 4) = \frac{2 - 4}{1 - 4} (x - 4)[/tex]

Simplify it.

[tex](y - 4) = \frac{ - 2}{ - 3} (x - 4)[/tex]

[tex](y - 4) = \frac{2}{3} (x - 4)[/tex]

[tex](y - 4) = \frac{2}{3} x - \frac{2}{3} \times 4[/tex]

[tex]y = \frac{2}{3}x - \frac{8}{3} + 4 [/tex]

[tex]y = \frac{2}{3} x - \frac{8 + 12}{3} [/tex]

[tex]y = \frac{2}{3} x + \frac{4}{3} [/tex]

Therefore, the equation is; y = 2/3x+4/3.

Hope it helps...

Answer:

Step-by-step explanation:

First you determine the variables x and y as:

x: the value for student tickets

y: the value for chaperone tickets.

Knowing that student tickets cost $ 2 more than companion tickets, it is represented by the equation:

x= y +2

On the other hand, there were 59 students and 6 companions. And the total cost of admission for the group was $ 508, that is to say that what all the students and the companions have paid adds up to $ 508. Expressed by an equation:

59x + 6y = 508

Then the system of equations to solve and thus obtain the price of a student ticket and the price of a companion ticket is:

[tex]\left \{ {{x=y+2} \atop {59x+6y=508}} \right.[/tex]

Solving for x, the price of a student ticket:

Rearranging  the first equation,

y = x - 2

Replacing in the second equation and solving for x:

59*x + 6*(x -2)=508

59*x + 6*x -12=508

65*x -12=508

65*x= 508 +12

65*x= 520

[tex]x=\frac{520}{65}[/tex]

x=8

The cost of a student ticket is 8$

Answer:

I think the answer you are looking for is 10.

Step-by-step explanation:

-5 x -2 = 10

Answer:

it would be b

Step-by-step explanation:

Answer:

1=$1

2=$2

3=$3

4=$4

Step-by-step explanation:

Answer:

3b+b and 2(2b)

Step-by-step explanation:

BRAINLIEST APPRECIATED!

THANKS!

Answer:

The answer is (7.8046875)

Step-by-step explanation:

Hope this helped

Answer:

66⁰ + x = 111⁰

x = 111⁰ - 66⁰

x = 45⁰

Answer:

First, I am taking the interior angle E as 'y' to be able to use the angle sum property to find 'x'.

So we can find 'y' by using 'linear pair'.

So Exterior angle 'E'+y=180 Degree.

=  111+y=180

By transposing: y=180-11

And y= 69 degrees.

And now have angles y & 'Angle G' we can use Angle sum property to find 'x'

THEREFOR, y+x+angle G=180 degrees.

=  69 degrees+66 degrees+x=180 degrees

=  135 degrees+x=180 degrees

by transposing,

x= 180 degrees-135 degrees

And, x= 45 degrees

BY USING EXTERIOR ANGLE PROPERTY.

ACCORDING TO EXTERIOR ANGLE PROPERTY OF TRIANGLE: "An exterior angle of a triangle is equal to the sum of its interior opposite angles"

So, Exterior Angle E= x+ Angle G

=  111 degrees= x+ 66 degrees

By transposing, x= 111 degrees-66 degrees

=  x=45 degrees.

So no matter whichever method is used, the value of x= 45 degrees.