At a time of 30 seconds a runner passes a distance marker labeled "125 meters." If the velocity of the runner is +5.0 m/s, when did the runner pass the distance marker for 75 meters?

Answer:

W= 0.319992 J  and distance is 3.75 cm

Explanation:

The energy needed to stretch the spring from 30 cm to 45 cm = 3 J

Now we required to find the requirement of energy when the spring is stretched from 35 cm to 37 cm.

So first find the work done to stretch the spring from 35 cm to 45 cm.

Work done, w = (1/2) kx^2

3 = (1/2)k(0.45 – 0.30)^2

k = 266.66 N/m

now, x1 = 0.35 – 0.30 = 0.05m

x2 = 0.37 – 0.30 = 0.07m

Now the amount of work done to stretch from 35cm to 37.

w = (1/2) k (x2^2 – x1^2)

w = (1/2) (266.66) (0.07^2 – 0.05^2 )

w= 0.319992 J

(b). Given F = 10 N

F = kx

x = F / k

x = 10 / 266.66

x = 0.0375m

x = 3.75 cm

Thus, distance is 3.75cm

Answer:

The tangential speed is [tex]v = 7.5 m/s [/tex]

The centripetal acceleration is [tex]a = 154 \ m/s^2[/tex]

Explanation

Generally the angular velocity is mathematically represented as

[tex]w = e * \frac{ 2 \ pi \ rad }{s}[/tex]

substituting 3.27 rev/s for e we have that

[tex]w = 3.27 * \frac{ 2 \ pi \ rad }{s}[/tex]

=> [tex]w = 20.55 \ rad /s[/tex]

The tangential speed is mathematically represented as

[tex]v = w * r[/tex]

substituting 0.365 m for r we have that

[tex]v = 20.55 * 0.365 [/tex]

=> [tex]v = 7.5 m/s [/tex]

Generally the centripetal acceleration is mathematically represented as

[tex]a = \frac{v^2}{r}[/tex]

=>      [tex]a =  \frac{7.5^2}{ 0.365}[/tex]

=>      [tex]a =  154 \  m/s^2[/tex]

Answer:

t = 6.09 seconds

Explanation:

Given that,

Speed, v = 44.1 cm/s

Distance, d = 269 cm

We need to find the time interval of the marble. Speed is distance per unit time.

[tex]v=\dfrac{d}{t}\\\\\implies t=\dfrac{d}{v}\\\\t=\dfrac{269\ \text{cm}}{44.1\ \text{cm/s}}\\\\t=6.09\ s[/tex]

Hence, the time interval of the marble is 6.09 seconds.

Boron

Sillicon

Germanium

Arsenic

Antimony

Tellurium

Pelorium

Metallic characteristics: lustrous, solid at room temperature

In-between characteristics: semiconducting, amphoteric

Nonmetallic: brittle

The answer is 3.53400621

Reduce the expression, if possible, by cancelling common factors.

Answer: 3.53400621

Explanation: Hope this helped! :)

Answer:

Newton's first law

Explanation:

Newton's first law of motion says, that an object will stay in its current motion, unless if a force acts upon it.

So an object already at rest, will stay at rest. And the ball rolling will keep rolling, if no other force such as friction slows it down.

Answer:

their is always a animal or bug in nature

Explanation:

Momentum = (mass) x (speed)

We don't know the mass of the bowling ball, but we know how much it weighs.  So if we knew the acceleration of gravity in the place where the ball is, we could calculate its mass.  The question doesn't tell us what planet the bowling ball is on.  So if we only use the information given in the question, there's no way to find the answer, and we're stuck here.

But I urgently need the points, so I'm going to go out on a limb here and make a big assumption:  I'll assume that the alley where this ball is rolling and bowling is located on planet Earth, where the acceleration  of gravity is around  9.8 m/s²  everywhere on the planet's surface.  NOW I can go ahead and answer the question that I just invented.

weight = m  g

Mass = (weight) / (g)

Mass = (78.0 N) / (9.8 m/s²)

Mass = 7.96 kilograms

Momentum = (mass) x (speed)

Momentum = (7.96 kg) x (8.00 m/s)

Momentum = 63.7 kg-m/s

Answer:

8

Explanation:

Answer:

Chemical Properties of Oxygen

At standard temperature and pressure (STP), two atoms of the element bind to form dioxygen, a colorless, odorless, tasteless diatomic gas with the formula O2. Oxygen is a member of the chalcogen group on the periodic table and is a highly reactive nonmetallic element.

Explanation:

Answer:

Yes, it does

Explanation:

There are not many explanations, but when thermal energy is shined on an object it usually starts to heat up.

Answer: A. a straight line inclined to the time axis

Explanation:

Answer:

1.) 19.21 m/s

2.) 57 degree

Explanation: Given that a model airplane is flying north with a velocity of of 15m/s. A strong wind blowing east at 12m/s

The airplanes resultant speed can be calculated by using pythagorean theorem

R = sqrt ( 15^2 + 12^2 )

R = sqrt( 225 + 144 )

R = sqrt( 369 )

R = 19.21 m/s

The magnitude of the resultant vector is 19.21 m/s

The direction of velocity vector will be:

Tan Ø = 15 /12

Tan Ø = 1.25

Ø = tan^-1(1.25)

Ø = 57.04

Ø = 57 degree.

Therefore, the airplanes is heading 57 degree in the horizontal direction of velocity vector

Answer:

Now e is due to the ring at a

So

We say

1/4πEo(ea/ a²+a²)^3/2

= 1/4πEo ea/2√2a³

So here E is faced towards the ring

Next is E due to a point at the centre

So

E² = 1/4πEo ( e/a²)

Finally we get the total

Et= E²-E

= e/4πEo(2√2-1/2√2)

So the direction here is away from the ring

Answer:

40 m/s

Explanation:

Answer:

The answer to your question is C

Explanation:

acceleration is a vector quantity because it has both magnitude and direction

Answer:

removal of heat by cooling towers

Answer:

90 m

Explanation:

There are two unknowns: the amount of time the squirrel spent running, and the length of the race.  Let's call these t and x, respectively.

The average velocity is the total distance divided by the total time.

5.0 m/s = x / (t + 3.0)

The total distance is the time she spent running times the speed she ran at.

x = (6.0 m/s) t

Substitute and solve:

5 = 6t / (t + 3)

5 (t + 3) = 6t

5t + 15 = 6t

t = 15

She ran for 15 seconds (not including the 3 seconds she stopped).  So the length of the race is:

x = (6.0 m/s) (15 s)

x = 90 m

Answer:

The value is [tex]v_s = 1.394 \ m/s[/tex]

Explanation:

From the question we are told that

The frequency of the second player is [tex]f_2 = 490 \ Hz[/tex]

The beat frequency is [tex]f_b = 2.0 \ Hz[/tex]

The speed of sound is [tex]v_s = 343 \ m/s [/tex]

Generally the frequency of the note played by the first player is mathematically represented as

[tex]f_1 = f_2 + f_b[/tex]

=> [tex]f_1 = 490 + 2.0 [/tex]

=> [tex]f_1 = 492 Hz[/tex]

From the relation of Doppler Shift we have that

[tex]f_1 = \frac{ f_2 (v+ v_o )}{v-v_s }[/tex]

Here [tex] v_o\ is\ the\ velocity\ of\ the\ observer\ with\ value\ 0 \ m/s [/tex]

So

[tex]492 = \frac{ 490 (343+0 )}{343 -v_s }[/tex]

=> [tex]v_s = 1.394 \ m/s[/tex]

Answer:

A) When a wave goes through a substance, _______________ has occurred.

This is refraction or transmission.

Refraction refers to the changes in the wave that occur when it enters a new medium, in this case, the substance.

Transmission refers to the transfer of energy that is now in the medium.

Usually, we have both of those together.

B) When a wave gets trapped or stuck in a substance, ______________ has occurred.

This is total internal reflection. This happens when, by the Snel Law, the angle of the transmited wave is 90° (or larger) which is traduced in no transmitted wave, this is why the wave is "trapped" in the substance.

C) When a wave bounces off of a surface, ______________ has occurred.

This is reflection.

D) The ____________________ states that the angle of an incoming wave is equal to the angle of the reflected wave.

This is the Law of Reflection, that says "when light is reflected from a surface, the angle of reflection is the same as the angle of incidence"

Answer:

False

Explanation:

constant velocity is also 0 net force

Answer:

FALSE

Explanation:

The object can be at rest or also could be in uniform motion (moving with constant velocity)

Answer:

Y(1s) = [tex]10\sqrt{3}[/tex] - 10.1

X(1s) = 10m/s

Explanation:

In annex I've done the explanation for the equations that I will just present here.

Assuming that the arrow stars from the position (0 ; 0) in the Cartesian Graphic, and with Xo and Yo the initial speeds:

[tex]Yo =\frac{\sqrt{3} }{2} . Vr\\Yo = \frac{\sqrt{3} }{2} . 20\\Yo = 10\sqrt{3} m/s \\Xo = \frac{1}{2} Vr\\Xo = 10m/s[/tex]

Ignoring friction with air, Xo = Xf

So, Xo is the same during all the movement.

X(1s) = 10m/s

For Yo is different. That component is suferring reductions from gravity.

We can find Yo(1s) with one the basic functions of cinematics:

Vf = Vo + at

Vf = Final Velocity

Vo = Start Velocity

a = aceleration - gravity (g) is negative here

t = time

Yf = Yo + gt

Yf = [tex]10\sqrt{3}[/tex] - 10.1

If you prefere, can be: Yf = 10. ([tex]\sqrt{3} - 1[/tex])

Answer:

newton force is the state of gravity force they abstract when they came closer

Answer:

mass of the block is 7.2Kg

Tension on string A = 72N

Tension on the string with an angle is =  108N

Explanation:

The Horizontal string will have the cos component of the force...

Hence, mg cos60 = 36

by keeping acceleration due to gravity = 10 m/s^2, we get,

m = 7.2Kg

The tension in String A = mg = 7.2*10 = 72N

since the whole string holding the block is pulled by another string with 36 N

the resultant force will be the tension of the string with an angle.

Hence, 72 +36 = 108 N

Please let me know whether I got this right or not...

Answer:Alpha decay, type of radioactive disintegration in which some unstable atomic nuclei dissipate excess energy by spontaneously ejecting an alpha particle.

Explanation:

Following are the calculation to the given question:

Given:

Please find the given question.

To find:

value=?

Solution:

With terminal voltage, no force equals zero.

So,

[tex]\to mg = 6\times \pi \times \eta \times r\times \vartheta \\\\[/tex]

As [tex]35\ V[/tex] is weight neutralizing voltage

[tex]\to mg= q\times v \times r\\\\[/tex]

So,

[tex]\to q\times v \times r= 6 \times \pi \times \eta \times r \times \vartheta \\\\\to q\times v = 6 \times \pi \times \eta \times \vartheta \\\\\to q =\frac{6 \times \pi \times \eta \times \vartheta}{v} \\\\[/tex]

      [tex]=\frac{6 \times 3.14 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 18.84 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\ =3.2 \times 10^{-10}\ coulombs[/tex]

Therefore

[tex]\to q= n \times e\\\\[/tex]

Hence n comes to be [tex]2\times 10^9\[/tex] electrons.

Learn more:

brainly.com/question/12816494

Answer:

The Answer Is B not C

Explanation:

Answer:b

Explanation:

Answer:

1) 23 N.m²/C

2) The point charge is moved just outside the sphere

3) 30 N.m²/C

Explanation:

1) The flux through the field can be gotten by finding the dot product of the angle the later is turned, and the given uniform electric field.

25 * cos 25 =

25 * 0.9063 =

22.66 or approximately, 23 N.m²/C

2) The point charge is moved just outside the sphere

3) Using Gauss' Law, the electric flux through one face of the cube is given as Φ = Q / 6ε₀, thus,

Φ = 0.8*10^-9 / 6 * 8.85*10^-12

Φ = 0.8*10^-9 / 5.311*10^-11

Φ = 15 N.m²/C

And therefore, the flux through any 2 faces of the cube is 2 * 15 = 30 N.m²/C

Answer:

F = 0.012 N

Explanation:

Given that,

Mass of the object, m = 6 g

Acceleration, a = 2 m/s²

1 kg = 1000 grams

6 g = 0.006 kg

Force, F = ma

So,

[tex]F=0.006\ kg\times 2\ m/s^2\\F=0.012\ N[/tex]

So, the force is 0.012 N.

Explanation:

Average speed = change in distance / change in time

In other words, the average speed is the slope of the line connecting two points on the graph.