At a particular chess club, it is quite common for a chess game to take over two hours to complete. Suppose that the lengths of these games are normally distributed with a mean of 153 minutes and a standard deviation of 45 minutes. Games which last in the longest 1% of all contests are given special recognition on an "Endurance Board" for all club members to see. How long would a game need to last to qualify for the "Endurance Board?"

Answer:

Create a table of xy values or use a graphing calc.

Step-by-step explanation:

Answer:

Three points you can plot are: (-6, -3.5) (-7, -5) (0, 5.5).

Step-by-step explanation:

You can use a graphing calculator to determine the points. Attached is an image.

Hope this helps! :)

Answer: 0.5

Step-by-step explanation:

To find the slope of a line with two given points, you use the formula [tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex].

[tex]m=\frac{2-1}{4-2}=\frac{1}{2}=0.5[/tex]

The slope is 0.5.

Answer:

1. 60 in cubed.

2. 36 m cubed.

3. 96 m cubed.

4. 60 yds cubed.

5. 120 in cubed.

Step-by-step explanation:

Alright, we need to know what the formula is for the volume of a triangular prism. Before that, here is the formula to find the volume of all shapes. Some formulas may be different for cones, spheres, and pyramids, but this is the general formula.

The formula is V=Bh.

V is your volume

B is the area of the base

h is the height of the prism..

The formula for calculating the volume for a triangular prism is 1/2bh times h. 1/2bh is the formula for finding the area of your triangle which is the base shape for a triangular prism. The other h is the height of your prism.

For number 1, they already calculated the area of the base for you, so just multiply that number with the height. 20 times 3 is 60.

That is 60 meters cubed.

Number 2, they haven't calculated the area of the base, so you have to do that. The length of the triangle is 4 and the height of the triangle is 3. Lets find the area of the triangle or the base, Do 4 times 3 which is 12 and divide it by 2 or multiply it by half. it is the same thing. You get 6, and that is the area of your base. Multiply that area by the height of the prism. You get 36 meters cubed. The reason why it is cubed is because meter times meter times meter is meter cubed.

Hope this helps!

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population proportion significantly differs from 0.89.

The requirements for the test are satisfief.

n(1-p)=70>10

Step-by-step explanation:

This is a hypothesis test for a proportion.

There are 3 requirements to have a valid test of proportion: random sample, independence and normal.

For the first two (random and independent sample) we don't have details, but we assume the sampling has been random.

The latter can be verified by calculating np and n(1-p):

[tex]np=430>10\\\\n(1-p)=70>10[/tex]

Both are bigger than 10, so the normal approximation can be considered appropiate.

The claim is that the population proportion significantly differs from 0.89.

Then, the null and alternative hypothesis are:

[tex]H_0: \pi=0.89\\\\H_a:\pi\neq 0.89[/tex]

The significance level is 0.01.

The sample has a size n=500.

The sample proportion is p=0.86.

[tex]p=X/n=430/500=0.86[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.89*0.11}{500}}\\\\\\ \sigma_p=\sqrt{0.000196}=0.014[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.86-0.89+0.5/500}{0.014}=\dfrac{-0.029}{0.014}=-2.072[/tex]

This test is a two-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=2\cdot P(z<-2.072)=0.038[/tex]

As the P-value (0.038) is greater than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population proportion significantly differs from 0.89.

Answer:

When f(x) = 2, x = 1/2, -2/3

Step-by-step explanation:

Step 1: Set equation equal to 2

[tex]2 = \frac{x-2}{3x^2 +x -2}[/tex]

Step 2: Multiply both sides by denominator

2(3x² + x - 2) = x - 2

Step 3: Distribute

6x² + 2x - 4 = x - 2

Step 4: Isolate everything to one side

6x² + x - 2 = 0

Step 5: Factor

(2x - 1)(3x + 2) = 0

Step 6: Find roots

x = 1/2, -2/3

Answer: r = 1/9

Step-by-step explanation:

y = rx  -->  [tex]r=\dfrac{y}{x}[/tex]

[tex]1)\ y=1\dfrac{2}{9}\rightarrow\dfrac{11}{9}\\\\.\quad x=11\\\\r=\dfrac{11}{9}\div11\\\\\\r=\dfrac{11}{9}\times \dfrac{1}{11}\quad =\large\boxed{r=\dfrac{1}{9}}[/tex]

[tex]2)\ y=2\dfrac{1}{3}\rightarrow\dfrac{7}{3}\\\\.\quad x=21\\\\r=\dfrac{7}{3}\div21\\\\\\r=\dfrac{7}{3}\times \dfrac{1}{21}\quad =\large\boxed{r=\dfrac{1}{9}}[/tex]

[tex]3)\ y=5\\\\.\quad x=45\\\\r=5\div45\\\\\\r=\dfrac{5}{45}\quad =\large\boxed{r=\dfrac{1}{9}}[/tex]

Answer:

Ivy's definition matches the comment that starts with "Sorry, this is incorrect. An ellipse..." because she didn't specify that the points that belong to the circle must be the same distance away from the center point. According to Ivy's definition, any curved and closed shape would be a circle but that's not true. For example, like the teacher said, an ellipse would match her circle definition but an ellipse is not a circle, it's more like an oval-ish shape. Ethan's definition is correct. Ebuka's definition matches the comment that starts with "Your definition is close..." because he/she didn't say that the shape must be closed. According to Ebuka's definition, an incomplete curve could count as a circle but that's not true, for example, as the teacher said, a semicircle is not a circle.

Answer: brainliest plz:)

ivy is the 3

ethan is correct

ebuka is close

Step-by-step explanation:

ivy is not even close to the correct

ethan got it right on and the last one was really close but not quite

Answer:

133

Step-by-step explanation:

1000 = 2 * 2 * 2 * 5 * 5 * 5

To not have a multiple of 10, you cannot have 2 and 5 as factors of the same number.

One number is 2^3 = 8.

The other number is 5^3 = 125.

8 * 125 = 1000, so the two do multiply to 1000.

Neither 8 nor 125 is a multiple of 10.

8 + 125 = 133

Answer:

133

Step-by-step explanation:

We are given that the product of two numbers is 1000. Let's first list out the factors of 1000 (factors are numbers that evenly divide into 1000):

1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

We see that the pairs are:

(1, 1000)

(2, 500)

(4, 250)

(5, 200)

(8, 125)

(10, 100)

(20, 50)

(25, 40)

An easy way to see if a number is divisible by 1000 is to check is it has a zero at the end. Notice that all of the pairs have at least one number that ends with at least 1 zero except (8, 125), so this is the pair of numbers we're looking for.

The sum is thus 8 + 125 = 133.

~ an aesthetics lover

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of moving violations for which the individual was cited during the last 3 years. The pmf of Y is:

y    |    P(Y)    

0    |     0.50  

1     |     0.20

2    |     0.25

3    |     0.05

Compute E(Y)

Suppose an individual with Y violations incurs a surcharge of $100Y2. Calculate the expected amount of the surcharge.

Answer:

The expected value E(Y) is

[tex]E(Y) = 0.85[/tex]

The expected amount of the surcharge is

[tex]E(100Y^2) = 165[/tex]

Step-by-step explanation:

Let Y be the number of moving violations for which the individual was cited during the last 3 years.

The given probability mass function (pmf) of Y is

y    |    P(Y)    

0    |     0.50  

1     |     0.20

2    |     0.25

3    |     0.05

Compute E(Y)

The expected value E(Y) is given by

[tex]E(Y) = \sum Y \cdot P(Y) \\\\E(Y) = 0 \cdot 0.50 + 1 \cdot 0.20 + 2 \cdot 0.25 + 3 \cdot 0.05 \\\\E(Y) = 0.85[/tex]

Suppose an individual with Y violations incurs a surcharge of $100Y2. Calculate the expected amount of the surcharge.

The expected amount of the surcharge is given by

[tex]E(100Y^2) = 100E(Y^2)[/tex]

Where

[tex]E(Y^2) = \sum Y^2 \cdot P(Y) \\\\E(Y^2) = 0^2 \cdot 0.50 + 1^2 \cdot 0.20 + 2^2 \cdot 0.25 + 3^2 \cdot 0.05\\\\E(Y^2) = 1.65[/tex]

So, the expected amount of the surcharge is

[tex]E(100Y^2) = 100E(Y^2) \\\\E(100Y^2) = 100 \cdot 1.65 \\\\E(100Y^2) = 165[/tex]

Answer:

5

Step-by-step explanation:

h(2)=5(2)-5

5 x 2 = 10

10 - 5 = 5

The value of the function h(x) = 5x - 5 at x = 2 will be 5.

When the relevant factors and natural laws of a mathematical model are given values, the outcome of the calculation it describes is the expression's outcome.

The function is given below.

h(x) = 5x - 5

Then the value of the function at x = 2 will be

h(2) = 5 (2) - 5

h(2) = 10 - 5

h(2) = 5

The value of the function h(x) = 5x - 5 at x = 2 will be 5.

More about the value of expression link is given below.

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Answer:

(a) The odds for and against E are (8:1) and (1:8) respectively.

(b) The odds for and against E are (7:2) and (2:7) respectively.

(c) The odds for and against E are (59:41) and (41:59) respectively.

(d) The odds for and against E are (71:29) and (29:71) respectively.

Step-by-step explanation:

The formula for the odds for an events E and against and event E are:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}[/tex]

(a)

The probability of the event E is:

[tex]P(E)=\frac{8}{9}[/tex]

Compute the odds for and against E as follows:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}=\frac{8/9}{1-(8/9)}=\frac{8/9}{1/9}=\frac{8}{1}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}=\frac{1-(8/9)}{8/9}=\frac{1/9}{8/9}=\frac{1}{8}[/tex]

Thus, the odds for and against E are (8:1) and (1:8) respectively.

(b)

The probability of the event E is:

[tex]P(E)=\frac{7}{9}[/tex]

Compute the odds for and against E as follows:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}=\frac{7/9}{1-(7/9)}=\frac{7/9}{2/9}=\frac{7}{2}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}=\frac{1-(7/9)}{7/9}=\frac{2/9}{7/9}=\frac{2}{7}[/tex]

Thus, the odds for and against E are (7:2) and (2:7) respectively.

(c)

The probability of the event E is:

[tex]P(E)=0.59[/tex]

Compute the odds for and against E as follows:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}=\frac{0.59}{1-0.59}=\frac{0.59}{0.41}=\frac{59}{41}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}=\frac{1-0.59}{0.59}=\frac{0.41}{0.59}=\frac{41}{59}[/tex]

Thus, the odds for and against E are (59:41) and (41:59) respectively.

(d)

The probability of the event E is:

[tex]P(E)=0.71[/tex]

Compute the odds for and against E as follows:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}=\frac{0.71}{1-0.71}=\frac{0.71}{0.29}=\frac{71}{29}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}=\frac{1-0.71}{0.71}=\frac{0.29}{0.71}=\frac{29}{71}[/tex]

Thus, the odds for and against E are (71:29) and (29:71) respectively.

Answer:

We failed to reject H₀

t < 2.06

1.5 < 2.06

We do not have significant evidence at significance level α=0.05 to show that the mean G.P.A. of CC students transferring to Sac State is above 3.3

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: μ = 3.3

Alternate hypotheses = H₁: μ > 3.3

Determine type of test:

Since the alternate hypothesis states that mean G.P.A. of CC students transferring to Sac State is above 3.3, therefore we will use a upper-tailed test.

Select the test statistic:  

Since the sample size is very small (n < 30) therefore, we will use t-distribution.

Determine level of significance and critical value:

Given level of significance = 5% = 0.05

Since it is a upper tailed test,

At α = 0.05 and DF = n – 1 =  25 - 1 = 24

t-score =  2.06

Set up decision rule:

Since it is a upper tailed test, using a t statistic at a significance level of 5%

We Reject H₀ if t > 2.06

Compute the test statistic:

[tex]$ t = \frac{\bar{x}-\mu}{\frac{s}{\sqrt{n} } } $[/tex]

[tex]$ t = \frac{ 3.45- 3.3 }{\frac{0.5}{\sqrt{25} } } $[/tex]

[tex]t = 1.5[/tex]

Conclusion:

We failed to reject H₀

t < 2.06

1.5 < 2.06

We do not have significant evidence at significance level α=0.05 to show that the mean G.P.A. of CC students transferring to Sac State is above 3.3

Answer:

1/10 per sec

Step-by-step explanation:

When he's walked x feet in the eastward direction, the angle Θ that the search light makes has tangent

tanΘ = x/18

Taking the derivative with respect to time

sec²Θ dΘ/dt = 1/18 dx/dt.

He's walking at a rate of 18 ft/sec, so dx/dt = 18.

After 3seconds,

Speed = distance/time

18ft/sec =distance/3secs

x = 18 ft/sec (3 sec)

= 54ft. At this moment

tanΘ = 54/18

= 3

sec²Θ = 1 + tan²Θ

1 + 3² = 1+9

= 10

So at this moment

10 dΘ/dt = (1/18ft) 18 ft/sec = 1

10dΘ/dt = 1

dΘ/dt = 1/10 per sec

At 1/10 per second is the rate when the light turns 3 seconds after he started walking east.

It is given that a man starts at point A and walks 18 feet north. He then turns and walks due east at 18 feet per second.

It is required to find at what rate is the light turning 3 seconds after he started walking east.

The trigonometric ratio is defined as the ratio of the pair of a right-angled triangle.

The [tex]\rm tan\theta[/tex] is the ratio of the perpendicular to the base.

When he started walking eastward direction, the searchlight makes an angle [tex]\theta[/tex]

Let the distance is x

And the  [tex]\rm tan\theta = \frac{x}{18}[/tex]

After performing the derivate with respect to time, we get:

[tex]\rm sec^2\theta\frac{d\theta}{dt} = \frac{1}{18} \frac{dx}{dt}[/tex] ...(1)    ( the differentiation of [tex]\rm tan\theta \ is \ sec^2\theta\\[/tex])

He walking at the rate of 18 ft per second ie.

[tex]\rm \frac{dx}{dt} = 18[/tex]  

After 3 seconds  [tex]\rm Speed=\frac{Distance}{Time}[/tex]

By using speed- time formula we can calculate the distance:

Distance x = 18×3 ⇒ 54 ft.

[tex]\rm tan\theta = \frac{54}{18}[/tex]  ⇒3

We know that:

[tex]\rm sec^2\theta = 1+tan^2\theta[/tex]

[tex]\rm sec^2\theta = 1+3^2\\\\\rm sec^2\theta = 10\\[/tex]

Put this value in the (1) equation, we get:

[tex]\rm 10\frac{d\theta}{dt} = \frac{1}{18} \times18[/tex]    ∵ [tex]\rm (\frac{dx}{dt} =18)[/tex]

[tex]\rm 10\frac{d\theta}{dt} = 1\\\\\rm \frac{d\theta}{dt} = \frac{1}{10} \\\\[/tex]per second.

Thus, at 1/10 per second what rate is the light turning 3 seconds after he started walking east.

Know more about trigonometry here:

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1) The marginal profit is [tex]4.3 - 0.7 ln(x)[/tex].

2) The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.

Thus, option (A) is correct.

C) To maximize profit 462,481 thousands of candles should be sold.

Given: [tex]P(x) = 5 x - 0.7 x[/tex] [tex]{\text}ln x.[/tex]

1) Take the derivative of the profit function P(x) with respect to x.

P(x) = 5x - 0.7x ln(x)

To find P'(x), differentiate each term separately using the power rule and the derivative of ln(x):

[tex]P'(x) = 5 - 0.7(1 + ln(x))[/tex]

       = [tex]5 - 0.7 - 0.7 ln(x)[/tex]

       = [tex]4.3 - 0.7 ln(x)[/tex]

2) Substitute x = 10 into the derivative:

P'(10) = 4.3 - 0.7 ln(10)

         = 4.3 - 0.7(2.30259)

         = 4.3 - 1.61181

         = 2.68819

Therefore, the additional profit for selling a thousand candles once 10,000 candles have already been sold.

Thus, option (A) is correct.

C) Set P'(x) = 0 and solve for x:

[tex]4.3 - 0.7 ln(x) = 0[/tex]

[tex]0.7 ln(x) = 4.3[/tex]

[tex]{\text} ln(x) = 4.3 / 0.7[/tex]

[tex]{\text} ln(x) = 6.14286[/tex]

[tex]x = e^{6.14286[/tex]

[tex]x = 462.481[/tex]

Therefore, 462,481 thousands of candles should be sold.

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1) The marginal profit, P'(x), is -0.7ln(x) + 4.3.

2) The number of thousands of candles that should be sold to maximize profit is approximately 466.9.

1) To find the marginal profit, P'(x), we need to take the derivative of the profit function, P(x), with respect to x. Using the power rule and the chain rule, we can differentiate the function:

P(x) = 5x - 0.7x ln(x)

Taking the derivative with respect to x:

P'(x) = 5 - 0.7(ln(x) + 1)

Simplifying:

P'(x) = 5 - 0.7ln(x) - 0.7

P'(x) = -0.7ln(x) + 4.3

2) To find P'(10), we substitute x = 10 into the marginal profit function:

P'(10) = -0.7ln(10) + 4.3

Using a calculator, we can evaluate this expression:

P'(10) ≈ -0.7(2.3026) + 4.3 ≈ -1.6118 + 4.3 ≈ 2.6882

The value of P'(10) is approximately 2.6882.

Now, let's interpret what P'(10) represents:

The correct interpretation is A. The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.

P'(10) represents the rate at which the profit is changing with respect to the number of candles sold when 10,000 candles have already been sold. In other words, it measures the additional profit (in thousands of dollars) for each additional thousand candles sold once 10,000 candles have already been sold.

Lastly, to determine the number of thousands of candles that should be sold to maximize profit, we need to find the critical points of the profit function P(x). This can be done by setting the derivative P'(x) equal to zero and solving for x.

-0.7ln(x) + 4.3 = 0

-0.7ln(x) = -4.3

ln(x) = 4.3 / 0.7

Using properties of logarithms:

x = e^(4.3 / 0.7)

Using a calculator, we can evaluate this expression:

x ≈ e^(6.1429) ≈ 466.9

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Answer:

6

Step-by-step explanation:

you have to distributw the 4 to the 1/4 so essentially youre multiplying the exponents. think of it as 4*1/4 and youll have 4/4 which equals to 1. 6^1 is just 6 so thats the answer

well first you have to multiply 6 by 1/4 and then you have to do this: 1.5*1.5*1.5*1.5 to get your answer i think....

Answer:

Step-by-step explanation:

The total number of ratio units is 5+4 = 9, so each of them represents ...

  (54 g)/9 = 6 g

of fruit. Multiplying the ratio by this value shows you the amount of each kind of fruit:

  strawberry : blueberry = 5 : 4 = 5(6 g) : 4(6 g)

  strawberry : blueberry = 30 g : 24 g

There are 30 g of strawberry and 24 g of blueberry in the smoothie.

Answer:

7

Step-by-step explanation:

Remove parentheses.

[tex]\frac{-8+4(4.5)}{6.25-8.25} \\[/tex]

Add −8 and 4.5.

[tex]\frac{4(-3.5)}{6.25 - 8.25} \\\\[/tex]

Subtract 8.25 from 6.25.

[tex]\frac{4*-3.5}{-2}[/tex]

Multiply 4 by −3.5.

[tex]\frac{-14}{-2}[/tex]

Divide −14 by −2.

= 7

Answer:

c. 0.10

Step-by-step explanation:

Hello!

To accept a batch of components, the proportion of defective components is at most 0.10.

X: Number of defective components in a sample of 10.

This variable has a binomial distribution with parameters n=10 and p= 0.10 (for this binomial experiment, the "success" is finding a defective component)

The distributor will accept the batch if at most two components are defective, symbolically:

P(X≤2)

Using the tables for the binomial distribution you can find the accumulated probability for a sample of n=10 with probability of success of p= 0.10 and number of successes x= 2

P(X≤2)= 0.9298

I hope this helps!

Answer:

a [tex]\mathbf{P(X=3)=0.1406}[/tex]

b [tex]\mathbf{\[P\left( {X = 3 \ or \ 4 } \right) = 0.1025}[/tex]

c  [tex]\mathbf{\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = 0.1035}[/tex]

Step-by-step explanation:

Given that:

In a multiple choice quiz:

there are 5 questions

and 4 choices for each question (a, b, c, d)

let X be the correctly answered question = 1 answer only

and Y be the choices for each question = 4 choices

The probability that Robin guessed the correct answer is:

Probability = n(X)/n(Y)

Probability = 1//4

Probability = 0.25

The probability mass function is :

[tex]P(X=x)=0.25 (1-0.25)^{x-1}[/tex]

We are to find the required probability that the first question she gets right is the 3rd question.

i.e when x = 3

[tex]P(X=3)=0.25 (1-0.25)^{3-1}[/tex]

[tex]P(X=3)=0.25 (0.75)^{2}[/tex]

[tex]\mathbf{P(X=3)=0.1406}[/tex]

b) Find the probability that  She gets exactly 3 or exactly 4 questions right

we know that :

n = 5 questions

Probability P =0.25

Let represent X to be the number of questions guessed correctly i,e 3 or 4

Then; the probability mass function can be written as:

[tex]\[P\left( {X = x} \right) = \left( {\begin{array}{*{20}{c}}\\5\\\\x\\\end{array}} \right){\left( {0.25} \right)^x}{\left( {1 - 0.25} \right)^{5 - x}}\][/tex]

[tex]P(X = 3 \ or \ 4)= P(X =3) +P(X =4)[/tex]

[tex]\[P\left( {X = 3 \ or \ 4 } \right) = \left( {\begin{array}{*{20}{c}}\\5\\\\3\\\end{array}} \right){\left( {0.25} \right)^3}{\left( {1 - 0.25} \right)^{5 - 3}}\] + \left( {\begin{array}{*{20}{c}}\\5\\\\4\\\end{array}} \right){\left( {0.25} \right)^4}{\left( {1 - 0.25} \right)^{5 - 4}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 } \right) = \dfrac{5!}{3!(5-3)!}\right){\left( {0.25} \right)^3}{\left( {1 - 0.25} \right)^{5 - 3}}\] + \dfrac{5!}{4!(5-4)!} \right){\left( {0.25} \right)^4}{\left( {1 - 0.25} \right)^{5 - 4}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 } \right) = \dfrac{5!}{3!(2)!}\right){\left( {0.25} \right)^3}{\left( {0.75} \right)^{2}}\] + \dfrac{5!}{4!(1)!} \right){\left( {0.25} \right)^4}{\left( {0.75} \right)^{1}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 } \right) = 0.0879+0.0146[/tex]

[tex]\mathbf{\[P\left( {X = 3 \ or \ 4 } \right) = 0.1025}[/tex]

c) Find the probability if She gets the majority of the questions right.

We know that the probability mass function is :

[tex]\[P\left( {X = x} \right) = \left( {\begin{array}{*{20}{c}}\\5\\\\x\\\end{array}} \right){\left( {0.25} \right)^x}{\left( {1 - 0.25} \right)^{5 - x}}\][/tex]

So; of She gets majority of her answers right ; we have:

The required probability is,

[tex]P(X>2) = P(X=3) +P(X=4) + P(X=5)[/tex]

∴

[tex]\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = \left( {\begin{array}{*{20}{c}}\\5\\\\3\\\end{array}} \right){\left( {0.25} \right)^3}{\left( {1 - 0.25} \right)^{5 - 3}}\] + \left( {\begin{array}{*{20}{c}}\\5\\\\4\\\end{array}} \right){\left( {0.25} \right)^4}{\left( {1 - 0.25} \right)^{5 - 4}}\]+ \left( {\begin{array}{*{20}{c}}\\5\\\\5\\\end{array}} \right){\left( {0.25} \right)^5}{\left( {1 - 0.25} \right)^{5 - 5}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = \dfrac{5!}{3!(5-3)!}\right){\left( {0.25} \right)^3}{\left( {1 - 0.25} \right)^{5 - 3}}\] + \dfrac{5!}{4!(5-4)!} \right){\left( {0.25} \right)^4}{\left( {1 - 0.25} \right)^{5 - 4}}\] + \dfrac{5!}{5!(5-5)!} \right){\left( {0.25} \right)^5}{\left( {1 - 0.25} \right)^{5 - 5}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = \dfrac{5!}{3!(5-3)!}\right){\left( {0.25} \right)^3}{\left( {1 - 0.75} \right)^{2}}\] + \dfrac{5!}{4!(5-4)!} \right){\left( {0.25} \right)^4}{\left( {0.75} \right)^{1}}\] + \dfrac{5!}{5!(5-5)!} \right){\left( {0.25} \right)^5}{\left( {0.75} \right)^{0}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = 0.0879 + 0.0146 + 0.001[/tex]

[tex]\mathbf{\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = 0.1035}[/tex]

Answer:

Step-by-step explanation:

the mass is 2000 mg, or 2 g.

the density is 8 g/cm^3

divide 2 by 8

0.25 cm^3

if this helped, mark as brainliest :)

Answer:

Option A is the right option.

Step-by-step explanation:

Sum of angles in triangle= 180°

[tex]85 + 53 + m < a = 180 \\ or \: 138 + m < a = 180 \\ or \:m < a = 180 - 138 \\ m < a = 42[/tex]

Applying sine rule:

[tex] \frac{sin \: a \: }{a} = \frac{sin \: b}{b} = \frac{sin \: c}{c} \\ \frac{sin \: b}{b} = \frac{sin \: c}{c} \\ \frac{sin \: (85)}{b} = \frac{sin(42)}{85} \\ 85 \: sin \: (85) = \: b \: sin \: (42) \\ b = \frac{85 \: sin \: (85)}{sin \: 42} \\ ac = 126.6[/tex]

Hope this helps....

Good luck on your assignment...

Answer: 8 & 13

Step-by-step explanation:

13 squared is 169 and 8 squared is 64, and the difference of those two squares would be 169 - 64 = 105. Hope this helps!

Answer:

[tex]\frac{7\sqrt{x} }{x}[/tex]

Step-by-step explanation:

To simplify 7/√x, we need to rationalize:

[tex]\frac{7}{\sqrt{x} } (\frac{\sqrt{x} }{\sqrt{x} } )[/tex]

When we multiply the 2, we should get our answer:

[tex]\frac{7\sqrt{x} }{x}[/tex]

Answer:

[tex]\frac{7\sqrt{x} }{x}[/tex]

Step-by-step explanation:

[tex]\frac{7}{\sqrt{x} } \\\\\frac{7}{\sqrt{x} } * \frac{\sqrt{x} }{\sqrt{x} } \\\\\frac{7\sqrt{x} }{\sqrt{x\sqrt{x} } } \\[/tex]

[tex]\frac{7\sqrt{x} }{x}[/tex]

Hope this helps! :)

Answer:

170

one-hundred seventy

Step-by-step explanation:

[tex]2(5(7+4(17 - 9)-22))=\\2(5(7+4(8)-22))=\\2(5(7+32-22))=\\2(5(39-22))=\\2(5(17))=\\2(85)=\\170[/tex]

Answer:

170.

Step-by-step explanation:

2{ 5[7 + 4(17 - 9) - 22]}

2{5[7+32 -22]}

2{5[17]}

2[85] = 170

Answer:

True.

Step-by-step explanation:

Try out some numbers:

3 + 3 = 6

5 + 5 = 10

11 + 11 = 22

Answer:

It is AA

Step-by-step explanation:

Answer:

Step-by-step explanation:

To get the missing values in the table, we will factorize the given expression and compare the factored expression with the expression containing the missing constants.

1) For the expression x²+2x-8, on factorizing we have;

x²+2x-8

= (x²+4x)-(2x-8)

Factoring out the common terms from both parenthesis;

= x(x+4)-2(x+4)

= (1x+4)(1x-2)

=  (1x-2)(1x+4)

Comparing the resulting expression with (ax+b)(cx+d)

a = 1, b = -2, c = 1 and d = 4

2) For the expression 2x³+2x²-24x

Factoring out the common term we will have;

= 2x(x²+x-12)

= 2x(x²-3x+4x-12)

= 2x{x(x-3)+4(x-3)}

= 2x{(x+4)(x-3)}

=  2x(1x-3)(1x+4)

Comparing the resulting expression with 2x(ax+b)(cx+d)

a = 1, b = -3. c = 1 and d = 4

3) For the expression 6x²-15x-9 we will have;

On simplifying,

= 6x²+3x-18x-9

= 3x(2x+1)-9(2x+1)

= (3x-9)(2x+1)

Comparing the resulting expression with (ax+b)(cx+d)

a = 3, b = -9, c = 2 and d = 1

Answer:

see picture attachment

Step-by-step explanation:

Answer:

See Explanation

Step-by-step explanation:

Given:

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).

(a)If we translate  quadrilateral JKLM 3 units down and 3 units left:

(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)

Therefore, we match it with: A translation 3 units down and 3 units left

(b)If we translate  quadrilateral JKLM 2 units right and 3 units down:

(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)

Therefore, we match it with:A translation 2 units right and 3 units down

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:

A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)

(d)If we translate  quadrilateral JKLM 3 units left and 2 units up:

(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)

Therefore, we match it with: A translation 3 units left and 2 units up

(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

No suitable transformation is found from JKLM to STUV.

Answer:

a translation 3 units down and 3 units left

W(5,1), X(1,7), Y(9,9), and Z(11,7)

a translation 2 units right and 3 units down

O(10,1), P(6,7), Q(14,9), and R(16,7)

a sequence of reflections across the

x- and y-axes, in any order

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

a translation 3 units left and 2 units up

E(5,6), F(1,12), G(9,14), and H(11,12)